I'm converting an NSString to an int for a project, in order to compare time stamps. This is the response I get from my NSLog when i convert it.
Server Time Stamp = 1363032033711 AND Server Time Stamp CONVERTED: 2147483647
I'm using this code to convert it:
NSString *msg = [NSString stringWithFormat:#"%#", message];
NSArray *subString = [msg componentsSeparatedByString:#" "];
NSString *timeStamp = [subString lastObject];
int serverTimeStamp = [timeStamp intValue];
NSLog(#"Server Time Stamp = %# AND Server Time Stamp CONVERTED: %d", timeStamp, serverTimeStamp);
I'm not sure why the converted number is so weird, is it a problem with my code, or with converting strings to ints?
1363032033711 is too big. It cannot be converted to an int (which appears to be 32 bits long on iOS). If you do a Google search for 2147483647, you find out that it's the maximal value of a 32-bit signed int. Perhaps that's how - [NSString intValue] indicates if it found a number that's too large to convert.
Solution: use a wider number type and NSScanner:
NSScanner *scn = [NSScanner scannerWithString:[subString lastObject]];
long long serverTimeStamp;
[scn scanLongLong:&serverTimeStamp];
Related
I have float like 3500,435232123. All I want to know if exists (in Objective C) a function that let me keep just the last 4 digits in my case is 2123.
You can use NSNumberFormatter
NSNumberFormatter *format = [[NSNumberFormatter alloc]init];
[format setNumberStyle:NSNumberFormatterDecimalStyle];
[format setRoundingMode:NSNumberFormatterRoundHalfUp];
[format setMaximumFractionDigits:4];
[format setMinimumFractionDigits:4];
string = [NSString stringWithFormat:#"%#",[format stringFromNumber:[NSNumber numberWithFloat:65.50055]] ;
Or simply
NSString *string = [NSString stringWithFormat:#"%.04f", floatValue];
If you want only last four digits, convert the float to a string
NSString *string = [NSString stringWithFormat:#"%f", floatValue];
and get the last four characters
NSString *lastFour = [string substringFromIndex: [string length] - 4];
It you want to get the decimal part, you can do x - floor(x). For instance:
float x = 3500,435232123;
NSString *string = [NSString stringWithFormat:#"%.04f", x - floor(x)];
And to get 4 decimal digits do what Fawad Masud says.
No there is no such function, as far as i know. But here is a way to achieve exactly what you want.
First you have to round it to four digits after point:
NSString *exampleString = [NSString stringWithFormat:#"%.04f", valueToRound];
Then you get the location for the comma inside the exampleString:
NSRange commaRange = [valueString rangeOfString:#","];
Finally you create the finalString with the values from that NSRange. The substring starts at commaRange.location+commaRange.lengthbecause thats the index directly after the comma.
NSString *finalString = [valueString substringWithRange:NSMakeRange(commaRange.location+commaRange.length,valueString.length-commaRange.location-commaRange.length)];
Hope that helps you.
I think is no predefined function for that.
and the solution i thought of is:
float floatNum = 3500.435232123;
converting float number to string and trim/substring the string, like for example:
NSString *stringFloat = [NSString stringWithFormat:#"%f", floatNum];
NSString *newString = [stringFloat substringWithRange:NSMakeRange(stringFloat.length - 4, stringFloat.length)];
NSLog(#"%#", newString);
another is something like:
NSString *stringFloat = [NSString stringWithFormat:#"%f", floatNum];
//separates the floating number to
arr[0] = whole number
arr[1] = decimals
NSArray *arr=[str componentsSeparatedByString:#"."];
since you just want to work on the decimal, i think arr[1] is what you need..
NSString *stringDecimals = (NSString *)arr[1];
if ( stringDecimals.length > 4) //check the length of the decimals then cut if exceeds 4 character..
{
stringDecimals = [stringDecimals substringWithRange:NSMakeRange(stringDecimals.length - 4, stringDecimals.length)];
}
NSLog(#"stringDecimals: %#", stringDecimals);
I have an NSString *fileName
This will contain a variable number from 1 to 3 digits. I want to extract all of the digits
I can get the first digit using
//create text for appliance identifier
char obsNumber = [fileName characterAtIndex:3];//get 4 character
NSLog(#"Obs number %c",obsNumber);
//Text label
[cell.titleLabel setText:[NSString stringWithFormat:#"Item No: %c",obsNumber]];
NSLog(#"Label for observation = %#",cell.titleLabel.text);
However if the string contains the number for example 78, or 204 I want to catch all two or three digits.
I tried this
//create text for appliance identifier
char obsNumber1 = [fileName characterAtIndex:3];//get 4 character
char obsNumber2 = [fileName characterAtIndex:4];//get 5 character
char obsNumber3 = [fileName characterAtIndex:5];//get 6 character
NSLog(#"Obs number %c,%c,%c",obsNumber1,obsNumber2,obsNumber3);
//Text label
[cell.titleLabel setText:[NSString stringWithFormat:#"Item No: %c,%c,%c",obsNumber1,obsNumber2,obsNumber3]];
NSLog(#"Label for observation = %#",cell.titleLabel.text);
This gave me 18c 1ce etc
Would this work for you?
