smartGWT: how to add items in selectOtherItem - smartgwt

I have create a selectOtherItem in my SmartGWT .
i have just shifted from GWT where we simply do
listBox.addItem("some Item");
and to put the values coming from a loop and also to save the id against every item (for values coming from db)
for(int i =0;i <list.size; i++){
listBox.addItem(list.getName(i), list.getId(i));
}
but i'm not able to do these stuff in smartGWT .
Now i am using selectOtherItem .
If you can please guide how i can do the same thing in smartGWT, which i have show above.
thanks

SmartGWT also has the same functionality. You can directly add the Strings to a ComboBoxItem or SelectItem as mentioned below:
comboboxItem.setValueMap("s", "a", "d");
OR you can also prepare a LinkedHashMap, to specify key-value pair as mentioned below:
LinkedHashMap<String, String> map = new LinkedHashMap<String, String>();
for (Obj obj : objList) {
map.put(String.valueOf(obj.getId()), obj.getName());
}
comboboxItem.setValueMap(map);
Besides, you can also fill up a ComboBoxItem or SelectItem using a DataSource.
For further details, refer this link.

Related

Firebase - How to sort the data by newly added child (Swift)? [duplicate]

I'm trying to test out Firebase to allow users to post comments using push. I want to display the data I retrieve with the following;
fbl.child('sell').limit(20).on("value", function(fbdata) {
// handle data display here
}
The problem is the data is returned in order of oldest to newest - I want it in reversed order. Can Firebase do this?
Since this answer was written, Firebase has added a feature that allows ordering by any child or by value. So there are now four ways to order data: by key, by value, by priority, or by the value of any named child. See this blog post that introduces the new ordering capabilities.
The basic approaches remain the same though:
1. Add a child property with the inverted timestamp and then order on that.
2. Read the children in ascending order and then invert them on the client.
Firebase supports retrieving child nodes of a collection in two ways:
by name
by priority
What you're getting now is by name, which happens to be chronological. That's no coincidence btw: when you push an item into a collection, the name is generated to ensure the children are ordered in this way. To quote the Firebase documentation for push:
The unique name generated by push() is prefixed with a client-generated timestamp so that the resulting list will be chronologically-sorted.
The Firebase guide on ordered data has this to say on the topic:
How Data is Ordered
By default, children at a Firebase node are sorted lexicographically by name. Using push() can generate child names that naturally sort chronologically, but many applications require their data to be sorted in other ways. Firebase lets developers specify the ordering of items in a list by specifying a custom priority for each item.
The simplest way to get the behavior you want is to also specify an always-decreasing priority when you add the item:
var ref = new Firebase('https://your.firebaseio.com/sell');
var item = ref.push();
item.setWithPriority(yourObject, 0 - Date.now());
Update
You'll also have to retrieve the children differently:
fbl.child('sell').startAt().limitToLast(20).on('child_added', function(fbdata) {
console.log(fbdata.exportVal());
})
In my test using on('child_added' ensures that the last few children added are returned in reverse chronological order. Using on('value' on the other hand, returns them in the order of their name.
Be sure to read the section "Reading ordered data", which explains the usage of the child_* events to retrieve (ordered) children.
A bin to demonstrate this: http://jsbin.com/nonawe/3/watch?js,console
Since firebase 2.0.x you can use limitLast() to achieve that:
fbl.child('sell').orderByValue().limitLast(20).on("value", function(fbdataSnapshot) {
// fbdataSnapshot is returned in the ascending order
// you will still need to order these 20 items in
// in a descending order
}
Here's a link to the announcement: More querying capabilities in Firebase
To augment Frank's answer, it's also possible to grab the most recent records--even if you haven't bothered to order them using priorities--by simply using endAt().limit(x) like this demo:
var fb = new Firebase(URL);
// listen for all changes and update
