In my app I do an xmlparser but I have a problem during parser because in a tag I have a special letter "รจ" and it read it as "\U00e8"; and it close a tag of my xml...and I have an error in my parsing...
I set my path in utf-8 in this way
NSString *path = #"emaple.com";
NSError *error;
NSURL *url = [NSURL URLWithString:path];
NSString * dataString = [[NSString alloc] initWithContentsOfURL:url encoding:NSUTF8StringEncoding error:&error];
NSData *data = [dataString dataUsingEncoding:NSUTF8StringEncoding];
affayfeed = [[NSMutableArray alloc]init];
parser = [[NSXMLParser alloc] initWithData:data];
but I have the same problem...why?
Related
I have a URL like so ANC & SHO.pdf
when I encode the URL like so:
NSString *escapedString = [PDFPath stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLHostAllowedCharacterSet]];
now when I use this URL it does not work and I have a feeling it has to do with the & because when I tried another file, it worked perfectly I was able to load the PDF, but with the file with & I was not.
What Am I doing wrong?
Here is the output of escapedString
escapedString __NSCFString * #"Ancaster%5CANC%20&%20SHO%20-%20Laundry%20Closets%20to%20be%20Checked.pdf" 0x16ea33c0
I then use that to call a method:
NSArray *byteArray = [dataSource.areaData GetPDFFileData:[NSString stringWithFormat:#"%#",escapedString]];
Here is the method:
-(NSArray *)GetPDFFileData:(NSString *)PDFFile
{
NSString *FileBrowserRequestString = [NSString stringWithFormat:#"%#?PDFFile=%#",kIP,PDFFile];
NSURL *JSONURL = [NSURL URLWithString:FileBrowserRequestString];
NSURLResponse* response = nil;
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:JSONURL];
NSData* data = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:nil];
if(data == nil)
return nil;
NSError *myError;
NSArray *tableArray = [[NSArray alloc]initWithArray:[NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&myError]];
return tableArray;
}
[NSCharacterSet URLHostAllowedCharacterSet] contains characters below:
!$&'()*+,-.0123456789:;=ABCDEFGHIJKLMNOPQRSTUVWXYZ[]_abcdefghijklmnopqrstuvwxyz~
which contains '&', so
NSString *escapedString = [PDFPath stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLHostAllowedCharacterSet]];
won't escape '&' for you, then it's not URLEncoded.
see the question about how to url encode a string.
I have this action here:
- (IBAction)searchButton:(id)sender {
NSString *textString = self.symbolSearchField.text;
NSURL *sourceURL = [[NSURL alloc] initWithString: [NSString stringWithFormat:#"http://query.yahooapis.com/v1/public/yql?q=select%%20*%%20from%%20yahoo.finance.quotes%%20where%%20symbol%%20in%%20%%28%%22%#%%22%%29&env=store://datatables.org/alltableswithkeys", textString]];
NSXMLParser *parser = [[NSXMLParser alloc] initWithContentsOfURL:sourceURL];
parser.delegate = self;
[parser parse];
I want it to take the text from the search field, modify the URL with that text, and parse the XML from the URL. However, when I escape the *s and %s, it appears the URL becomes "broken", and it doesn't parse. If I leave the URL as it was without escaping...
NSURL *sourceURL = [[NSURL alloc] initWithString: [NSString stringWithFormat:#"http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20yahoo.finance.quotes%20where%20symbol%20in%20%28%22%#%22%29&env=store://datatables.org/alltableswithkeys", textString]];
... then I get an "Invalid conversion specifier '*'" and a "More '%' conversions than data arguments" warning.
So my question is, how can I escape the symbols without breaking the URL?
Edit
For clarity, here is the code I have at the moment after making some adjustments.
