I am getting lost and nuts with the DATETIME in Informix.I have two problems which I can hardly solve:
I have a DATETIME column (e.g. starttime) which I need to convert into an int value, e.g. seconds of year or epoch, or whatever. I found some conversion into utc, but this depends on the timezone the server runs, which I have no idea how to specify for the conversion.... Any other hint, how to convert it into seconds would be appreciated.
I need to calculate the difference between two DATETIME-fields (e.g. endtime-starttime) and then sum it up. To my understanding the result is interval day(13) to fraction(3). I need to convert the sum once again into seconds, cause I need to update other values with this result.
So, can anybody help me as to how to convert within a SQL-statement the different result-types?
CAST it to INT, example:
select
((current + 5 units day - current)::interval second(9) to second)
,((current + 5 units day - current)::interval second(9) to second)::char(10)::int8
from systables
where tabid=1
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How to SUM duration in Google Sheets?
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I'm making calculations on production cost (in number of resources) and duration.
I have a process that takes 5 minutes. Using the Duration format, I would enter that as 00:05:00.
I want to queue up this process a certain number of times and calculate the total duration. The output should either be something like 16:35:00 or 5 02:15:00. A "d HH.mm.ss" format.
How, in Google Sheets, do I multiply a Duration by an integer to get a total Duration? To be clear, I am not doing a summation of a column of durations. I am taking a duration constant, such as 5 minutes or 25 minutes, and multiplying it by an integer representing the number of times the process will be run, consecutively.
All these attempts resulted in Formula Parse Error:
=(5*00:05:00)
=(112*00:05:00.000)
=(VALUE(C27)*00:05:00)
=MULTIPLY(VALUE(C27),00:05:00.000)
Well, blow me down. I came up with a workaround while I was trying different ways to fail. I assigned 00:05:00 to it's own cell with the Duration format, then referenced that cell in the formula.
I.E. =C27*J7 gives me 9:20:00 when C27 equates to 112 (it's a summation of it's own) and J7 is the cell holding 00:05:00.
Still doesn't give me days when it goes over 24 hours, and I'd rather have the duration value as a constant in the formula, but it's a step forward.
Would something like this work for you?? It's no longer a number, but if it's for expressing the amount in your desired format it may be useful:
=IF(ROUNDDOWN(W2*W3),ROUNDDOWN(W2*W3)&"d "&TEXT(W2*W3-ROUNDDOWN(W2*W3),"hh:mm:ss"),TEXT(W2*W3,"hh:mm:ss"))
Change the cell references, obviously
PS: If you want to have the value as a constant in your formula, you can try to change the cell reference with TIME function within your formula:
In both Excel and Google spreadsheet, DATE are represented in a number start counting from 1899/12/30,
which...
1 is equal to 1 day
1/24 is equal to 1 hour
1/24/60 is equal to 1 minute
1/24/60/60 is equal to 1 second
you can do like:
=TODAY()+1 which gives you tomorrow, or...
=TODAY()+12/24 which gives you "date of today" 12:00:00
and when you are done with the calculations, you can simply use a TEXT() to format the NUMBER back into DATE format, such as:
=TEXT(TODAY()+7 +13/24 +15/24/60,"yyyy-mm-dd hh:mm:ss")
will return the date of a week away from today at 01:15:00 p.m.
This date/time format doesn't requires a full date to work, you can get difference of two time format like this:
=TEXT(1/24/60 - 1/24/60/60,"hh:mm:ss")
since 1/24/60 is 1 min, and 1/24/60/60 is 1 second,
this formula returns 00:00:59, telling you that there is a 59 seconds diff. between 1 min and 1 sec.
I am recording my time spent on a project in google excel sheet. There is a column which does addition of the recorded time and output total time to column say D40. The output time looks like <hoursspent>:<minutesspent>:<secondsspend>. For example 30:30:50 would mean that i have worked for 30 hours and 30 minutes and 50 seconds on a project.
