Shuffling a greek word in iOS prints unknown symbols - ios

I want to shuffle a string that contains Greek characters:
Here is my code:
- (void)shuffle {
NSLog(#"Will shuffle :%#",anagram2);
NSData* data = [anagram2 dataUsingEncoding:NSWindowsCP1253StringEncoding];
NSLog(#"after encoding :%#",anagram2);
NSString *someString = [[NSString alloc]initWithData:data encoding:NSWindowsCP1253StringEncoding];
NSLog(#"Greek word:%#",someString);
int length = anagram2.length;
NSMutableArray *letters = [[NSMutableArray alloc] init];
for (int i = 0; i< length; i++) {
NSString *letter = [NSString stringWithFormat:#"%c", [someString characterAtIndex:i]];
NSLog(#"Character:%#",letter);
[letters addObject:someLetter];
}
for (int i = 0; i<length; i++) {
int value = arc4random() % (length-1);
//NSLog(#"Value is : %i", value);
[letters exchangeObjectAtIndex:i withObjectAtIndex:value];
}
}
I can see the Greek word correctly. But the shuffling does not work. How can I extract each character and add it to a letters array. It works with English words but not with Greek ones, so I suppose that I should replace this:
NSString *letter = [NSString stringWithFormat:#"%c", [someString characterAtIndex:i]];
with something else.

The main problem seems to me that
[NSString stringWithFormat:#"%c":...]
works only with ASCII characters. You would have to use at least the "%C" format to make
it work with Unicode characters.
Also the conversion from NSString to NSData and back would fail as soon as you have any characters that are not available in the specified encoding.
The following method avoids all these problems and should work with arbitrary Unicode characters
(even with Emojis, which are internally represented as 2 UTF-16 characters):
NSString *string = #"Ελλάδα 😄";
NSLog(#"Will shuffle: %#", string);
// Convert string to an array of (32 bit) Unicode characters:
NSMutableData *data = [[string dataUsingEncoding:NSUTF32BigEndianStringEncoding] mutableCopy];
uint32_t *letters = [data mutableBytes];
int length = [data length]/4; // The number of 32-bit Unicode characters
// Shuffle the Unicode characters:
for (int i = 0; i<length; i++) {
int value = arc4random() % (length-1);
uint32_t tmp = letters[i];
letters[i] = letters[value];
letters[value] = tmp;
}
// Create new string from the shuffled Unicode characters:
NSString *shuffled = [[NSString alloc] initWithData:data encoding:NSUTF32BigEndianStringEncoding];
NSLog(#"Shuffled: %#", shuffled);
Output:
Will shuffle: Ελλάδα 😄
Shuffled: α😄άλλ Εδ

Related

How to remove 08 hexadecimal character from an NSString

I have a long string, and I would like to remove a specific hexadecimal character from it.
NSString * myString = #"longlongstringwithcharacters\"ofallsorts\"";
Any suggestions?
The hex character I am after is 08, that corresponds to backspace. How can I use code like the following to substitute it? I have no idea on how to represent 08 in a string:
NSString *stringWithoutSpaces = [myString
stringByReplacingOccurrencesOfString:#" " withString:#""];
EDIT:
I will try to clarify a bit more what I am trying to do..
I am trying to remove all occurrences of a character that corresponds to 08 hex from the string that I receive as payload.
The payload is in a string format and I found out the character by using Xcode debugger and view the hex codes of the string as there was an invalid character when trying to covert the NSData corresponding to the string to a NSDictionary.
I am not sure how to phrase the problem correctly..
- (NSString *)stringFromHexString:(NSString *)hexString {
// The hex codes should all be two characters.
if (([hexString length] % 2) != 0)
return nil;
NSMutableString *string = [NSMutableString string];
for (NSInteger i = 0; i < [hexString length]; i += 2) {
NSString *hex = [hexString substringWithRange:NSMakeRange(i, 2)];
NSInteger decimalValue = 0;
sscanf([hex UTF8String], "%x", &decimalValue);
[string appendFormat:#"%c", decimalValue];
}
return string;
}
Try this code...This will help you to convert Hex to string
NSString * str = #"68656C6C6F";
NSMutableString * newString = [[[NSMutableString alloc] init] autorelease];
int i = 0;
while (i < [str length])
{
NSString * hexChar = [str substringWithRange: NSMakeRange(i, 2)];
int value = 0;
sscanf([hexChar cStringUsingEncoding:NSASCIIStringEncoding], "%x", &value);
[newString appendFormat:#"%c", (char)value];
i+=2;
}
this will help u to convert Hex to NSString
This code worked for me:
NSString * dataString = message.payloadString;
NSString * wrongCharacter = [[NSString alloc] initWithFormat:#"%c", (char)0x08];
dataString = [dataString stringByReplacingOccurrencesOfString:wrongCharacter withString:#""];

