I have some inbuilt method in BootstrapBaseController.cs like
public void Success(string message)
{
TempData.Add(Alerts.SUCCESS, message);
}
I haven't used it yet but I guess it shows some success message that i pass to this method.
I want to use this method in my other controller called PortalController. In following method I want to show success message when a user is added to database.
Suggestions?
[HttpPost]
public ActionResult Register(RegisterModel user)
{
if (ModelState.IsValid && (user.Password == user.ConfirmPassword))
{
var regUser = _db.Users.Create();
regUser.UserName = user.UserName;
regUser.Password = user.Password;
_db.Users.Add(regUser);
_db.SaveChanges();
}
return View();
}
You'll need to make PortalController inherits from BootstrapBaseController.
public class PortalController : BootstrapBaseController
If this is not an option you may need to move that common method to a third class used by both controllers.
Make PortalController inherit from BootstrapBaseController
Before returning the View call Sucess and set the message
On your _layout.cshtml view (and I'm assuming all your views inherit use this layout) check for that temp variable and display your message
Updated Controller method:
[HttpPost]
public ActionResult Register(RegisterModel user)
{
if (ModelState.IsValid && (user.Password == user.ConfirmPassword))
{
var regUser = _db.Users.Create();
regUser.UserName = user.UserName;
regUser.Password = user.Password;
_db.Users.Add(regUser);
_db.SaveChanges();
}
Success("User Created successfully");
return View();
}
_Layout.cshtml
#if (TempData["VariableName"] != null)
{
<div>#TempData["VariableName"]</div>
}
Related
I'm developing a simple Custom Role-based Web Application using ASP.Net MVC, In my login Action, I'm creating a Profile session as below:
[HttpPost]
[AllowAnonymous]
[ValidateAntiForgeryToken]
public ActionResult Login(LoginModel model, string returnUrl)
{
using (HostingEnvironment.Impersonate())
{
if (ModelState.IsValid)
{
if (Membership.ValidateUser(model.UserName, model.Password))
{
var employeeProfile = AccountBal.Instance.GetEmployee(loginId);
Session["Profile"] = employeeProfile;
FormsAuthentication.SetAuthCookie(model.UserName, true);
}
}
// If we got this far, something failed, redisplay form
ModelState.AddModelError("", #"The user name or password provided is incorrect.");
return View(model);
}
}
And I'm checking this or using this session in all Controller Actions as below:
[HttpPost]
[ValidateAntiForgeryToken]
public ActionResult CreateOrEdit(MyModel model)
{
var employee = (Employee) Session["Profile"];
if (employee == null)
return RedirectToAction("Login", "Account");
if (ModelState.IsValid)
{
// Functionality goes here....
}
}
Is there any way I can move this piece of session checking code in a base class or centralized class? so that, I do not need to check it every time in a Controller Actions instead I will access the properties directly
say,
[HttpPost]
[ValidateAntiForgeryToken]
public ActionResult CreateOrEdit(MyModel model)
{
var employee = _profileBase.GetCurrentProfile();
if (employee == null)
return RedirectToAction("Login", "Account");
if (ModelState.IsValid)
{
// Functionality goes here....
}
}
Create a base controller that contains your GetCurrentProfile method to retrieve current user profile like
public class BaseController : Controller
{
public Employee GetCurrentProfile()
{
return (Employee)Session["Profile"];
}
public bool SetCurrentProfile(Employee emp)
{
Session["Profile"] = emp;
return true;
}
}
And inherit your desired controller with above BaseController and access your GetCurrentProfile method like below
public class HomeController : BaseController
{
public ActionResult SetProfile()
{
var emp = new Employee { ID = 1, Name = "Abc", Mobile = "123" };
//Set your profile here
if (SetCurrentProfile(emp))
{
//Do code after set employee profile
}
return View();
}
public ActionResult GetProfile()
{
//Get your profile here
var employee = GetCurrentProfile();
return View();
}
}
GetCurrentProfile and SetCurrentProfile directly available to your desired controller because we directly inherit it from BaseController.
You may usetry/catch in above code snippet.
Try once may it help you
I created an Umbraco DocumentType with the alias Personal and created a controller that inherits
Umbraco.Web.Mvc.RenderMvcController
I added two Actions, one is the default action and the other is called Test.
