.net Razor alternative to PHP echo - asp.net-mvc

Question

I'm new to .net MVC and Razor engine but I have been using PHP for a long time. I'm trying to do this PHP code in Razor:
var data = [
<?php for ($i = 0; $i < 50; ++$i) {
echo '[' . $i . ',' . sin($i) . ']';
if ($i != 49)
echo ',';
?>
],
I managed to do it using this, but it looks bad and complex for something so simple
var data = [
#for(int i = 0; i < 50; ++i) {
<text>[</text>#i<text>,</text>#Math.Sin(i)<text>]</text>if (i != 49) {<text>,</text>}
}
];
The problem is that [, ] and , are confused with Razor syntax and gives syntax errors, so I had to wrap them on <text> tags.
Is there a simpler/nicer way to do this? Maybe something like the PHP echo.
Thanks.

Answer 1

A gerenal equivalent of echo in MVC cshtml might be:
#Html.Raw("SomeStringDirectlyInsideTheBrowserPageHTMLCode")
This renders the (dynamic) string at its position where '<' and '>' no need to be HTML-coded. For example #Html.Raw(String.Format("<div class=\"{0}\" style=\"{1}\">", myclass, mystyle)) works fine.
Note that the HTML tags rendered by #Html.Raw(MyString) cannot be checked by the compiler. I mean: #Html.Raw("<div ....>") cannot be closed by mere </div> because you will get an error (<div ....> is not detected by the compiler) so you must close the tag with #Html.Raw("</div>")
P.S.In some cases this doesn't work (for example it fails within DevExpress) - use ViewContext.Writer.Write() or ViewContext.Writer.WriteLine() instead.

Answer 2

Use this:
#String.Format("[{0},{1}]", i, Math.Sin(i))
And for comma you can use String.Join() if you create array (String.Join Method )

Answer 3

Old question I know, but an alternative is to use the plaintext syntax #:
var data = [
#for (int i = 0; i < 50; ++i)
{
#:[#i,#Math.Sin(i)]
#(i != 49 ? "," : "")
}
];

Answer 4

Constructing a JSON object using a view is not really the best way to go about it. You can use the native JSON support to do this directly from a controller, for example:
public JsonResult SinArray()
{
return new JsonResult() {
Data = Enumerable.Range(0, 50).Select(i => new[] { i, Math.Sin(i) }),
JsonRequestBehavior = JsonRequestBehavior.AllowGet
};
}
This returns
[[0,0],[1,0.8414709848078965],[2,0.90929742682568171],.....,[49,-0.95375265275947185]]
As a bonus you get the correct content-type.