I am new to ASP.NET and web development of any kind. I have searched for many hours for a solution to my problem, but I can't seem to get my partial view to show up in the div.
What is happening is the view is showing up, but it's replacing the entire page instead of showing up in the div within the main page.
My controller looks something like this:
public class MyController
{
public ActionResult ShowView(int id)
{
// get view model from id
return PartialView(viewModel);
}
}
My Main View looks something like this
#model List<viewModelType>
<div>
#foreach (var item in Model)
{
<div>
#Html.ActionLink(item.Name, "ShowView", new { id = item.ID }, new { #class = "btn-sm" })
</div>
}
</div>
<div>
// here is where I want to partial view to go!
</div>
This is what the partial view looks like:
#model viewModelType
<div>Model.DataToDisplay</div>
Would this work for you?
[ChildActionOnly]
public class MyController
{
public ActionResult ShowView(int id)
{
// get view model from id
return PartialView(viewModel);
}
}
And in your view:
<div>
// here is where I want to partial view to go!
#Html.Action("ShowView")
</div>
Okay I figured it out with Christos' help.
The main view should look like this:
#model List<viewModelType>
<div>
#foreach (var item in Model)
{
<div>
<button class="js-showViewBtn" data-itemId=#item.ID>item.Name</button>
</div>
}
</div>
<div class="js-show-view">
// here is where I want to partial view to go!
</div>
<script type="text/javascript">
$(function () {
$('.js-showViewBtn').click(function (e) {
e.preventDefault();
var itemId = $(this).data("itemId");
$.ajax({
method: "GET",
url: "/MyController/ShowView",
data: { id: itemId },
cache: false
}).success(function(data){
$('.js-show-view').html(data);
});
})
});
</script>
For some reason the id of the item was not being returned, so I tried it like this and it worked. Hope this helps others too.
Thanks for your help Christos.
You need a bit of JavaScript to do that you want. Basically, you have to wire up a click event handler for your links and when the user click on one of them an ajax request would be triggered.
#model List<viewModelType>
<div>
#foreach (var item in Model)
{
<div>
#Html.ActionLink(item.Name, "ShowView", new { id = item.ID }, new { #class = "btn-sm js-show-view-btn" })
</div>
}
</div>
<div class="js-show-view">
// here is where I want to partial view to go!
</div>
<!-- Before the following script been loaded, he jQuery should have been loaded -->
<script>
$(function(){
$(".js-show-view-btn").click(function(e){
e.preventDefault();
$.ajax({
method: "GET",
url: "/MyController/ShowView",
data: { id = $(e).id },
cache: false
}).success(function(data)
{
$(".js-show-view").html(data);
});
})
});
</script>
I have a sort of Master-Detail Edit form and I'm trying to follow this post: Using Ajax... to get the partial view to postback.
My Edit form has a partial view that has a list of sub items, and another partial create view in it to add new items. I'd like the partial create view to post back and update the list without refreshing the whole page if possible.
Here's what I have so far:
MyController.cs -
public ActionResult Edit(int? id)
{
//...
ViewBag.CustomFormId = id;
using (var _db = new MkpContext())
{
//...
return View(profileEdit);
}
}
[HttpPost]
[ValidateAntiForgeryToken]
public ActionResult Edit(CustomForm editForm)
{
//...
if (!ModelState.IsValid) return View(editForm);
using (var _db = new MkpContext())
{
var form = _db.CustomForms.Find(editForm.CustomFormId);
//...