How to convert HEX to NSString in Objective-C j?

I have a NSString with hex string like "&# x62a;&# x631;&# x642;&# x628;" which means "ترقب".
Now I want to convert the hex string into another NSString object which shows "ترقب". How to do that ?
- (NSMutableString *) hextostring:(NSString *) str{
//ت
NSMutableString *string = [[NSMutableString alloc]init];
str = [str stringByReplacingOccurrencesOfString:#"&#" withString:#"0"];
str = [str stringByReplacingOccurrencesOfString:#" " withString:#"z;"];
NSArray *arr = [str componentsSeparatedByString:#";"];
for (int i =0; i<[arr count]; i++) {
if ([[arr objectAtIndex:i] isEqualToString:#"z"]) {
[string appendString:#" "];
} else {
unsigned x;
[[NSScanner scannerWithString: [arr objectAtIndex:i]] scanHexInt: &x];
[string appendFormat:#"%C",(unichar)x];
}
}
NSLog(#"%#",string);
return string;
}
Your string looks like HTML escape sequences, except for the spaces after the #'s. If this is really what you have (check something isn't just displaying Unicode as escapes) then there is a myriad of ways to convert it. You can just process the string picking out the hex chars and producing UniChar values from them, etc.
If you want a high-level, maybe somewhat long-winded approach, you and try:
- (NSString *)decodeHTMLescapes:(NSString *)raw
{
NSString *nospaces = [raw stringByReplacingOccurrencesOfString:#" " withString:#""]; // one way to remove the spaces
const char *cString = [nospaces UTF8String]; // C string
NSData *bytes = [[NSData alloc] initWithBytesNoCopy:(void *)cString length:strlen(cString) freeWhenDone:NO]; // as bytes
NSAttributedString *attributed = [[NSAttributedString alloc] initWithHTML:bytes documentAttributes:nil]; // interpret as HTML
NSString *decoded = attributed.string; // and finally as plain text
return decoded;
}
That (a) strips the spaces, (b) creates a C string and (c) creates a byte buffer, all that so we can (d) interpret that byte buffer as HTML, and (e) finally gets the string back. The use of initWithBytesNoCopy:length:freeWhenDone: is to reduce the copying all this does.
Use it like:
NSString *raw = #"&# x62a;&# x631;&# x642;&# x628;";
NSString *decoded = [self decodeHTMLescapes:raw];
NSLog(#"%# -> %#", raw, decoded);
HTH

How convert string utf-8?

i've an NSString like this:
NSString *word = #"119,111,114,100"
So, what i want to do is to convert this NSString to word
So the question is, in which way can i convert a string to a word?
// I have added some values to your sample input :-)
NSString *word = #"119,111,114,100,32,240,159,145,141";
// Separate components into array:
NSArray *array = [word componentsSeparatedByString:#","];
// Create NSData containing the bytes:
NSMutableData *data = [[NSMutableData alloc] initWithLength:[array count]];
uint8_t *bytes = [data mutableBytes];
for (NSUInteger i = 0; i < [array count]; i++) {
bytes[i] = [array[i] intValue];
}
// Convert to NSString (interpreting the bytes as UTF-8):
NSString *str = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSLog(#"%#", str);
Output:
word 👍
Try this:
NSString *word = #"119,111,114,100";
NSArray *array=[word componentsSeparatedByString:#","];
for (NSString *string in array) {
char character=[string integerValue];
NSLog(#"%c",character);
}
Output:
w
o
r
d
libicu it's an UTF8 library that supports a conversion from an array of bytes as stated here.
The thing is, it offers Java, C or C++ APIs, not obj-c.

