This seems like it should be simple.
I have a CSV file with multiple currency values (so I'd like to avoid writing a bunch of string-manipulation steps if it can be avoided), and I was excited to see that the CSV File Input step has fields like Currency Separator, decimal symbol, grouping symbol (and mine are the default "$", ".", and ",", respectively).
The documentation describes these as for:
Currency Used to interpret numbers like $10,000.00 or E5.000,00
Decimal A decimal point can be a "." (10;000.00) or "," (5.000,00)
Grouping A grouping can be a dot "," (10;000.00) or "." (5.000,00)
(http://wiki.pentaho.com/display/EAI/Text+File+Input)
But as of the current production version (4.4)... these settings do not seem to have an effect.
Has anyone had success with number masks or similar such that a string like "$10,000,238.48" can yield a number that can be pushed into a database? Anything I do is either "Unparsable" in the text input or "truncated field" error at the insert...
When I do a get fields on a text input step with your example number in it, it sets Currency, Decimal, and Group to '$', '.', ',' respectively, and it reads your number just fine. It also sets a Format string of '$#,##0.00;($#,##0.00)', which it seems is the key piece. The text file input step will examine as many rows as you specify from a CSV and guess the formats for each column.
Here is PDI's number formatting table:
Number Formatting Table
If you have different currency formats mixed in the same column, I would use a UDJE step and this answer:
Parsing a Currency string in Java
Or a JavaScript Step and this answer:
Convert Currency string with JavaScript
to strip out all non digit and non decimal point characters, then pass it through a Select Values step. Note, that this will be very tricky if you have mixed decimal separators in the input column.
Related
The title says it all. One thing I want to avoid is long formulas. If it's more than a single function, something is clearly wrong since this should be a common use case.
I've tried TO_PURE_NUMBER and VALUE
Your question suggests that the value $71.4145 is not a number but a text string. That can happen if your spreadsheet locale is such that it expects comma as decimal mark, or expects a different currency symbol. It will also happen if you have formatted the value as plain text rather than currency.
To convert the text string $71.4145 into the number 71.4145 (seventy-one and change), use regexextract(), like this:
=iferror( value( regexextract( to_text(A2), "[\d.]+" ) ) )
Just use -- to suppress text to equivalent number values. Try-
=--A1
try:
=SUBSTITUTE(A1; "$"; )*1
I have a field where I need to extract the text between two characters.
I've found regexextract and I got it to work when there is one character but I can't for the life get it to work with multiple characters.
2020-02: Test Course (QAS)
I need to extract text after : and before (
So it would just return "Test Course"
TYIA
If it's for just one cell (say A2):
=IFERROR(TRIM(REGEXEXTRACT(A2,":([^\(]+)")))
This will return what you want regardless of spaces after the colon or before the opening parenthesis. If no match is found, null will be returned.
If it's to process an entire range (say, A2:A), place the following in, say, B2 of an otherwise empty Col B:
=ArrayFormula(IF(A2:A="",,IFERROR(TRIM(REGEXEXTRACT(A2:A,":([^\(]+)")),A2:A)))
This will return what you want regardless of spaces after the colon or before the opening parenthesis. If no match is found, the original string will be returned.
In both cases, the REGEX string...
:([^\(]+)
... means "a grouping of any number of characters that aren't an opening parenthesis and which follows a colon."
One way to do that would be with the INDEX() and SPLIT() functions like this:
=TRIM(INDEX(SPLIT(A2,":("),2)
Split splits the text into 3 parts using the : and (, then INDEX chooses the second part.
The TRIM() just gets rid of the spaces.
Ideally what I'm looking for is to get the dollar amount extracted no matter the format.
Sheet link:
https://docs.google.com/spreadsheets/d/1drTPlnQmVTsbUXwJDfQr7DnHjSbnGx-fLthad6KxfM8/edit?usp=sharing
Delete everything from Column B, including the header. Then place the following formula in cell B1:
=ArrayFormula({"Header"; IF(A2:A="",,VALUE(IFERROR(REGEXEXTRACT(A2:A,"\$(\d+\.?\d*)"))))})
You may change the header text within the formula as you like.
If a cell in A2:A is blank, the corresponding cell in B2:B will be left blank as well.
Otherwise REGEXEXTRACT will look for a pattern that begins with a literal dollar sign. The parenthesis within the quotes denote the beginning and end of a capture group (i.e., what will be returned if found) following that literal dollar sign. The pattern \d+\.?\d* means "a group of one or more digits, followed by zero or one literal period symbols, followed by zero or more digits."
IFERROR will cause null to be rendered instead of an error if such a pattern is not able to be extracted.
VALUE will convert the extracted string (or null) to a real number.