fb.endAt().limit(100).on('value', update);
// print the output of our array
function update(snap) {
var list = [];
snap.forEach(function(ss) {
var data = ss.val();
data['.priority'] = ss.getPriority();
data['.name'] = ss.name();
list.unshift(data);
});
// print/process the results...
}
Note that this is quite performant even up to perhaps a thousand records (assuming the payloads are small). For more robust usages, Frank's answer is authoritative and much more scalable.
This brute force can also be optimized to work with bigger data or more records by doing things like monitoring child_added/child_removed/child_moved events in lieu of value, and using a debounce to apply DOM updates in bulk instead of individually.
DOM updates, naturally, are a stinker regardless of the approach, once you get into the hundreds of elements, so the debounce approach (or a React.js solution, which is essentially an uber debounce) is a great tool to have.
There is really no way but seems we have the recyclerview we can have this
query=mCommentsReference.orderByChild("date_added");
query.keepSynced(true);
// Initialize Views
mRecyclerView = (RecyclerView) view.findViewById(R.id.recyclerView);
mManager = new LinearLayoutManager(getContext());
// mManager.setReverseLayout(false);
mManager.setReverseLayout(true);
mManager.setStackFromEnd(true);
mRecyclerView.setHasFixedSize(true);
mRecyclerView.setLayoutManager(mManager);
I have a date variable (long) and wanted to keep the newest items on top of the list. So what I did was:
Add a new long field 'dateInverse'
Add a new method called 'getDateInverse', which just returns: Long.MAX_VALUE - date;
Create my query with: .orderByChild("dateInverse")
Presto! :p
You are searching limitTolast(Int x) .This will give you the last "x" higher elements of your database (they are in ascending order) but they are the "x" higher elements
if you got in your database {10,300,150,240,2,24,220}
this method:
myFirebaseRef.orderByChild("highScore").limitToLast(4)
will retrive you : {150,220,240,300}
In Android there is a way to actually reverse the data in an Arraylist of objects through the Adapter. In my case I could not use the LayoutManager to reverse the results in descending order since I was using a horizontal Recyclerview to display the data. Setting the following parameters to the recyclerview messed up my UI experience:
llManager.setReverseLayout(true);
llManager.setStackFromEnd(true);
The only working way I found around this was through the BindViewHolder method of the RecyclerView adapter:
#Override
public void onBindViewHolder(final RecyclerView.ViewHolder holder, int position) {
final SuperPost superPost = superList.get(getItemCount() - position - 1);
}
Hope this answer will help all the devs out there who are struggling with this issue in Firebase.
Firebase: How to display a thread of items in reverse order with a limit for each request and an indicator for a "load more" button.
This will get the last 10 items of the list
FBRef.child("childName")
.limitToLast(loadMoreLimit) // loadMoreLimit = 10 for example
This will get the last 10 items. Grab the id of the last record in the list and save for the load more functionality. Next, convert the collection of objects into and an array and do a list.reverse().
LOAD MORE Functionality: The next call will do two things, it will get the next sequence of list items based on the reference id from the first request and give you an indicator if you need to display the "load more" button.
this.FBRef
.child("childName")
.endAt(null, lastThreadId) // Get this from the previous step
.limitToLast(loadMoreLimit+2)
You will need to strip the first and last item of this object collection. The first item is the reference to get this list. The last item is an indicator for the show more button.
I have a bunch of other logic that will keep everything clean. You will need to add this code only for the load more functionality.
list = snapObjectAsArray; // The list is an array from snapObject
lastItemId = key; // get the first key of the list
if (list.length < loadMoreLimit+1) {
lastItemId = false;
}
if (list.length > loadMoreLimit+1) {
list.pop();
}
if (list.length > loadMoreLimit) {
list.shift();
}
// Return the list.reverse() and lastItemId
// If lastItemId is an ID, it will be used for the next reference and a flag to show the "load more" button.
