I was wondering if it is possible to store the output created by silex. What I want to achieve is something like this :
<?php
require('core.php');
$out = $app->run();
echo $app['twig']->render('header.html');
echo $out;
echo $app['twig']->render('footer.html');
I'd like to do it this way because some of the navigation is build inside my dynamic controllers and registered as a global into twig. I've tried to use the out buffering ob_start mechanism without succes :
<?php
require('core.php');
ob_start();
$app->run();
$out = ob_get_contents();
ob_end_clean();
echo $app['twig']->render('header.html');
echo $out;
echo $app['twig']->render('footer.html');
Any other ideas on this subject ?
Instead of having a split of header/main/footer and using the global variables, you should use an unique template with template inheritence.
http://twig.sensiolabs.org/doc/templates.html#template-inheritance
Related
I am trying to grab a parameter from a webpage and insert it into a URL link on that same page but am having problems with the syntax.
So, for example, the webpage is www.website.com?src=mm
Currently the code on the page that does not pull in the parameter is
<?php echo "<A HREF='http://www.website2.com?offer=AAt&sub1=422'><B>Click Here</B></A><BR>" ?>
I would like to include that "mm" parameter at the end of the URL so the final URL is:
http://www.website2.com?offer=AA&sub1=422&sub2=mm
I tried the following but does not work:
<?php echo "<B>Click Here</B><BR>" ?>
Any ideas on how to get this to work? Thanks
Your code doesn't even compile:
Parse error: syntax error, unexpected 'http' (T_STRING), expecting ',' or ';' in /var/www/html/ImagePT/test.php on line 1
it has to be
<?php echo '<B>Click Here</B><BR>'; ?>
but since I'm just in the mood to give you some further advice:
You don't have to write HTML in uppercase, it's rather unusual (not impossible, but you don't see it very often) - then this script is horrible, when the $_GET['src'] variable is undefinied, therefore I'd check if it is set and then modifiy the URL accordingly. So my advice would be to use the following:
<?php
if(isset($_GET['src']))
{
echo '<b>Click Here</b></br>';
}
else
{
echo '<b>Click Here</b></br>';
}
?>
When using:
echo "${env.PRODUCT_NAME}"
it will echo:
MyProdName
When using:
echo "${env.MyProdName_Key}"
it will echo:
123456789
I would like to use something as follows:
echo "${env.${env.PRODUCT_NAME}_Key}"
Is this possible? How?
In Bash this is termed as variable in direction
Try using variables to make it further simplified
PRODUCT_NAME=$(echo "${env.PRODUCT_NAME}")
This would assign PRODUCT_NAME=MyProdName
Similarly
MyProdName=$(echo "${env.MyProdName_Key}")
This would assign MyProdName=123456789
Now when you print PRODUCT_NAME value you will get
echo ${PRODUCT_NAME}
MyProdName
And adding '!' variable indirection will give you the value of another variable values
echo ${!PRODUCT_NAME}
123456789
Maybe this will help you somehow:
def env = [
PRODUCT_NAME:'MyProdName',
MyProdName_Key: 123456789,
]
println "${env[env.PRODUCT_NAME+'_Key']}"
env is Map in the example provided but it works in the exactly same way.
Important note, regardless of how you're deriving variables:
There's no need to use string interpolation if the only value in a
string is a variable itself. This just clutters your code.
Instead of:
echo "${env.PRODUCT_NAME}"
you can do:
echo.PRODUCT_NAME.
Additionally you can grab nested object values dynamically using bracket notation
def obj = [a: '1']
echo obj[a] // outputs '1'
Using these put together, you can do:
def prodName = env.PRODUCT_NAME //will set var prodName to "MyProdName"
echo env[prodName + '_Key'] //gets nested field with key "MyProdName_Key"
(Note: this is similar to Opal's answer, hopefully my breakdown helps)
i'm using zendframwork 2 , i implement the album exemple in the official documentation
http://framework.zend.com/manual/2.1/en/user-guide/overview.html#the-tutorial-application (so in my model folder i have Album.php and AlbumTable.php) and all works fine , i just want to make a small modification :
i want to have acces to the third element in album . in the index.phtml view (originally i have this code )
<?php foreach ($albums as $album) : ?>
<?php echo $this->escapeHtml($album->title);?>
<?php echo $this->escapeHtml($album->artist);?>
<?php endforeach; ?>
i tried things like
<?php echo $this->escapeHtml($album->title[3]);?>
<?php echo $this->escapeHtml($album[3]->title);?>
but i always get this error
( ! ) Fatal error: Cannot use object of type Auth\Model\Album as array in C:\wamp\www\zf2-album\module\Auth\view\auth\auth\index.phtml on line 14
any help please ?
thanks every one
Do you need ONLY the third one? Then write your Query to be more efficient ;) For all other cases, since you are working with a Zend\Db\ResultSet\ResultSet, which uses Iterator you have different options.
The first one would be to still iterate through the fieldset like
while ($albums->key() != 3) {
$albums->next();
}
$album = $albums->current();
The alternative would be to simply convert the ResultSet into an array
$myAlbums = $albums->toArray();
$album = $myAlbums[3];
Depending on how big your ResultSet is and how many entries you really need, either Solution may be faster for you. Guess you have to test that one ;)
I want to be able to have multiple forms of the same parameter like so:
param(
[string]$p or $path = "C:\",
[string]$f or $filter = "*.txt",
[switch]$o or $overwrite
)
but I'm not sure how to do this. Most times, you would only be able to choose one (e.g. only $p or only $path). Is it possible to use multiple names for the same variable/parameter?
Like this:
param(
[Alias('p')]
[string]$path = "C:\",
[Alias('f')]
[string]$filter = "*.txt",
[Alias('o')]
[switch]$overwrite
)
Note you can have multiple aliases too: [Alias('p','thepath')]
PowerShell partial parameter name matching may be what your looking for.
# test.ps1
param($path)
write-host $path
Calling .\test.ps1 with either .\test.ps1 -path "c:\windows" or .\test.ps1 -p "c:\windows" will both match, and populate, the $path parameter.
To get php.ini path i simply run
<?php
phpinfo();
?>
what is the way to get the php.ini path to show to the user. without showing the whole phpinfo file.
phpinfo(INFO_GENERAL) would be smaller
http://us3.php.net/manual/en/function.phpinfo.php
If you have PHP 5.2.4 or later, you can simply use the php_ini_loaded_file() method which returns the path as a string.
If you don't have that version, here's one way.
ob_start();
phpinfo(INFO_GENERAL);
$data = ob_get_contents();
ob_end_clean();
$lines = explode("\n", $data);
foreach($lines as $line){
list($name, $value) = explode("=>", $line);
if (trim($name) == 'Loaded Configuration File') break;
}
echo $name . ' - ' . $value."\n";
That simply prints:
Loaded Configuration File -
/etc/php5/cli/php.ini
Of course you could use a regex match or something fancier like that if you wanted to.