How to calculate the center coordinates of CLLocationDistance - ios

I want calculate the center point between my location and some annotation. So far I have done this:
CLLocation *myLoc = self.locMgr.location;
MKPointAnnotation *middleAnnotation = [locationV.annotations objectAtIndex:locationV.annotations.count/2];
CLLocation *someStuiodLoc = [[CLLocation alloc] initWithLatitude:middleAnnotation.coordinate.latitude longitude:middleAnnotation.coordinate.longitude];
CLLocationDistance dist = [myLoc distanceFromLocation:someStuiodLoc];
How can I calculate the center point/cordinate of "dist" ??

#define ToRadian(x) ((x) * M_PI/180)
#define ToDegrees(x) ((x) * 180/M_PI)
+ (CLLocationCoordinate2D)midpointBetweenCoordinate:(CLLocationCoordinate2D)c1 andCoordinate:(CLLocationCoordinate2D)c2
{
c1.latitude = ToRadian(c1.latitude);
c2.latitude = ToRadian(c2.latitude);
CLLocationDegrees dLon = ToRadian(c2.longitude - c1.longitude);
CLLocationDegrees bx = cos(c2.latitude) * cos(dLon);
CLLocationDegrees by = cos(c2.latitude) * sin(dLon);
CLLocationDegrees latitude = atan2(sin(c1.latitude) + sin(c2.latitude), sqrt((cos(c1.latitude) + bx) * (cos(c1.latitude) + bx) + by*by));
CLLocationDegrees longitude = ToRadian(c1.longitude) + atan2(by, cos(c1.latitude) + bx);
CLLocationCoordinate2D midpointCoordinate;
midpointCoordinate.longitude = ToDegrees(longitude);
midpointCoordinate.latitude = ToDegrees(latitude);
return midpointCoordinate;
}

I have written library function in Swift to calculate the midpoint between multiple coordinates as following:
// /** Degrees to Radian **/
class func degreeToRadian(angle:CLLocationDegrees) -> CGFloat{
return ( (CGFloat(angle)) / 180.0 * CGFloat(M_PI) )
}
// /** Radians to Degrees **/
class func radianToDegree(radian:CGFloat) -> CLLocationDegrees{
return CLLocationDegrees( radian * CGFloat(180.0 / M_PI) )
}
class func middlePointOfListMarkers(listCoords: [CLLocationCoordinate2D]) -> CLLocationCoordinate2D{
var x = 0.0 as CGFloat
var y = 0.0 as CGFloat
var z = 0.0 as CGFloat
for coordinate in listCoords{
var lat:CGFloat = degreeToRadian(coordinate.latitude)
var lon:CGFloat = degreeToRadian(coordinate.longitude)
x = x + cos(lat) * cos(lon)
y = y + cos(lat) * sin(lon);
z = z + sin(lat);
}
x = x/CGFloat(listCoords.count)
y = y/CGFloat(listCoords.count)
z = z/CGFloat(listCoords.count)
var resultLon: CGFloat = atan2(y, x)
var resultHyp: CGFloat = sqrt(x*x+y*y)
var resultLat:CGFloat = atan2(z, resultHyp)
var newLat = radianToDegree(resultLat)
var newLon = radianToDegree(resultLon)
var result:CLLocationCoordinate2D = CLLocationCoordinate2D(latitude: newLat, longitude: newLon)
return result
}
Detailed answer can be found here

U can calculate the midPoint of two coordinates using the mid point formula (http://www.purplemath.com/modules/midpoint.htm) which gives a close approximation to the actual geographical point if the distances are lesser than 500 miles. If you consider that the earth is spherical, then a more complex treatment of the points would be involved.

Related

Find Locations within a radius of 15 meters in linq

I have a Location Table and save Lat,Lon of loctions in it.
I want to find Locations in radius of special location
How to find it?
var lon = 52.12457;
var lat = 58.9542154;
var locations=db.Locations.Where(m=>?)
Translating the JS function from this answer from my above comment to C# gives you the following
public static double GetDistance(double lat1, double lon1, double lat2, double lon2) {
var R = 6371; // Radius of the earth in km
var dLat = Deg2Rad(lat2-lat1); // deg2rad below
var dLon = Deg2Rad(lon2-lon1);
var a = Math.Sin(dLat/2) * Math.Sin(dLat/2) +
Math.Cos(deg2rad(lat1)) * Math.Cos(deg2rad(lat2)) *
Math.Sin(dLon/2) * Math.Sin(dLon/2);
var c = 2 * Math.Atan2(Math.Sqrt(a), Math.Sqrt(1-a));
var d = R * c; // Distance in km
return d * 1000; //distance in m
}
public static double Deg2Rad(double deg) {
return deg * (Math.PI/180);
}
which you then can easily call in your Where clause
var lon = 52.12457;
var lat = 58.9542154;
var locations = db.Locations.Where(m=> GetDistance(lat, lon, m.lat, m.lon) < 15);

How to get buffer polygon coordinates (latitude and longitude) in iOS?

