I'm porting a very simple piece of code from OpenGLES 1.0 to OpenGLES 2.0.
In the original version, I have blending enabled with
glEnable(GL_BLEND);
glBlendEquation(GL_FUNC_ADD);
glBlendFunc(GL_ONE, GL_ONE_MINUS_SRC_ALPHA);
I'm using the same code in my ES 2.0 implementation as I need to blend the newly rendered quads with what was in the render buffer (I'm retaining the render buffer, I can't re-render the scene).
I'm using a texture (alpha values displaying a radial gradient from center to the outside, alpha goes from 1 to 0) that serves as an alpha mask, containing only white pixels with different alpha values. I give my vertices the same color say red with alpha of 100/255. My background is transparent black. Below that, I have a plain white surface (UIView). I render 4 quads.
Result with OpenGLES 1.0 (desired result)
My observations tells me that the fragment shader should simply be:
gl_FragColor = DestinationColor * texture2D(Texture, TexCoordOut);
(I got to that conclusion by trying different values for my vertices and the texture. That's also what I've read on some tutorials.)
I'm trying to write some OpenGL 2.0 code (including vertex + fragment shaders) that would give me the exact same result as in OpenGLES 1.0, nothing more, nothing less. I don't need/want to do any kind of blending in the fragment shader except applying the vertex color on the texture. Using the simple shader, here's the result I got:
I tried pretty much every combination of *, +, mix I could think of but I couldn't reproduce the same result. This is the closest I got so far, but that's definitely not the right one (and that doesn't make any sense either)
varying lowp vec4 DestinationColor;
varying lowp vec2 TexCoordOut;
uniform sampler2D Texture;
void main(void) {
lowp vec4 texture0Color = texture2D(Texture, TexCoordOut);
gl_FragColor.rgb = mix(texture0Color.rgb, DestinationColor.rgb, texture0Color.a);
gl_FragColor.a = texture0Color.a * DestinationColor.a;
}
This shader gives me the following:
By reading this and this, one can construct the blending function.
Since you're using glBlendFunc and not glBlendFuncSeparate, all the 4 channels are being blended. Using the GL_FUNC_ADD parameter sets the output O to O = sS + dD, where s and d are the blending parameters, and S and D are the source and destination colors.
The s and d parameters are set by the glBlendFunc. GL_ONE sets s to (1, 1, 1, 1), and GL_ONE_MINUS_SRC_ALPHA sets d to (1-As, 1-As, 1-As, 1-As), where As is the alpha value of the source. Therefore, your blend is doing this (in vector form):
O = S + (1-As) * D which in GLSL is O = mix(D, S, As), or:
gl_FragColor = mix(DestinationColor, TexCoordOut, As).
If the result doesn't look similar, then please verify that you're not using glBlend or any other OpenGL APIs that may change the appearance of your final result. If that doesn't help, please post a screenshot of the different outputs.
this can't be done easily with shaders since blending have to read current framebuffer state.
You can achieve this with rendering to texture and passing it to shader, if you can get color would be in framebuffer then you are ok.
your equation is:
gl_FragColor = wouldBeFramebufferColor + (1-wouldBeFramebufferColor.a) * texture0Color;
but why do you want to do it in shaders AFAIK blending was not removed in OpenGL ES 2.0
Stupid mistake. I only needed to normalize the vertex color in the vertex shader as I'm passing unsigned bytes in.
Related
I have started experimenting with the info-beamer software for Raspberry Pi. It appears to have support for display PNGs, text, and video, but when I see GLSL primitives, my first instinct is to draw a texture-mapped polygon.
Unfortunately, I can't find the documentation that would allow me to draw so much as a single triangle using the shaders. I have made a few toys using GLSL, so I'm familiar with the pipeline of setting transform matrices and drawing triangles that are filtered by the vertex and fragment shaders.
I have grepped around in info-beamer-nodes on GitHub for examples of GL drawing, but the relevant examples have so far escaped my notice.
How do I use info-beamer's GLSL shaders on arbitrary UV mapped polygons?
Based on the comment by the author of info-beamer it is clear that functions to draw arbitrary triangles are not available in info-beamer 0.9.1.
