I have a User model and an Item model. I want to rank users according to the value of the items they have. I want to do the equivalent of this query:
SELECT rank() OVER (ORDER BY grand_total DESC), u.*, grand_total
FROM users AS u
JOIN
(SELECT user_id, SUM(amount) AS grand_total FROM items WHERE EXTRACT(YEAR FROM sold_at)='2012' GROUP BY user_id) AS i
ON u.id = i.user_id;
Specifically, I don't know how to join on my select.
Given the problem as you describe it, I would write the query thus:
select users.*, sum(items.amount) as rank
from users
join items on items.user_id = users.id
group by users.id
order by rank desc;
Which would translate into AREL as:
User.select('users.*, sum(items.amount) as rank').joins('join items on items.user_id = users.id').group('users.id').order('rank desc')
This has the handy side-effect that you can call .rank on the resulting User objects and get the value of the rank column from the query, in case you need to display it.
Is there something about your situation I'm not grasping here, or would this work?
Related
I have a table skills and a table programs_skills which references skill_id as a foreign key, I want to retrieve the 10 most present skills in table programs_skills (I need to count the number of occurrence of skill_id in programs_skills and then order it by descending order).
I wrote this in my skill model:
def self.most_used(limit)
Skill.find(
ActiveRecord::Base.connection.execute(
'SELECT programs_skills.skill_id, count(*) FROM programs_skills GROUP BY skill_id ORDER BY count DESC'
).to_a.first(limit).map { |record| record['skill_id'] }
)
end
This is working but I would like to find a way to perform this query in a more elegant, performant, "activerecord like" way.
Could you help me rewrite this query ?
Just replace your query by:
WITH
T AS
(
SELECT skill_id, COUNT(*) AS NB, RANK() OVER(ORDER BY COUNT(*) DESC) AS RNK
FROM programs_skills
GROUP BY skill_id
)
SELECT wojewodztwo, NB
FROM T
WHERE RNK <= 10
This use CTE and windowed function.
ProgramsSkills.select("skill_id, COUNT(*) AS nb_skills")
.group(:skill_id).order("nb_skills DESC").limit(limit)
.first(limit).pluck(:skill_id)
I have two tables users and posts and they have association of has_many. I want to fetch details of both users and posts in a single query. I'm able to manage the sql query but I don't want to use the raw query in the code (using execute method) as i think it is kind of simple thing and can be written using active record.
Here is the sql query
SELECT a.id, a.name, a.timestamp, b.id, b.user_id, b.title
FROM users a
INNER JOIN (SELECT id, user_id, title, from, to FROM posts) b on b.user_id = a.id
where id IN ( 1, 2, 3);
I think includes does not help here because i'm dealing with large data.
Can any one help me ?
If you just want those specific columns and nothing else then this will work
User.joins(:post)
.where(id: [1,2,3])
.select("users.id, users.name, users.timestamp,
posts.id as post_id, posts.user_id as post_user_id,
posts.title as post_title")
This will return an ActiveRecord::Relation of User objects with virtual attributes for post_id, post_user_id (Not sure why you need this one since you already selected users.id), and post_title.
The query produced will be
SELECT users.id,
users.name,
users.timestamp,
posts.id as post_id,
posts.user_id as post_user_id,
posts.title as post_title
FROM users
INNER JOIN posts on posts.user_id = users.id
where users.id IN ( 1, 2, 3);
Please note you may have multiple User objects, one for each Post, just as the SQL query does.
You can execute your exact query using the string version of joins e.g.
User.joins("INNER JOIN (SELECT id, user_id, title, from, to FROM posts) b on b.user_id = users.id")
.where(id: [1,2,3])
.select("users.id, users.name, users.timestamp,
b.id as post_id, b.user_id as post_user_id,
b.title as post_title")
Additionally to avoid some of the overhead you can use arel instead e.g.
users_table = User.arel_table
posts_table = Post.arel_table
query = users_table.project(Arel.star)
.join(posts_table)
.on(posts_table[:user_id].eq(users_table[:id]))
.where(users_table[:id].in([1,2,3]))
ActiveRecord::Base.connection.exec_query(query.to_sql)
This will return an ActiveRecord::Result with 2 useful methods columns (the columns selected) and rows. You can convert this to a Hash(#to_hash) but note that any columns with duplicate names (id for instance) will overwrite one another.