_db.Entry(form).State = EntityState.Modified;
_db.SaveChanges(User.ProfileId);
return RedirectToAction("Index");
}
}
public ActionResult _CustomFieldList(int id)
{
ViewBag.CustomFormId = id;
using (var _db = new MkpContext())
{
var formCustomFields = (from cf in _db.CustomFields
where cf.CustomFormId == id
select cf);
return PartialView(formCustomFields.ToList());
}
}
// Nested in _CustomFieldList
public ActionResult _CustomFieldCreate(int id)
{
var newField = new CustomField
{
CustomFormId = id
};
return PartialView(newField);
}
[HttpPost]
[ValidateAntiForgeryToken]
public ActionResult _CustomFieldCreate(CustomField addField)
{
ViewBag.CustomFormId = addField.CustomFormId;
if (ModelState.IsValid)
{
using (var _db = new MkpContext())
{
_db.CustomFields.Add(addField);
_db.SaveChanges();
}
var newField = new CustomField
{
CustomFormId = addField.CustomFormId
};
return PartialView(newField); // Probably need to change this somehow
}
return PartialView(addField);
}
And the views:
Edit.cshtml -
#model PublicationSystem.Model.CustomForm
#{
ViewBag.Title = "Edit Custom Form";
Layout = "~/Views/Shared/_LayoutSmBanner.cshtml";
}
<div class="form-horizontal">
<div class="row">
#using (Html.BeginForm())
{
#Html.AntiForgeryToken()
#* Fields for this form *#
}
<div id="CustomFields" class="col-md-6">
#Html.Action("_CustomFieldCreate", new { id = ViewBag.CustomFormId })
</div>
</div>
</div>
<script>
$(function () {
$("#createFieldForm").on("submit", function (e) {
e.preventDefault(); //This prevent the regular form submit
$.ajax({
url: this.action,
type: this.method,
data: $(this).serialize(),
success: function (result) {
$("#CustomFields").html(result);
}
});
return false;
});
});
</script>
_CustomFieldCreate.cshtml -
#model PublicationSystem.Model.CustomField
#using (Html.BeginForm())
{
#Html.AntiForgeryToken()
<div id="result"></div>
<div class="form-horizontal">
<h4>CustomField</h4>
<hr />
#Html.ValidationSummary(true, "", new { #class = "text-danger" })
#Html.HiddenFor(model =>model.CustomFormId)
<div class="row">
#* Fields for the form *#
</div>
<div class="form-group">
<div class="col-md-offset-2 col-md-10">
<input type="submit" value="Create" class="btn btn-default" />
</div>
</div>
</div>
}
<div id="customFieldList">
#Html.Action("_CustomFieldList", new { id = ViewBag.CustomFormId })
</div>
_CustomFieldList.cshtml
#model System.Collections.Generic.IEnumerable<PublicationSystem.Model.CustomField>
<table class="table">
#* List table code *#
</table>
Edit: I rewrote the pages so that the list is part of the create partial view. What happens now is, if you enter data for _CustomFieldCreate and press submit, the first time, it refreshes just that view (including the nested list view). However the second time, it redirects to the view, probably because the first refresh didn't rebind the javascript to the submit button. Also, the Create view doesn't clear out the fields, but persists the originally entered data.
You will need a form in your partial view whose submit action binds to a javascript function that posts to your controller.
For example if your form id is MyForm:
$('#MyForm').on('submit', function (e) {
e.preventDefault(); //This prevent the regular form submit
$.ajax({
url: $(this).action, // This will submit the post to whatever action your form goes to
type: "POST", // This tells it that it is a post
data: $(this).serialize(), // This sends the data in the form to the controller
success: function (data) {
// do some javascript on success
},
error: function (xhr, ajaxOptions, thrownError) {
// do some javascript on error
}
});
});
This javascript overrides the default form submit and does an ajax post to your controller and then returns with success or error where you can do anything you want.
Here is some jquery ajax documentation:
http://api.jquery.com/jquery.ajax/
You should look into using AJAX. That should accomplish what I think you are describing. You'll want to create a javascript function that handles the submit event on the form, then post the form data to some create action in your MVC app using AJAX. If you are using jQuery, the library makes it pretty simple.
http://api.jquery.com/jquery.ajax/
I have a form in a view (Edit view), and a partial view inside that form on the Edit view. The partial view has its own form which performs a lookup. The lookup in the partial view is successfully returning the results to the Edit view. However, the POST from the partial view is then hitting the controller a second time (trying to submit the form in the Edit view). How do I stop the POST from hitting the controller a second time?
Here is where the partial view is called in the Edit view:
<div class="form-group" id="search-pac">
#Html.Action("PacSearch", "ItemRequest");
</div>
<div class="form-group" id="search-pac-results">
</div>
Here is where the controller gets the partial view:
[HttpGet]
public ActionResult PacSearch()
{
return PartialView("_PacSearchFormPartial");
}
Here is the form in the partial view:
#using (Ajax.BeginForm("PacSearch", "ItemRequest", FormMethod.Post,
new AjaxOptions
{
InsertionMode = InsertionMode.Replace,
HttpMethod = "POST",
UpdateTargetId = "search-pac-results"
}))
{
<div>
#Html.TextBox("pacupc")
<input type="submit" value="Find PAC" />
</div>
}
Which then hits the controller here:
[HttpPost]
public ActionResult PacSearch(string pacupc)
{
//do lookup stuff, and call a partial view to display the results
}
Once the results are displayed on the Edit view, POST then hits the controller here (which I don't want unless the submit button in the Edit view is clicked):
[HttpPost]
public ActionResult Edit(ItemRequest itemRequest, HttpPostedFileBase upcImage, Comment comment, String FinalApproval)
{
//handle form submission from Edit View
}
How do I keep the POST from the partial view from hitting the HttpPost for Edit view in the controller?