NSString *textString = self.symbolSearchField.text;
NSString *query = [NSString stringWithFormat:#"select * from yahoo.finance.quotes where symbol in (\"%#\")", textString];
NSString *escapedStoreURL = [#"store://datatables.org/alltableswithkeys" stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLHostAllowedCharacterSet]];
NSString *escapedQuery = [query stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLHostAllowedCharacterSet]];
NSString *URLString = [NSString stringWithFormat:#"http://query.yahooapis.com/v1/public/yql?q=%#&env=%#", escapedQuery, escapedStoreURL];
NSURL *sourceURL = [NSURL URLWithString:URLString];
NSXMLParser *parser = [[NSXMLParser alloc] initWithContentsOfURL:sourceURL];
parser.delegate = self;
[parser parse];
Try this:
NSString *firstPart = #"http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20yahoo.finance.quotes%20where%20symbol%20in%20%28%22";
NSString *lastPart = #"%22%29&env=store://datatables.org/alltableswithkeys";
NSURL *sourceURL = [[NSURL alloc] initWithString: [NSString stringWithFormat:#"%#%#%#", firstPart, textString, lastPart]];
Edit
You may also want to consider escaping that query programmatically instead of having all that escaping in there beforehand. The store URL also needs to be URL encoded.
NSString *query = [NSString stringWithFormat:#"select * from yahoo.finance.quotes where symbol in (\"%#\")", textString];
NSString *escapedStoreUrl = [#"store://datatables.org/alltableswithkeys" stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLHostAllowedCharacterSet]];
NSString *escapedQuery = [query stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLHostAllowedCharacterSet]];
NSString *urlString = [NSString stringWithFormat:#"http://query.yahooapis.com/v1/public/yql?q=%#&env=%#", escapedQuery, escapedStoreUrl];
Edit 2
So I got back and was looking at this problem again, and it turns out there were some invisible characters between the u and the o in yahoo.finance.quotes and the two Ls of alltableswithkeys (Specifically, two of U+200c). Removing these should fix your issue. Turns out this was caused by StackOverflow.
Why don't you just use a NSMutableString, and append the strings step-by-step?
NSString *textString = #"AAPL";
NSMutableString *query = [[NSMutableString alloc] init];
NSString *startString = #"http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20yahoo.finance.quotes%20where%20symbol%20in%20%28%22";
NSString *endString = #"%22%29&env=store://datatables.org/alltableswithkeys";
[query appendString:startString];
[query appendFormat:#"%#",textString];
[query appendString:endString];
NSURL *sourceURL = [[NSURL alloc] initWithString:query];
Now, the variable sourceURL is your URL with the symbols "escaped".
I am trying to request a URL and I am getting error saying
"Data parameter is nil".
I had found that the variables used has got space dot(.). I think this is the problem that is being caused by the URL. So is there any way to send URL having space and dot without crashing?
NSURL *url = [[NSURL alloc]initWithString:[NSString stringWithFormat:#"192.168.1.5/mobileapp?/signin=%#&%#",username,password]];
NSError *errors;
NSData *data = [NSData dataWithContentsOfURL:url];
NSDictionary *json = (NSDictionary *)[NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&errors];
Try using NSUTF8StringEncoding
NSString *myUnencodedString = [NSString stringWithFormat:#"192.168.1.5/mobileapp?/signin=%#&%#",username,password]
NSString *encodedString = [myUnencodedString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *myURL = [[NSURL alloc] initWithString:encodedString]
I am trying to request the following URL and i am getting an error saying "Data parameter is nil". i had found that the 'seller_name' has got space and 'amount' has got dot(.). I think this is the problem that is being caused by the URL. So is there any way to send URL having space and dot without loosing the information?
