i have a file as below.
0033613766442
007969947485
01027709100
0113204909
01132049819
01132100218
01132127941
01132179212
I would like a command to only display the lines which contain 11 characters exactly?.
You can say:
grep -P '^.{11}$' filename
That'd print lines that contain 11 characters.
Using awk you can do like this
awk 'length($0)==11' file
01027709100
01132049819
01132100218
01132127941
01132179212
Or this short variation
awk 'NF==11' FS= file
Related
Hello How can I grep only match before : mark?
If I run grep test1 file, it shows all three lines.
test1:x:29688:test1,test2
test2:x:22611:test1
test3:x:25163:test1,test3
But I would like to get an output test1:x:29688:test1,test2
I would appreciate any advice.
If the desired lines always start with test1 then you can do:
grep '^test1' file
If it's always followed by : but not the other (potential) matches then you can include it as part of the pattern:
grep 'test1:' file
As your data is in row, columns delimited by a character, you may consider awk:
awk -F: '$1 == "test1"' file
I think that you just need to add “:” after “test1”, see an example:
grep “test1:” file
I am trying to grep the output of a command that outputs unknown text and a directory per line. Below is an example of what I mean:
.MHuj.5.. /var/log/messages
The text and directory may be different from time to time or system to system. All I want to do though is be able to grep the directory out and send it to a variable.
I have looked around but cannot figure out how to grep to the end of a word. I know I can start the search phrase looking for a "/", but I don't know how to tell grep to stop at the end of the word, or if it will consider the next "/" a new word or not. The directories listed could change, so I can't assume the same amount of directories will be listed each time. In some cases, there will be multiple lines listed and each will have a directory list in it's output. Thanks for any help you can provide!
If your directory paths does not have spaces then you can do:
$ echo '.MHuj.5.. /var/log/messages' | awk '{print $NF}'
/var/log/messages
It's not clear from a single example whether we can generalize that e.g. the first occurrence of a slash marks the beginning of the data you want to extract. If that holds, try
grep -o '/.*' file
To fetch everything after the last space, try
grep -o '[^ ]*$' file
For more advanced pattern matching and extraction, maybe look at sed, or Awk or Perl or Python.
Your line can be described as:
^\S+\s+(\S+)$
That's assuming whitespace is your delimiter between the random text and the directory. It simply separates the whitespace from the non-whitespace and captures the second part.
Or you might want to look into the word boundary character class: \b.
I know you said to use grep, but I can't help to mention that this is trivially done using awk:
awk '{ print $NF }' input.txt
This is assuming that a whitespace is the delimiter and that the path does not contain any whitespaces.
I have a file and I want to know how many times does a word is inside that file.(NOTE: A row can have the same word)
You can use this command. Hope this wil help you.
grep -o yourWord file | wc -l
Use the grep -c option to count the number of occurences of a search pattern.
grep -c searchString file
awk solution:
awk '{s+=gsub(/word/,"&")}END{print s}' file
test:
kent$ cat f
word word word
word
word word word
kent$ awk '{s+=gsub(/word/,"&")}END{print s}' f
7
you may want to add word boundary if you want to match an exact word.
Yes, i know you want a grep solution, but my favorite perl with the rolex operator can't missing here... ;)
perl -0777 -nlE 'say $n=()=m/\bYourWord\b/g' filename
# ^^^^^^^^
if yoy want match the YourWord surrounded with another letters like abcYourWordXYZ, use
perl -0777 -nlE 'say $n=()=m/YourWord/g' filename
I need to find some matching conditions from a file and recursively find the next conditions in previously matched files , i have something like this
input.txt
123
22
33
The files where you need to find above terms in following files, the challenge is if 123 is found in say 10 files , the 22 should be searched in these 10 files only and so on...
Example of files are like f1,f2,f3,f4.....f1200
so it is like i need to grep -w "123" f* | grep -w "123" | .....
its not possible to list them manually so any easier way?
You can solve this using awk script, i ve encountered a similar problem and this will work fine
awk '{ if(!NR){printf("grep -w %d f*|",$1)} else {printf("grep -w %d f*",$1)} }' input.txt | sh
What it Does?
it reads input.txt line by line
until it is at last record , it prints grep -w %d | (note there is a
pipe here)
which is then sent to shell for execution and results are piped back
to back
and when you reach the end the pipe is avoided
Perhaps taking a meta-programming viewpoint would help. Have grep output a series of grep commands. Or write a little PERL program. Maybe Ruby, if the mood suits.
You can use grep -lw to write the list of file names that matched (note that it will stop after finding the first match).
You capture the list of file names and use that for the next iteration in a loop.
I want to grep for the string THREAD: 2. It has a space in between. Not able to figure out how.
I tried with grep "THREAD:[ \2]", but its not working
Please let me know.
Try grep "THREAD: 2" <filename>? You just want a literal '2', right?
If you are using GNU grep you could try using the alias egrep or grep -e with 'THREAD: 2$'
You might have to use '^.*THREAD: 2$'
grep reports back the entire line that has matched your pattern. If you wish to look at lines that contains THREAD: 2 then the following should work -
grep "THREAD: 2" filename
However, if you wish to fetch lines that could contain THREAD: and any number then you can use a character class. So in that case the answer would be -
grep "THREAD: [0-9]" filename
You can add + after the character class which means one or more numbers so that you can match numbers like 1,2,3 or 11,12,13 etc.
If you only want to fetch THREAD: 2 from your line then you will have to use an option of grep which is -o. It means show me only my pattern from the file not the entire line.
grep -o "THREAD: 2" filename
You can look up man page for grep and play around with all the options.