You could fix this by specifying the colums you want selected in the project portion. e.g. your current query would be:
query = users_table.project(
users_table[:id],
users_table[:name],
users_table[:timestamp],
posts_table[:id].as('post_id'),
posts_table[:user_id].as('post_user_id'),
posts_table[:title].as('post_title')
).join(posts_table)
.on(posts_table[:user_id].eq(users_table[:id]))
.where(users_table[:id].in([1,2,3]))
ActiveRecord::Base.connection.exec_query(query.to_sql).to_hash
Since none of the names collide now it can be structured into a nice Hash where the keys are the column names and the values or the row value for that record.
users = User.joins(:posts).includes(:posts).where(id: [1, 2, 3])
Will give you all the users with theirs posts.
then you can do whatever you want with them, but to access posts data for first retrieved user
first_user_posts = users.first.posts # this will not make additional DB queries as you used includes and data is already added
We use joins to have INNER JOIN statement in the SQL
We use includes to load all posts in the memory
I have two tables users and posts and they have association of
has_many. I want to fetch details of both users and posts in a single
query.
can be done with includes like
users = User.includes(:posts).where({posts: {user_id: [1,2,3]}})
other is eager_load and preload you can use as per your requirements, for more https://blog.arkency.com/2013/12/rails4-preloading/
This is a hard problem to describe but I have Rails query where I join another table and I want to exclude any results where the join table contain one of three conditions.
I have a Device model that relates to a CarUserRole model/record. In that CarUserRole record it will contain one of three :role - "owner", "monitor", "driver". I want to return any results where there is no related CarUserRole record where role: "owner". How would I do that?
This was my first attempt -
Device.joins(:car_user_roles).where('car_user_roles.role = ? OR car_user_roles.role = ? AND car_user_roles.role != ?', 'monitor', 'driver', 'owner')
Here is the sql -
"SELECT \"cars\".* FROM \"cars\" INNER JOIN \"car_user_roles\" ON \"car_user_roles\".\"car_id\" = \"cars\".\"id\" WHERE (car_user_roles.role = 'monitor' OR car_user_roles.role = 'driver' AND car_user_roles.role != 'owner')"
Update
I should mention that a device sometimes has multiple CarUserRole records. A device can have an "owner" and a "driver" CarUserRole. I should also note that they can only have one owner.
Anwser
I ended up going with #Reub's solution via our chat -
where(CarUserRole.where("car_user_roles.car_id = cars.id").where(role: 'owner').exists.not)
Since the car_user_roles table can have multiple records with the same car_id, an inner join can result in the join table having multiple rows for each row in the cars table. So, for a car that has 3 records in the car_user_roles table (monitor, owner and driver), there will be 3 records in the join table (each record having a different role). Your query will filter out the row where the role is owner, but it will match the other two, resulting in that car being returned as a result of your query even though it has a record with role as 'owner'.
Lets first try to form an sql query for the result that you want. We can then convert this into a Rails query.
SELECT * FROM cars WHERE NOT EXISTS (SELECT id FROM car_user_roles WHERE role='owner' AND car_id = cars.id);
The above is sufficient if you want devices which do not have any car_user_role with role as 'owner'. But this can also give you devices which have no corresponding record in car_user_roles. If you want to ensure that the device has at least one record in car_user_roles, you can add the following to the above query.
AND EXISTS (SELECT id FROM car_user_roles WHERE role IN ('monitor', 'driver') AND car_id = cars.id);
Now, we need to convert this into a Rails query.
Device.where(
CarUserRole.where("car_user_roles.car_id = cars.id").where(role: 'owner').exists.not
).where(
CarUserRole.where("car_user_roles.car_id = cars.id").where(role: ['monitor', 'driver']).exists
).all
You could also try the following if your Rails version supports exists?:
Device.joins(:car_user_roles).exists?(role: ['monitor', 'driver']).exists?(role: 'owner').not.select('cars.*').distinct
Select the distinct cars
SELECT DISTINCT (cars.*) FROM cars
Use a LEFT JOIN to pull in the car_user_roles
LEFT JOIN car_user_roles ON cars.id = car_user_roles.car_id
Select only the cars that DO NOT contain an 'owner' car_user_role
WHERE NOT EXISTS(SELECT NULL FROM car_user_roles WHERE cars.id = car_user_roles.car_id AND car_user_roles.role = 'owner')
Select only the cars that DO contain either a 'driver' or 'monitor' car_user_role
AND (car_user_roles.role IN ('driver','monitor'))
Put it all together:
SELECT DISTINCT (cars.*) FROM cars LEFT JOIN car_user_roles ON cars.id = car_user_roles.car_id WHERE NOT EXISTS(SELECT NULL FROM car_user_roles WHERE cars.id = car_user_roles.car_id AND car_user_roles.role = 'owner') AND (car_user_roles.role IN ('driver','monitor'));
Edit:
Execute the query directly from Rails and return only the found object IDs
ActiveRecord::Base.connection.execute(sql).collect { |x| x['id'] }
Let's say users have comments and I want all users with three comments or more.
