I need to insert string parameters startDate and endDate into URL string and I am trying with stringWithFormat, however xcode complains about many other characters in the URL string which it interprets probably as invalid specifiers.
NSString *urlString = [NSString stringWithFormat:#"https://api.xmltime.com/astronomy?accesskey=l1fMY6Om37&expires=2013-06-05T18%3A00%3A00%2B00%3A00&signature=12P2tr1MyD4NnLjqhWzc%2BpsBKR0%3D&object=sun&placeid=netherlands%2Famsterdam&startdt=2013-06-04&enddt=2013-07-04&geo=0&isotime=0&lang=en&utctime=0&types=all", startDate, endDate];
I put my variables with %# specifiers on the place of 2013-06-04 and 2013-07-04 strings. I guess xcode does not like the other percent signs in the string. What is the right way of setting parameters in this string? Thank you.
Use %% to place % in stringWithFormat.
So your code becomes:
NSString *urlString = [NSString stringWithFormat:#"https://api.xmltime.com/astronomy?accesskey=l1fMY6Om37&expires=2013-06-05T18%%3A00%%3A00%%2B00%%3A00&signature=12P2tr1MyD4NnLjqhWzc%%2BpsBKR0%%3D&object=sun&placeid=netherlands%%2Famsterdam&startdt=2013-06-04&enddt=2013-07-04&geo=0&isotime=0&lang=en&utctime=0&types=all", startDate, endDate];
Related
Let's say I have the following string:
[NSString stringWithFormat:#"Booked for %# at %#", colleagueName, time];
And I realise I've forgotten to localise that string, so I replace it:
[NSString stringWithFormat:NSLocalizedString(#"bookings.bookedFor", "Booked for user at time"), colleagueName, time];
Now when doing translations, I find that the language X needs the parameters the other way round; something closer to:
<time> for booking of <colleague> is done.
What is the best way to address the fact that now I need the second parameter of my formatted string to be time and the third to be colleagueName please?
As is often the case, my colleague found the solution almost as soon as I had asked on here! Apparently Objective-C has positional arguments
The positions are 1-indexed so %1$# refers to the first argument.
NSString *firstParam = #"1st";
NSString *secondParam = #"2nd";
NSLog(#"First %1$# Second: %2$#", firstParam, secondParam);
NSLog(#"Second %2$# First: %1$#", firstParam, secondParam);
This prints:
First 1st Second: 2nd
Second 2nd First: 1st
You can try like this:
NSString * language = [[NSLocale preferredLanguages] objectAtIndex:0];
if ([language isEqualToString:#"X"]) {//X is language code like "fr","de"
[NSString stringWithFormat:NSLocalizedString(#"bookings.bookedFor", "Booked for user at time"), time, colleagueName];
} else {
[NSString stringWithFormat:NSLocalizedString(#"bookings.bookedFor", "Booked for user at time"), colleagueName,time];
}
I have a strange problem encoding my String
For example:
NSString *str = #"\u0e09\u0e31\u0e19\u0e23\u0e31\u0e01\u0e04\u0e38\u0e13";
NSString *utf = [str stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSLog("utf: %#", utf);
This worked perfectly in log
utf: ฉันรักคุณ
But, when I try using my string that I parsed from JSON with the same string:
//str is string parse from JSON
NSString *str = [spaces stringByReplacingOccurrencesOfString:#"U" withString:#"u"];
NSLog("str: %#, str);
NSString *utf = [str stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSLog("utf: %#", utf);
This didn't work in log
str: \u0e09\u0e31\u0e19\u0e23\u0e31\u0e01\u0e04\u0e38\u0e13
utf: \u0e09\u0e31\u0e19\u0e23\u0e31\u0e01\u0e04\u0e38\u0e13
I have been finding the answer for hours but still have no clue
Any would be very much appreciated! Thanks!
The string returned by JSON is actually different - it contains escaped backslashes (for each "\" you see when printing out the JSON string, what it actually contains is #"\").
In contrast, your manually created string already consists of "ฉันรักคุณ" from the beginning. You do not insert backslash characters - instead, #"\u0e09" (et. al.) is a single code point.
You could replace this line
NSString *utf = [str stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
with this line
NSString *utf = str;
and your example output would not change. The stringByReplacingPercentEscapesUsingEncoding: refers to a different kind of escaping. See here about percent encoding.
What you need to actually do, is parse the string for string representations of unicode code points. Here is a link to one potential solution: Using Objective C/Cocoa to unescape unicode characters. However, I would advise you to check out the JSON library you are using (if you are using one) - it's likely that they provide some way to handle this for you transparently. E.g. JSONkit does.
I am having a link that i want to post the data.
