how to move sprite with delay in cocos2d? - ios

Question

i have number of sprite in array. now i want to moving that sprite with delay time 0.5.i am use below code at that time all sprite are fall at same time but i want to falling the sprite one by one.i am also use CCDelay method but also not get required result.
for (int j = 1; j < [ary count]; j++)
{
torpedoOne.position = ccp(160,580);
id actionMove = [CCMoveTo actionWithDuration:2.0
position:ccp(30 + (j*25),300)];
id deleay = [CCDelayTime actionWithDuration:1.0];
[torpedoOne runAction:[CCSequence actions:actionMove,deleay,nil]];
[self addChild:torpedoOne];
}
first of all for loop is complete after the action is run so that all sprite has same acion with same time.
how can i run action when each time go in for loop?
i am aslo try COCOS2D: how to animate falling bricks into a grid

Answer 1

you logic is weird. Try
for (int j = 0;j<[ary count]; j++{ // gets all objects in ary : 0 to count-1
torpedoOne = [ary objectAtIndex:j]; // I am assuming this is what you wanted
torpedoOne.position = ccp(160,580);
id actionMove = [CCMoveTo actionWithDuration:2.0
position:ccp(30 + (j*25),300)];
float delayTime = j*0.5f;
torpedoOne.visible = NO;
id show = [CCShow action]; // if you want them invisible prior to start move
id delay = [CCDelayTime actionWithDuration:delayTime];
[torpedoOne runAction:[CCSequence actions:delay,show,actionMove,nil]];
}
also, you should set torpedoOne inside the loop.

Answer 2

After a long time,i got one by one with sprite with animation by particular delay in cocos2d .
dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_LOW, 0),
^{
for (int j = 1; j < [ary count]; j++)
{
dispatch_async(dispatch_get_main_queue(),
^{
torpedoOne.position = ccp(160,580);
id actionMove = [CCMoveTo actionWithDuration:2.0
position:ccp(30 + (j*25),300)];
id deleay = [CCDelayTime actionWithDuration:1.0];
[torpedoOne runAction:[CCSequence actions:actionMove,deleay,nil]];
[self addChild:torpedoOne];
});
[NSThread sleepForTimeInterval:delay];
}
});