User.joins(:comments) will get me any user that has
one or more comments. What is the nicest way to get Users with at least three comments?
A nicer way might be to write that subquery using the API:
subquery = Comment.select("user_id").
group(:user_id).
having("COUNT(*) >= 3").to_sql
User.where("id IN (#{subquery})")
SQL like this:
SELECT users.* FROM users
WHERE EXISTS (SELECT id FROM comments WHERE user_id = users.id GROUP BY user_id HAVING COUNT(*) >= 3)
Which in ActiveRecord notation translates to:
User.where('EXISTS (SELECT id FROM comments WHERE user_id = users.id GROUP BY user_id HAVING COUNT(*) >= 3)')
I have a users table, which has a one-to-many relationship with a user_purchases table via the foreign key user_id. That is, each user can make many purchases (or may have none, in which case he will have no entries in the user_purchases table).
user_purchases has only one other field that is of interest here, which is purchase_date.
I am trying to write a Sequel ORM statement that will return a dataset with the following columns:
user_id
date of the users SECOND purchase, if it exists
So users who have not made at least 2 purchases will not appear in this dataset. What is the best way to write this Sequel statement?
Please note I am looking for a dataset with ALL users returned who have >= 2 purchases
Thanks!
EDIT FOR CLARITY
Here is a similar statement I wrote to get users and their first purchase date (as opposed to 2nd purchase date, which I am asking for help with in the current post):
DB[:users].join(:user_purchases, :user_id => :id)
.select{[:user_id, min(:purchase_date)]}
.group(:user_id)
You don't seem to be worried about the dates, just the counts so
DB[:user_purchases].group_and_count(:user_id).having(:count > 1).all
will return a list of user_ids and counts where the count (of purchases) is >= 2. Something like
[{:count=>2, :user_id=>1}, {:count=>7, :user_id=>2}, {:count=>2, :user_id=>3}, ...]
If you want to get the users with that, the easiest way with Sequel is probably to extract just the list of user_ids and feed that back into another query:
DB[:users].where(:id => DB[:user_purchases].group_and_count(:user_id).
having(:count > 1).all.map{|row| row[:user_id]}).all
Edit:
I felt like there should be a more succinct way and then I saw this answer (from Sequel author Jeremy Evans) to another question using select_group and select_more : https://stackoverflow.com/a/10886982/131226
This should do it without the subselect:
DB[:users].
left_join(:user_purchases, :user_id=>:id).
select_group(:id).
select_more{count(:purchase_date).as(:purchase_count)}.
having(:purchase_count > 1)
It generates this SQL
SELECT `id`, count(`purchase_date`) AS 'purchase_count'
FROM `users` LEFT JOIN `user_purchases`
ON (`user_purchases`.`user_id` = `users`.`id`)
GROUP BY `id` HAVING (`purchase_count` > 1)"
Generally, this could be the SQL query that you need:
SELECT u.id, up1.purchase_date FROM users u
LEFT JOIN user_purchases up1 ON u.id = up1.user_id
LEFT JOIN user_purchases up2 ON u.id = up2.user_id AND up2.purchase_date < up1.purchase_date
GROUP BY u.id, up1.purchase_date
HAVING COUNT(up2.purchase_date) = 1;
Try converting that to sequel, if you don't get any better answers.
The date of the user's second purchase would be the second row retrieved if you do an order_by(:purchase_date) as part of your query.
To access that, do a limit(2) to constrain the query to two results then take the [-1] (or last) one. So, if you're not using models and are working with datasets only, and know the user_id you're interested in, your (untested) query would be:
DB[:user_purchases].where(:user_id => user_id).order_by(:user_purchases__purchase_date).limit(2)[-1]
Here's some output from Sequel's console:
DB[:user_purchases].where(:user_id => 1).order_by(:purchase_date).limit(2).sql
=> "SELECT * FROM user_purchases WHERE (user_id = 1) ORDER BY purchase_date LIMIT 2"
Add the appropriate select clause:
.select(:user_id, :purchase_date)
and you should be done:
DB[:user_purchases].select(:user_id, :purchase_date).where(:user_id => 1).order_by(:purchase_date).limit(2).sql
=> "SELECT user_id, purchase_date FROM user_purchases WHERE (user_id = 1) ORDER BY purchase_date LIMIT 2"