I have a UILabel that shows the outside temperature, the problem is, sometimes it shows it as a XX.XXº format instead of the normal XXº or XXXº format used to show temperature, is there anyway to force the label to only show the temperature without the decimals or at least force it to only be able to use 2 characters?
You can use this to eliminate the decimals:
NSString* numberString = [NSString stringWithFormat:#"%.0f", d]; // 0 means no decimals
Otherwise I believe this will work to limit the number of chars to 2:
NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
formatter.usesSignificantDigits = YES;
formatter.maximumSignificantDigits = 2;
I have not really used NSNumberFormatter very much though.
NSString *temp = [galleryEntryTree objectForKey:#"description"];
if ([temp length] > 500) {
NSRange range = [temp rangeOfComposedCharacterSequencesForRange:(NSRange){0, 500}];
temp = [temp substringWithRange:range];
temp = [temp stringByAppendingString:#" …"];
}
coverView.label2.text = temp;
You may also use substring method
NSString *newformat = [NSString stringWithFormat:#"%#",[temperature substringWithRange:NSMakeRange(0,2)]];
In this case temperature is a string that you set for your label and you are only retrieving the 1st 2 digits only
Related
I have float like 3500,435232123. All I want to know if exists (in Objective C) a function that let me keep just the last 4 digits in my case is 2123.
You can use NSNumberFormatter
NSNumberFormatter *format = [[NSNumberFormatter alloc]init];
[format setNumberStyle:NSNumberFormatterDecimalStyle];
[format setRoundingMode:NSNumberFormatterRoundHalfUp];
[format setMaximumFractionDigits:4];
[format setMinimumFractionDigits:4];
string = [NSString stringWithFormat:#"%#",[format stringFromNumber:[NSNumber numberWithFloat:65.50055]] ;
Or simply
NSString *string = [NSString stringWithFormat:#"%.04f", floatValue];
If you want only last four digits, convert the float to a string
NSString *string = [NSString stringWithFormat:#"%f", floatValue];
and get the last four characters
NSString *lastFour = [string substringFromIndex: [string length] - 4];
It you want to get the decimal part, you can do x - floor(x). For instance:
float x = 3500,435232123;
NSString *string = [NSString stringWithFormat:#"%.04f", x - floor(x)];
And to get 4 decimal digits do what Fawad Masud says.
No there is no such function, as far as i know. But here is a way to achieve exactly what you want.
First you have to round it to four digits after point:
NSString *exampleString = [NSString stringWithFormat:#"%.04f", valueToRound];
Then you get the location for the comma inside the exampleString:
NSRange commaRange = [valueString rangeOfString:#","];
Finally you create the finalString with the values from that NSRange. The substring starts at commaRange.location+commaRange.lengthbecause thats the index directly after the comma.
NSString *finalString = [valueString substringWithRange:NSMakeRange(commaRange.location+commaRange.length,valueString.length-commaRange.location-commaRange.length)];
Hope that helps you.
I think is no predefined function for that.
and the solution i thought of is:
float floatNum = 3500.435232123;
converting float number to string and trim/substring the string, like for example:
NSString *stringFloat = [NSString stringWithFormat:#"%f", floatNum];
NSString *newString = [stringFloat substringWithRange:NSMakeRange(stringFloat.length - 4, stringFloat.length)];
NSLog(#"%#", newString);
another is something like:
NSString *stringFloat = [NSString stringWithFormat:#"%f", floatNum];
//separates the floating number to
arr[0] = whole number
arr[1] = decimals
NSArray *arr=[str componentsSeparatedByString:#"."];
since you just want to work on the decimal, i think arr[1] is what you need..
NSString *stringDecimals = (NSString *)arr[1];
if ( stringDecimals.length > 4) //check the length of the decimals then cut if exceeds 4 character..
{
stringDecimals = [stringDecimals substringWithRange:NSMakeRange(stringDecimals.length - 4, stringDecimals.length)];
}
NSLog(#"stringDecimals: %#", stringDecimals);
I want the concatenated NSString I have to be output in the format "00:00", the 0s being the digits in the concatenated string. And if there are not enough characters in the NSString, the other digits are made to be 0.
And if there are more than 4 digits than I want to only have the furthest right digits.
I have done this in Java before, I am assuming it's possible in Objective-C as well.
UIButton *button = sender;
NSString *concatenated = [self.input stringByAppendingString: button.titleLabel.text];
self.input = concatenated;
self.userOutput.text = self.input;
For example, I might get "89" as my concatenated string. I then want, self.input = 00:89.
