I'm trying to follow this Railscast and create a morris.js line chart for my Enquiry model.
I've grouped the counts using date_trunc into months, but now I'm not quite sure at how to get the X-axis to iterate over months (e.g Jun 2012, Jul 2013) as opposed to by date as in the railscasts notes.
I've tried the range#step method here, but now the graph displays only one date (2012-07-01) without a count and nothing else. Commenting out the .step(1.month) method from the range variable and the graph works fine but the x-axis iterates by date.
class Enquiry < ActiveRecord::Base
def self.chart_data(start = 1.year.ago)
total_count = total_count_by_month(start)
start = start.to_date.beginning_of_month
today = Date.today.beginning_of_month
range = (start..today).step(1.month)
range.map do |month|
{
created_at: month,
total_enquiries: total_count[] || 0
}
end
end
def self.total_count_by_month(start)
enquiries = unscoped.where(created_at: start.beginning_of_month..Time.now)
enquiries = enquiries.group("date_trunc('month', created_at)")
enquiries = enquiries.select("date_trunc('month', created_at) as created_at, count(*) as count")
enquiries.each_with_object({}) do |enquiry, counts|
counts[enquiry.created_at.to_date] = enquiry.count
end
end
end
How do I get the chart's x-axis to iterate by months (Jun 2013, Jul 2013 ....) instead of by dates?
For anyone else facing the same problem, the solution is outlined below:
def self.chart_data(start = 1.year.ago)
total_count = total_count_by_month(start)
##############################################
start = start.to_date.beginning_of_month
today = Date.today.beginning_of_month
range = (start..today).select {|d| d.day == 1}
##############################################
range.map do |month|
{
created_at: month,
total_enquiries: total_count[] || 0
}
end
end
The chart's x-axis now iterates by month.
The solution is found here.
I'm still looking for solutions on how the chart dates might display (%b %Y) as opposed to the current format of (yyyy-mm-dd).
Related
I am working on a feature that given my daily work hours and the start and end date of my contract displays in a calendar my work hours. The problem is when I have 2 or more shifts on the same day. Let's say Julian has a shift from 03:00 to 04:00 and another one on the same day from 5:00 to 6:00 every Monday starting from July 17, 2019 to July 31, 2019. That means that my calendar should display these 2 shifts in July 22 and July 29. I have coded the logic to get me the correct dates. As of right now my JSON response looks like this
{"user":"Julian","start":"2019-07-22","day":"Monday","start_time":["03:00","05:00"],"end_time":["04:00","06:00"]},{"user_":"Julian","start":"2019-07-29","day":"Monday","start_time":["03:00","05:00"],"end_time":["04:00","06:00"]}
which is being generated by the following code in my JSON builder file
json.array! event.each do |inevent|
json.id hr_schedule.id
json.user_id hr_schedule.user_id
json.start inevent.strftime('%Y-%m-%d')
day_of_week = inevent.strftime('%A')
json.day day_of_week
if day_of_week == "Monday"
json.start_time hr_schedule.monday_st
json.end_time hr_schedule.monday_end
elsif day_of_week == "Tuesday"
json.start_time hr_schedule.tuesday_st
json.end_time hr_schedule.tuesday_end
elsif day_of_week == "Wednesday"
json.start_time hr_schedule.wednesday_st
json.end_time hr_schedule.wednesday_end
elsif day_of_week == "Thursday"
json.start_time hr_schedule.thursday_st
json.end_time hr_schedule.thursday_end
elsif day_of_week == "Friday"
json.start_time hr_schedule.friday_st
json.end_time hr_schedule.friday_end
elsif day_of_week == "Saturday"
json.start_time hr_schedule.saturday_st
json.end_time hr_schedule.saturday_end
elsif day_of_week == "Sunday"
json.start_time hr_schedule.sunday_st
json.end_time hr_schedule.sunday_end
end
end
what I want to achieve is to be able to have all my events as a unique JSON object like the following
{"user":"Julian","start":"2019-07-22","day":"Monday","start_time":"03:00","end_time":"04:00"},{"user":"Julian","start":"2019-07-22","day":"Monday","start_time":"05:00","end_time":"06:00"},
{"user":"Julian","start":"2019-07-29","day":"Monday","start_time":"03:00","end_time":"04:00"},{"user":"Julian","start":"2019-07-29","day":"Monday","start_time":"05:00","end_time":"06:00"}
I'm not sure what class json is, nor what array! is doing. But the basic way to do what you want is to use map to turn your events into an Array of Hashes. Then turn the Array into JSON with to_json.
