How to delete the blank-space and “< >” - ios

Question

I got iOS deviceToken like this
<72c7f0 e943d3 36713b 827e23 4337e3 91a968 73210d 2eecc4>
now , I want delete the blank-space and "<" ">" , to get to
72c7f0e943d336713b827e234337e391a96873210d2eecc4
what can I do for this ?
The other question is
- (void)application:(UIApplication *)app didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)deviceToken {
NSString *deviceString = [[NSString alloc] initWithData:deviceToken encoding:NSUTF8StringEncoding];
NSLog(#"%#",deviceString);
}
but the output is "null" , why ??

Answer 1

NSString *token = [[deviceToken description] stringByTrimmingCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#"<>"]];
token = [token stringByReplacingOccurrencesOfString:#" " withString:#""];

Answer 2

You ask why this didn't work:
NSString *deviceString = [[NSString alloc] initWithData:deviceToken encoding:NSUTF8StringEncoding];
That's because the initWithData assumes that the NSData contains a UTF8 string. But in your case, the deviceToken is not a UTF8 string; it is binary data.
The rest of your question presumes that you will create the <72c7f0 e943d3 36713b 827e23 4337e3 91a968 73210d 2eecc4> string (presumably that you created with stringWithFormat or description methods), and you're asking how to trim the <, >, and remove the spaces. (I think others have answered that question.)
I might suggest a different approach, though. You could simply have a routine to create the hexadecimal string directly, like so:
NSString *deviceString = [self hexadecimalStringForData:deviceToken];
You could then have a hexadecimalStringForData method like so:
- (NSString *)hexadecimalStringForData:(NSData *)data
{
NSMutableString *hexadecimalString = [[NSMutableString alloc] initWithCapacity:[data length] * 2];
uint8_t byte;
for (NSInteger i = 0; i < [data length]; i++)
{
[data getBytes:&byte range:NSMakeRange(i, 1)];
[hexadecimalString appendFormat:#"%02x", byte];
}
return hexadecimalString;
}
You certainly can use the description/stringWithFormat approach and then clean up that string, as others have suggested, but the above strikes me as a more direct solution.

Answer 3

You can use below code for this:
NSString *newString1 = [deviceString stringByReplacingOccurrencesOfString:#" " withString:#""];
NSString *newString2 = [newString1 stringByReplacingOccurrencesOfString:#"<" withString:#""];
NSString *finalString = [newString2 stringByReplacingOccurrencesOfString:#">" withString:#""];
NSlog("%#",finalString);

Answer 4

Simply use this code
- (void)application:(UIApplication*)application didRegisterForRemoteNotificationsWithDeviceToken:(NSData*)deviceToken
{
NSLog(#"My token is: %#", deviceToken);
NSString *devToken;
devToken = [[[[deviceToken description]
stringByReplacingOccurrencesOfString:#"<"withString:#""]
stringByReplacingOccurrencesOfString:#">" withString:#""]
stringByReplacingOccurrencesOfString:#" "withString:#""];
NSLog(#"%#",devToken);
}

Answer 5

To replace any character/string in any string, you can use :
[yourString stringByReplacingOccurrencesOfString:strToBeReplaced withString:strToBeReplacedWith];
In your case, you can use this:
NSString * str= #"<72c7f0 e943d3 36713b 827e23 4337e3 91a968 73210d 2eecc4>";
str = [str stringByReplacingOccurrencesOfString:#"<" withString:#""];
str = [str stringByReplacingOccurrencesOfString:#">" withString:#""];
str = [str stringByReplacingOccurrencesOfString:#" " withString:#""];
You can use this also (Taken from this question):
NSString *deviceToken = [[webDeviceToken description] stringByTrimmingCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#"<>"]];
deviceToken = [deviceToken stringByReplacingOccurrencesOfString:#" " withString:#""];

Answer 6

Use this code.
- (void)application:(UIApplication*)application didRegisterForRemoteNotificationsWithDeviceToken:(NSData*)deviceToken
{
NSString *newToken = [deviceToken description];
newToken = [newToken stringByTrimmingCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#"<>"]];
self.deviceToken = [newToken stringByReplacingOccurrencesOfString:#" " withString:#""];
}

Answer 7

Write below method in your view controller .m file
-(NSString*)contentsInParenthesis:(NSString *)str
{
NSString *subString = nil;
NSRange range1 = [str rangeOfString:#"<"];
NSRange range2 = [str rangeOfString:#">"];
if ((range1.length == 1) && (range2.length == 1) && (range2.location > range1.location))
{
NSRange range3;
range3.location = range1.location+1;
range3.length = (range2.location - range1.location)-1;
subString = [str substringWithRange:range3];
}
return subString;
}
And use this method like:
NSString *string = #"<72c7f0 e943d3 36713b 827e23 4337e3 91a968 73210d 2eecc4>";
NSString *str=[self contentsInParenthesis:string];
Now, Printing description of str:
72c7f0 e943d3 36713b 827e23 4337e3 91a968 73210d 2eecc4