Navigate through Array by Pointer to Pointer - pointer-to-pointer

Question

I have tried to move through array by double pointer. Here is the Code.
void pptr (int **sptr2,int **ptr2)
{
**ptr2 = (**sptr2 + 7); //Works Fine
*sptr2++; *ptr2++; //Probable problem Statement
**ptr2 = (**sptr2 + 7); //Not Workign
}
void ppointer (int *sptr,int *ptr)
{
pptr (&sptr,&ptr);
}
main()
{
int sour[2];
sour[0] = 40;
sour[1] = 50;
int var[2];
var[0] = 10;
var[1] = 20;
printf("befor change %d %d\n",var[0],var[1]);
ppointer(&sour[0],&var[0]);
printf("pointer to pointer change %d %d\n",var[0],var[1]);
}
I wish to update var in pptr function. I can use double pointer (**sptr,**pptr) to reference pointer (sptr,ptr) (which are pointing to array) into function. I am able to update first one but second one has no change. I think problem is with statement *sptr++ & *ptr++.
Please help me understand how can i navigate through array by double pointer.
Thank you

Answer 1

I think it is the compiler just being silly with the "*sptr++;" and the "*ptr++;"
void pptr (int **sptr2, int **ptr2)
{
**ptr2 = (**sptr2 + 7);
///////////////////////////////////////////////////////
*sptr2++; //This is the problem these two statements
*ptr2++;
///////////////////////////////////////////////////////
**ptr2 = (**sptr2 + 7);
}
Now however if you change it to "*sptr2 += 1;" and "*ptr += 1;" it then works
void pptr (int **sptr2, int **ptr2)
{
**ptr2 = (**sptr2 + 7);
///////////////////////////////////////////////////////
*sptr2 += 1; //Now no problem
*ptr2 += 1;
///////////////////////////////////////////////////////
**ptr2 = (**sptr2 + 7);
}
I dont really know why the compiler does this due to lack of experience of using the "variable++" operator, I just generally use "variable += 1" instead.