I have created one polygon on map with some set of coordinates.
I need help regarding making one buffered polygon with some given distance outside of original polygon border.
so what i need a method with such algorithm in which i pass set of coordinates as input and should get buffered set of coordinates as output.
I tried to achieve this by using arcgis library for ios with bufferGeometry method of AGSGeometryEngine but problem is, this is tightly coupled and only will work their GIS Map but I am using Mapbox which is different Map. So I want one generic method which can resolve my problem independent to map.
The solution of #Ravikant Paudel though comprehensive didn't work for me so I have implemented the approach myself.
Also, I implemented the approach in kotlin and adding it here so that someone else who is facing a similar problem will find it helpful.
Approach:
Find the angle of the angle bisector theta for every vertice of the polygon.
Draw a circle with radius = bufferedDistance / sin(angleBisctorTheta)
Find intersections of the circle and angle bisector.
Out of the 2 intersection points the one inside the polygon will give you the buffered vertice for the shrunk polygon and the outside point for the buffered polygon.
This approach does not account for the corner cases in which both points somehow fall inside or outside the polygon -> in which case the buffered polygon formed will be malformed.
Code:
private fun computeAngleBisectorTheta(
prevLatLng: LatLng,
currLatLng: LatLng,
nextLatLng: LatLng
): Double {
var phiBisector = 0.0
try {
val aPrime = getDeltaPrimeVector(prevLatLng, currLatLng)
val cPrime = getDeltaPrimeVector(nextLatLng, currLatLng)
val thetaA = atan2(aPrime[1], aPrime[0])
val thetaC = atan2(cPrime[1], cPrime[0])
phiBisector = (thetaA + thetaC) / 2.0
} catch (e: Exception) {
logger.error("[Error] in computeAngleBisectorSlope: $e")
}
return phiBisector
}
private fun getDeltaPrimeVector(
aLatLng: LatLng,
bLatLng: LatLng
): ArrayList<Double> {
val arrayList: ArrayList<Double> = ArrayList<Double>(2)
try {
val aX = convertToXY(aLatLng.latitude)
val aY = convertToXY(aLatLng.longitude)
val bX = convertToXY(bLatLng.latitude)
val bY = convertToXY(bLatLng.longitude)
arrayList.add((aX - bX))
arrayList.add((aY - bY))
} catch (e: Exception) {
logger.error("[Error] in getDeltaPrimeVector: $e")
}
return arrayList
}
private fun convertToXY(coordinate: Double) =
EARTH_RADIUS * toRad(coordinate)
private fun convertToLatLngfromXY(coordinate: Double) =
toDegrees(coordinate / EARTH_RADIUS)
private fun computeBufferedVertices(
angle: Double, bufDis: Int,
centerLatLng: LatLng
): ArrayList<LatLng> {
var results = ArrayList<LatLng>()
try {
val distance = bufDis / sin(angle)
var slope = tan(angle)
var inverseSlopeSquare = sqrt(1 + slope * slope * 1.0)
var distanceByInverseSlopeSquare = distance / inverseSlopeSquare
var slopeIntoDistanceByInverseSlopeSquare = slope * distanceByInverseSlopeSquare
var p1X: Double = convertToXY(centerLatLng.latitude) + distanceByInverseSlopeSquare
var p1Y: Double =
convertToXY(centerLatLng.longitude) + slopeIntoDistanceByInverseSlopeSquare
var p2X: Double = convertToXY(centerLatLng.latitude) - distanceByInverseSlopeSquare
var p2Y: Double =
convertToXY(centerLatLng.longitude) - slopeIntoDistanceByInverseSlopeSquare
val tempLatLng1 = LatLng(convertToLatLngfromXY(p1X), convertToLatLngfromXY(p1Y))
results.add(tempLatLng1)
val tempLatLng2 = LatLng(convertToLatLngfromXY(p2X), convertToLatLngfromXY(p2Y))
