Detect iPhone different resolution in iOS - ios

I am using cocos2d in iOS .
I am having a problem detecting the iphone5 resolution(1136*640).
I am using code:
CGRect screenBounds = [[UIScreen mainScreen] bounds];
When we run app on iPhone simulator (4 inch), it gives screenWidth and screnHeight-320,480 respectively.
Can anyone tell me the solution for this?

Write this code in .m file.
#define WIDESCREEN ( fabs( ( double )[ [UIScreen mainScreen ]bounds ].size.height-( double )568 ) < DBL_EPSILON )
Now you can know the screen size like this.
if(WIDESCREEN)
{
NSLog(#"iPhone5 is here");
}
else
{
NSLog(#"iPhone4 is here");
}

you can add checks in your code for iPhone 4inch screens and 3.5 inch screens
CGSize result = [[UIScreen mainScreen] bounds].size;
if(result.height == 480)
{
// iPhone Classic
// set your frames for classic iPhone here
}
if(result.height == 568)
{
// iPhone 5, iPhone 5S, iPhone 5C
// set your frames for 4 inch iPhone here
}

iPhone 5 resolution is 1136*640 only. If you wanna check just Log below Code
the resolution it will give exactly (1136*640)
CGRect screenBounds = [[UIScreen mainScreen] bounds];
CGFloat screenScale = [[UIScreen mainScreen] scale];
CGSize screenSize = CGSizeMake(screenBounds.size.width * screenScale, screenBounds.size.height * screenScale);
NSLog(#"Screen SIze %#",NSStringFromCGSize (screenSize));
#define IS_IPHONE5 ([[UIScreen mainScreen] bounds].size.width >= 568 || [[UIScreen mainScreen] bounds].size.height >= 568)?YES:NO
#define IS_IPHONE4 ([[UIScreen mainScreen] bounds].size.width >= 480 || [[UIScreen mainScreen] bounds].size.height >= 480)?YES:NO
if(UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
{
if(IS_IPHONE4)
{
// iPhone 4
}
if(IS_IPHONE5)
{
// iPhone 5
}
}

Related

ios using size classes

Using ios Size classes how do I differentiate between iphone 5.5inch in portrait and any other iphone in portrait.
For example if I set the text size - width compact and height any - this seems to apply to ALL iphones. Is there a size class that you can apply to iphone 6 - that is different from all the other smaller iphones?
If I understood your problem correctly, you have to do this programmatically.
Use this code to check for the size of the iPhone:
if ([[UIScreen mainScreen] bounds].size.height == 480) {
//3.5 inch iPhone
}
if ([[UIScreen mainScreen] bounds].size.height == 568) {
//4 inch iPhone
}
if ([[UIScreen mainScreen] bounds].size.height == 667) {
//4.7 inch iPhone
}
if ([[UIScreen mainScreen] bounds].size.height == 736) {
//5.5 inch iPhone
}