calendar = event.map do |inevent|
json = {}
json[:id] = hr_schedule.id
json[:user] = hr_schedule.user_id
json[:start] = inevent.strftime('%Y-%m-%d')
json[:day] = inevent.strftime('%A')
case inevent.wday
when 0
json[:start_time] = hr_schedule.sunday_st
json[:end_time] = hr_schedule.sunday_end
when 1
json[:start_time] = hr_schedule.monday_st
json[:end_time] = hr_schedule.monday_end
when 2
json[:start_time] = hr_schedule.tuesday_st
json[:end_time] = hr_schedule.tuesday_end
when 3
json[:start_time] = hr_schedule.wednesday_st
json[:end_time] = hr_schedule.wednesday_end
when 4
json[:start_time] = hr_schedule.thursday_st
json[:end_time] = hr_schedule.thursday_end
when 5
json[:start_time] = hr_schedule.friday_st
json[:end_time] = hr_schedule.friday_end
when 6
json[:start_time] = hr_schedule.saturday_st
json[:end_time] = hr_schedule.saturday_end
end
json
end
puts calendar.to_json
I've simplified it a bit by using a case/when and Time#wday. strftime(%A) might change if the language of the application changes, and the day of week numbers are harder to typo.
As a side note, this event structure limits itself to only events which end before midnight. Consider instead using a full ISO8061 datetimes for start and end. In general, it's easier to work with a full datetime than separate date and time. The event day can be inferred from start.
{"user":"Julian","start":"2019-07-22T03:00","end":"2019-07-22T04:00"}
Or if the events are relative, like they happen every Monday, consider a start and a duration. And use an ISO weekday number for the day instead of a string, less parsing for the receiver to do.
{"user":"Julian","day":1,"start":"03:00","duration":"P1H"}
I can currently set a time range like so:
start_date: "2018-09-11"
end_date: "2018-11-19"
How can I do this for start to end of months? Examples:
time_range = ["2018-09-11".."2018-09-30"]
time_range = ["2018-10-01".."2018-10-31"]
time_range = ["2018-11-01".."2018-11-19"]
I'm not sure what's exactly your desired outcome but, given start date and end date as Date objects, you can perform
(start_date..end_date).to_a.group_by(&:month).values
and at the end what you get is a three element array, and each element contains an array with all the dates in that range for a month
I do not know if I understand very well what you asked, but I'll try to help you.
The Date class has several methods that will help you to work with dates.
Date < Object
Examples
my_date_range_array = [Date.today.beginning_of_year..Date.today.end_of_year]
my_date_time_range_array = [Time.now.beginning_of_year..Time.now.end_of_year]
my_date_range_array = [6.months.ago..Date.today]
YourModel.where date: Date.today.beginning_of_month..Date.today
YourModel.where date: 6.months.ago..Date.today
If you need every single date in the range, you can use something like this:
(Date.today.beginning_of_year..Date.today.end_of_year).map{ |date| date }
I hope that my answer helps you
This is a pure Ruby solution, but I believe (though I don't know Rails) it can be simplified slightly by replacing my methods first_day_of_month and first_day_of_month with Rails methods beginning_of_month and end_of_month, respectively. I designed the method for efficiency over simplicity.