How can I fire the Test Action from the Personal controller?
public class PersonalController : Umbraco.Web.Mvc.RenderMvcController
{
// GET: Personal
public override ActionResult Index(RenderModel model)
{
return base.Index(model);
}
public String Test(RenderModel model)
{
return "fff";
}
}
When I put the url like this: localHost/personal/test it shows:
No umbraco document matches the url '/test'.
Which is right, so how can I call it?
I would do it like this
[HttpPost]
public ActionResult SubmitSearchForm(SearchViewModel model)
{
if (ModelState.IsValid)
{
if (!string.IsNullOrEmpty(model.SearchTerm))
{
model.SearchTerm = model.SearchTerm;
model.SearchGroups = GetSearchGroups(model);
model.SearchResults = _searchHelper.GetSearchResults(model, Request.Form.AllKeys);
}
return RenderSearchResults(model.SearchResults);
}
return null;
}
public ActionResult RenderSearchResults(SearchResultsModel model)
{
return PartialView(PartialViewPath("_SearchResults"), model);
}
See this blog post for the full context behind where this code snippet came from.
http://www.codeshare.co.uk/blog/how-to-search-by-document-type-and-property-in-umbraco/
(MVC)How to RedirectToAction and keep the content of a Html.Textbox in MVC4? This is my controller how do I fix it and what goes in the view?
[HttpPost]
public ActionResult Index(string ssn)
{
var exist = false;
var record = _db.Citations.Where(u => u.SSN == ssn).FirstOrDefault();
if (record != null)
{
exist = true;
return RedirectToAction("EditDetails", new { id = record.CitationID });
}
else
{
return RedirectToAction("Index", "SubmitAward", ssn); // wiped out ssn! I need to keep the ssn
// so that the user can fill out the form.
}
If your get action is like this:
public ActionResult Index(string ssn)
{
.........
..........
.........
}
then do like this:
return RedirectToAction("Index", "SubmitAward", new { ssn = ssn});
but if it is the same index view of post action which is posted in question, you can pass the object back to view if your view is strongly typed to this class:
return View(record);
Try below code
return RedirectToAction("Index", "SubmitAward", new { ssn = ssn});
And your redirect action will be
public ActionResult Index(string ssn)
{
ViewBag.SSN=ssn;
return View(record);
}
And your view will contain textbox like
#Html.TextBox("SSN",ViewBag.SSN)
It may helps you..
On POST , if validation failed and before sending back the ViewModel to the same View with Model State errors, do you rebuild ViewModel for all SelectLists, ReadOnly fields etc?
right now I have separate methods for Fill First Time(for GET Edit-Method) / Rebuild ViewModels from domain objects, what is the best practice so I can be DRY and also not have to change two methods any time I add a new readonly property to ViewModel?
My Solution: Followed this Pattern
Followed pattern suggested here: https://stackoverflow.com/a/2775656/57132
In IModelBuilder Implementation
Build(..)
{
var viewModel = new ViewModel();
// and Fill all Non-ReadOnly fields
...
...
call CompleteViewModel(viewModel)
}
CompleteViewModel(ViewModel viewModel)
{
//Fill all ReadOnly & SelectLists
...
}
The reason I went with this solution is because I don't want to store stuff on server to retrieve across the HTTP Requests
I don't rebuild it, because I don't stay at POST. I follow POST-REDIRECT-GET pattern, so if I post to /User/Edit/1 using POST HTTP method, I get redirected to /User/Edit/1 uasing GET.
ModelState is transferred to TempData to follow Post-Redirect-Get and be availabe at GET call. View model is built in one place, at GET call. Example:
[HttpPost]
[ExportModelStateToTempData]
public ActionResult Edit(int id, SomeVM postedModel)
{
if (ModelState.IsValid) {
//do something with postedModel and then go back to list
return RedirectToAction(ControllerActions.List);
}
//return back to edit, because there was an error
return RedirectToAction(ControllerActions.Edit, new { id });
}
[ImportModelStateFromTempData]
public ActionResult Edit(int id)
{
var model = //create model here
return View(ControllerActions.Edit, model);
}
This is code for attributes importing/exporting ModelState:
public abstract class ModelStateTempDataTransferAttribute : ActionFilterAttribute
{
protected static readonly string Key = typeof(ModelStateTempDataTransferAttribute).FullName;
}
public class ExportModelStateToTempDataAttribute : ModelStateTempDataTransferAttribute
{
public override void OnActionExecuted(ActionExecutedContext filterContext)
{
//Only export when ModelState is not valid
if (!filterContext.Controller.ViewData.ModelState.IsValid)
{
//Export if we are redirecting
if ((filterContext.Result is RedirectResult) || (filterContext.Result is RedirectToRouteResult))
{
filterContext.Controller.TempData[Key] = filterContext.Controller.ViewData.ModelState;
}
}
base.OnActionExecuted(filterContext);
}
}
public class ImportModelStateFromTempDataAttribute : ModelStateTempDataTransferAttribute
{
public override void OnActionExecuted(ActionExecutedContext filterContext)
{
ModelStateDictionary modelState = filterContext.Controller.TempData[Key] as ModelStateDictionary;
if (modelState != null)
{
//Only Import if we are viewing
if (filterContext.Result is ViewResult)
{
filterContext.Controller.ViewData.ModelState.Merge(modelState);
}
else
{
//Otherwise remove it.
