in thymeleaf, how can write th:each to combine rows and columns? - thymeleaf

Question

I want to write 4 columns in a row like this
<div class="row">
<div class="span3">Something</div>
<div class="span3">Something</div>
<div class="span3">Something</div>
<div class="span3">Something</div>
</div>
<div class="row">
<div class="span3">Something</div>
<div class="span3">Something</div>
<div class="span3">Something</div>
<div class="span3">Something</div>
</div>
data sizes are dynamic, so it can be 4, 8 or more.
this is archived in other template engine
{{#each list}}
{{#if #index % 4 == 0}}
<div class="row">
{{/if}}
<div class="span3">{{this.name}}</div>
{{#if #index % 4 == 0}}
</div>
{{/if}}
{{/each}}
but how can I archive this in thymeleaf?
I can't find the way because th:each is in tag(<div class="row"> or <div class="span3">) as attribute.

Answer 1

Model code
List<String> data = new ArrayList<String>();
data.add("1");
data.add("2");
data.add("3");
data.add("4");
data.add("5");
data.add("6");
data.add("7");
data.add("8");
model.addAttribute("datas", data);
Thymeleaf view code
<div th:each="data, row: ${datas}" th:with="numList=${#strings.listSplit('3,2,1,0', ',')}" th:if="${row.current} % 4 == 0" class="span3">
<span th:each="num : ${numList}" th:with="dataIndex=(${row.index} - ${num})" th:text="${datas[dataIndex]}">data</span>
</div>
Result
<div class="span3">
<span>1</span><span>2</span><span>3</span><span>4</span>
</div>
<div class="span3">
<span>5</span><span>6</span><span>7</span><span>8</span>
</div>
I used an array to solve this problem.
I think you will find a better way.

Answer 2

This can be done using numbers.sequence too. Set colCount to whatever number of columns you'd like:
<th:block th:with="colCount=${4}">
<div th:each="r : ${#numbers.sequence(0, datas.size(), colCount)}" class="row">
<div th:each="c : ${#numbers.sequence(0, colCount - 1)}" th:if="${r + c < datas.size()}" th:text="${datas.get(r + c)}" class="span3"></div>
</div>
</th:block>

Answer 3

I just created an account here to correct the accepted answer. The accepted answer works great so long as the "datas" being passed in is an array of consecutive integers. However, to make it work with any kind of data structure, "row.current" needs to change to "row.count", as follows:
<div th:each="data, row: ${datas}" th:with="numList=${#strings.listSplit('3,2,1,0', ',')}" th:if="${row.count} % 4 == 0" class="span3">
<span th:each="num : ${numList}" th:with="dataIndex=(${row.index} - ${num})" th:text="${datas[dataIndex]}">data</span>
</div>
If you use row.current, then it uses the actual item in the list, which is great in the example shown, but not so great for any other kind of data structure. Hope this helps.
EDIT:
I have to further refine this because the accepted answer also does not work if the number of items in the list is not evenly divisible by 4. Here is a better (though probably not perfect) solution:
<div th:each="data, row: ${datas}" th:with="numList=${ {3,2,1,0} }" th:if="${row.count % 4 == 0 or row.last}" class="span3">
<!-- Show all rows except the leftovers -->
<span th:each="num : ${numList}" th:with="dataIndex=(${row.index} - ${num})" th:if="${row.count % 4 == 0}" th:text="${datas[dataIndex]}">data</span>
<!-- Show the remainders (eg, if there are 9 items, the last row will have one item in it) -->
<span th:each="num : ${numList}" th:with="dataIndex=(${row.index} - ${num})" th:if="${row.last} and ${row.count % 4 != 0} and ${num < row.count % 4}" th:text="${datas[dataIndex]}">data</span>
</div>
This may be able to be refactored to eliminate one of the spans, but I have to move on now.

Answer 4

th:each can be used on any element basically. So something like this:
<div class="row" th:each="row : ${rows}">
<div class="span3" th:each="name : ${row.names}" th:text="${name}">Something</div>
</div>

Answer 5

<div class="row" th:each="museum,step : ${museums}">
<span th:if="${step.index % 2 == 0}">
<div class="column" style="background-color:#aaa;" >
<h2 th:text="'Name: ' + ${museum.name}"></h2>
<p th:text="'Address: ' + ${museum.address}"></p>
<p th:text="'Capacity: ' + ${museum.capacity}"></p>
</div>
</span>
<span th:if="${step.index < 3 and step.index %2 == 0} ">
<div class="column" style="background-color:#bbb;">
<h2 th:text="'Name: ' + ${museums[step.index+1].name}"></h2>
<p th:text="'Address: ' + ${museums[step.index+1].address}"></p>
<p th:text="'Capacity: ' + ${museums[step.index+1].capacity}"></p>
</div>
</span>
</div>
This is how I would approach the problem. Using a simple odd or even trick

Answer 6

I had the same problem and I saw the accepted answer but it was not easy enough for me so I tried a new solution and it does the job with much less code and much easier to understand
this is what I came up with:
// rowNum your situation, but be aware that you have to change all its instances to
<div th:each="i: ${#numbers.sequence(1, rowNum)}" class="row">
<div th:each="j: ${#numbers.sequence(((i-1) * rowNum), ((i-1) * rowNum) + (rowNum - 1)) }"
th:if="${j < #lists.size(list)}"
class="col col-md-5">
<span th:text=${list.get(j)}>item</span>
</div>
</div>

Answer 7

These are all so complicated when the answer is so simple as answered here.
<div colCount=${4} class="row">
<div class="span3" th:each="data : ${data}">...</div>
</div>
It limits the for each to 4 element blocks. I'm guessing that's a relatively new feature. Pretty cool.