OR
if I get 89374374 from my concatenated string, I then want self.input = 43:74.
I hope I am being clear
The following method should give the desired output:
- (NSString *)getFormattedTimeStringFromString:(NSString *)string
{
int input = [string intValue];
int mins = input % 100;
input /= 100;
int hours = input % 100;
return [NSString stringWithFormat:#"%02d:%02d", hours, mins];
}
You can use this by calling
self.input = [self getFormattedTimeStringFromString:concatenated];
Like this:
NSDateFormatter * df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"HH:mm"];
NSString *dateTimeStr = [df stringFromDate:[NSDate date]];
if ([concatenated length] == 2) {
self.input = [NSString stringWithFormat:#"00:%#",concatenated];
}
else
{
NSString *test = [concatenated substringFromIndex:[concatenated length] -4];
self.input = [NSString stringWithFormat:#"%#:%#",[test substringToIndex:2],[test substringFromIndex:[test length]-2]];
}
Please try above code it will fail if [concatenated length] is 3 or 1 , modify it accordingly
This question already has answers here:
How do I convert an integer to the corresponding words in objective-c?
(7 answers)
Closed 8 years ago.
I am not sure how to explain this but I need something like this and I'm not quite sure how to do it. I have a textfield where the user enters a number. For example "200". I got a label that must show "Two Hundred"(The number entered in Words )
Any ideas on how to do this?
Thanks in advance sorry for my bad english
try this:
//textField.text is 200
NSInteger someInt = [textField.text integerValue];
NSString *numberWord;
NSNumber *numberValue = [NSNumber numberWithInt:someInt];
NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc] init];
[numberFormatter setNumberStyle:NSNumberFormatterSpellOutStyle];
numberWord = [numberFormatter stringFromNumber:numberValue];
NSLog(#"numberWord= %#", numberWord); // Answer: two hundred
yourLabel.text = numberWord;
You can use a NSNumberFormatter It can convert an NSNumber into its word representation.
NSNumber* number = #100;
NSString* textNumber;
NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc] init];
[numberFormatter setNumberStyle:NSNumberFormatterSpellOutStyle];
textNumber = [numberFormatter stringFromNumber:number];
Here's something totally different. A bit more complex and weird, but you can fiddle around with it if you seek more manual control over the output. This is set up to serve a value up to 100,000 (to demonstrate a conditional set up).
Have fun:
int theInteger = 1,123;
int convert1000 = 0;
int convert100 = 0;
int convert10 = 0;
int convert1 = 0;
NSString * wordThousand = #"Thousand";
NSString * wordHundred = #"Hundred";
NSArray *wordsArraySingleDigit = [[NSArray alloc] initWithObjects:#"Zero",#"One",#"Two",#"Three",#"Four",#"Five",#"Six",#"Seven",#"Eight",#"Nine",nil];
NSArray *wordsArrayDoubleDigit = [[NSArray alloc] initWithObjects:#"Ten",#"Eleven",#"Twelve",...,#"Ninety Eight", #"Ninety Nine",nil];
convert1000 = (theInteger - (theInteger % 1000))/1000;
convert100 = ((theInteger - (convert1000 * 1000)) - ((theInteger - (convert1000 * 1000)) % 100))/100;
convert10 = ((theInteger - (convert1000 *1000)-(convert100 *100)) - ((theInteger -(convert1000 *1000) - (convert100 *100)) % 10))/10;
convert1 = (theInteger - (convert1000 *1000)-(convert100 *100) - (convert10 *10));
if (theInteger > = 10000 && < 100000){
NSString * convertedThousand = [wordsArrayDoubleDigit objectAtIndex : convert1000];
convertedThousand = [NSString stringWithFormat: #“%# %#“,convertedThousand,wordThousand];
NSLog (convertedThousand);
}
if (theInteger >= 1000 && <= 10000){
NSString * convertedThousand = [wordsArraySingleDigit objectAtIndex : convert1000];
convertedThousand = [NSString stringWithFormat: #“%# %#“,convertedThousand,wordThousand];
NSLog (convertedThousand);
}
NSString * convertedHundred = [wordsArraySingleDigit objectAtIndex : convert100];
convertedHundred = [NSString stringWithFormat: #“%# %#“, convertedHundred,wordHundred];
NSLog (convertedHundred);
NSString * convertedTen = [wordsArraySingleDigit objectAtIndex : convert10];
convertedTen = [NSString stringWithFormat: #“%#“, convertedTen];
NSLog (convertedTen);
NSString *convertedOne = [wordsArraySingleDigit objectAtIndex : convert1];
NSLog (convertedOne);
Hope this helps or gives you a starting point for an alternative approach.