UPDATE:
Upon the suggestion to use a direct AJAX call, I ditched the partial views and changed my Edit view to:
<div class="form-group" id="search-pac">
#Html.TextBox("pacupc")
<input type="button" id="btn-pacupc" value="Find PAC" />
#* #Html.Action("PacSearch", "ItemRequest");*#
</div>
<div class="form-group" id="search-pac-results">
</div>
And AJAX call:
<script type="text/javascript">
$(document).ready(function () {
$(document).on('click', '#btn-pacupc', function () {
var pacupc = $("#pacupc").val();
$.ajax({
type: "POST",
url: "#Url.Action("PacSearch")",
data: { pacupc: pacupc },
success: function (result) { $('#search-pac-results').html(result); }
});
});
});
</script>
There's no support for forms within forms in HTML. A submission inside the innermost form will also submit any parent form. The solution then, is to not rely on Ajax.BeginForm, which will print a form element to the page, and instead, wire your AJAX manually. This is a prime example of why I encourage everyone to not use the Ajax family of helpers. They simply do too much, hidden to the developer, and often lead to confusion when things don't work as expected, which happens far more often than not.
have a simple search form with a textbox. And upon submitting the form I send the contents of the textbox to a stored procedure which returns to me the results. I want the results to be displayed on the same page the form was, except just below it.
Right now I'm doing the following but it's not working out exactly the way I want:
sathishkumar,
You don't tag the question as being an ajax related solution or not. I'm going to present a simple ajax approach which may or may not be suitable.
in the controller:
public ActionResult Search(string searchTerm)
{
// you don't add code re your stored proc, so here is a repo based approach
var searchItems = _repository.Find(x => x.searchfield.Contains(searchTerm));
return PartialView("SearchPartial", searchItems);
}
main view (index.aspx or whatever) (below where your main content is defined, add):
<div id="searchResults"></div>
in another part of the page (semi psuedo-code):
<script type="text/javascript">
function getSearchResults() {
// #yoursearchbox is a textbox on the index.aspx aview
var tdata = { searchTerm: $('#yoursearchbox').val()};
// or your data in the format that will be used ??
$.ajax({
type: "GET",
data: tdata,
url : '<%= Url.Action("Search", "Home") %>',
success: function (result) { success(result); }
});
});
function success(result){
$("#searchResults").html(result);
}
</script>
You'd then add a partial view SearchPartial.ascx that contained your model for the search results.
Hope this helps.
You can use Ajax to solve the problem.
<div>
`#using (Ajax.BeginForm("action", "controller", new AjaxOptions
{
UpdateTargetId = "results",
HttpMethod = "GET",
}))
{
#Html.TextBox()
<input type="submit" value="Search" />
}`
<div id="results"></div>
</div>
Can anyone tell me how can I submit values to Controller using ActionLink and POST method?
I don't want to use buttons.
I guess it has something with jquery.
If you're using ASP MVC3 you could use an Ajax.ActionLink(), that allows you to specify a HTTP Method which you could set to "POST".
You can't use an ActionLink because that just renders an anchor <a> tag.
You can use a jQuery AJAX post.
Or just call the form's submit method with or without jQuery (which would be non-AJAX), perhaps in the onclick event of whatever control takes your fancy.
You can use jQuery to do a POST for all your buttons. Just give them the same CssClass name.
Use "return false;" at the end of your onclick javascript event if you want to do a server side RedirectToAction after the post otherwise just return the view.
Razor Code
#using (Html.BeginForm())
{
#Html.HiddenFor(model => model.ID)
#Html.ActionLink("Save", "SaveAction", "MainController", null, new { #class = "saveButton", onclick = "return false;" })
}
JQuery Code
$(document).ready(function () {
$('.saveButton').click(function () {
$(this).closest('form')[0].submit();
});
});
C#
[AcceptVerbs(HttpVerbs.Post)]
public ActionResult SaveAction(SaveViewModel model)
{
// Save code here...
return RedirectToAction("Index");
//return View(model);
}
#Aidos had the right answer just wanted to make it clear since it is hidden inside a comment on his post made by #CodingWithSpike.
#Ajax.ActionLink("Delete", "Delete", new { id = item.ApkModelId }, new AjaxOptions { HttpMethod = "POST" })
Here was an answer baked into the default ASP.NET MVC 5 project I believe that accomplishes my styling goals nicely in the UI. Form submit using pure javascript to some containing form.