NSString *filename = #"obs127observation"; //An example variable with your format
This code could be tidier but you should get the idea:
NSString *filenameNumber = [[filename
stringByReplacingOccurrencesOfString:#"observation"
withString:#""]
stringByReplacingOccurrencesOfString:#"obs"
withString:#""];
you can trim other letters except the decimals.
NSString *onlyNumbers=[yourstring stringByTrimmingCharactersInSet:[[NSCharacterSet decimalDigitCharacterSet] invertedSet]];
As your comment says , It has predefined set of values, right. Then try like this
NSstring *str = [filename substringFromIndex:11];
// Convert the str to char[]
Then you should try with the NSScanner :
NSString *numberString;
NSScanner *scanner = [NSScanner scannerWithString:filename];
NSCharacterSet *numbers = [NSCharacterSet characterSetWithCharactersInString:#"0123456789"];
// Throw away characters before the first number.
[scanner scanUpToCharactersFromSet:numbers intoString:NULL];
// Collect numbers.
[scanner scanCharactersFromSet:numbers intoString:&numberString];
// Result.
int number = [numberString integerValue];
// you can play around with the set of number
Your approach of separating one character at a time and then combining them back into a string is an awkward, overly complex way of going about this. Kumar's suggestion of using NSScanner is a good option if you have a number in the middle of a string.
However, you make it sound like your string will always contain a number and only a number. Is that true? Or will there be characters you need to ignore?
You need to define the problem clearly and completely before you can select the best solution.
It might be as simple as using the NSString method substringWithRange.
I'm parsing data from a JSON webservice and adding it to the database so when I insert an int, I have to convert it to NSNumber in this way it's working fine: 24521478
NSString *telephone = [NSString stringWithFormat:#"%#",[user objectForKey:#"telephone"]];
int telephoneInt = [telephone intValue];
NSNumber *telephoneNumber = [NSNumber numberWithInt:telephoneInt];
patient.telephone = telephoneNumber;
but when I want to display it and convert the NSNumber to NSString I'm getting wrong numbers: -30197
NSString *telephoneString = [NSString stringWithFormat:#"%d", [user.telephone intValue], nil];
labelTelephone.text =telephoneString ;
Can someone explain this?
NSNumber comes with dedicated methods for each data type.If you want to convert NSNumber to NSString use:
NSString *telephoneString = [user.telephone stringValue];
The issue may coming because of the data type you used for the variable patient.telephone
If you have control over the web service, then you should return the telephone number as string in the JSON
Reasons
if the telephone number begin with zero then the NSNumber will remove that zero as it has no value (ex: 00123456789 will be 123456789 which will wrong data)
You will not be able to display the telephone number is a user friendly way by adding "+" and "-" (ex: +123-456-789)
You really should make the json return the number as string if you have a control over that
In my project, I have a function that runs and spits out a 5 digit number into a label on my interface. The number can be a double or a float but I would like it to display like ###+##.##
Example Number 12345.67
Shown like 123+45.67
The output will always be a 5 digit number with decimals. I researched data formatting specifically number formatting but haven't come across anything specific for this case. This is where I change the number to a string and assign it to a label. Please help and thank you in advance for your time.
NSString *outputNumber = [NSString stringWithFormat:#"%f",numberHere];
_stationing.text = outputNumber;
There are a couple of ways this could be done.
NSMutableString *outputNumber = [[NSString stringWithFormat:#"%.2f", numberHere] mutableCopy];
[outputNumber insertString:#"+" atIndex:outputNumber.length - 5];
_stationing.text = outputNumber;
Another:
int high = numberHere / 100;
float low = numberHere - (high * 100);
NSString *outputNumber = [NSString stringWithFormat:#"%d+%.2f", high, low];
These approaches won't work well if the number is less than 100.
Hope this help
NSStirng *numberString = [NSString stringWithFormat:#"%.2f",numberHere];
NSString *firstPart = [numberString substringWithRange:NSMakeRange(0, 3)];
NSString *secondPart [numberString substringWithRange:NSMakeRange(3, 5)];
NSString *outputString = [NSString stringWithFormat:#"%#+%#", firstPart, secondPart];
If the number's format is not permanent, you should check the length first.
I'm getting a JSON string back from a web service I'm using, one of the items is a float, which is formatted like this: "1.2".
But I actually want to make it show like a time number, so like this: "01:20".
What would be the easiest way of doing this?
I thought about converting the float to a string and then splitting it into 2 pieces
timeValue = [NSString stringWithFormat:#"%.2f", timeValue];
NSArray *tmpArr = [timeValue componentsSeparatedByString:#"."];
NSString *tmpFirst = (NSString *)[tmpArr objectAtIndex:0];
NSString *tmpSecond = (NSString *)[tmpArr objectAtIndex:0];
But somehow when I convert it, it returns me a negative number
NSLog(#"timeValue: %#", timeValue);
timeValue: -1.99
I think the problem is in this line.
timeValue = [NSString stringWithFormat:#"%.2f", timeValue];
I think timeValue is of type NSString if not then why are you using same variable twice.
It should be like
timeValueString = [NSString stringWithFormat:#"%.2f", timeValueFloat];