filterContext.Controller.TempData.Remove(Key);
}
}
base.OnActionExecuted(filterContext);
}
}
The simplest solution would be to pass in you viewModel to the method and account for null
private MyViewModel BuildViewModel(MyViewModel model = null)
{
model = model ?? new MyViewModel();
model.ReadOnlyList = new .....
.
.
return model;
}
for Create:
var model = BuildViewModel();
for rebuild:
model = buildViewModel(model);
I like #LukLed's answer above - it looks very interesting. If you want another option, here's what I currently do.
In my service layer, I have a method to build my view model. I call that on GET and return the the view model to the view. On POST, I build the model from the incoming ID and then TryUpdateModel(model). From there, you can do whatever you like (save, check model state, etc.). With this method, you only have 1 build method and only have to update it once if your model changes (i.e. add/remove properties in the future, etc.).
[HttpGet]
public ActionResult AssessFocuses(int apaID)
{
var model = this.apaService.BuildAssessFocusesViewModel(apaID);
return this.View(model);
}
[HttpPost]
public ActionResult AssessFocuses(int apaID, string button)
{
var model = this.apaService.BuildAssessFocusesViewModel(apaID);
this.TryUpdateModel(model);
switch (button)
{
case ButtonSubmitValues.Back:
case ButtonSubmitValues.Next:
case ButtonSubmitValues.Save:
case ButtonSubmitValues.SaveAndClose:
{
try
{
this.apaService.SaveFocusResults(model);
}
catch (ModelStateException<AssessFocusesViewModel> mse)
{
mse.ApplyTo(this.ModelState);
}
if (!this.ModelState.IsValid)
{
this.ShowErrorMessage(Resources.ErrorMsg_WEB_ValidationSummaryTitle);
return this.View(model);
}
break;
}
default:
throw new InvalidOperationException(string.Format(Resources.ErrorMsg_WEB_InvalidButton, button));
}
switch (button)
{
case ButtonSubmitValues.Back:
return this.RedirectToActionFor<APAController>(c => c.EnterRecommendationsPartner(model.ApaID));
case ButtonSubmitValues.Next:
return this.RedirectToActionFor<APAController>(c => c.AssessCompetenciesPartner(model.ApaID));
case ButtonSubmitValues.Save:
this.ShowSuccessMessage(Resources.Msg_WEB_NotifyBarSuccessGeneral);
return this.RedirectToActionFor<APAController>(c => c.AssessFocuses(model.ApaID));
case ButtonSubmitValues.SaveAndClose:
default:
return this.RedirectToActionFor<UtilityController>(c => c.CloseWindow());
}
}
I am working on a ASP.NET MVC website and I am new to this.
I have a controller with few actions. I want to use these actions through out my website.
For example
[HttpPost]
public ActionResult MyAction(ViewModel model)
{
if (ModelState.IsValid)
{
//code is here
}
return RedirectToAction(); // redirect to same view
}
I want to redirect to same view from where request is generated. I am not sure if this is possible or not ?
Based on your comment, I would create a Controller that looks like:
public MyController : Controller
{
private ActionResult SharedMethod(SomeModel model)
{
if (ModelState.IsValid)
{
//code is here
}
// viewname is required, otherwise the view name used will be
// the original calling method (ie public1.cshtml, public2.cshtml)
return this.View("SharedViewName");
}
public ActionResult Public1(SomeModel model)
{
return this.SharedMethod(model);
}
public ActionResult Public1(SomeModel model)
{
return this.SharedMethod(model);
}
}