How to call a phone number from ios app? [duplicate] - ios

Question

This question already has answers here:
What’s the correct URL for placing a call on an iPhone?
(5 answers)
Closed 9 years ago.
I'm trying to call a phone number from ios app using:
It's not working, although the method gets called:
-(IBAction)callPhone:(id)sender {
NSString *phoneCallNum = [NSString stringWithFormat:#"tel://%#",listingPhoneNumber ];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneCallNum]];
NSLog(#"phone btn touch %#", phoneCallNum);
}
NSLog output: phone btn touch tel://[phone]

Answer 1

your code is correct. did you check in real device. this function will not work in simulator.
try this also,
NSString *phNo = #"[phone]";
NSURL *phoneUrl = [NSURL URLWithString:[NSString stringWithFormat:#"telprompt:%#",phNo]];
if ([[UIApplication sharedApplication] canOpenURL:phoneUrl]) {
[[UIApplication sharedApplication] openURL:phoneUrl];
} else
{
calert = [[UIAlertView alloc]initWithTitle:#"Alert" message:#"Call facility is not available!!!" delegate:nil cancelButtonTitle:#"ok" otherButtonTitles:nil, nil];
[calert show];
}
** Swift 3 version**
if let url = URL(string: "telprompt:\(phoneNumber)") {
if UIApplication.shared.canOpenURL(url) {
UIApplication.shared.open(call, options: []) { result in
// do something with result
}
}
}

Answer 2

Telephony does not work on simulators/iPod/iPad, you will require to run the app on an iPhone with active sim card.
Also the URL scheme to invoke the telephony application is tel:<phone_number>. Refer Apple docs.
Ideally, you should check if the device is having the telephony module and then perform the openURL: call. Use this code to perform the check,
if([[UIApplication sharedApplication] canOpenURL:callUrl]) {
[[UIApplication sharedApplication] openURL:callUrl];
}
else {
//Show error message to user, etc.
}

Answer 3

Use following method to make call:
NSString *phoneNumber = [#"tel://" stringByAppendingString:number];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneNumber]];

Answer 4

You can try like below.
NSString *phoneNumber = [#"tel://" stringByAppendingString:Number];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneNumber]];
Hope it helps you.

Answer 5

NSString *phoneNumber = [#"tel://" stringByAppendingString:#"9414481799"];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneNumber]];
This will only run on device.