"Can not initialize the default wsdl from..." -- Why? - wsdl

Question

My pom.xml contains the following to auto generate a client for a working web service having the WSDL specified below:
<plugin>
<groupId>org.apache.cxf</groupId>
<artifactId>cxf-codegen-plugin</artifactId>
<version>2.3.1</version>
<executions>
<execution>
<id>generate-sources</id>
<configuration>
<sourceRoot>${basedir}/target/generated/src/main/java</sourceRoot>
<wsdlOptions>
<wsdlOption>
<wsdl>${basedir}/src/main/wsdl/myclient.wsdl</wsdl>
<extraargs>
<extraarg>-client</extraarg>
<extraarg>-verbose</extraarg>
</extraargs>
<wsdlLocation>wsdl/myclient.wsdl</wsdlLocation>
</wsdlOption>
</wsdlOptions>
</configuration>
<goals>
<goal>wsdl2java</goal>
</goals>
</execution>
</executions>
</plugin>
The project builds fine, without any errors or warnings and I can see the the file myclient.wsdl in the JAR file right under a wsdl folder.
But when I try running that JAR:
java -Xmx1028m -jar myclient-jar-with-dependencies.jar
It complains that "Can not initialize the default wsdl from wsdl/myclient.wsdl"
Why?
What am I missing?
How can I find out what path that wsdl/myclient.wsdl in pom.xml translates into, that makes the client's JAR complain at run time?
Update: I am aware of some solutions/workarounds that involve modifying the auto-generated code:
Pass "null" for the wsdl URL and then use the ((BindingProvider)port).getRequestContext().put(BindingProvider.ENDPOINT_ADDRESS_PROPERTY, "http://example.com/....") to set the address.
load the WSDL as a Java resource and pass its location into your service's constructor.
But I am more interested in a solution that requires entering the right values into the pom.xml like the classpath approach (but unfortunately classpath didn't work for me for some reason).
Any ideas what I should be typing there instead? Apparently this is a very simply case of figuring out the correct path rules for that particular plugin, but I am missing something and I don't know what it is.

Answer 1

The error comes from the static initializer of your generated service class (which is annotated by #WebServiceClient). It tries to load the wsdl file as resource. The generator uses the value which you have provided by the parameter wsdlLocation. You should leave away the "wsdl/" prefix:
<wsdlLocation>myclient.wsdl</wsdlLocation>
because the wsdl is located directly in the root of the classpath folder.
BTW: If you omit the parameter <wsdlLocation> the value of the param <wsdl> is used (which is not correct at runtime in your case, but would be correct if the provided URL would be a remote URL address, i.e. directly fetched from the webservice server).
BTW2: Your workaround 2 is in fact +/- what the generated code of the service class does if you use the parameterless constructor.

Answer 2

I notice the cfx examples use slightly different locations for sourceRoot, wsdl and wsdlLocation.
Remember that typically, files in src/main/resources are included in the produced artifact. In order for files in src/main/wsdl to be included, it needs to be added as a resource in the pom.xml:
<resources>
<resource>
<directory>src/main/wsdl</directory>
</resource>
</resources>
Tips:
Set the paths you suspect to known bad paths and see if you get the same error-message.
Unzip the produced *.jar-file(s) and check if the wsdl is included, and what the path is.