#using (Html.BeginForm("Logout", "Account", FormMethod.Post, new { id = "logoutForm", #class = "navbar-right" }))
{
<a href="javascript:document.getElementById('logoutForm').submit()">
<span>Sign out</span>
</a>
}
The fully shown use case is a logout dropdown in the navigation bar of a web app.
#using (Html.BeginForm("Logout", "Account", FormMethod.Post, new { id = "logoutForm", #class = "navbar-right" }))
{
#Html.AntiForgeryToken()
<div class="dropdown">
<button type="button" class="btn btn-default dropdown-toggle" data-toggle="dropdown">
<span class="ma-nav-text ma-account-name">#User.Identity.Name</span>
<i class="material-icons md-36 text-inverse">person</i>
</button>
<ul class="dropdown-menu dropdown-menu-right ma-dropdown-tray">
<li>
<a href="javascript:document.getElementById('logoutForm').submit()">
<i class="material-icons">system_update_alt</i>
<span>Sign out</span>
</a>
</li>
</ul>
</div>
}
ActionLink will never fire post. It always trigger GET request.
Use the following the Call the Action Link:
<%= Html.ActionLink("Click Here" , "ActionName","ContorllerName" )%>
For submitting the form values use:
<% using (Html.BeginForm("CustomerSearchResults", "Customer"))
{ %>
<input type="text" id="Name" />
<input type="submit" class="dASButton" value="Submit" />
<% } %>
It will submit the Data to Customer Controller and CustomerSearchResults Action.
This is taken from the MVC sample project
#if (ViewBag.ShowRemoveButton)
{
using (Html.BeginForm("RemoveLogin", "Manage"))
{
#Html.AntiForgeryToken()
<div>
#Html.Hidden("company_name", account)
#Html.Hidden("returnUrl", Model.returnUrl)
<input type="submit" class="btn btn-default" value="Remove" title="Remove your email address from #account" />
</div>
}
}
Use this link inside Ajax.BeginForm
#Html.ActionLink(
"Save",
"SaveAction",
null,
null,
onclick = "$(this).parents('form').attr('action', $(this).attr('href'));$(this).parents('form').submit();return false;" })
;)
My Solution to this issue is a fairly simple one. I have a page that does a customer search one by the whole email and the other by a partial, the partial pulls and displays a list the list has an action link that points to a actionresult called GetByID and passes in the id
the GetByID pulls the data for the selected customer then returns
return View("Index", model);
which is the post method
This has been a difficult problem for me to solve. How can I build a dynamic link in razor and html that can call an action method and pass a value or values to a specific action method? I considered several options including a custom html helper. I just came up with a simple and elegant solution.
The view
#model IEnumerable<MyMvcApp.Models.Product>
#using (Html.BeginForm()) {
<table>
<thead>
<tr>
<td>Name</td>
<td>Price</td>
<td>Quantity</td>
</tr>
</thead>
#foreach (Product p in Model.Products)
{
<tr>
<td>#p.Name</td>
<td>#p.Price.ToString()</td>
<td>#p.Quantity.ToString()</td>
</tr>
}
</table>
}
The action method
public ViewResult Edit(Product prod)
{
ContextDB contextDB = new ContextDB();
Product product = contextDB.Products.Single(p => p.ProductID == prod.ProductId);
product = prod;
contextDB.SaveChanges();
return View("Edit");
}
The point here is that Url.Action does not care whether the action method is a GET or a POST. It will access either type of method. You can pass your data to the action method using
#Url.Action(string actionName, string controllerName, object routeValues)
the routeValues object. I have tried this and it works. No, you are not technically doing a post or submitting the form but if the routeValues object contains your data, it doesnt matter if its a post or a get. You can use a particular action method signature to select the right method.
I have done the same issue using following code:
#using (Html.BeginForm("Delete", "Admin"))
{
#Html.Hidden("ProductID", item.ProductID)
<input type="submit" value="Delete" />
}
This is my solution for the problem.
This is controller with 2 action methods
public class FeedbackController : Controller
{
public ActionResult Index()
{
var feedbacks =dataFromSomeSource.getData;
return View(feedbacks);
}
[System.Web.Mvc.HttpDelete]
[System.Web.Mvc.Authorize(Roles = "admin")]
public ActionResult Delete([FromBody]int id)
{
return RedirectToAction("Index");
}
}
In View I render construct following structure.
<html>
..