How can you tell if a user is using an iPhone 6 or 6+

Forgive me if this is a really stupid question I am just a beginner at all of this stuff. I want to make a separate interface for the iPhone 6 and 6 Plus but I don't know how the best way to be going about this is. This is a very simple app just to get myself more familiar with the language, etc. I was wondering if there is an easy way to tell if a user is using a 6 or 6 plus to make a separate interface for them. Thanks :)
Use single storyboard. Learn autolayout from raywanderlich, it think its a very good resource.
Also,now take advantage of the size classes introduced for ios 8 in xcode 6. This is called adaptive layout.
So instead of making the above four views for 3.5, 4, 4.7, 5.5 inch devices separately, and then worry about combining their respective landscape modes as well, just go for the 4 combination of size classes using auto layout (if possible, highly recommended) and relax for any other device size that may come into future.
To detect iPhone Version Please use below code.
if ([[UIScreen mainScreen] respondsToSelector:#selector(scale)]) {
if ([[UIScreen mainScreen] scale] == 2.0) {
if([UIScreen mainScreen].bounds.size.height == 667){
// iPhone retina-4.7 inch(iPhone 6)
}
else if([UIScreen mainScreen].bounds.size.height == 568){
// iPhone retina-4 inch(iPhone 5 or 5s)
}
else{
// iPhone retina-3.5 inch(iPhone 4s)
}
}
else if ([[UIScreen mainScreen] scale] == 3.0)
{
if([UIScreen mainScreen].bounds.size.height == 736.0){
//iPhone retina-5.5 inch screen(iPhone 6 plus)
}
}
}
Reference from Here
write this code in .pch file
#define IS_IPHONE_6 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 667.0)
#define IS_IPHONE_6_PLUS (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 736.0)
and wwhenever you need in any controller you simply check the condition.
Below are methods that do what you asked. One major thing to look out for is in iOS7 and below, when you check [[UIScreen mainScreen] bounds] for the screen bounds, it always lists the width and height as the same no matter what orientation the phone is in. So if it's an iPhone5 in landscape mode, it will still list the width as 320 and height as 568. In iOS8, this changed, now if that same iPhone5 is in landscape, it will list the width as 568 and the height as 320. Below are methods which account for this:
+ (BOOL) deviceHasFourInchScreen
{
return [DeviceType deviceHasScreenWithIdiom:UIUserInterfaceIdiomPhone scale:2.0 height:568.0];
}
+ (BOOL) deviceHasFourPointSevenInchScreen
{
return [DeviceType deviceHasScreenWithIdiom:UIUserInterfaceIdiomPhone scale:2.0 height:667.0];
}
+ (BOOL) deviceHasFivePointFiveInchScreen
{
return [DeviceType deviceHasScreenWithIdiom:UIUserInterfaceIdiomPhone scale:3.0 height:736.0];
}
+ (BOOL) deviceHasScreenWithIdiom:(UIUserInterfaceIdiom)userInterfaceIdiom scale:(CGFloat)scale height:(CGFloat)height
{
CGRect mainScreenBounds = [[UIScreen mainScreen] bounds];
CGFloat mainScreenHeight;
if ([OperatingSystemVersion operatingSystemVersionLessThan:#"8.0"])
{
mainScreenHeight = mainScreenBounds.size.height;
}
else
{
mainScreenHeight = (UIDeviceOrientationIsLandscape([[UIApplication sharedApplication] statusBarOrientation])) ? mainScreenBounds.size.width : mainScreenBounds.size.height;
}
if ([[UIDevice currentDevice] userInterfaceIdiom] == userInterfaceIdiom && [[UIScreen mainScreen] scale] == scale && mainScreenHeight == height)
{
return YES;
}
else
{
return NO;
}
}
Also here are the accompanying OperatingSystem class methods:
+ (NSString *) currentOperatingSystemVersion
{
return [[UIDevice currentDevice] systemVersion];
}
+ (BOOL) operatingSystemVersionLessThanOrEqualTo:(NSString *) operatingSystemVersionToCompare
{
return ([[self currentOperatingSystemVersion] compare: operatingSystemVersionToCompare options:NSNumericSearch] != NSOrderedDescending);
}
Put below lines in prefix.pch
#define iPhoneVersion ([[UIScreen mainScreen] bounds].size.height == 568 ? 5 : ([[UIScreen mainScreen] bounds].size.height == 480 ? 4 : ([[UIScreen mainScreen] bounds].size.height == 667 ? 6 : ([[UIScreen mainScreen] bounds].size.height == 736 ? 61 : 999))))
Now in programming you can say...
if (iPhoneVersion==4) {
NSLog("This is 3.5 inch iPhone - iPhone 4s or below");
} else if (iPhoneVersion==5) {
NSLog("This is 4 inch iPhone - iPhone 5 family");
} else if (iPhoneVersion==6) {
NSLog("This is 4.7 inch iPhone - iPhone 6");
} else if (iPhoneVersion==61) {
NSLog("This is 5.5 inch iPhone - iPhone 6 Plus.. The BIGGER");
} else {
NSLog("This is iPad");
}
However, I would say use one storyboard for all iPhones by learning autolayout.

How to detect Retina HD display?

