Actionscript: compare variables from an array - actionscript

Question

Need Help, I have totalA - totalB - totalC - totalD, need to select the highest variable from this 4 but if the highest one equal an other one, must show which variables equals.
I have used this code but when it meets the equals ( A = B = C ) it dispalys just D
var aNumber:Array = new Array(totalA , totalB , totalC , totalD );
for(var i:Number = 0; i < aNumber.length; i++)
{
if(aNumber[i] < aNumber[i+1])
{
bigger = aNumber[i+1];
}
}

Answer 1

If you're wanting to output a letter/etc for the scores, I'd use an object/dictionary rather than a straight array.
Basically, the algorithm would be:
Capture the scores in an object/dictionary, where the key is the name of the player and the value is their score.
Enumerate each item/player in the object/dictionary and compare the current score to the maximum score.
If the current score is greater than the maximum score, clear all previous winners, set the new maximum score and add the current player to the winners.
If the current score is equal to the maximum score, add the current player to the winners array.
Following is some hastily concocted actionscript.
var scores:Object = {
'A': totalA,
'B': totalB,
'C': totalC,
'D': totalD
};
var maxScore:Number = -1;
var winners:Array = new Array();
for(var player:String in scores)
{
var score:Number = scores[player];
if (score > maxScore)
{
maxScore = score;
winners = new Array();
winners.push(player);
}
else if (score == maxScore)
{
winners.push(player);
}
}
At the end of this segment of code, you should have the highest score in maxScore and the names of the winning players in the winners array.

Answer 2

var aNumber:Array = new Array(totalA , totalB , totalC , totalD );
bigger = aNumber[0];
for(var i:Number = 1, var j:Number = (aNumber.length)-1; i<j ; i++)
{
if(bigger < aNumber[i])
{
bigger = aNumber[i];
}
}
var highest:Array = new Array();
highest[] = bigger;
for(var i:Number = 0, var j:Number = (aNumber.length); i<j ; i++){
if(aNumber[i] == bigger){
highest[] = aNumber[i];
}
}
Array highest will now hold the highest score(s)

Answer 3

This solution can be a bit more elegant (assuming that a array contains integer values):
<?xml version="1.0" encoding="utf-8"?>
<mx:Application xmlns:mx="http://www.adobe.com/2006/mxml" creationComplete="init()">
<mx:Script>
<![CDATA[
import mx.collections.ArrayCollection;
import mx.collections.Sort;
import mx.collections.SortField;
import mx.controls.Alert;
private var array:Array = [1,2,3,4,3];
public function init():void{
var maxValue:Number = getMaxValue(new ArrayCollection(array));
Alert.show(String(maxValue)); //show value 4
}
private function getMaxValue(tempArr:ArrayCollection):Number {
var dataSort:Sort = new Sort();
dataSort.fields = [new SortField(null,false,true,true)];;
tempArr.sort = dataSort;
tempArr.refresh();
return tempArr[0];
}
]]>
</mx:Script>
</mx:Application>
According to this example, I order the array from highest to lowest and take the first. Its works perfectly. I hope this helps