require 'date'
DATE_FMT = "%Y-%m-%d"
def date_ranges(start_date_str, end_date_str)
start_date = Date.strptime(start_date_str, DATE_FMT)
end_date = Date.strptime(end_date_str, DATE_FMT)
return [start_date_str..end_date_str] if
[start_date.year, start_date.month] == [end_date.year, end_date.month]
d = start_date
ranges = [start_date_str..last_day_of_month(d)]
loop do
d = d >> 1
break if [d.year, d.month] == [end_date.year, end_date.month]
ranges << (first_day_of_month(d)..last_day_of_month(d))
end
ranges << (first_day_of_month(d)..end_date_str)
end
def first_day_of_month(d)
(d - d.day + 1).strftime(DATE_FMT)
end
def last_day_of_month(d)
((d >> 1)-d.day).strftime(DATE_FMT)
end
date_ranges("2018-09-11", "2019-02-11")
#=> ["2018-09-11".."2018-09-30", "2018-10-01".."2018-10-31",
# "2018-11-01".."2018-11-30", "2018-12-01".."2018-12-31",
# "2019-01-01".."2019-01-31", "2019-02-01".."2019-02-11"]
date_ranges("2018-09-08", "2018-09-23")
#=> ["2018-09-08".."2018-09-23"]
With the information provided by the OP, this is what I understand he is looking for.
Given a set range for example:
time_range = "2018-09-11".."2018-09-19"
new_range_min = time_range.min.to_date.beginning_of_month
new_range_max = time_range.max.to_date.end_of_month
new_range = new_range_min..new_range_max
I use Elasticsearch where I have one index per day, and I want my Ruby on Rails application to query documents in a given period by specifying the smallest and most precise list of indices.
I can't find the code to get that list of indices. Let me explain it:
Consider a date formatted in YYYY-MM-DD.
You can use the joker * at the end of the date string. E.g. 2016-07-2* describes all the dates from 2016-07-20 to 2016-07-29.
Now, consider a period represented by a start date and an end date.
The code must return the smallest possible array of dates representing the period.
Let's use an example. For the following period:
start date: 2014-11-29
end date: 2016-10-13
The code must return an array containing the following strings:
2014-11-29
2014-11-30
2014-12-*
2015-*
2016-0*
2016-10-0*
2016-10-10
2016-10-11
2016-10-12
2016-10-13
It's better (but I'll still take a unoptimized code rather than nothing) if:
The code returns the most precise list of dates (i.e. doesn't return dates with a joker that describes a period starting before the start date, or ending after the end date)
The code returns the smallest list possible (i.e. ["2016-09-*"] is better than ["2016-09-0*", "2016-09-1*", "2016-09-2*", "2016-09-30"]
Any idea?
Okay, after more thinking and the help of a coworker, I may have a solution. Probably not totally optimized, but still...
def get_indices_from_period(start_date_str, end_date_str)
dates = {}
dates_strings = []
start_date = Date.parse(start_date_str)
end_date = Date.parse(end_date_str)
# Create a hash with, for each year and each month of the period: {:YYYY => {:MMMM => [DD1, DD2, DD3...]}}
(start_date..end_date).collect do |date|
year, month, day = date.year, date.month, date.day
dates[year] ||= {}
dates[year][month] ||= []
dates[year][month] << day
end
dates.each do |year, days_in_year|
start_of_year = Date.new(year, 1, 1)
max_number_of_days_in_year = (start_of_year.end_of_year - start_of_year).to_i + 1
number_of_days_in_year = days_in_year.collect{|month, days_in_month| days_in_month}.flatten.size
if max_number_of_days_in_year == number_of_days_in_year
# Return index formatted as YYYY-* if full year
dates_strings << "#{year}-*"
else
days_in_year.each do |month, days_in_month|
formatted_month = format('%02d', month)
if Time.days_in_month(month, year) == days_in_month.size
# Return index formatted as YYYY-MM-* if full month
dates_strings << "#{year}-#{formatted_month}-*"
else
decades_in_month = {}
days_in_month.each do |day|
decade = day / 10
decades_in_month[decade] ||= []
