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Closed 9 years ago.
I want to know what will be the result of the following code
NSString *str = #"0";
NSString *str1 = #"12";
NSLog(#"str int value %d, %d",str, str1);
Result I got is 18036, 18052
I used a wrong format specifier in my code and came across this weird result. I fixed it later through. But I wanted to know what exactly it print out.
Thanks
NSLog(#"str int value %d, %d",str, str1);
You're passing pointers to strings as the parameters, but the format string specifies integers. A good guess is that the pointers will be interpreted as integers, so the output will depend on where in memory the strings happen to be allocated.
I guess it printed out the string pointer address
Related
It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.
Closed 9 years ago.
I want to convert a string representing an exponential number to a long value. Anyone having any ideas how can I do this conversion in Objective-C?
My exponential number is "9.91350253E8"
NSString *str = #"9.91350253E8";
NSDictionary *l = [NSDictionary dictionaryWithObject:#"." forKey:NSLocaleDecimalSeparator];
NSDecimalNumber *number = [NSDecimalNumber decimalNumberWithString:str locale:l];
NSLog(#"%lld", [number longLongValue]);
Try this.
You can use like this -
NSString *str=#"9.91350253E8";
long temp = str.longLongValue ;
NSLog(#"long-%ld",temp);
It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.
Closed 9 years ago.
I have two strings that are taken as input from a textfield in my application. I know that they are both 4 characters in length.
Is there some way I can "halve" those strings, and create two strings per original string that have two characters each?
Sure. NSString has the very useful methods "substringToIndex:" and "substringFromIndex:". The magic number (index) here appears to be 2.
A simple approach would be to use the NSString substringWithRange: method to obtain each of the pairs of characters you require.
For example:
NSString *sourceString = #"ABCD";
assert([sourceString length] == 4); // Handle error conditions here.
NSString *firstSection = [sourceString substringWithRange:NSMakeRange(0,2)];
NSString *secondSection = [sourceString substringWithRange:NSMakeRange(2,2)];
See the NSString class reference for more information.
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Closed 9 years ago.
For instance 1 is made of 2 dashes, 8 is made of 7 dashes and so on.write a function that takes this string message as an input and returns a corresponding value in terms of a number. This number is the count of dashes in the string message.
String has a count method:
"abc--de-f-".count('-') #=> 4
Just get a string with nothing but the dashes from your input string, and then check the length of that string:
dash_string = input_string.gsub(/[^-]/, '')
number = dash_string.length
You might want to subtract 1 from that answer based on your examples, bearing in mind that a string with no dashes would turn into -1 in that case.
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Closed 10 years ago.
Corona/Lua how to sort a table of strings from shortest to longest
Assuming your table is a indexed table and not a keyed one try
test = {'123','1234','1245','1','12'}
table.sort(test, function(a,b) return #a<#b end)
for i,v in ipairs(test) do
print (i,v)
end
The important line here is
table.sort(test, function(a,b) return #a<#b end)
Words will only sorted by length and order within matching lengths will be arbitrary. If you want to sort by additional criteria, extend the function for the sort
eg function(a,b) return #a<#b end
It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.
Closed 10 years ago.
I am trying to read values from a .txt file and keep getting the above error. My code reads:
file <- readFile "films.txt"
let database = (read file :: [Film])
and Film is a data type I declared as:
type Film = (String, String, Int)
Still quite new to Haskell so have no idea how to parse a string back into the required type. Sort of assumed it would be nice and do it for me like it does with writeFile!
Any hints?