}
I'm using ReactFire for easy Firebase integration.
Basically, it helps me storing the datas into the component state, as an array. Then, all I have to use is the reverse() function (read more)
Here is how I achieve this :
import React, { Component, PropTypes } from 'react';
import ReactMixin from 'react-mixin';
import ReactFireMixin from 'reactfire';
import Firebase from '../../../utils/firebaseUtils'; // Firebase.initializeApp(config);
#ReactMixin.decorate(ReactFireMixin)
export default class Add extends Component {
constructor(args) {
super(args);
this.state = {
articles: []
};
}
componentWillMount() {
let ref = Firebase.database().ref('articles').orderByChild('insertDate').limitToLast(10);
this.bindAsArray(ref, 'articles'); // bind retrieved data to this.state.articles
}
render() {
return (
<div>
{
this.state.articles.reverse().map(function(article) {
return <div>{article.title}</div>
})
}
</div>
);
}
}
There is a better way. You should order by negative server timestamp. How to get negative server timestamp even offline? There is an hidden field which helps. Related snippet from documentation:
var offsetRef = new Firebase("https://<YOUR-FIREBASE-APP>.firebaseio.com/.info/serverTimeOffset");
offsetRef.on("value", function(snap) {
var offset = snap.val();
var estimatedServerTimeMs = new Date().getTime() + offset;
});
To add to Dave Vávra's answer, I use a negative timestamp as my sort_key like so
Setting
const timestamp = new Date().getTime();
const data = {
name: 'John Doe',
city: 'New York',
sort_key: timestamp * -1 // Gets the negative value of the timestamp
}
Getting
const ref = firebase.database().ref('business-images').child(id);
const query = ref.orderByChild('sort_key');
return $firebaseArray(query); // AngularFire function
This fetches all objects from newest to oldest. You can also $indexOn the sortKey to make it run even faster
I had this problem too, I found a very simple solution to this that doesn't involved manipulating the data in anyway. If you are rending the result to the DOM, in a list of some sort. You can use flexbox and setup a class to reverse the elements in their container.
.reverse {
display: flex;
flex-direction: column-reverse;
}
myarray.reverse(); or this.myitems = items.map(item => item).reverse();
I did this by prepend.
query.orderByChild('sell').limitToLast(4).on("value", function(snapshot){
snapshot.forEach(function (childSnapshot) {
// PREPEND
});
});
Someone has pointed out that there are 2 ways to do this:
Manipulate the data client-side
Make a query that will order the data
The easiest way that I have found to do this is to use option 1, but through a LinkedList. I just append each of the objects to the front of the stack. It is flexible enough to still allow the list to be used in a ListView or RecyclerView. This way even though they come in order oldest to newest, you can still view, or retrieve, newest to oldest.
You can add a column named orderColumn where you save time as
Long refrenceTime = "large future time";
Long currentTime = "currentTime";
Long order = refrenceTime - currentTime;
now save Long order in column named orderColumn and when you retrieve data
as orderBy(orderColumn) you will get what you need.
just use reverse() on the array , suppose if you are storing the values to an array items[] then do a this.items.reverse()
ref.subscribe(snapshots => {
this.loading.dismiss();
this.items = [];
snapshots.forEach(snapshot => {
this.items.push(snapshot);
});
**this.items.reverse();**
},
For me it was limitToLast that worked. I also found out that limitLast is NOT a function:)
const query = messagesRef.orderBy('createdAt', 'asc').limitToLast(25);
The above is what worked for me.
PRINT in reverse order
Let's think outside the box... If your information will be printed directly into user's screen (without any content that needs to be modified in a consecutive order, like a sum or something), simply print from bottom to top.
So, instead of inserting each new block of content to the end of the print space (A += B), add that block to the beginning (A = B+A).
If you'll include the elements as a consecutive ordered list, the DOM can put the numbers for you if you insert each element as a List Item (<li>) inside an Ordered Lists (<ol>).
This way you save space from your database, avoiding unnecesary reversed data.

