I´ve a small app with a UIWebView for web surfing in it. On some pages opens the Appstore for promotional purposes (that is annoying). How can i prevent that? Is there a special method? or just fake the browserid?
http://bjango.com/articles/ituneslinks/
here is the complete reference for link formation of the appstore, itunes.
from above reference link, apple.com is common for all kind of links.
So we can create regex or simply search string "apple.com" from url and avoid to load in webview.
If you wanna,use without regex following code may be help you :
-(BOOL) webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType
{
NSURL *currentURL = request.URL;
NSString *urlString = url.absoluteString;
NSRange range = [urlString rangeOfString:#"apple.com"];
if (range.location != NSNotFound)
return YES;
else
return NO;
}
Use UIWebViewDelegate method webView:shouldStartLoadWithRequest:navigationType: to detect what URLs are getting loaded in the webview. App store URLs usually contain itunes.apple.com or phobos.apple.com.
When you encounter such urls are clicked, you can return NO from the web view delegate method to stop loading the url.
Hope that helps!
Use the following UIWebView Delegate method for this :
-(BOOL) webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType
{
NSURL *currentURL = request.URL;
NSString *urlString = url.absoluteString;
NSRange range = [urlString rangeOfString:#"https://itunes.apple.com"]; // Change URL if other than this.
if (range.location != NSNotFound)
return YES;
else
return NO;
}
Related
i am currently using http://something.com this link inside the uiwebview for my ios app. In this dummy website there is another link. I wanna open native ios camera screen after clicking this link. Right now i am able to open cam only for http://something.com this url. But i need to open the cam by clicking another link inside this http://something.com. When i click the other link url is changing to ``http://something.com\webapp`. So how can i make it work? Any ideas?
- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType {
NSURL *url = request.URL;
NSString *urlString = url.absoluteString;
NSRange range = [urlString rangeOfString:#"http://something.com"];
if (range.location != NSNotFound) {
[self showCamera]; //camera starts
return YES;
} else {
return NO;
}
This should do the trick:
if ([request.URL.absoluteString containsString:#"webapp"]) {
[self showCamera];
return NO;
} else {
return YES;
}
I'm trying to get my webview's current URL by using the following code in webViewDidStartLoad:
NSString *currentURL = _webview.request.URL.absoluteString;
I set a break point and I found out that currentURL is actually empty. I went through the Internet some saying that you won't be able to get the URL until the webpage has compeletely loaded. Is that true?
You are trying to get the current URL of the webpage. You just have to log the request object and that will give you the URL that you clicked on the webview.
- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)**request** navigationType:(UIWebViewNavigationType)navigationType{
NSLog(#"request on invite -=- %#", request);
}
You just have to use that request object and this will provide you the URL that is clicked.
Try to implement the following feature
<UIWebViewDelegate>
webview.delegate = self;
- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType{
return YES;
}
//get url from webView augment variable
- (void)webViewDidStartLoad:(UIWebView *)webView{
NSString *currentURL = webView.request.URL.absoluteString;
NSLog(#"url:%#",currentURL);
}
NSString *testString =[NSString stringWithFormat:#" Google"];
[webView loadHTMLString:testString baseURL:nil];
I want to get the URL when I click on this UIWebView content in
-(BOOL) webView:(UIWebView *)inWeb shouldStartLoadWithRequest:(NSURLRequest *)inRequest navigationType:(UIWebViewNavigationType)inType {
if ( inType == UIWebViewNavigationTypeLinkClicked ) {
[[UIApplication sharedApplication] openURL:inRequest.mainDocumentURL];
return NO;
}
return YES;
}
delegate method.
When I click google hyperlink in webview it gives
URL: applewebdata://
Please help me.
You question is not very clear if you want to get the tapped url on webview or the webview's loaded page url ,
If you want to get webview loaded page url you can use NSURLRequestObject,something like
NSString * url = [request URL];
If you want to get the clicked link url , you will have to use this java script
NSString *url = [webView stringByEvaluatingJavaScriptFromString:#"window.location"];
you can do like this way
-(BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType
{
if ([request.URL.absoluteString rangeOfString:#"www.google.com"].location!=NSNotFound)
{
[[UIApplication sharedApplication]openURL:request.URL];
return NO;
}
return YES;
}
For Swift:
Whenever your webpage is loaded you can use this, I use it for a label in this case:
webUrlLabel.text = webView.request.URL.absoluteString
For Objective-C:
NSString *currentPage = [NSString stringWithFormat:#"%#", webView.request.URL.absoluteString];
webUrlLabel is a UILabel
webView is my UIWebView
You already have NSURLRequest object. Access url from that.
inRequest.URL
way 1:
NSString *currentURL = myWebView.request.URL.absoluteString;
Way 2:
- (BOOL)webView:(UIWebView*)webView shouldStartLoadWithRequest:(NSURLRequest*)request navigationType:(UIWebViewNavigationType)navigationType {
//CAPTURE USER LINK-CLICK.