I am using url encoding like,
http://admin:testsite#www.arabcircleonline.com/index.php?%#=%#",form_urlencode_rfc3986(#"do"),form_urlencode_rfc3986(#"/webservice/whisper/login_chauhankevalp#gmail.com/password_keval/action_whisper/whisperdata_{\"user_status\":\"last123\",\"privacy\":0,\"privacy_comment\":0}
This is giving the response intended when a record should be added, but the record is not getting added, when i execute this link on browser, it works fine.
Please help me out of this.. i am working on this last 2 days with no solution
form_urlencode_rfc3986 method i am using is,
NSString* form_urlencode_rfc3986(NSString* s) {
CFStringRef charactersToLeaveUnescaped = CFSTR(" ");
CFStringRef legalURLCharactersToBeEscaped = CFSTR("/%&=?$#+-~#<>|\\*,.()[]{}^!");
NSString *result = CFBridgingRelease(CFURLCreateStringByAddingPercentEscapes( kCFAllocatorDefault,(__bridge CFStringRef)s,charactersToLeaveUnescaped,legalURLCharactersToBeEscaped, kCFStringEncodingUTF8));
return [result stringByReplacingOccurrencesOfString:#" " withString:#"+"];
}
You are probably trying to do this:
You have a url with a query. The query component is separated by a "?" as illustrated below:
URL := scheme-authority-path "?" query
In your case "scheme-authority-path" is
http://admin:testsite#www.arabcircleonline.com/index.php,
and a "query" is a list of parameters, separated by a "&".
Your URL string without query (scheme, authority and path):
NSString* urlString = #"http://admin:testsite#www.arabcircleonline.com/index.php";
Compose a parameter (which is part of the query), e.g. in BNF
parameter := name "=" value
NOTE: name and value need to be encoded with the helper function.
which corresponds in code:
NSString* parameterString = [NSString stringWithFormat:#"%#=%#",
form_urlencode_rfc3986(#"do"),
form_urlencode_rfc3986(
#"/webservice/whisper/login_chauhankevalp#gmail.com/password_keval/action_whisper/whisperdata_{\"user_status\":\"last123\",\"privacy\":0,\"privacy_comment\":0")
];
A query string is composed by concatenating (encoded) parameters and separating them by a "&", e.g. in BNF:
query := parameter ["&" parameter]
You have only one parameter, thus our query string becomes just the parameter string:
NSString* queryString = parameterString;
Now, compose the complete url string (including the query) from the former urlString (scheme, authority and path) and the query, by concatenating urlString, a "?" and the query. For example:
NSString* urlStringWithQuery = [NSString stringWithFormat:#"%#?%#", urlString, queryString];
I have some code to send a url to a remote server. If I do not encode the url, it works perfectly. But if I encode the url, it does not work. So I am pretty sure something is not right with the way I encode the url query string.
Here is my code:
// URL TO BE SUBMITTED.
NSString *urlString =
#"http://www.mydomain.com/test.php?";
// NOW CREATE URL QUERY STRING
NSString *unencoded_query_string =
#"name=%#&user_id=%#&person_name=%#&person_email=%#&privacy=%#";
// PUT PREVIOUSLY SET VALUES INTO THE QUERY STRING
NSString *unencoded_url_with_params =
[NSString stringWithFormat:unencoded_query_string, business , user_id , name , email , privacy_string];
// ENCODE THE QUERY STRING
NSString *escapedString = (__bridge_transfer NSString *)CFURLCreateStringByAddingPercentEscapes(
NULL,
(__bridge CFStringRef)unencoded_url_with_params,
NULL,
(CFStringRef)#"!*'();:#&=+$,/?%#[]",
kCFStringEncodingUTF8);
// NOW APPEND URL TO QUERY STRING
NSString *full_encoded_url_string =
[urlString stringByAppendingString: escapedString];
and then I send this string to the server, and the server does have the correct request file invoked, but isn't able to read the parameters.
Would anyone know what I doing incorrectly here? I am using arc by the way.
Thanks!
I think you probably want to escape each param, not the entire request. Basically you want to escape ampersands, spaces etc that show up in your get variables. Your encoded URL probably looks like this:
http://www.mydomain.com/test.php?name%3DPeter%20Willsey%26user_id%3DUSERID%26person_name%3DPeter%20Willsey%26person_email%3Dpeter%40test.com%26privacy%3D1
and it should look like this:
http://www.mydomain.com/test.php?name=Peter%20Willsey&user_id=25&person_name=Peter%20Willsey&person_email=peter%40test.com&privacy=1
I'm trying to figure how to append some parameters to a localized string?
The desired result (in a string) is "TITLE-xxxx ddmmyy".
TITLE is to be localized.
xxxx is a calculated number and ddmmyy is a fixed date format.
Thanks for any help!
Given TITLE, myDateFormatter which is a NSDateFormatter and number, which is an int:
NSString* myString = [NSString stringWithFormat:#"%#-%d %#", NSLocalizedString(TITLE, #"comment"), number, [myDateFormatter stringFromDate:date]];
Of course you can change number to an NSNumber or something if you wish so (change %d to %# then).