NSString replace unicode characters

I'w working with a server and I have to download text to my iOS application. Only problem : all characters like "é à ç" are replaced by "\U008" for example. Is there a way to fix this problem, to replace this code by the right character ?
Try to parse the received text (textToParse variable) with this one:
NSString *encodedString = textToParse;
NSString *decodedString = [NSString stringWithUTF8String:[encodedString cStringUsingEncoding:[NSString defaultCStringEncoding]]];
I tested some encodings and NSMacOSRomanStringEncoding fit well.
My test was:
NSString *encodedString = [NSString stringWithCString:"Você realmente deseja sair da área restrita" encoding:NSMacOSRomanStringEncoding];
Remember that the message has to be a C-string ("string") and not an NSString(#"string")
You can get character buffer and validate each character like so:
- (NSString *) removeUnicode:(NSString *) unicodeString {
NSUInteger len = [unicodeString length];
unichar buffer[len+1];
[unicodeString getCharacters:buffer range:NSMakeRange(0, len)];
unichar okBuffer[len+1];
int index = 0;
for(int i = 0; i < len; i++) {
if(buffer[i] < 128) {
okBuffer[index] = buffer[i];
index = index + 1;
}
}
NSString *removedUnicode = [[NSString alloc] initWithCharacters:okBuffer length:index];
return removedUnicode;
}
or you can use this sample:
NSCharacterSet *notAllowedChars = [[NSCharacterSet characterSetWithCharactersInString:[NSCharacterSet alphanumericCharacterSet]] invertedSet];
stringWithOutUnicode = [[stringWithUnicode componentsSeparatedByCharactersInSet:notAllowedChars] componentsJoinedByString:#""];
and you can create your own valid character set and get not allowed characters
NSString *allowedCharacters = #"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ";
NSCharacterSet *notAllowedChars = [[NSCharacterSet characterSetWithCharactersInString: allowedCharacters] invertedSet];

How to split string into substrings on iOS?

I received an NSString from the server. Now I want to split it into the substring which I need.
How to split the string?
For example:
substring1:read from the second character to 5th character
substring2:read 10 characters from the 6th character.
You can also split a string by a substring, using NString's componentsSeparatedByString method.
Example from documentation:
NSString *list = #"Norman, Stanley, Fletcher";
NSArray *listItems = [list componentsSeparatedByString:#", "];
NSString has a few methods for this:
[myString substringToIndex:index];
[myString substringFromIndex:index];
[myString substringWithRange:range];
Check the documentation for NSString for more information.
I wrote a little method to split strings in a specified amount of parts.
Note that it only supports single separator characters. But I think it is an efficient way to split a NSString.
//split string into given number of parts
-(NSArray*)splitString:(NSString*)string withDelimiter:(NSString*)delimiter inParts:(int)parts{
NSMutableArray* array = [NSMutableArray array];
NSUInteger len = [string length];
unichar buffer[len+1];
//put separator in buffer
unichar separator[1];
[delimiter getCharacters:separator range:NSMakeRange(0, 1)];
[string getCharacters:buffer range:NSMakeRange(0, len)];
int startPosition = 0;
int length = 0;
for(int i = 0; i < len; i++) {
//if array is parts-1 and the character was found add it to array
if (buffer[i]==separator[0] && array.count < parts-1) {
if (length>0) {
[array addObject:[string substringWithRange:NSMakeRange(startPosition, length)]];
}
startPosition += length+1;
length = 0;
if (array.count >= parts-1) {
break;
}
}else{
length++;
}
}
//add the last part of the string to the array
[array addObject:[string substringFromIndex:startPosition]];
return array;
}

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