Is it possible to format the output of NOW() to a string that displays YYYY-MM-DD?
This is the output of NOW(): 29/02/2012 12.07.37
The reason is, that I need to use the current date in a QUERY.
QUERY only accepts date in the format YYYY-MM-DD . I can't get a date directly from a cell, because it gets formatted as (even if I change the formatting): DD/MM/YYYY
Perhaps some regular expression?
If this is supposed to be an in-cell formula then you can use
=TEXT(NOW(),"yyyy-mm-dd")
I will follow JMax's suggestion and convert my comment to an answer.
Now() returns the current date and time as a number. The integer part gives the date and the fraction part gives the time. If you print or display that date, the default is to give the full date in what Microsoft think's is the local format.
Format(expn, fmt) allows you to convert an expression to a string. For example:
Dim DateStg as String
DateStg = Format(Now(),"yyyy-mm-dd")
fmt defines the format to which the expn is to be converted. fmt is a mixture of code letters (such as: "yyyy", "mm", "dd") and punctuation (such as "-"). "yyyy-mm-dd" appears to meet your current needs but you can also usethe following to format dates:
"mmm" to give three letter month (Jan, Feb, etc.)
"mmmm" to give full name of month (January, February, etc)
"ddd" to give three letter day of week (Mon, Tue, etc)
"dddd" to give full name of day of week (Monday, Tuesday, etc)
In VB.net you can do the following:
Dim dateStr As String = Now().ToString("yyyy-MM-dd")
In C# you can do it like this:
String dateStr = DateTime.Now.ToString("yyyy-MM-dd");
Related
I have a column, in which datetime in text format "2022-04-12 07:09:10 UTC". I want to change this into IST time zone and convert it into date format only
You'll need to extract the date and time then add on 5h30m. From there you can either wrap it with INT or format the column to show just the date. For the one below, I used INT, which will strip the time after it is converted.
=ARRAYFORMULA(
IF(ISBLANK(A2:A),,
REGEXREPLACE(A2:A,"UTC","")+
TIME(5,30,0)))
Unfortunately, the Google-Sheets sync extension saves the timestamp as a string. (Example: February 6, 2022 at 11:40 pm). Is there any way of automatically converting this automatically to an actual date? I tried the usual date conversion formulas but they dont work. Maybe a work-around?
if a timestamp is in cell A2, try this:
=1*SUBSTITUTE(A2,"at","")
This just gets rid of the word "at" and then multiplying by 1 forces an attempt to convert it into a date value. Then you can just do a regular Format>Number>Date and Time on that cell and it should show how you'd want.
Suppose that your string-dates are in A2:A.
Place the following formula into the Row-2 cell of any other open column (e.g., B2):
=IF(A2:A="",,DATEVALUE(REGEXEXTRACT(A2:A,"^(.+),\s"))+REGEXEXTRACT(A2:A,"\d+:.+$"))
I want to compare string representations of weeks, e.g. week "01/17" is before "02/17" and after "52/16".
The following code throws an exception, I guess because my string doesn't hint at the exact day of each week. However, I don't care - it could all be Mondays or Thursdays or whatever:
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("ww/YY", Locale.GERMANY);
LocalDate date1 = formatter.parse(str1, LocalDate::from);
Do I need to modify the parser? Or parse to some other format? Unfortunatley there is no object like YearMonth for weeks...
One solution would be to always default to the same day, say the Monday. You could build a custom formatter for that:
DateTimeFormatter fmt = new DateTimeFormatterBuilder()
.appendPattern("ww/YY")
.parseDefaulting(ChronoField.DAY_OF_WEEK, 1)
.toFormatter(Locale.GERMANY);
You can now build LocalDates representing the Monday of the given week:
LocalDate d1 = LocalDate.parse("01/17", fmt);
LocalDate d2 = LocalDate.parse("52/16", fmt);
System.out.println(d1.isAfter(d2));
which prints true because 01/17 is after 52/16.
I wasn't able to find a way for this to work with the DateTimeFormatter class, but I would like to suggest a different approach.
The Threeten Extra library contains a number of classes that were deemed too specific to include in the java.time library. One of them is the YearWeek class you mention.
Your problem can be solved by parsing the week-number and year manually from the input-string and then invoking the YearWeek creator-method like this:
YearWeek yw = YearWeek.of(year, monthOfYear);
tl;dr
YearWeek.parse( "2017-W01" )
ISO 8601
Or parse to some other format?