results.add(tempLatLng2)
} catch (e: Exception) {
logger.error("[Error] in computeBufferedVertices: $e")
}
return results
}
private fun getVerticesOutsidePolygon(
verticesArray: ArrayList<LatLng>,
polygon: ArrayList<LatLng>
): LatLng {
if (isPointInPolygon(
verticesArray[0].latitude,
verticesArray[0].longitude,
polygon
)
) {
if (sPointInPolygon(
verticesArray[1].latitude,
verticesArray[1].longitude,
polygon
)
) {
logger.error("[ERROR] Malformed polygon! Both Vertices are inside the polygon! $verticesArray")
} else {
return verticesArray[1]
}
} else {
if (PolygonGeofenceHelper.isPointInPolygon(
verticesArray[1].latitude,
verticesArray[1].longitude,
polygon
)
) {
return verticesArray[0]
} else {
logger.error("[ERROR] Malformed polygon! Both Vertices are outside the polygon!: $verticesArray")
}
}
//returning a vertice anyway because there is no fall back policy designed if both vertices are inside or outside the polygon
return verticesArray[0]
}
private fun toRad(angle: Double): Double {
return angle * Math.PI / 180
}
private fun toDegrees(radians: Double): Double {
return radians * 180 / Math.PI
}
private fun getVerticesInsidePolygon(
verticesArray: ArrayList<LatLng>,
polygon: ArrayList<LatLng>
): LatLng {
if (isPointInPolygon(
verticesArray[0].latitude,
verticesArray[0].longitude,
polygon
)
) {
if (isPointInPolygon(
verticesArray[1].latitude,
verticesArray[1].longitude,
polygon
)
) {
logger.error("[ERROR] Malformed polygon! Both Vertices are inside the polygon! $verticesArray")
} else {
return verticesArray[0]
}
} else {
if (PolygonGeofenceHelper.isPointInPolygon(
verticesArray[1].latitude,
verticesArray[1].longitude,
polygon
)
) {
return verticesArray[1]
} else {
logger.error("[ERROR] Malformed polygon! Both Vertices are outside the polygon!: $verticesArray")
}
}
//returning a vertice anyway because there is no fall back policy designed if both vertices are inside or outside the polygon
return LatLng(0.0, 0.0)
}
fun getBufferedPolygon(
polygon: ArrayList<LatLng>,
bufferDistance: Int,
isOutside: Boolean
): ArrayList<LatLng> {
var bufferedPolygon = ArrayList<LatLng>()
var isBufferedPolygonMalformed = false
try {
for (i in 0 until polygon.size) {
val prevLatLng: LatLng = polygon[if (i - 1 < 0) polygon.size - 1 else i - 1]
val centerLatLng: LatLng = polygon[i]
val nextLatLng: LatLng = polygon[if (i + 1 == polygon.size) 0 else i + 1]
val computedVertices =
computeBufferedVertices(
computeAngleBisectorTheta(
prevLatLng, centerLatLng, nextLatLng
), bufferDistance, centerLatLng
)
val latLng = if (isOutside) {
getVerticesOutsidePolygon(
computedVertices,
polygon
)
} else {
getVerticesInsidePolygon(
computedVertices,
polygon
)
}
if (latLng.latitude == 0.0 && latLng.longitude == 0.0) {
isBufferedPolygonMalformed = true
break
}
bufferedPolygon.add(latLng)
}
if (isBufferedPolygonMalformed) {
bufferedPolygon = polygon
logger.error("[Error] Polygon generated is malformed returning the same polygon: $polygon , $bufferDistance, $isOutside")
}
} catch (e: Exception) {
logger.error("[Error] in getBufferedPolygon: $e")
}
return bufferedPolygon
}
You'll need to pass an array of points present in the polygon in the code and the buffer distance the third param is to get the outside buffer or the inside buffer. (Note: I am assuming that the vertices in this list are adjacent to each other).
I have tried to keep this answer as comprehensive as possible. Please feel free to suggest any improvements or a better approach.