NSURL *url = [request URL];
yourTextBox.text = [url absoluteString];
return YES;
}
Please let me know if it works. Thanks
I have UIWebview in my app and this is how i navigate some times in the application to URL:
NSURL *url = [NSURL URLWithString:#"http://mp3skull.com/mp3/nirvana.html"];
NSURLRequest* request = [NSURLRequest requestWithURL:url];
[webView loadRequest:request];
And sometimes i noticed that if i click on link the AppStore application is opened with some app.
It is possible to disable it?
In the method - (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType
You could do
- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType
{
NSString *requestedURL = [[request URL] absoluteString];
// URL for opening itunes according to Apple docs is something like this #"http://itunes.apple.com
// But I do believe that it will be some sort of URL scheme that opens it specifically to the app on the app store.
// So without an example this is the best I can provide.
if([requestedURL isEqualToString:#"http://itunes.apple.com"]) {
// or if([requestedURL rangeOfString:#"itunes.apple.com"].location==0) {
// What is happening here is that if the request url that is being request is
// "http://mp3skull.com/mp3/nirvana.html" then we don't want to continue with the request so stop.
return NO;
}
// Otherwise for all other requests continue
return YES;
}
Remember you will need to set the delegate on your UIWebView as this method is a UIWebViewDelegate method - see Apple Documentation on UIWebViewDelegate for more information
Yes it happens, some times when you click on some links, the application will open another application.
Because, those links contain other app schemas. (link)
so, to disable opening such url-schemas, we have to detect them and not load them.
As appStore has "itunes.apple.com",
- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType
{
NSString *requestedURL = [[request URL] absoluteString];
if([requestedURL rangeOfString:#"itunes.apple.com"].location==0) {
return NO;
}
return YES;
}
I have NSString as follows
NSString *textOutStations = [NSString stringWithFormat:#"Hello Everyone. Please check out website:<br> http://www.google.com/</br>"];
I want to show google.com as below in URL, as I will load this in UIWebView.
www.google.com
So, whenever user click it, It must open Safari in iPhone.
NSString *textOutStations = [NSString stringWithFormat:#"Hello Everyone. Please check out website:<br> http://www.google.com/"];
[self.webView loadHTMLString:textOutStations baseURL:[NSURL fileURLWithPath:[[NSBundle mainBundle] bundlePath]]];
Then in UIWebView delegate:
- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType
{
// Opening safari
[[UIApplication sharedApplication] openURL:request.URL];
....
}
Try this one
NSString *textOutStations = #"<html><head><title></title></head><body><div> Hello Everyone. Please check out website:<br/> http://www.google.com/ </div></body></html>";
[self.webView loadHTMLString:textOutStations baseURL:[NSURL fileURLWithPath:[[NSBundle mainBundle] bundlePath]]];
This will help you......
You can not specify a URL with in a string and have it be clickable, this type of functionality is dependant on the object to which is using it, aka, UITextView UITextField UILabel UIWebView etc,
A UIWebview will show your url with in the webview it will not open the link in safari. IF you want to load it in ui web view, it's already ansered above, if you want to open it in safari, you have to do
[[UIAplication sharedApplication] openUrl:urlObject];
if you want to open it to be text with in a UITextView i would suggest this other stack overflow link here
I checked the link option in Attribute Inspector of UIWebView and it detected the link.
Method to OPEN in SAFARI...
-(BOOL) webView:(UIWebView *)inWeb shouldStartLoadWithRequest:(NSURLRequest *)inRequest navigationType:(UIWebViewNavigationType)inType {
if ( inType == UIWebViewNavigationTypeLinkClicked ) {
[[UIApplication sharedApplication] openURL:[inRequest URL]];
return NO;
}
return YES;
}