Yes, use another format.
Use the standard ISO 8601 formats when serializing date-time values to text. The standard includes support for week dates.
For a year-week that would be four year digits, a hyphen, a W, and two digits for the week of the year.
2017-W01
Get clear on your definition of a “week”. The ISO 8601 definition is that:
The Week # 1 contains the first Thursday of the year, and
Runs Monday-Sunday.
So years run either 52 or 53 weeks long. And note that under this definition, the first few days of the year may be in the prior year when week-numbering. Likewise, the last few days of the year may be in the following year when week-numbering.
If you want to indicate a particular day within that week, append a hyphen and a single digit running 1-7 for Monday-Sunday.
Tip: To see ISO 8601 week numbers by default on your computer, you may need to adjust your OS setting. For example, on macOS set System Preferences > Language & Region > Calendar > ISO 8601 to make apps such as Calendar.app to display week numbers with this standard definition.
2017-W01-7
By the way, a couple of similar representations:
An ordinal date meaning the year and the day-of-year-number running from 1-366 is year, a hyphen, and a three-digit number: 2017-123
Month-Day without year is two hyphens, month number, hyphen, and day-of-month number: --01-07
Note that the use of Locale as seen in the Question is irrelevant here with the standard ISO 8601 formats.
YearWeek
Unfortunatley there is no object like YearMonth for weeks...
Ahhh, but there is such a class.
For a class to directly represent the idea of a week-year, see the correct Answer by Henrik. That Answer shows the ThreeTen-Extra library’s class YearWeek.
The YearWeek class can directly parse and generate strings in standard format.
YearWeek yw = YearWeek.parse( "2017-W01" );
You can compare the YearWeek objects with methods: compareTo, equals, isBefore, isAfter.
yw.isBefore( thatYw )
The ThreeTen-Extra project offers other classes such as YearQuarter that you may find useful.
I am using the below query with date filtering, but I am getting wrong result.
SELECT * FROM TRANSACTIONSHISTORY
WHERE DATE > "29-01-2015 12:00:00"
AND DATE < "30-01-2015 00:00:00" AND USERID=abc
I am getting result with date column with value of 29-Jan-2016 records, what am I missing here, can any one help me to get out of this value.
The date format in your SQL will not work because SQLite doesn't have a native datetime type, so it's generally stored either as a string, in YYYY-MM-DD HH:MM:SS.SSS format, or as an numeric value representing the number of seconds since 1970-01-01 00:00:00 UTC. See date and time types on SQLite.org. Note that if you're using the string representation that the sequence is year, month, day (which, when sorting/querying this string field, the this alphanumeric string will sort correctly by year first, then month, and then day, which is critical when doing queries like yours).
If you really stored dates in the database as a string in the DD-MM-YYYY HH:MM:SS format, you should consider changing the format in which you saved the values into one of the approved date formats. It will make the date interactions with the database much, much easier, allowing queries like the one you asked for (though, obviously, with DD-MM-YYYY replaced with YYYY-MM-DD format).
You have cast your string to Date
SELECT * FROM TRANSACTIONSHISTORY WHERE DATE between Datetime('29-01-2015 12:00:00') and Datetime('30-01-2015 00:00:00') AND USERID=abc
The first answer is exactly what you need. What you did in your code would be comparing strings using ASCII values.
I would recommend you to use the linux time stamps like: 1453818208, which is easier to save and compare. In addition, it can always be translated to human-readable dates like: 29-01-2015 12:00:00.
SELECT * FROM TRANSACTIONSHISTORY
WHERE DATE > "29-01-2015 12:00:00"
AND DATE < "30-01-2015 00:00:00" AND USERID=abc
I hope this helps you :)
Try this first try without Time,after that try date and time both , Hope i will work for you
SELECT TRANSACTIONSHISTORY
FROM SHIPMENT
WHERE DATE
BETWEEN '11-15-2010'
AND '30-01-2015'
// you can try this one also
SELECT * FROM TRANSACTIONSHISTORY WHERE DATE BETWEEN "2011-01-11" AND "2011-8-11"
I have the date variable which is in string format. I need to convert this to numeric or date format. How can I do this?
Example:
var1
2010/07/09
2010/07/16
Thanks,
Tanuvi
If you read in the date value as a string, you can use Transform > Date and Time Wizard to convert it to an SPSS date variable. Although date variables look like dates in various formats, they are actually represented as the number of seconds since 1582 and can consist of calendar and time information.