<script src="~/Scripts/bootbox.min.js"></script>
<script>
function confirmDelete(id) {
bootbox.confirm('#Resources.Resource.AreYouSure', function(result) {
if (result) {
document.getElementById('idField').value = id;
document.getElementById('myForm').submit();
}
}.bind(this));
}
</script>
#using (Html.BeginForm("Delete", "Feedback", FormMethod.Post, new { id = "myForm" }))
{
#Html.HttpMethodOverride(HttpVerbs.Delete)
#Html.Hidden("id",null,new{id="idField"})
foreach (var feedback in #Model)
{
if (User.Identity.IsAuthenticated && User.IsInRole("admin"))
{
#Html.ActionLink("Delete Item", "", new { id = #feedback.Id }, new { onClick = "confirmDelete("+feedback.Id+");return false;" })
}
}
...
</html>
Point of interest in Razor View:
JavaScript function confirmDelete(id) which is called when the link generated with #Html.ActionLink is clicked;
confirmDelete() function required id of item being clicked. This item is passed from onClick handler confirmDelete("+feedback.Id+");return false; Pay attention handler returns false to prevent default action - which is get request to target. OnClick event for buttons could be attached with jQuery for all buttons in the list as alternative (probably it will be even better, as it will be less text in the HTML page and data could be passed via data- attribute).
Form has id=myForm, in order to find it in confirmDelete().
Form includes #Html.HttpMethodOverride(HttpVerbs.Delete) in order to use the HttpDelete verb, as action marked with the HttpDeleteAttribute.
In the JS function I do use action confirmation (with help of external plugin, but standard confirm works fine too. Don't forget to use bind() in call back or var that=this (whatever you prefer).
Form has a hidden element with id='idField' and name='id'. So before the form is submitted after confirmation (result==true), the value of the hidden element is set to value passed argument and browser will submit data to controller like this:
Request URL:http://localhost:38874/Feedback/Delete
Request Method:POST Status Code:302 Found
Response Headers
Location:/Feedback
Host:localhost:38874
Form Data X-HTTP-Method-Override:DELETE id:5
As you see it is POST request with X-HTTP-Method-Override:DELETE and data in body set to "id:5". Response has 302 code which redirect to Index action, by this you refresh your screen after delete.
I would recommend staying pure to REST principles and using an HTTP delete for your deletes. Unfortunately HTML Specs only has HTTP Get & Post. A tag only can a HTTP Get. A form tag can either do a HTTP Get or Post. Fortunately if you use ajax you can do a HTTP Delete and this is what i recommend. See the following post for details: Http Deletes
Calling $.post() won't work as it is Ajax based. So a hybrid method needs to be used for this purpose.
Following is the solution which is working for me.
Steps:
1. Create URL for href which calls the a method with url and parameter
2. Call normal POST using JavaScript method
Solution:
In .cshtml:
View
Note: the anonymous method should be wrapped in (....)()
i.e.
(function() {
//code...
})();
postGo is defined as below in JavaScript.
Rest are simple..
#Url.Action("View") creates url for the call
{ 'id': #receipt.ReceiptId } creates parameters as object which is in-turn converted to POST fields in postGo method. This can be any parameter as you require
In JavaScript:
(function ($) {
$.extend({
getGo: function (url, params) {
document.location = url + '?' + $.param(params);
},
postGo: function (url, params) {
var $form = $("<form>")
.attr("method", "post")
.attr("action", url);
$.each(params, function (name, value) {
$("<input type='hidden'>")
.attr("name", name)
.attr("value", value)
.appendTo($form);
});
$form.appendTo("body");
$form.submit();
}
});
})(jQuery);
Reference URLs which I have used for postGo
Non-ajax GET/POST using jQuery (plugin?)
http://nuonical.com/jquery-postgo-plugin/
jQuery.post() will work if you have custom data. If you want to post existing form, it's easier to use ajaxSubmit().
And you don't have to setup this code in the ActionLink itself, since you can attach link handler in the document.ready() event (which is a preferred method anyway), for example using $(function(){ ... }) jQuery trick.
Came across this needing to POST from a Search (Index) page to the Result page. I did not need as much as #Vitaliy stated but it pointed me in the right direction. All I had to do was this:
#using (Html.BeginForm("Result", "Search", FormMethod.Post)) {
<div class="row">
<div class="col-md-4">
<div class="field">Search Term:</div>
<input id="k" name="k" type="text" placeholder="Search" />
</div>
</div>
<br />
<div class="row">
<div class="col-md-12">
<button type="submit" class="btn btn-default">Search</button>
</div>
</div>
}
My Controller had the following signature method:
[HttpPost]
public async Task<ActionResult> Result(string k)