OpenCV Mean/SD filter - opencv

Question

I'm throwing this out there in hope that someone will have attempted something this ridiculous before. My goal is to take in an input image, and segment it based upon the standard deviation of a small window around each pixel. Bascially, this should mathematically resemble a gauss or box filter, in that it will be applied to a compile time (or even run-time) user specified window size around each pixel, and the destination array will contain the SD information at each pixel, in an image the same size as the original.
The idea is to do this on an image in HSV space, so that I can easily find regions of homogeneous color (i.e. those with small local SDs in the Hue and Sat planes) and extract them from the image for more in-depth processing.
So the question is, has anyone ever built a custom filter like this before? I don't know how to do the SD in a simple box type filter kernel like the ones used for gauss and blur, so I'm guessing I'll have to use the FilterEngine construct. Also, I forgot to mention I'm doing this in C++.
Your advice and musings are much appreciated.

Answer 1

Wikipedia has a nice explanation of standard deviation, which you can use to for a standard deviation filter.
Basically, it boils down to blurring the image with a box filter, blurring the square of the image with a box filter, and taking the square root of their difference.
UPDATE: This is probably better shown with the equation from Wikipedia...
You can think of the OpenCV blur function as representing the expected value (i.e., E[X] a.k.a. the sample mean) of the neighborhood of interest. The random samples X in this case are represented by image pixels in the local neighborhood. Therefore, by using the above equivalence we have something like sqrt(blur(img^2) - blur(img)^2) in OpenCV. Doing it this way allows you to compute the local means and standard deviations.
Also, just in case you are curious about the mathematical proof. This equivalence is known as the computational formula for variance.
Here is how you can do this in OpenCV:
#include <iostream>
#include <opencv2/core/core.hpp>
#include <opencv2/highgui/highgui.hpp>
#include <opencv2/imgproc/imgproc.hpp>
using namespace std;
using namespace cv;
Mat mat2gray(const Mat& src)
{
Mat dst;
normalize(src, dst, 0.0, 1.0, NORM_MINMAX);
return dst;
}
int main()
{
Mat image = imread("coke-can.jpg", 0);
Mat image32f;
image.convertTo(image32f, CV_32F);
Mat mu;
blur(image32f, mu, Size(3, 3));
Mat mu2;
blur(image32f.mul(image32f), mu2, Size(3, 3));
Mat sigma;
cv::sqrt(mu2 - mu.mul(mu), sigma);
imshow("coke", mat2gray(image32f));
imshow("mu", mat2gray(mu));
imshow("sigma",mat2gray(sigma));
waitKey();
return 0;
}
This produces the following images:
Original
Mean
Standard Deviation
Hope that helps!

Answer 2

In case you want to use this in more general way this can produce nan values
Values close to zero can be sometimes "negative".
Mat sigma;
cv::sqrt(mu2 - mu.mul(mu), sigma);
correct way should be
Mat sigma;
cv::sqrt(cv::abs(mu2 - mu.mul(mu)), sigma);