NSMutableArray adding into a cycle - ios

Question

I have this...
allTableData = [[NSMutableArray alloc] initWithObjects:
[[Food alloc] initWithName:#"1" andDescription:#"Hi man!"],
[[Food alloc] initWithName:#"2" andDescription:#"Hi woman"],
nil ];
How can I do something like that?
NSArray *array = [NSArray arrayWithObjects:#"Hi man",#"Hi woman",nil];
allTableData = [[NSMutableArray alloc] initWithObjects
for(i=0; i<2; i++)
{
NSString *aString = [NSString stringWithFormat:#"%d", i];
[[Food alloc] initWithName:aString andDescription:#"array[i]"];
}
...as well as enter through a cycle?

Answer 1

[[Food alloc] initWithName:aString andDescription:#"array[i]"];
should be
[[Food alloc] initWithName:aString andDescription:array[i]];
In the first case you were adding the string "array[i]", where instead you want to access the i-th element of the array.
Also, there's a shorter way for converting an int to NSString
[NSString stringWithFormat:#"%d", i];
can be replaced by
#(i).stringValue
The # syntax for numbers is a feature introduced by llvm 3.3, that allows you to create NSNumbers literals. NSNumber has then the method stringValue that you can use to get the desired NSString.

Answer 2

Try this
NSArray *array = [NSArray arrayWithObjects:#"Hi man",#"Hi woman",nil];
allTableData = [NSMutableArray array];
for(i=0; i<[array count]; i++){
NSString *aString = [#(i) stringValue];
Food *food = [[Food alloc] initWithName:aString andDescription:array[i]];
[allTableData addObject:food];
}

Answer 3

NSArray *array = [NSArray arrayWithObjects:#"Hi man",#"Hi woman",nil];
NSMutableArray* tableData = [NSMutableArray arrayWithCapacity:array.count];
[array enumerateObjectsUsingBlock:^(id obj,NSUInteger index,BOOL* stop){
[tableData addObject:[[Food alloc] initWithName:[#(index) stringValue] andDescription:obj]];
}];