I'ld like to overwrite the system() function. Is that possible?
Sure, you can overwrite nearly everything in Ruby (whether useful or not):
system "ls /" # returns "/etc /var...", normal behaviour
def system args
puts args
end
system "ls /" # returns "ls /"
If it doesn't matter to use system at all then you can use backticks. The backticks execute the command and return the output as a string.
You can then assign the value to a variable like so:
output = `ls`
p output
Related
I want to capture the total number of rubocop offenses to determine whether my codebase is getting better or worse. I have almost no experience with ruby scripting.
This is my script so far:
#!/usr/bin/env ruby
#script/code_coverage
var = `rubocop ../ -f fuubar -o ../coverage/rubocop_results.txt -f offenses`
puts var
So I ./rails-app/script/code_coverage and my terminal displays
...
--
6844 Total
When I var.inspect I get a long string. I want to either read the output of rubocop ../ -f ... line by line (preferred) or capture each line of output into an array.
I would like to be able to do something like this:
var.each |line| do
if line.contains('total')
...
total = ...
end
Is this possible? I guess this would be similar to writing the output to a file and and then reading the file in line by line.
If you want to keep it simple, you can simply split your var string.
var = `rubocop ../ -f fuubar -o ../coverage/rubocop_results.txt -f offenses`.split("\n")
Then you can iterate on var like you wanted to.
use open3 library of ruby. Open3 grants you access to stdin, stdout, stderr and a thread to wait the child process when running another program. You can specify various attributes, redirections, current directory, etc., of the program as Process.spawn.
http://blog.bigbinary.com/2012/10/18/backtick-system-exec-in-ruby.html
require 'open3'
# Run lynx on this file.
cmd = "lynx -crawl -dump /data/feed/#{file_name}.html > /data/feed/#{file_name}"
Open3.popen3(cmd) do |stdin, stdout, stderr, wait_thr|
cmdout = stdout.read
$logger.debug "stdout is:" + stdout.read
$logger.debug "stderr is:" + stderr.read
end
I write this code in my rails project.It's to execute a shell script ,But my shell script can catch #directdown only.
rails script
#cmd = "/downafile.sh #{#directdown} #{#file.id} #{#filename}"
`#{#cmd}`
shell script
echo $1 >> /tmp/ceshi.tmp
echo $2 >> /tmp/ceshi.tmp
echo $3 >> /tmp/ceshi.tmp
Thanks.
`` and system command works in similar manner.
But system method will return true on success.
Try with this:
#cmd = "/downafile.sh '#{#directdown}' '#{#file.id}' '#{#filename}'"
`#{#cmd}`
Try using puts #cmd to see the command generated and see whether the command is what you intended. If it is try executing it from the terminal to test whether your shell script works. I think the parameters #file.id and #filename value may be nil so on interpolation it will be replaced by "". puts their values also to check.
I don't know what is the meaning of `` in Ruby, but I think you can use the system function to invoke an external program. Something like,
#cmd = "/downafile.sh #{#directdown} #{#file.id} #{#filename}"
system(#cmd)
Hope it helps.
Here is my case:
I want to use a web browser to connect to a Rails application that runs this example code on the server side:
Dir.chdir path_typed_in_by_user
system "ls -la"
I want the output of "ls -la" to be displayed on the web browser.
Is this possible somehow?
This links may help you run command line command into ruby ...
http://zhangxh.net/programming/ruby/6-ways-to-run-shell-commands-in-ruby/
Calling shell commands from Ruby
http://blog.jayfields.com/2006/06/ruby-kernel-system-exec-and-x.html
%x[command].each do |f|
value = f
end
try in a controller:
Dir.chdir path_typed_in_by_user
#out = system `ls -la` # !! look here !! " change `
in a view:
I'm trying to set up a shell script that will start a screen session (or rejoin an existing one) only if it is invoked from an interactive shell. The solution I have seen is to check if $- contains the letter "i":
#!/bin/sh -e
echo "Testing interactivity..."
echo 'Current value of $- = '"$-"
if [ `echo \$- | grep -qs i` ]; then
echo interactive;
else
echo noninteractive;
fi
However, this fails, because the script is run by a new noninteractive shell, invoked as a result of the #!/bin/sh at the top. If I source the script instead of running it, it works as desired, but that's an ugly hack. I'd rather have it work when I run it.
So how can I test for interactivity within a script?
Give this a try and see if it does what you're looking for:
#!/bin/sh
if [ $_ != $0 ]
then
echo interactive;
else
echo noninteractive;
fi
The underscore ($_) expands to the absolute pathname used to invoke the script. The zero ($0) expands to the name of the script. If they're different then the script was invoked from an interactive shell. In Bash, subsequent expansion of $_ gives the expanded argument to the previous command (it might be a good idea to save the value of $_ in another variable in order to preserve it).
From man bash:
0 Expands to the name of the shell or shell script. This is set
at shell initialization. If bash is invoked with a file of com‐
mands, $0 is set to the name of that file. If bash is started
with the -c option, then $0 is set to the first argument after
the string to be executed, if one is present. Otherwise, it is
set to the file name used to invoke bash, as given by argument
zero.
_ At shell startup, set to the absolute pathname used to invoke
the shell or shell script being executed as passed in the envi‐
ronment or argument list. Subsequently, expands to the last
argument to the previous command, after expansion. Also set to
the full pathname used to invoke each command executed and
placed in the environment exported to that command. When check‐
ing mail, this parameter holds the name of the mail file cur‐
rently being checked.