UIScreen has a new, nativeScale property in iOS 8 but the documentation does not say a word about it.
#property(nonatomic, readonly) CGFloat nativeScale
There is also a scale property but the docs say it is 2 for retina displays.
#property(nonatomic, readonly) CGFloat scale
I am wondering if there is a way to distinguish the displays. The reason why I need to know whether the device has Retina HD display is because I want to request images with different sizes based on the displays.
Thanks for any help!
Below works very well to detect type of display on iPhone6Plus.
if ([[UIScreen mainScreen] respondsToSelector:#selector(scale)] && [[UIScreen mainScreen] scale] == 3.0)
NSLog(#"Retina HD");
else
NSLog(#"Non Retina HD");
Check the below code:
CGRect screenBounds = [[UIScreen mainScreen] bounds];
CGFloat screenScale = [[UIScreen mainScreen] scale];
CGSize screenSize = CGSizeMake(screenBounds.size.width * screenScale, screenBounds.size.height * screenScale);
NSLog(#"WIDTH:%f",screenSize.height);
NSLog(#"WIDTH:%f",screenSize.width);
float height =screenSize.height;
float width = screenSize.width;
NSString *deviceType=#"";
if (height==1136.000000 && width==640.000000)
{
deviceType =#"iPhone 5,5S and 5C Retina";
}
if (height==1920.000000 && width==1080.000000)
{
deviceType =#"iPhone 6 Plus Retina Downsample";
}
if (height==2208.000000 && width==1242.000000)
{
deviceType =#"iPhone 6 Plus Retina";
}
if (height==1334.000000 && width==750.000000)
{
deviceType =#"iPhone 6 Retina";
}
if (height==960.000000 && width==640.000000)
{
deviceType =#"iPhone 4 and 4S Retina";
}
if (height==480.000000 && width==320.000000)
{
deviceType =#"iPhone 3g and 3gs Non retina ";
}
NSLog(#"Your Result:%#",deviceType);
Reference:
iPhone Resoution

IOS 7.1: Not able to detect retina device in ipad2

I know,
We can detect retina device by either of the following methosds:
BOOL isRetina;
if ([[UIScreen mainScreen] respondsToSelector:#selector(scale)] && [[UIScreen mainScreen] scale] == 2){
isRetina = YES;
} else {
isRetina = NO;
}
or
if ([[UIScreen mainScreen] respondsToSelector:#selector(displayLinkWithTarget:selector:)]){
NSLog(#"scale = %f",[[UIScreen mainScreen] scale]);
if ([[UIScreen mainScreen] scale] > 1.0) {
NSLog(#"Retina Display iPad3");
}
else
{
NSLog(#"Non Retina Display iPad 1/2");
}
}
But when i run this code into my ipad 2 which has ios 7.1, i am getting , it is non-retina device and when i run this code into ipad retina device's simulator it is working perfectly there.
Any guideline?
The code is correct. The iPad 2 does not have a Retina screen.

coding for iphone 5 screen

I have taken a universal project. I have coded for iPhone 5 screen but it doesn't detect it.
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {
//ui for ipad
}
else if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
CGRect screenBounds = [[UIScreen mainScreen] bounds];
if (screenBounds.size.height == 568) {
tableView.frame = CGRectMake(0, 40, 320 ,508);
}
else {
tableView.frame = CGRectMake(0, 40, 320 ,420);
}
}
It doesn't work though. When I debug the code on iPhone 5 screenBounds = 320*480.
Where am I going wrong?
It is so simple to detect iPhone5 screen,
Just write
#define IS_IPHONE5 (([[UIScreen mainScreen] bounds].size.height-568)?NO:YES)
in your .pch file.... and you can further check for iPhone5 screen like if(IS_IPHONE5).
Choose your UITableView from the IB and select the size as Retina 4 for all screens, even the main window xib file. This works fine even on the iphone 4.
you add Splash Screen for iphone 5.Default-568h#2x.png file then its work fine
This code works fine for me
#define IS_IPHONE_5 ( fabs( ( double )[ [ UIScreen mainScreen ] bounds ].size.height - ( double )568 ) < DBL_EPSILON )
if (IS_IPHONE_5)
   {
//iphone 5
}
Try using this to detect iPhone 5 instead:
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
{
CGSize theHeight = [[UIScreen mainScreen] bounds].size;
if(theHeight.height == 568) {
// iPhone 5
tableView.frame = CGRectMake(0, 40, 320 ,508);
}
else {
// iPhone 4
tableView.frame = CGRectMake(0, 40, 320 ,420);
}
}
Alternatively you can define this:
#define IS_IPHONE5 (([[UIScreen mainScreen] bounds].size.height-568)?NO:YES)
Which you can re-use whenever you need to find out if it's iPhone 5 or not.
Try this code ::
if ([[UIScreen mainScreen] bounds].size.height == 568)
{
[tableView setFrame:CGRectMake(0, 40, 320 ,508)];
}
else if ([[UIScreen mainScreen] bounds].size.height == 480)
{
[tableView setFrame:CGRectMake(0, 40, 320 ,420)];
}
Hope, it'll help you.
Thanks.
I used this code to check iPhone 5 device.
float scrnheight = [[UIScreen mainScreen] bounds].size.height ;
if(scrnheight == 568.0f)
{
self.isIphone5 = true;
}

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