The specific effect I was going to attempt was a rectangle that faded to transparent at the margins. Fortunately the 30c3-room/ example in the info-beamer-nodes sources illustrates a technique where we draw an image as a rectangle that is filtered by the GL fragment shader. The 1x1 white PNG is a perfectly reasonable template whose color can be replaced by the calculations of the shader in my application.
While arbitrary triangles are not available, UV-mapped rectangles (and rotated rectangles) are supported and are suitable for many use cases.
I used the following shader:
uniform sampler2D Texture;
varying vec2 TexCoord;
uniform float margin_h;
uniform float margin_v;
void main()
{
float q = min((1.0-TexCoord.s)/margin_h, TexCoord.s/margin_h);
float r = min((1.0-TexCoord.t)/margin_v, TexCoord.t/margin_v);
float p = min(q,r);
gl_FragColor = vec4(0,0,0,p);
}
and this LUA in my node.render()
y = phase * 30 + center.y
shader:use {
margin_h=0.03;
margin_v=0.2;
}
white:draw(x-20,y-20,x+700,y+70)
shader:deactivate()
font:write(x, y, "bacon "..(phase), 50, 1,1,0,1)
This question has been asked before but the quite a few years ago in my searches. The answer was always to use texture mapping but what I really want to do is represent the star as a single vertex - you may think I'm copping out with a simplistic method but in fact, a single point source of light actually looks pretty good and realistic. But I want to process that point of light with something like a gaussian blur too give it a little more body when zooming in or for brighter stars. I was going to texture map a gaussian blur image but if I understand things correctly I would then have to draw each star with 4 vertexes. Maybe not so difficult but I don't want to go there if I can just process a single vertex. Would a vertex-shader do this? Can GLKBaseEffects get me there? Any suggestions?
Thanks.
You can use point sprites.
Draw Calls
You use a texture containing the image of the star, and use the typical setup to bind a texture, bind it to a sampler uniform in the shader, etc.
You draw a single vertex for each star, with GL_POINTS as the primitive type passed as the first argument to glDrawArrays()/glDrawElements(). No texture coordinates are needed.
Vertex Shader
In the vertex shader, you transform the vertex as you normally would, and also set the built-in gl_PointSize variable:
uniform float PointSize;
attribute vec4 Position;
void main() {
gl_Position = ...; // Transform Position attribute;
gl_PointSize = PointSize;
}
For the example, I used a uniform for the point size, which means that all stars will have the same size. Depending on the desired effect, you could also calculate the size based on the distance, or use an additional vertex attribute to specify a different size for each star.
Fragment Shader
In the fragment shader, you can now access the built-in gl_PointCoord variable to get the relative coordinates of the fragment within the point sprite. If your point sprite is a simple texture image, you can use it directly as the texture coordinates.
uniform sampler2D SpriteTex;
void main() {
gl_FragColor = texture2D(SpriteTex, gl_PointCoord);
}
Additional Material
I answered a somewhat similar question here: Render large circular points in modern OpenGL. Since it was for desktop OpenGL, and not for a textured sprite, this seemed worth a separate answer. But some of the steps are shared, and might be explained in more detail in the other answer.
I've been busy educating myself on this and trying it but I'm getting strange results. It seems to work with regard to vertex transform - because I see the points moved out on the screen - but pointsize and colour are not being affected. The colour seems to be some sort of default yellow colour with some shading between vertices.
What bothers me too is that I get error messages on built-ins in the vertex shader. Here are the vertex/fragment code and the error messages:
#Vertex shader
precision mediump float;
precision lowp int;
attribute float Pointsize;
varying vec4 color_out;
void main()
{
gl_PointSize = Pointsize;
gl_Position = gl_ModelViewMatrix * gl_Vertex;
color_out = vec4(0.0, 1.0, 0.0, 1.0); // output only green for test
}
#Fragment shader
precision mediump float;
precision lowp int;
varying vec4 color_out;
void main()
{
gl_FragColor = color_out;
}
Here's the error message:
ERROR: 0:24: Use of undeclared identifier 'gl_ModelViewMatrix'
ERROR: 0:24: Use of undeclared identifier 'gl_Vertex'
ERROR: One or more attached shaders not successfully compiled
It seems the transform is being passed from my iOS code where I'm using GLKBaseEffects such as in the following lines:
self.effect.transform.modelviewMatrix = modelViewMatrix;
[self.effect prepareToDraw];
But I'm not sure exactly whats happening, especially with the shader compile errors.