decades_in_month[decade] << day
end
decades_in_month.each do |decade, days_in_decade|
if (decade == 0 && days_in_decade.size == 9) ||
((decade == 1 || decade == 2) && days_in_decade.size == 10)
# Return index formatted as YYYY-MM-D* if full decade
dates_strings << "#{year}-#{formatted_month}-#{decade}*"
else
# Return index formatted as YYYY-MM-DD
dates_strings += days_in_decade.collect{|day| "#{year}-#{formatted_month}-#{format('%02d', day)}"}
end
end
end
end
end
end
return dates_strings
end
Test call:
get_indices_from_period('2014-11-29', '2016-10-13')
=> ["2014-11-29", "2014-11-30", "2014-12-*", "2015-*", "2016-01-*", "2016-02-*", "2016-03-*", "2016-04-*", "2016-05-*", "2016-06-*", "2016-07-*", "2016-08-*", "2016-09-*", "2016-10-0*", "2016-10-10", "2016-10-11", "2016-10-12", "2016-10-13"]
I am trying to created a list of year-week (equivalent to mySQL's YEARWEEK(date,1)) falling between two date values in Rails. List is generating perfectly if start-date and end-date are falling in same year. Here is my code:
campaign_start_date = "2013-08-02 06:59:00"
campaing_end_date = "2013-09-01 06:59:00"
start_year = DateTime.parse(campaign_start_date).cwyear
start_week = "%04d%02d" % [start_year, DateTime.parse(campaign_start_date).cweek]
end_year = DateTime.parse(campaing_end_date).cwyear
end_week = "%04d%02d" % [end_year, DateTime.parse(campaing_end_date).cweek]
if start_year == end_year
(start_week..end_week).each{ |i| result << i }
else
# need to build a suitable logic here. to handle the case when duration spans over multiple years. for example started in 01-Nov-14 and ended in 01-May-15
end
return result
there will be no problem with above date values, it will fall to if case and the result I will get is:
[
"201331",
"201332",
"201332",
"201333",
"201334",
"201335"
]
which is also what I exactly want. BUT if my start-date and end-date values are these for example:
campaign_start_date = "2014-07-23 06:59:00"
campaing_end_date = "2015-03-01 06:59:00"
means falling in different years, then it need different logic that the one I have in if condition because for these date values (start_week=201430 and end_week=201509) the if condition is not suitable here because it would generate 80 values, which is wrong because number of weeks between these dates are not 80. Need help to develop the logic for else case. May be its easy but right now I am just tired to dig it any deeper.
Special attention: the solutions should care about commercial year and commercial week (refer .cwyear and .cweek functions of rails) For example yearweek of 2016-01-01 would be 201553 not 201601
any help in this regard would be much appreciated.
Thank you to those who replied t. I've finally solved the problem like this:
campaign_weeks = []
campaign_start_date = "2014-07-23 06:59:00" # or any date
campaing_end_date = "2015-03-01 06:59:00" # or any date
start_year = DateTime.parse(campaign_start_date).cwyear
start_cweek_of_the_campaign = "%04d%02d" % [start_year, DateTime.parse(campaign_start_date).cweek]
end_year = DateTime.parse(campaing_end_date).cwyear
end_cweek_of_the_campaign = "%04d%02d" % [end_year, DateTime.parse(campaing_end_date).cweek]
if start_year == end_year
(start_cweek_of_the_campaign..end_cweek_of_the_campaign).each do |w|
campaign_weeks << ("%04d%02d" % [start_year, w])
end
else
(start_year..end_year).each do |y|
first_cweek_number_of_the_year = (y == start_year) ? start_cweek_of_the_campaign : 1
last_cweek_number_of_the_year = (y == end_year) ? end_cweek_of_the_campaign : DateTime.new(y, 12, 28).cweek
(first_cweek_number_of_the_year .. last_cweek_number_of_the_year).each do |w|
campaign_weeks << ("%04d%02d" % [y, w])
end
end
end
return campaign_weeks
Notes: 28th Dec always fall in the last cweek/iso-week of the year. last ISO week of the year is either 52 or 53.