NSURL *url1 = [[NSURL alloc]initWithString:[NSString stringWithFormat:#"192.168.1.85/localex_postsale.html?contactid=%#&exchangeid=%#&token=%#&buyerid=%#&seller_name=%#&desc=%#&amount=%#&sellerid=%#",contactid,exchangeid,token,buyervalue,sellers,_Description,_Amount,contactid]];
NSError *errors1;
NSData *data1 = [NSData dataWithContentsOfURL:url1];
NSDictionary *json1 = (NSDictionary *)[NSJSONSerialization JSONObjectWithData:data1 options:kNilOptions error:&errors1];
Take a look at the -stringByAddingPercentEscapesUsingEncoding: method in NSString, e.g.:
NSString *myUnencodedString = [NSString stringWithFormat:#"192.168.1.85/localex_postsale.html?contactid=%#&exchangeid=%#&token=%#&buyerid=%#&seller_name=%#&desc=%#&amount=%#&sellerid=%#",contactid,exchangeid,token,buyervalue,sellers,_Description,_Amount,contactid]
NSString *encodedString = [myUnencodedString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *myURL = [[NSURL alloc] initWithString:encodedString]
...
Cf.: Apple documentation.
It is happening because URL should not contain white space. It should be encode to %20 if there is any space. We can encode space and special character in NSString using NSUTF8StringEncoding as below
NSString *string = [[NSString stringWithFormat:#"192.168.1.85/localex_postsale.html?contactid=%#&exchangeid=%#&token=%#&buyerid=%#&seller_name=%#&desc=%#&amount=%#&sellerid=%#",contactid,exchangeid,token,buyervalue,sellers,_Description,_Amount,contactid]stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *url1 = [[NSURL alloc]initWithString:string];
NSError *errors1;
NSData *data1 = [NSData dataWithContentsOfURL:url1];
NSDictionary *json1 = (NSDictionary *)[NSJSONSerialization JSONObjectWithData:data1 options:kNilOptions error:&errors1];
I get the data from an XML file and I am storing it in NSData object. I want to convert that NSData into an NSDictionary and store that data in a plist.
My code is as follows:
NSURL *url = [NSURL URLWithString:#"http://www.fubar.com/sample.xml"];
NSData *data = [NSData dataWithContentsOfURL:url];
NSLog(#"%#", data);
To convert the data, I am using:
- (NSDictionary *)downloadPlist:(NSString *)url {
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:url] cachePolicy:NSURLRequestReloadIgnoringLocalCacheData timeoutInterval:10];
NSURLResponse *resp = nil;
NSError *err = nil;
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&resp error:&err];
if (!err) {
NSString *errorDescription = nil;
NSPropertyListFormat format;
NSDictionary *samplePlist = [NSPropertyListSerialization propertyListFromData:responseData mutabilityOption:NSPropertyListImmutable format:&format errorDescription:&errorDescription];
if (!errorDescription)
return samplePlist;
[errorDescription release];
}
return nil;
}
Can anyone please tell me how to do that?
or this:
NSString* dataStr = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
SBJSON *jsonParser = [SBJSON new];
NSDictionary* result = (NSDictionary*)[jsonParser objectWithString:dataStr error:nil];
[jsonParser release];
[dataStr release];
Try this code:
NSString *newStr1 = [[NSString alloc] initWithData:theData1 encoding:NSUTF8StringEncoding];
NSString *newStr2 = [[NSString alloc] initWithData:theData2 encoding:NSUTF8StringEncoding];
NSString *newStr3 = [[NSString alloc] initWithData:theData3 encoding:NSUTF8StringEncoding];
NSArray *keys = [NSArray arrayWithObjects:#"key1", #"key2", #"key3", nil];
NSArray *objects = [NSArray arrayWithObjects:newStr1 , newStr2 , newStr3 , nil];
NSDictionary *dictionary = [NSDictionary dictionaryWithObjects:objects forKeys:keys];
for (id key in dictionary) {
NSLog(#"key: %#, value: %#", key, [dictionary objectForKey:key]);
}
NSString *path = [[NSBundle mainBundle] pathForResource:#"Login" ofType:#"plist"];
[dictionary writeToFile:path atomically:YES];
//here Login is the plist name.
Happy coding