I'm trying to implement the Atkinson dithering algorithm in a fragment shader in GLSL using our own Brad Larson's GPUImage framework. (This might be one of those things that is impossible but I don't know enough to determine that yet so I'm just going ahead and doing it anyway.)
The Atkinson algo dithers grayscale images into pure black and white as seen on the original Macintosh. Basically, I need to investigate a few pixels around my pixel and determine how far away from pure black or white each is and use that to calculate a cumulative "error;" that error value plus the original value of the given pixel determines whether it should be black or white. The problem is that, as far as I could tell, the error value is (almost?) always zero or imperceptibly close to it. What I'm thinking might be happening is that the texture I'm sampling is the same one that I'm writing to, so that the error ends up being zero (or close to it) because most/all of the pixels I'm sampling are already black or white.
Is this correct, or are the textures that I'm sampling from and writing to distinct? If the former, is there a way to avoid that? If the latter, then might you be able to spot anything else wrong with this code? 'Cuz I'm stumped, and perhaps don't know how to debug it properly.
varying highp vec2 textureCoordinate;
uniform sampler2D inputImageTexture;
uniform highp vec3 dimensions;
void main()
{
highp vec2 relevantPixels[6];
relevantPixels[0] = vec2(textureCoordinate.x, textureCoordinate.y - 2.0);
relevantPixels[1] = vec2(textureCoordinate.x - 1.0, textureCoordinate.y - 1.0);
relevantPixels[2] = vec2(textureCoordinate.x, textureCoordinate.y - 1.0);
relevantPixels[3] = vec2(textureCoordinate.x + 1.0, textureCoordinate.y - 1.0);
relevantPixels[4] = vec2(textureCoordinate.x - 2.0, textureCoordinate.y);
relevantPixels[5] = vec2(textureCoordinate.x - 1.0, textureCoordinate.y);
highp float err = 0.0;
for (mediump int i = 0; i < 6; i++) {
highp vec2 relevantPixel = relevantPixels[i];
// #todo Make sure we're not sampling a pixel out of scope. For now this
// doesn't seem to be a failure (?!).
lowp vec4 pointColor = texture2D(inputImageTexture, relevantPixel);
err += ((pointColor.r - step(.5, pointColor.r)) / 8.0);
}
lowp vec4 textureColor = texture2D(inputImageTexture, textureCoordinate);
lowp float hue = step(.5, textureColor.r + err);
gl_FragColor = vec4(hue, hue, hue, 1.0);
}
There are a few problems here, but the largest one is that Atkinson dithering can't be performed in an efficient manner within a fragment shader. This kind of dithering is a sequential process, being dependent on the results of fragments above and behind it. A fragment shader can only write to one fragment in OpenGL ES, not neighboring ones like is required in that Python implementation you point to.
For potential shader-friendly dither implementations, see the question "Floyd–Steinberg dithering alternatives for pixel shader."
You also normally can't write to and read from the same texture, although Apple did add some extensions in iOS 6.0 that let you write to a framebuffer and read from that written value in the same render pass.
As to why you're seeing odd error results, the coordinate system within a GPUImage filter is normalized to the range 0.0 - 1.0. When you try to offset a texture coordinate by adding 1.0, you're reading past the end of the texture (which is then clamped to the value at the edge by default). This is why you see me using texelWidth and texelHeight values as uniforms in other filters that require sampling from neighboring pixels. These are calculated as a fraction of the overall image width and height.
I'd also not recommend doing texture coordinate calculation within the fragment shader, as that will lead to a dependent texture read and really slow down the rendering. Move that up to the vertex shader, if you can.
Finally, to answer your title question, usually you can't modify a texture as it is being read, but the iOS texture cache mechanism sometimes allows you to overwrite texture values as a shader is working its way through a scene. This leads to bad tearing artifacts usually.
#GarrettAlbright For the 1-Bit Camera app I ended up with simply iterating over the image data using raw memory pointers and (rather) tightly optimized C code. I looked into NEON intrisics and the Accelerate framework, but any parallelism really screws up an algorithm of this nature so I didn't use it.