You can find the detailed math behind the above code on my portfolio page.
Finding angle bisector
To approximate latitude and longitude to a 2D cartesian coordinate system.
To check if the point is inside a polygon I am using the approach mentioned in this geeks for geeks article
I have same problem in my app and finally found the solution by the help of this site
I am an android developer and my code may not be useful to you but the core concept is same.
At first we need to find the bearing of the line with the help of two points LatLng points.(i have done by using computeDistanceAndBearing(double lat1, double lon1,double lat2, double lon2) function)
Now to get the buffering of certain point we need to give the buffering distance ,LatLng point and bearing (which i obtain from computeDistanceAndBearing function).(I have done this by using computeDestinationAndBearing(double lat1, double lon1,double brng, double dist) function ). from single LatLng point we get two points by producing them with their bearing with certain distance.
Now we need to find the interestion point of the two point to get the buffering that we want. for this remember to take new obtain point and bearing of another line and same with another. This helps to obtain new intersection point with buffering you want.(i have done this in my function computeIntersectionPoint(LatLng p1, double brng1, LatLng p2, double brng2))
Do this to all the polygon points and then you get new points whichyou joint to get buffering.
This is the way i have done in my android location app whis is
Here is my code
//computeDistanceAndBearing(double lat1, double lon1,
double lat2, double lon2)
public static double[] computeDistanceAndBearing(double lat1, double lon1,
double lat2, double lon2) {
// Based on http://www.ngs.noaa.gov/PUBS_LIB/inverse.pdf
// using the "Inverse Formula" (section 4)
double results[] = new double[3];
int MAXITERS = 20;
// Convert lat/long to radians
lat1 *= Math.PI / 180.0;
lat2 *= Math.PI / 180.0;
lon1 *= Math.PI / 180.0;
lon2 *= Math.PI / 180.0;
double a = 6378137.0; // WGS84 major axis
double b = 6356752.3142; // WGS84 semi-major axis
double f = (a - b) / a;
double aSqMinusBSqOverBSq = (a * a - b * b) / (b * b);
double L = lon2 - lon1;
double A = 0.0;
double U1 = Math.atan((1.0 - f) * Math.tan(lat1));
double U2 = Math.atan((1.0 - f) * Math.tan(lat2));
double cosU1 = Math.cos(U1);
double cosU2 = Math.cos(U2);
double sinU1 = Math.sin(U1);
double sinU2 = Math.sin(U2);
double cosU1cosU2 = cosU1 * cosU2;
double sinU1sinU2 = sinU1 * sinU2;
double sigma = 0.0;
double deltaSigma = 0.0;
double cosSqAlpha = 0.0;
double cos2SM = 0.0;
double cosSigma = 0.0;
double sinSigma = 0.0;
double cosLambda = 0.0;
double sinLambda = 0.0;
double lambda = L; // initial guess
for (int iter = 0; iter < MAXITERS; iter++) {
double lambdaOrig = lambda;
cosLambda = Math.cos(lambda);
sinLambda = Math.sin(lambda);
double t1 = cosU2 * sinLambda;
double t2 = cosU1 * sinU2 - sinU1 * cosU2 * cosLambda;
double sinSqSigma = t1 * t1 + t2 * t2; // (14)
sinSigma = Math.sqrt(sinSqSigma);
cosSigma = sinU1sinU2 + cosU1cosU2 * cosLambda; // (15)
sigma = Math.atan2(sinSigma, cosSigma); // (16)
double sinAlpha = (sinSigma == 0) ? 0.0 : cosU1cosU2 * sinLambda
/ sinSigma; // (17)
cosSqAlpha = 1.0 - sinAlpha * sinAlpha;
cos2SM = (cosSqAlpha == 0) ? 0.0 : cosSigma - 2.0 * sinU1sinU2
/ cosSqAlpha; // (18)
double uSquared = cosSqAlpha * aSqMinusBSqOverBSq; // defn