Vaadin: How do I add options to a combo box?

I have a combo box that I am trying to add options to. How Do I go about this? This is what I have so far:
ComboBox contactPrefixNametf = new ComboBox("Prefix");
contactPrefixNametf.setItemCaption(contactPrefixNametf, "Mr");
fLayout.addComponent(contactPrefixNametf);
contactPrefixNametf.setImmediate(true);
I guess .setItemCaption() is not the correct method? What is the correct method?
Thank you in advance!
Use addItem() method:
final ComboBox my_combox_box = new ComboBox("My Combo Box");
for (final My_object mo: list_of_my_objects)
{
my_combox_box.addItem(mo);
my_combox_box.setItemCaption(mo, mo.name());
}
This example uses addItem inconjunction with setItemCaption() to store the actual object selected by the user with a display friendly name (if toString() is not appropriate).
myComboBox.addItem("Option 1");
(Especially if you are new to Vaadin), I suggest to try Viritin add-on and its TypedSelect variant of ComboBox. Its well typed API makes many things ridiculously simpler. For instance it has a (typed) setOptions method and its value change listeners provide the value directly instead of through untyped Property interface.
A code example of its usage:
List<Person> options = service.findMyPersons();
TypedSelect<Person> select = new TypedSelect<>(Person.class)
.withSelectType(ComboBox.class);
select.setOptions(options);
// If toString() representation is not good, modify it to something else
select.setCaptionGenerator(person -> person.getFirstName() + person.getLastName());
select.addMValueChangeListener(event -> {
Person person = event.getValue();
});
Disclaimer: I'm the maintainer of Viritin, but also have maintained Vaadin for 8 years and nowadays work as its developer advocate.

Creating HtmlSelectOneMenu dynamically - assigning SelectItem list

I have a JSF application where I need to create almost all of the UIComponents dynamically based on certain parameters to the page. The components are created and added to an HtmlPanelGrid. I've been successfully creating HtmlLabel, HtmlInputText, UISelectBoolean, and HtmlCommandButton. Now I need to create an HtmlSelectOneMenu and add it, and I'm having a hard time finding examples that show how to attach the list of items to select.
The selection list is this, where I've made cfaItems a property of my backing bean:
SelectItem[] cfaItems = {
new SelectItem(1, "1"),
new SelectItem(2, "2"),
new SelectItem(3, "3"),
new SelectItem(4, "4"),
new SelectItem(5, "5")
};
The creation of the HtmlSelectOneMenu:
HtmlSelectOneMenu cfaMenu = (HtmlSelectOneMenu)
getApplication().createComponent(HtmlSelectOneMenu.COMPONENT_TYPE);
cfaMenu.setId("cfaMenu");
grid.getChildren().add(cfaMenu);
As best as I can figure it out, I need to create a ValueExpression that would bind the cfaItems list to the cfaMenu but not finding any examples is a problem. I think that I need to do something like this
String menuBinding =
"#{" + beanName + ".cfaItems}";
ValueExpression menuVE = getApplication().getExpressionFactory().
createValueExpression(FacesContext.getCurrentInstance().
getELContext(), menuBinding, String.class);
cfaMenu.setValueExpression("value", menuVE);
But I don't think that's correct. Any suggestions?
You need to create an UISelectItems instance with the given select item array as value and then add it as child of the menu, exactly as you'd do with <f:selectItems> in the view side.
UISelectItems selectItems = new UISelectItems();
selectItems.setValue(cfaItems);
cfaMenu.getChildren().add(selectItems);

