Change resource into arrays [closed] - ruby-on-rails

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Is there a way to change resources into array?
For example:
#video = Video.all
to
[["Test", 1],["Test2", 2],["Test3", 3]]
I tried #video.to_a but it didn't work

By resources you mean an ActiveRecord collection?
If so, it can be something like
#video.map{ |video, index| [video.name, index+1] }

You can use ActiveRecord::Calculations#pluck to select one or more attributes:
Video.pluck(:name, :id)
#=> [["foo", 1], ["bar", 2], ["baz", 3]]

Related

How to exclude special characters in ruby [closed]

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I am new to ruby and looking for a solution where I wanted to remove search a lines in a file with specific string and that string does not contains special characters.
eg:
irb(main):005:0> File.readlines("test.sh").select {|line| line =~ /Passphr|passphrs/}
=> ["passphrs=mw4test\n", "Passphrase=$passphrs\n", "Passphrase=$passphrs\n"]
I want ignore the text which is having "=$" as combination and desire output should be as:
passphrs=mw4test
Please suggest?
Perhaps just add a second condition to your select block:
File
.readlines("test.sh")
.select { |line| line =~ /Passphr|passphrs/ && !line.include?('=$') }

How to use Entity Framework to combine nested cross join and left join [closed]

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I want to write the following code with Entity Framework.
select* from LocaleStringResource as locale
cross join Language language
left join LocaleStringResourceLanguage localeLang
on locale.Id = localeLang.RecordId and
language.ID = localeLang.LanguageId
How can I do this?
I assumed some information because you don't give us enough information about the entities. I guess that you trying to do this. Try this en let us know if it's the right approach.
var query = (from locale in _context.LocaleStringResource
from language in _context.Language
join localeLangBefLJ in _context.LocaleStringResourceLanguage on new { field1 = locale.Id, field2 = language.ID } equals new { field1 = localeLangBefLJ.RecordId, field2 = localeLangBefLJ.LanguageId }
into localeLang
from x in localeLang.DefaultIfEmpty()
select new
{
locale,
language,
x
})

Checking multip hash keys if present [closed]

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Any tips to refactor this condition?
params = {:p1=>"foo", :p2=>true, :p3=>nil, :pN=>""}
if params[:p1].present? && params[:p2].present? && params[:pN].present?
# do something...
Something like this:
params.values_at(:p1, :p2, :pN).all?(&:present?)
if params.values_at(*%i[p1 p2 p3]).all?(&:present?)
values_at returns an Array of the values for each key you provide.
all? is true iff the predicate (present?) is true for every member of the enumerable. values_at will include nil for a missing key (rather than omit it), so you don't need to worry about the array collapsing down to only present values.
keys = [:p1, :p2, :pN]
puts "hi" if keys.all? { |k| params[k].present? }
This has the advantage of terminating the hash lookup as soon as params[k].present? is false.

Remove trailing commas in ruby string [closed]

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I am getting the following value in my params: "45,284"
How can I remove the the leading and trailing double quotes from my string?
The output that I should get is: 45,284
You can do this to your params[:userValues] to make it suitable for IN clause in your query
"45,284".split(",").map(&:to_i) #=> [45, 248]
So for params[:userValues] it will be
user_values = params[:userValues].split(",").map(&:to_i)
Now the query will look like this
#user = User.where('is_active = ? and is_support_user = ? and id IN (?)', true, false, user_values).order(:user_name)
This will work, try it out
class String
def trim
self.gsub!(/\A"|"\Z/, '')
end
end
"\"45,284\"".trim

Ruby: Dynamically build member name of a struct? [closed]

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I have two questions.
1) I need to create a dynamic structure, whose members are driven through an array.
For ex:
members = [:a, :b]
Config = Struct.new(members) #=> Struct.new(:a, :b)
FlatConfig = Struct.new(members) #=> Struct.new(:a, :b)
config = Config.new()
flat = FlatConfig.new()
After some days, If I need to add another member to these struct, then all I need to do is add a member in that members array (memebers = [:a, :b, :c]) and I don't need to tough the code further. Thus I am asking this. How to achieve this?
2) Now I need to build the values of flat Struct members by means of doing some manipulation on config struct member values.
For eg:
config.each{|configMember|
result = configMember.collect{|c| someArray.collect{|s| s + '--' + y}}
flat[":#{cofigMember}"] = result #=> Intent is to store result in same member as iterated through config struct.
}
How to achieve (1) and (2)?
Thanks in advance.
For your 1), use the splat operator:
Struct.new(*members)
I don't really understand your second question. Is "how can I access the same variable in two configs"?
config.members.each { |key|
configMember = config[key]
# do something
flat[key] = result
}

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