A = 1 + (uSquared / 16384.0) * // (3)
(4096.0 + uSquared * (-768 + uSquared * (320.0 - 175.0 * uSquared)));
double B = (uSquared / 1024.0) * // (4)
(256.0 + uSquared * (-128.0 + uSquared * (74.0 - 47.0 * uSquared)));
double C = (f / 16.0) * cosSqAlpha * (4.0 + f * (4.0 - 3.0 * cosSqAlpha)); // (10)
double cos2SMSq = cos2SM * cos2SM;
deltaSigma = B
* sinSigma
* // (6)
(cos2SM + (B / 4.0)
* (cosSigma * (-1.0 + 2.0 * cos2SMSq) - (B / 6.0) * cos2SM
* (-3.0 + 4.0 * sinSigma * sinSigma)
* (-3.0 + 4.0 * cos2SMSq)));
lambda = L
+ (1.0 - C)
* f
* sinAlpha
* (sigma + C * sinSigma
* (cos2SM + C * cosSigma * (-1.0 + 2.0 * cos2SM * cos2SM))); // (11)
double delta = (lambda - lambdaOrig) / lambda;
if (Math.abs(delta) < 1.0e-12) {
break;
}
}
double distance = (b * A * (sigma - deltaSigma));
results[0] = distance;
if (results.length > 1) {
double initialBearing = Math.atan2(cosU2 * sinLambda, cosU1 * sinU2
- sinU1 * cosU2 * cosLambda);
initialBearing *= 180.0 / Math.PI;
results[1] = initialBearing;
if (results.length > 2) {
double finalBearing = Math.atan2(cosU1 * sinLambda, -sinU1 * cosU2
+ cosU1 * sinU2 * cosLambda);
finalBearing *= 180.0 / Math.PI;
results[2] = finalBearing;
}
}
return results;
}
//computeDestinationAndBearing(double lat1, double lon1,double brng, double dist)
public static double[] computeDestinationAndBearing(double lat1, double lon1,
double brng, double dist) {
double results[] = new double[3];
double a = 6378137, b = 6356752.3142, f = 1 / 298.257223563; // WGS-84
// ellipsiod
double s = dist;
double alpha1 = toRad(brng);
double sinAlpha1 = Math.sin(alpha1);
double cosAlpha1 = Math.cos(alpha1);
double tanU1 = (1 - f) * Math.tan(toRad(lat1));
double cosU1 = 1 / Math.sqrt((1 + tanU1 * tanU1)), sinU1 = tanU1 * cosU1;
double sigma1 = Math.atan2(tanU1, cosAlpha1);
double sinAlpha = cosU1 * sinAlpha1;
double cosSqAlpha = 1 - sinAlpha * sinAlpha;
double uSq = cosSqAlpha * (a * a - b * b) / (b * b);
double A = 1 + uSq / 16384
* (4096 + uSq * (-768 + uSq * (320 - 175 * uSq)));
double B = uSq / 1024 * (256 + uSq * (-128 + uSq * (74 - 47 * uSq)));
double sinSigma = 0, cosSigma = 0, deltaSigma = 0, cos2SigmaM = 0;
double sigma = s / (b * A), sigmaP = 2 * Math.PI;
while (Math.abs(sigma - sigmaP) > 1e-12) {
cos2SigmaM = Math.cos(2 * sigma1 + sigma);
sinSigma = Math.sin(sigma);
cosSigma = Math.cos(sigma);
deltaSigma = B
* sinSigma
* (cos2SigmaM + B
/ 4
* (cosSigma * (-1 + 2 * cos2SigmaM * cos2SigmaM) - B / 6
* cos2SigmaM * (-3 + 4 * sinSigma * sinSigma)
* (-3 + 4 * cos2SigmaM * cos2SigmaM)));
sigmaP = sigma;
sigma = s / (b * A) + deltaSigma;
}
double tmp = sinU1 * sinSigma - cosU1 * cosSigma * cosAlpha1;
double lat2 = Math.atan2(sinU1 * cosSigma + cosU1 * sinSigma * cosAlpha1,
(1 - f) * Math.sqrt(sinAlpha * sinAlpha + tmp * tmp));
double lambda = Math.atan2(sinSigma * sinAlpha1, cosU1 * cosSigma - sinU1
* sinSigma * cosAlpha1);
double C = f / 16 * cosSqAlpha * (4 + f * (4 - 3 * cosSqAlpha));
double L = lambda
- (1 - C)
* f
* sinAlpha
* (sigma + C * sinSigma
* (cos2SigmaM + C * cosSigma * (-1 + 2 * cos2SigmaM * cos2SigmaM)));
double lon2 = (toRad(lon1) + L + 3 * Math.PI) % (2 * Math.PI) - Math.PI; // normalise
// to
// -180...+180
double revAz = Math.atan2(sinAlpha, -tmp); // final bearing, if required
results[0] = toDegrees(lat2);
results[1] = toDegrees(lon2);
results[2] = toDegrees(revAz);
return results;
}
private static double toRad(double angle) {
return angle * Math.PI / 180;
}