Additional criteria to symfony filter

i'm working on a symfony project to manage a database. First i explain how it works:
In the database, all elements are associated to an unique element 'scene'. When a user accesses the application, chooses what scene he wants to see (it saves that in a user parameter). So when listing elements, the application should only list elements associated with the scene selected by the user.
*Note: all elements have an scene attribute in the table definition.
So my problem comes here:
I developed a listing of an element entities using the help of a sfPropelPager class to paginate. Also added some filters to search in the list, and for that i used the filter system provided by symfony (<element>FormFilter.class.php and stuff).
Now i want the list to not show elements from other scenes than the selected by the user.
How can i do to add additional criteria to the criteria given by the filter class?
or How would you solve the problem?
here is my action code:
public function executeUnidadfilter(sfWebRequest $request){
$this->filter = new BaUnidadorganizativaTblFormFilter();
$c = $this->filter->getCriteria();
$this->filter->bind($request->getParameter($this->filter->getName()));
if($this->filter->isValid()){
$this->pager = new sfPropelPager('BaUnidadorganizativaTbl',$this->sfPropelPagerLines);
echo $this->getUser()->getEscenario();
$this->pager->setCriteria($c);
$this->pager->init();
}else{
$this->pager = new sfPropelPager('BaUnidadorganizativaTbl',$this->sfPropelPagerLines);
$this->pager->init();
}
$this->setTemplate('Unidadlist');
}
*Note: 'scene' mentioned below is Escenario in the code
thank you very much for your time
I solved the problem. The trouble was that i assigned the formfilter generated criteria to my criteria var Before the filter was filled. That's why of the error.
The resulting code is that:
public function executeUnidadfilter(sfWebRequest $request){
$this->filter = new BaUnidadorganizativaTblFormFilter();
$this->filter->bind($request->getParameter($this->filter->getName()));
if($this->filter->isValid()){
$this->pager = new sfPropelPager('BaUnidadorganizativaTbl',$this->sfPropelPagerLines);
$esc = $this->getUser()->getEscenario();
$c = new Criteria();
$c = $this->filter->getCriteria();
$c->addAnd('codigo_escenario',$esc);
$this->pager->setCriteria($c);
$this->pager->init();
}else{
$this->pager = new sfPropelPager('BaUnidadorganizativaTbl',$this->sfPropelPagerLines);
$this->pager->setCriteria($this->filter->getCriteria());
$this->pager->init();
}
$this->message=null;
$this->messageType=null;
$this->setTemplate('Unidadlist');
}

db4o issue with graph of objects

I am a new to db4o. I have a big problem with persistance of a graph of objects. I am trying to migrate from old persistance component to new, using db4o.
Before I peristed all objects its graph looked like below (Take a look at Zrodlo.Metadane.abstrakt string field with focused value) [its view from eclipse debuger] with a code:
ObjectContainer db=Db4o.openFile(DB_FILE);
try {
db.store(encja);
db.commit();
} finally{
db.close();
}
After that, I tried to read it with a code:
ObjectContainer db=Db4o.openFile((DB_FILE));
try{
Query q = db.query();
q.constrain(EncjaDanych.class);
ObjectSet<Object> objectSet = q.execute();
logger.debug("objectSet.size" + objectSet.size());
EncjaDanych encja = (EncjaDanych) objectSet.get(0);
logger.debug("ENCJA" + encja.toString());
return encja;
}finally{
db.close();
}
and I got it (picture below) - string field "abstrakt" is null now !!!
I take a look at it using ObjectManager (picture below) and abstrakt field has not-null value there!!! The same value, that on the 1st picture.
Please help me :) It is my second day with db4o. Thanks in advance!
I am attaching some code with structure of persisted class:
public class EncjaDanych{
Map mapaIdRepo = new HashMap();
public Map mapaNazwaRepo = new HashMap(); }
!!!!!!!!UPDATED:
When I tried to read only Metadane object (there was only one such a object), it is all right - it's string field abstrakt could be read correctly.
try{
Query q = db.query();
q.constrain(Metadane.class);
ObjectSet<Object> objectSet = q.execute();
logger.error("objectSet.size" + objectSet.size());
Metadane meta = (Metadane) objectSet.get(0);
logger.debu("Metadane" + meta.toString());
return meta;
}finally{
db.close();
}
This is a common db4o FAQ, an issue with what db4o calls "activation". db4o won't instantiate the entire graph you stored when you load an object from an ObjectContainer. By default, objects are instantiated to depth 5. You can change the default configuration to a higher value, but that is not recommended since it will slow down object loading in principle because the depth will be used everywhere you load an object with a query.
Two approaches are possible to solve your issue:
(1) You can activate an object to a desired depth by hand when you need a specific depth.
db.activate(encja, 10) // 10 is arbitrary
(2) You can work with Transparent Activation. There are multiple chapters on how to use Transparent Activation (TA) in the db4o tutorial and in the reference documentation.
You're not setting a filter in your query so you're reading the first object. Are you sure you didn't have a previous object in the database?

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