If you would prefer that null be returned instead of 0 where no pattern match is found, you can use the following variation of the formula instead:
=ArrayFormula({"Header"; IFERROR(VALUE(IFERROR(REGEXEXTRACT(A2:A,"\$(\d+\.?\d*)"),"x")))})
If your strings may include numbers with comma separators, use the following versions of the above two formulas, respectively:
=ArrayFormula({"Header V1"; IF(A2:A="",,VALUE(IFERROR(REGEXEXTRACT(SUBSTITUTE(A2:A,",",""),"\$(\d+\.?\d*)"))))})
=ArrayFormula({"Header V2"; IFERROR(VALUE(IFERROR(REGEXEXTRACT(SUBSTITUTE(A2:A,",",""),"\$(\d+\.?\d*)"),"x")))})
try:
=INDEX(IFNA(REGEXEXTRACT(A2:A, "\$(\d+.\d+|\d+)")*1))
I am using the following formula to extract the substring venue01 from column C, the problem is that when value string in column C is shorter it only extracts the value 1 I need it to extract anything straight after the - (dash) no matter the length of the value text in column c
={"VenueID";ARRAYFORMULA(IF(ISBLANK(A2:A),"",RIGHT(C2:C,SEARCH("-",C2:C)-21)))}
There is a much simpler solution using regular expressions.
=REGEXEXTRACT(A1,".*-(.*)")
In case you are no familiar with Regular Expressions what this means is, get me every string of characters ((.*)) after a dash (-).
Example
Reference
REGEXTRACT
Test regular expressions
Cheat sheet for regular expressions
To answer bomberjackets question in the comment of Raserhin:
To select the part of the string before the "-"
=REGEXEXTRACT(A1,"(.*)-.*")
EXAMPLE
example of code
Adding to your original formula. I think if you'd use RIGHT and inside it reverse the order of the string with ARRAY then that may work.
=Right(A1,FIND("-",JOIN("",ARRAYFORMULA(MID(A1,LEN(A1)-ROW(INDIRECT("1:"&LEN(A1)))+1,1))))-1)
It takes string from the right side up to X number of characters.
Number of character is fetched from reversing the text, then finding
the dash "-".
It adds one more +1 of the text as it will take out so it accounts
for the dash itself, if no +1 is added, it will show the dash on
the extracted string.
The REGEX on the other answer works great too, however, you can control a number of character to over or under trim. E.g. if there is a space after the dash and you would like to always account for one more char.
I have a column in open office like this:
abc-23
abc-32
abc-1
Now, I need to get only the sum of the numbers 23, 32 and 1 using a formula and regular expressions in calc.
How do I do that?
I tried
=SUMIF(F7:F16,"([:digit:].)$")
But somehow this does not work.
Starting with LibreOffice 6.4, you can use the newly added REGEX function to generically extract all numbers from a cell / text using a regular expression:
=REGEX(A1;"[^[:digit:]]";"";"g")
Replace A1 with the cell-reference you want to extract numbers from.
Explanation of REGEX function arguments:
Arguments are separated by a semicolon ;
A1: Value to extract numbers from. Can be a cell-reference (like A1) or a quoted text value (like "123abc"). The following regular expression will be applied to this cell / text.
"[^[:digit:]]": Match every character which is not a decimal digit. See also list of regular expressions in LibreOffice
The outer square brackets [] encapsulate the list of characters to search for
^ adds a NOT, meaning that every character not included in the search list is matched
[:digit:] represents any decimal digit
"": replace matching characters (every non-digit) with nothing = remove them
"g": replace all matches (don't stop after the first non-digit character)
Unfortunately Libre-Office only supports regex in find/replace and in search.
If this is a once-only deal, I would copy column A to column to B, then use [data] [text to columns] in B and use the - as a separator, leaving you with all the text in column B and the numbers in column C.
Alternatively, you could use =Right(A1,find("-",A1,1)+1) in column B, then sum Column C.
I think that this is not exactly what do you want, but maybe it can help you or others.
It is all about substring (in Calc called [MID][1] function):
First: Choose your cell (for example with "abc-23" content).
Secondly: Enter the start length ("british" --> start length 4 = tish).
After that: To print all remaining text, you can use the [LEN][2] function (known as length) with your cell ("abc-23") in parameter.
Code now looks like this:
D15="abc-23"
=MID(D15; 5; LEN(D15))
And the output is: 23
When you edit numbers (in this example 23), no problem. However, if you change anything before (text "abc-"), the algorithm collapses because the start length is defined to "5".
Paste the string in a cell, open search and replace dialog (ctrl + f) extended search option mark regular expression search for ([\s,0-9])([^0-9\s])+ and replace it with $1
adjust regex to your needs
I didn't figure out how to do this in OpenOffice/LibreOffice directly. After frustrations in searching online and trying various formulas, I realised my sheet was a simple CSV format, so I opened it up in vim and used vim's built-in sed-like feature to find/replace the text in vim command mode:
:%s/abc-//g
This only worked for me because there were no other columns with this matching text. If there are other columns with the same text, then the solution would be a bit more complex.
If your sheet is not a CSV, you could copy the column out to a text file and use vim to find/replace, and then paste the data back into the spreadsheet. For me, this was a lot less frustrating than trying to figure this out in LibreOffice...
I won't bother with a solution without knowing if there really is interest, but, you could write a macro to do this. Extract all the numbers and then implement the sum by checking for contained numbers in the text.