private static double toDegrees(double radians) {
return radians * 180 / Math.PI;
}
//computeIntersectionPoint(LatLng p1, double brng1, LatLng p2, double brng2)
public static LatLng computeIntersectionPoint(LatLng p1, double brng1, LatLng p2, double brng2) {
double lat1 = toRad(p1.latitude), lng1 = toRad(p1.longitude);
double lat2 = toRad(p2.latitude), lng2 = toRad(p2.longitude);
double brng13 = toRad(brng1), brng23 = toRad(brng2);
double dlat = lat2 - lat1, dlng = lng2 - lng1;
double delta12 = 2 * Math.asin(Math.sqrt(Math.sin(dlat / 2) * Math.sin(dlat / 2)
+ Math.cos(lat1) * Math.cos(lat2) * Math.sin(dlng / 2) * Math.sin(dlng / 2)));
if (delta12 == 0) return null;
double initBrng1 = Math.acos((Math.sin(lat2) - Math.sin(lat1) * Math.cos(delta12)) / (Math.sin(delta12) * Math.cos(lat1)));
double initBrng2 = Math.acos((Math.sin(lat1) - Math.sin(lat2) * Math.cos(delta12)) / (Math.sin(delta12) * Math.cos(lat2)));
double brng12 = Math.sin(lng2 - lng1) > 0 ? initBrng1 : 2 * Math.PI - initBrng1;
double brng21 = Math.sin(lng2 - lng1) > 0 ? 2 * Math.PI - initBrng2 : initBrng2;
double alpha1 = (brng13 - brng12 + Math.PI) % (2 * Math.PI) - Math.PI;
double alpha2 = (brng21 - brng23 + Math.PI) % (2 * Math.PI) - Math.PI;
double alpha3 = Math.acos(-Math.cos(alpha1) * Math.cos(alpha2) + Math.sin(alpha1) * Math.sin(alpha2) * Math.cos(delta12));
double delta13 = Math.atan2(Math.sin(delta12) * Math.sin(alpha1) * Math.sin(alpha2), Math.cos(alpha2) + Math.cos(alpha1) * Math.cos(alpha3));
double lat3 = Math.asin(Math.sin(lat1) * Math.cos(delta13) + Math.cos(lat1) * Math.sin(delta13) * Math.cos(brng13));
double dlng13 = Math.atan2(Math.sin(brng13) * Math.sin(delta13) * Math.cos(lat1), Math.cos(delta13) - Math.sin(lat1) * Math.sin(lat3));
double lng3 = lng1 + dlng13;
return new LatLng(toDegrees(lat3), (toDegrees(lng3) + 540) % 360 - 180);
}
I will suggest you to go through the the above site and get the knowledge as i had also done the same.
Hope this may help , i know the is not in ios but the concept is same as i done my project by changing code of javascript.
Cheers !!!
My requirement was something similar to this. I ended up writing up my own algo for this. https://github.com/RanaRanvijaySingh/PolygonBuffer
All you need to use is this line
double distance = 0.0001;
List bufferedPolygonList = AreaBuffer.buffer(pointList, distance);
It gives you a list of buffered polygon points at a given distance from your original polygon.
I would recommend to use Turf.js library for buffering and many basic gis operations. You would be able to retrieve each edge from the path that returned. For geometry buffer, it is easy to use, quite light weighted and it works without any problem for my applications using MapBox.js or leaflet.
More details : Turf.js Buffer
But if you are looking for a geodesic distance buffer that could be problem. I would use Arcgis Javascript API
Take a look at BOOST this is a big C++ library, you may find library/source code for almost everything up there like, buffer methods with different types such as miter,round,square.
Just install the latest version of the Boost which I guess is 1.58.0 right now, and take a look at BOOST/Geometry/Strategies/Cartesian/buffer[Something]-Square/Miter/Round
Here it is a good document
You need to convert your geodetic coordinates (lat/long) to cartesian (x/y) and use the Boost library and reverse the conversion. you do not need to use ArcGIS or any other GIS library at all.