$_ may not work in every POSIX compatible sh, although it probably works in must.
$PS1 will only be set if the shell is interactive. So this should work:
if [ -z "$PS1" ]; then
echo noninteractive
else
echo interactive
fi
try tty
if tty 2>&1 |grep not ; then echo "Not a tty"; else echo "a tty"; fi
man tty :
The tty utility writes the name of the terminal attached to standard
input to standard output. The name that is written is the string
returned by ttyname(3). If the standard input is not a terminal, the
message ``not a tty'' is written.
You could try using something like...
if [[ -t 0 ]]
then
echo "Interactive...say something!"
read line
echo $line
else
echo "Not Interactive"
fi
The "-t" switch in the test field checks if the file descriptor given matches a terminal (you could also do this to stop the program if the output was going to be printed to a terminal, for example). Here it checks if the standard in of the program matches a terminal.
Simple answer: don't run those commands inside ` ` or [ ].
There is no need for either of those constructs here.
Obviously I can't be sure what you expected
[ `echo \$- | grep -qs i` ]
to be testing, but I don't think it's testing what you think it's testing.
That code will do the following:
Run echo \$- | grep -qs i inside a subshell (due to the ` `).
Capture the subshell's standard output.
Replace the original ` ` expression with a string containing that output.
Pass that string as an argument to the [ command or built-in (depending on your shell).
Produce a successful return code from [ only if that string was nonempty (assuming the string didn't look like an option to [).
Some possible problems:
The -qs options to grep should cause it to produce no output, so I'd expect [ to be testing an empty string regardless of what $- looks like.
It's also possible that the backslash is escaping the dollar sign and causing a literal 'dollar minus' (rather than the contents of a variable) to be sent to grep.
On the other hand, if you removed the [ and backticks and instead said
if echo "$-" | grep -qs i ; then
then:
your current shell would expand "$-" with the value you want to test,
echo ... | would send that to grep on its standard input,
grep would return a successful return code when that input contained the letter i,
grep would print no output, due to the -qs flags, and
the if statement would use grep's return code to decide which branch to take.
Also:
no backticks would replace any commands with the output produced when they were run, and
no [ command would try to replace the return code of grep with some return code that it had tried to reconstruct by itself from the output produced by grep.
For more on how to use the if command, see this section of the excellent BashGuide.
If you want to test the value of $- without forking an external process (e.g. grep) then you can use the following technique:
if [ "${-%i*}" != "$-" ]
then
echo Interactive shell
else
echo Not an interactive shell
fi
This deletes any match for i* from the value of $- then checks to see if this made any difference.
(The ${parameter/from/to} construct (e.g. [ "${-//[!i]/}" = "i" ] is true iff interactive) can be used in Bash scripts but is not present in Dash, which is /bin/sh on Debian and Ubuntu systems.)
I'm trying to setup a simple timer that gets started from a Rails Application. This timer should wait out its duration and then start a shell script that will start up ./script/runner and complete the initial request. I need script/runner because I need access to ActiveRecord.
Here's my test lines in Rails
output = `at #{(Time.now + 60).strftime("%H:%M")} < #{Rails.root}/lib/parking_timer.sh STRING_VARIABLE`
return render :text => output
Then my parking_timer.sh looks like this
#!/bin/sh
~/PATH_TO_APP/script/runner -e development ~/PATH_TO_APP/lib/ParkingTimer.rb $1
echo "All Done"
Finally, ParkingTimer.rb reads the passed variable with
ARGV.each do|a|
puts "Argument: #{a}"
end
The problem is that the Unix command "at" doesn't seem to like variables and only wants to deal with filenames. I either get one of two errors depending on how I position "s
If I put quotes around the right hand side like so
... "~/PATH_TO_APP/lib/parking_timer.sh STRING_VARIABLE"
I get,
-bash: ~/PATH_TO_APP/lib/parking_timer.sh STRING_VARIABLE: No such file or directory
I I leave the quotes out, I get,
at: garbled time
This is all happening on a Mac OS 10.6 box running Rails 2.3 & Ruby 1.8.6
I've already messed around w/ BackgrounDrb, and decided its a total PITA. I need to be able to cancel the job at any time before it is due.
After playing around with irb a bit, here's what I found.
The backtick operator invokes the shell after ruby has done any interpretation necessary. For my test case, the strace output looked something like this:
execve("/bin/sh", ["sh", "-c", "echo at 12:57 < /etc/fstab"], [/* 67 vars */]) = 0
Since we know what it's doing, let's take a look at how your command will be executed:
/bin/sh -c "at 12:57 < RAILS_ROOT/lib/parking_timer.sh STRING_VARIABLE"
That looks very odd. Do you really want to pipe parking_timer.sh, the script, as input into the at command?
What you probably ultimately want is something like this:
/bin/sh -c "RAILS_ROOT/lib/parking_timer.sh STRING_VARIABLE | at 12:57"
Thus, the output of the parking_timer.sh command will become the input to the at command.
So, try the following:
output = `#{Rails.root}/lib/parking_timer.sh STRING_VARIABLE | at #{(Time.now + 60).strftime("%H:%M")}`
return render :text => output
You can always use strace or truss to see what's happening. For example:
strace -o strace.out -f -ff -p $IRB_PID
Then grep '^exec' strace.out* to see where the command is being executed.