I also toyed around with the idea to do a decent enough aproximation of the error distribution on the GPU first, and then do the thresholding in another pass, but I never got anything but a rather ugly noise dither from those experiments. There are some papers around covering other ways of approaching diffusion dithering on the GPU.
I'm trying to achieve the following blending when the texture at one vertex merges with another:
Here's what I currently have:
I've enabled blending and am specifying the blending function as:
glBlendFunc(GL_ONE, GL_ONE_MINUS_SRC_ALPHA);
I can see that the image drawn in the paper app is made up of a small circle that merges with the same texture before and after and has some blending effect on the color and the alpha.
How do I achieve the desired effect?
UPDATE:
What I think is happening is that the intersected region of the two textures is getting the alpha channel to be modified (either additive or some other custom function) while the texture is not being drawn in the intersected region. The rest of the region has the rest of the texture drawn. Like so:
I'm not entirely sure of how to achieve this result, though.
You shouldn't need blending for this (and it won't work the way you want).
I think as long as you define your texture coordinate in the screen space, it should be seamless between two separate circles.
To do this, instead of using a texture coordinate passed through the vertex shader, just use the position of the fragment to sample the texture, plus or minus some scaling:
float texcoord = gl_FragCoord / vec2(xresolution_in_pixels, yresolution_in_pixels);`
gl_FragColor = glTexture2D(papertexture, texcoord);
If you don't have access to GLSL, you could do something instead with the stencil buffer. Just draw all your circles into the stencil buffer, use the combined region as a stencil mask, and then draw a fullscreen quad of your texture. The color will be seamlessly deposited at the union of all the circles.
You can achieve this effect with max blending for alpha. Or manual (blending off) with shader (OpenGL ES 2.0):
#extension GL_EXT_shader_framebuffer_fetch : require
precision highp float;
uniform sampler2D texture;
uniform vec4 color;
varying vec2 texCoords;
void main() {
float res_a =gl_LastFragData[0].a;
float a = texture2D(texture, texCoords).a;
res_a = max(a, res_a);
gl_FragColor = vec4(color.rgb * res_a, res_a);
}
Result:
I want to accomplish a GLSL Shader, that can texture and color my vertex objects. In fact, it works for me in 2 from 3 cases:
1) If I only have an texture assigned (but no specific color - so the color is "white"), I simply get an textured object - works
2) If I have an texture and an color assigned, I get an textured Object modulated with that color - works
3) If I only have an color assigned but no texture, I get an black object - doesn't work
My Shader looks like this:
varying lowp vec4 colorVarying;
varying mediump vec2 texcoordVarying;
uniform sampler2D texture;
void main(){
gl_FragColor = texture2D(texture, texcoordVarying) * colorVarying;
}
I guess that, texture2D(...,...) returns zero if no texture is assigned - so that seems to be the problem. Is there a way in GLSL I can check, if no texture is assigned (in this case, I want simply gl_FragColor = colorVarying;)
"If" isn't really an option in an GLSL Shader, if I understanded correctly - any ideas to accomplish this? Or is it really necessary to make 2 different shaders for both cases?
Like you I'd picked up the general advice that 'if' is to be avoided on current mobile hardware, but a previous optimisation discussion on StackOverflow seemed to suggest it wasn't a significant hurdle. So don't write it off. In any case, the GLSL compiler is reasonably smart and may chose to switch which code it actually runs depending on the values set for uniforms, though in that case all you're getting is the same as if you'd just supplied alternative shaders.
That said, if you're absolutely certain you want to use the same shader for all purposes and want to avoid if statements then you probably want something like:
uniform lowp float textureFlag;
[...]
gl_FragColor = textureFlag * texture2D(texture, texcoordVarying) * colorVarying +
(1.0 - textureFlag) * colorVarying;
Or even:
gl_FragColor = mix(
colorVarying,
texture2D(texture, texcoordVarying) * colorVarying,
textureFlag
)
With you setting textureFlag to 1.0 or 0.0 depending on whether you want the texture values to be factored in.
I'm not aware of any way to determine (i) whether a sampler2D is pointed to an actual texture unit; and (ii) whether a particular texture unit has a buffer bound to it for which data has been uploaded.