Now, I was using this formula to calculate my total invoice
=(C41*HOUR(D40))+(C41*((Minute(D40)/60)))+(C41*((SECOND(D40)/3600)))
Where C41 cell contains my hourly rate (say $50).
This is working fine as long as the numbers of hours that i have worked are less than 24. The moment my numer of hours go above 24. The Hour function return the modulus value i.e., HOUR(30) would return 6.
How can I make this calculation generic in a way that it oculd calculate on more than 24 hours value too.
Try
=C41*D40*24
and change formet on the result as $
one hour is part of a day, as you know 1/24th of a day, that's why you could multiply by 24 to get hours, and then multiply it by the rate
Try below formula-
=SUMPRODUCT(SPLIT(D40,":"),{C41,C41/60,C41/3600})
When you store a value as HH:mm:ss into an Excel sheet, it automatically formats it as a Time, so it makes sense that HOUR modulos by 24.
Which is why you can simply ignore it. If you have a cell that is formatted as currency (FORMAT > Math > Currency) or any other normal Number-like format, then you can see, if you perform a numerical operation like multiplication, that it stores times like "30:30:50" as if it were a TIMEVALUE with a value over 1. Simply multiply that by 24, and then by your hourly rate, and you'll get your value, i.e,
=D40 * C41 * 24 :
Just replace HOUR(D40) with INT(D40)*24+HOUR(D40)
I have song based objects with their duration attribute saved in milliseconds. In short I was looking for a way to take a string like this: 3:25 (3 minutes/25 seconds) and convert it to milliseconds. The problem I'm facing is that taking such a value and using it with Time wouldn't work to my knowledge since it would consider it a time of day vs minutes delimited by a semicolon. Was wondering the best way to parse and convert a value like this to be presented. Was also wondering of a way to convert back.
duration string to total milliseconds:
def custom_convertor(duration_str) # format of duration_str -> "12:34"
mins, secs = duration_str.split(":").map(&:to_i)
1000*(60*mins+secs)
end
Maybe i am missing something very stupid so forgive me .
Comparing a date that is 1 month later than another date , starts to give me strange numbers.
I guess its because the result is float ? Here is how i do the comparison :
int daysToCheckUses=60;
long seconds=60*60*24*daysToCheckUses;
NSDate *today=[NSDate date];
if([today timeIntervalSinceDate:date]>seconds) //date can be more than 60 days old
Is there something wrong with this,when using big numbers? for example when the interval is 1 month i get 518400,but for 3 months i get 18662400000 i know that the comparisons returns float number that can't hold these numbers. I am afraid also to get a crash when a few months will pass.
This method to calculate a big distance is not that good, i found a great and better way for this using a great answer from here :
Number of days between two NSDates
Where the comparison is for days, than months will only give a few 100's integer .
I'm trying to display a simple tableview in IOS with data from Sqlite. My database date is stored as a timestamp. I thought was an unix timestamps but if i try to use dateWithTimeIntervalSince1970 i've really strange result.
Examples of date rows stored:
1352208510267
1352208512266
1352208514266
1352208516266
1352208530266
1352208532265
Use a query like this
SELECT datetime(timestamp, 'unixepoch') from YOURTABLENAME
WHERE id = someId;
This should convert it to some readable value.
Have a look here
I found the answer here. I compared the results with the previous answers:
SELECT strftime('%Y-%m-%d %H:%M:%S', datetime(ZDATE+978307200, 'unixepoch', 'localtime')), datetime(ZDATE, 'unixepoch', 'localtime') FROM ZTABLE
The query with the adjustment for Apple's epoch (Jan 1 2001) gives me the correct date:
"2015-09-29 20:50:51", "1984-09-28 20:50:51"
"2015-09-29 21:03:10", "1984-09-28 21:03:10"
"2015-09-29 21:25:30", "1984-09-28 21:25:30"
Unix timestamps are defined as the number of seconds since Jan 1 1970.
Just now, this would be about 1365525702.
Your values are one thousand times larger, i.e., they are measured in milliseconds.
Decide whether you actually need the millisecond precision, and then add * 1000 or / 1000 at the appropriate places.