Create perpendicular lat long from single cllocation coordinate of X meter

I have user current location i.e. CLLocation Coordinate (location lat & long) and user is on race track pointing to one direction with the help of user current location i created one region now I want some more race track coordinate(say 2m , 4m , 6m away from race track in perpendicular direction) and the track is 10 m long. Please check the image and the red points are on the track.
Please check this image
/**
* Returns the destination point from initial point having travelled the given distance on the
* given initial bearing (bearing normally varies around path followed).
*
* #param {double} distance - Distance travelled, in same units as earth radius (default: metres).
* #param {double} bearing - Initial bearing in degrees from north.
*
* #returns {CLLocationCoordinate} Destination point.
*/
#define kEarthRadius 6378137
- (CLLocationCoordinate2D)destinationPointWithStartingPoint:(MKMapPoint)initialPoint distance:(double)distance andBearing:(double)bearing {
CLLocationCoordinate2D location = MKCoordinateForMapPoint(initialPoint);
double delta = distance / kEarthRadius;
double omega = [self degreesToRadians:bearing];
double phi1 = [self degreesToRadians:location.latitude];
double lambda1 = [self degreesToRadians:location.longitude];
double phi2 = asin(sin(phi1)*cos(delta) + cos(phi1) * sin(delta) * cos(omega));
double x = cos(delta) - sin(phi1) * sin(phi2);
double y = sin(omega) * sin(delta) * cos(phi1);
double lambda2 = lambda1 + atan2(y, x);
return CLLocationCoordinate2DMake([self radiansToDegrees:phi2], ([self radiansToDegrees:lambda2]+540)%360-180);
}
- (CLLocationCoordinate2D)rhumbDestinationPointForInitialPoint:(MKMapPoint)initialPoint distance:(double)distance andBearing:(double)bearing {
CLLocationCoordinate2D location = MKCoordinateForMapPoint(initialPoint);
double delta = distance / kEarthRadius;
double omega = [self degreesToRadians:bearing];
double phi1 = [self degreesToRadians:location.latitude];
double lambda1 = [self degreesToRadians:location.longitude];
double delta_phi = delta * cos(omega);
double phi2 = phi1 + delta_phi;
// check for some daft bugger going past the pole, normalise latitude if so
if (fabs(phi2) > M_PI / 2) {
phi2 = phi2 > 0 ? M_PI-phi2 : -M_PI-phi2;
}
double delta_gamma = log(tan(phi2/2+M_PI/4)/tan(phi1/2+M_PI/4));
double q = fabs(delta_gamma) > 10e-12 ? delta_phi / delta_gamma : cos(phi1);
double delta_lambda = delta*sin(omega)/q;
double lambda2 = lambda1 + delta_lambda;
return CLLocationCoordinate2DMake([self radiansToDegrees:phi2], ([self radiansToDegrees:lambda2]+540)%360-180);
}
- (double)degreesToRadians:(double)degrees {
return degrees * M_PI / 180.0;
}
- (double)radiansToDegrees:(double)radians {
return radians * 180.0 / M_PI;
}
Adapted from : http://www.movable-type.co.uk/scripts/latlong.html
More information on bearing : https://en.wikipedia.org/wiki/Bearing_(navigation)
And rhumb line : https://en.wikipedia.org/wiki/Rhumb_line

Can't get Panoramio Data with API

I am trying to get panoramio picture around a given coordinate. However always my query returns zero photos. This is the code I am using.
const double WGS84_a = 6378137.0;
const double WGS84_b = 6356752.3;
double Deg2rad(double degrees) {
return degrees * M_PI / 180.0;
}
double Rad2deg(double radians) {
return radians * 180.0 / M_PI;
}
double WGS84EarthRadius(double lat)
{
double An = WGS84_a*WGS84_a * cos(lat);
double Bn = WGS84_b*WGS84_b * sin(lat);
double Ad = WGS84_a * cos(lat);
double Bd = WGS84_b * sin(lat);
return sqrt( (An*An + Bn*Bn)/(Ad*Ad + Bd*Bd) );
}
MapRect LatLonDestPoint(CLLocationCoordinate2D origin, double halfSideInKm) {
double lat = Deg2rad(origin.latitude);
double lon = Deg2rad(origin.longitude);
double halfSide = 1000*halfSideInKm;
double radius = WGS84EarthRadius(lat);
double pradius = radius*cos(lat);
double latMin = lat - halfSide/radius;
double latMax = lat + halfSide/radius;
double lonMin = lon - halfSide/pradius;
double lonMax = lon + halfSide/pradius;
return MKMapRectMake(Rad2deg(latMin), Rad2deg(lonMin), Rad2deg(latMax), Rad2deg(lonMax));
}
Now for a coordinate (60.1190935704,-149.439081366) I get the API like
http://www.panoramio.com/map/get_panoramas.php?set=public&from=0&to=20&minx=60.029034&miny=-149.619843&maxx=60.209152&maxy=-149.258316&size=medium&mapfilter=true
This always returns me zero results. Please help me with what I am doing wrong.
You have x and y coordinates the wrong way around.
Swapping these returns:-
{"count":379,"has_more":true,"map_location":{"lat":60.118290103595498,"lon":-149.45469385385852,"panoramio_zoom":6}
etc
ps Do not rely on the count being correct. Use the has_more flag.