I think you should account for every possibility and make a set of IF statements, for example, if the first digit of the number is 3, write "three", if the number has 4 digits, display "thousands"... of course you can organize your code to make the process easy.
Say I have an NSString, it represents a price that otherwise would be a double of course. I am trying to make it truncate the string at the hundredths place so it is something like 19.99 instead of 19.99412092414 for example. Is there a way, once detecting the decimal like so...
if ([price rangeOfString:#"."].location != NSNotFound)
{
// Decimal point exists, truncate string at the hundredths.
}
for me to cut off the string 2 characters after that ".", without separating it into an array then doing a max size truncate on the decimal before finally reassembling them?
Thank you very much in advance! :)
This is string manipulation, not math, so the resulting value won't be rounded:
NSRange range = [price rangeOfString:#"."];
if (range.location != NSNotFound) {
NSInteger index = MIN(range.location+2, price.length-1);
NSString *truncated = [price substringToIndex:index];
}
This is mostly string manipulation, tricking NSString into doing that math for us:
NSString *roundedPrice = [NSString stringWithFormat:#"%.02f", [price floatValue]];
Or you might consider keeping all numeric values as numbers, thinking of strings as just a way to present them to the user. For that, use NSNumberFormatter:
NSNumber *priceObject = // keep these sorts values as objects
NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc] init];
[numberFormatter setNumberStyle: NSNumberFormatterCurrencyStyle];
NSString *presentMeToUser = [numberFormatter stringFromNumber:priceObject];
// you could also keep price as a float, "boxing" it at the end with:
// [NSNumber numberWithFloat:price];
I am using following NSNumberFormatter to add commas and symbol in the currency value.
self.currencyFormatter = [NSNumberFormatter new];
self.currencyFormatter.numberStyle = NSNumberFormatterCurrencyStyle;
self.currencyFormatter.currencySymbol = #"£";
self.currencyFormatter.currencyCode = #"GBP";
self.currencyFormatter.roundingMode = NSNumberFormatterRoundHalfUp;
self.currencyFormatter.maximumFractionDigits = 0;
Usage:
self.principleAmountTextField.text = [self.currencyFormatter stringFromNumber:[NSNumber numberWithInteger:100000]];
This displays £100,000 as expected. Now if I insert two more digits (text becomes £100,00096) in textfield and try to convert string to Integer I get 0! Basically following line returns 0. I have no idea how to deal with this issue.
NSLog(#"%d", [[self.currencyFormatter numberFromString:#"£100,00096"] integerValue]);
FYI I have custom inputview to textfield which just allows numbers to enter into textfield. In Did Edit End even I format number and display with comma.
You need to remove the commas for this to work, you can still show them in your text field but you should strip them out before you pass the string to the formatter. Something like this:
NSString *userInput = #"£100,00096";
userInput = [userInput stringByReplacingOccurrencesOfString:#"," withString:#""];
NSLog(#"%ld", (long)[[currencyFormatter numberFromString:userInput] integerValue]);
100,00096 isn't correct...
Do you mean one of these?
[[self.currencyFormatter numberFromString:#"£10000096"] integerValue]
[[self.currencyFormatter numberFromString:#"£100,000.96"] integerValue]
[[self.currencyFormatter numberFromString:#"£100000.96"] integerValue]
[[self.currencyFormatter numberFromString:#"£10,000,096"] integerValue]
My final code for the reference. The number with currency symbol also an invalid! Following takes care of everything.
NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:[NSString stringWithFormat:#"%#%#", self.currencyFormatter.groupingSeparator, self.currencyFormatter.currencySymbol]];
self.amountTextField.text = [[self.amountTextField.text componentsSeparatedByCharactersInSet:doNotWant] componentsJoinedByString:#""];
self.amountTextField.text = [NSString stringWithFormat:#"£%#", self.amountTextField.text];
NSUInteger amount = [[self.currencyFormatter numberFromString:self.amountTextField.text] integerValue];
self.amountTextField.text = [self.currencyFormatter stringFromNumber:[NSNumber numberWithInteger:amount]]