Reference: http://en.wikipedia.org/wiki/ISO_week_date#Last_week
Got some hint from this answer: Calculating the number of weeks in a year with Ruby
The bottleneck is (start_week..end_week) range. It apparently goes through hundred (since we are on decimals):
2014xx ⇒ 201452 ⇒ 201453 ⇒ ... ⇒ 201499 ⇒ 201500 ⇒ ...
You should probably filter your range, like:
r = (start_week..end_week)
r.to_a.reject { |e| e[-2..-1].to_i > 52 }
Depending on how you count weeks (=-based, or 1-based,) the 201500 should be likely filtered as well:/
r.to_a.select { |e| e[-2..-1].to_i.between? 1, 52 }
Try this out; it will work for any set of dates irrespective of whether the years are the same or not:
campaign_start_date = "2014-07-23 06:59:00"
campaign_end_date = "2015-03-01 06:59:00"
start_date = DateTime.parse(campaign_start_date)
end_date = DateTime.parse(campaign_end_date)
while start_date < end_date
puts "%04d%02d" % [start_date.cw_year, start_date.cweek]
start_date = start_date + 7.days
end
A bit late in the discussion but here is what I used to get the number of commercial weeks between two dates:
def cweek_diff(start_date, end_date)
return if end_date < start_date
cweek_diff = (end_date.cweek - start_date.cweek) + 1
cwyear_diff = end_date.cwyear - start_date.cwyear
cyear_diff * 53 + cweek_diff - cwyear_diff
end
It worked perfectly in my case. Hope it helps ;)
Having pulled donations from the past two years, I'm trying to derive the sum of those donations per month, storing the keys (each month) and the values (the sum of donations for each month) in an array of hashes. I would like the keys to be numbers 1 to 24 (1 being two years ago and 24 being this month) and if there are no donations for a given month, the value would be zero for that month. How would I do this as an array of hashes in Ruby/Rails?
This is my variable with the donations already in it.
donations = Gift.where(:date => (Date.today - 2.years)..Date.today)
the following gives you a hash, with keys '2013/09" , etc...
monthly_donations = {}
date = Time.now
while date > 2.years.ago do
range = date.beginning_of_month..date.end_of_month
monthly_donations[ "{#date.year}/#{date.month}" ] = Giftl.sum(:column, :conditions => {created_at >= range})
date -= 30.days
end
To select the records in that time-span, this should be enough:
donations = Gift.where("date >= #{2.years.ago}")
you can also do this:
donations = Gift.where("date >= :start_date AND date <= :end_date",
{start_date: 2.years.ago, end_date: Time.now} )
See also: 2.2.1 "Placeholder Conditions"
http://guides.rubyonrails.org/active_record_querying.html
To sum-up a column in the database record, you can then do this:
sum = Gift.sum(:column , :conditions => {created_at >= 2.years.ago})
First, we need a function to find the difference in months from the current time.
def month_diff(date)
(Date.current.year * 12 + Date.current.month) - (date.year * 12 + date.month)
end
Then we iterate through #donation, assuming that :amount is used to store the value of each donation:
q = {}
#donations.each do |donation|
date = month_diff(donation.date)
if q[date].nil?
q[date] = donation.amount
else
q[date] += donation.amount
end
end
I found a good solution that covered all the bases--#user1185563's solution didn't bring in months without donations and #Tilo's called the database 24 times, but I very much appreciated the ideas! I'm sure this could be done more efficiently, but I created the hash with 24 elements (key: beginning of each month, value: 0) and then iterated through the donations and added their amounts to the hash in the appropriate position.
def monthly_hash
monthly_hash = {}
date = 2.years.ago
i = 0
while date < Time.now do
monthly_hash["#{date.beginning_of_month}"] = 0
date += 1.month
i += 1
end
return monthly_hash
end
#monthly_hash = monthly_hash
#donations.each do |donation|
#monthly_hash["#{donation.date.beginning_of_month}"] += donation.amount
end