Adding random MKAnnotations around Current Location in a MKMapView

I have an MKMapView that shows the current users location. When I click a button in the navigation bar, I want to randomly drop 10 MKAnnotation pins. These can be dropped anywhere, randomly, but only within the current visible map area and around the current location.
How would go about doing something like this? Is there a way to have a long/lat range that is around the users location, but within the map area? Then, I could randomly choose from this range?
Basically, I need to find what coordinates are available in the current MKCoordinateRegion.
Is there a better way to go about this?
You can get your annotations using the distance between user location and other location
check out below code
#define DISTANCE_RADIUS 10.0 // in KM
-(NSArray *)findNearMe:(NSArray *)lounges {
NSMutableArray *arNearme = [NSMutableArray array];
CLLocation *currentLocation;
for(NSDictionary *d in lounges)
{
currentLocation = [[CLLocation alloc] initWithLatitude:29.33891 longitude:48.077202];
CGFloat latitude=[[d valueForKey:#"latitude"] floatValue];
CGFloat longitude=[[d valueForKey:#"longitude"] floatValue];
CLLocation *newPinLocation=[[CLLocation alloc] initWithLatitude:latitude longitude:longitude];
double distanceValue=[currentLocation distanceFromLocation:newPinLocation];
if(distanceValue/1000.0<=DISTANCE_RADIUS) {
[arNearme addObject:d];
}
}
return arNearme;
}
It will returns you an array of range of 1 to 1000 km near user location.
Used the annotations array and show your annotations in to map view with user location.
I figured it out, here is how I did it:
/**
* Adds new pins to the map
*
* #version $Revision: 0.1
*/
+ (void)addPinsToMap:(MKMapView *)mapView amount:(int)howMany {
//First we need to calculate the corners of the map so we get the points
CGPoint nePoint = CGPointMake(mapView.bounds.origin.x + mapView.bounds.size.width, mapView.bounds.origin.y);
CGPoint swPoint = CGPointMake((mapView.bounds.origin.x), (mapView.bounds.origin.y + mapView.bounds.size.height));
//Then transform those point into lat,lng values
CLLocationCoordinate2D neCoord = [mapView convertPoint:nePoint toCoordinateFromView:mapView];
CLLocationCoordinate2D swCoord = [mapView convertPoint:swPoint toCoordinateFromView:mapView];
// Loop
for (int y = 0; y < howMany; y++) {
double latRange = [MapUtility randomFloatBetween:neCoord.latitude andBig:swCoord.latitude];
double longRange = [MapUtility randomFloatBetween:neCoord.longitude andBig:swCoord.longitude];
// Add new waypoint to map
CLLocationCoordinate2D location = CLLocationCoordinate2DMake(latRange, longRange);
MPin *pin = [[MPin alloc] init];
pin.coordinate = location;
[mapView addAnnotation:pin];
}//end
}//end
/**
* Random numbers
*
* #version $Revision: 0.1
*/
+ (double)randomFloatBetween:(double)smallNumber andBig:(double)bigNumber {
double diff = bigNumber - smallNumber;
return (((double) (arc4random() % ((unsigned)RAND_MAX + 1)) / RAND_MAX) * diff) + smallNumber;
}//end
In Swift 3.0
func addPins() {
let nePoint = CGPoint(x: mapView.bounds.origin.x + mapView.bounds.size.width, y: mapView.bounds.origin.y)
let sePoint = CGPoint(x: mapView.bounds.origin.x, y: mapView.bounds.origin.y + mapView.bounds.size.height)
let neCoord = mapView.convert(nePoint, toCoordinateFrom: mapView)
let seCoord = mapView.convert(sePoint, toCoordinateFrom: mapView)
var y = 5
while y > 0 {
let latRange = randomBetweenNumbers(firstNum: Float(neCoord.latitude), secondNum: Float(seCoord.latitude))
let longRange = randomBetweenNumbers(firstNum: Float(neCoord.longitude), secondNum: Float(seCoord.longitude))
let location = CLLocationCoordinate2D(latitude: CLLocationDegrees(latRange), longitude: CLLocationDegrees(longRange))
let pin = MKPointAnnotation()
pin.coordinate = location
pin.title = "Home"
mapView.addAnnotation(pin)
y -= 1
}
}
func randomBetweenNumbers(firstNum: Float, secondNum: Float) -> Float{
return Float(arc4random()) / Float(UINT32_MAX) * abs(firstNum - secondNum) + min(firstNum, secondNum)
}
swift 4:
// returned coordinates all restricted to the provided bound
// nwCoordinate: north West coordinate of the target bound
// seCoordinate: south east coordinate of the target bound
func createRandomLocation(nwCoordinate: CLLocationCoordinate2D, seCoordinate: CLLocationCoordinate2D) -> [CLLocationCoordinate2D]
{
return (0 ... 30).enumerated().map { _ in
let latitude = randomFloatBetween(nwCoordinate.latitude, andBig: seCoordinate.latitude)
let longitude = randomFloatBetween(nwCoordinate.longitude, andBig: seCoordinate.longitude)
return CLLocationCoordinate2D(latitude: latitude, longitude: longitude)
}
}
private func randomFloatBetween(_ smallNumber: Double, andBig bigNumber: Double) -> Double {
let diff: Double = bigNumber - smallNumber
return ((Double(arc4random() % (UInt32(RAND_MAX) + 1)) / Double(RAND_MAX)) * diff) + smallNumber
}

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