Rails searching with multiple conditions (if values are not empty) - ruby-on-rails

Let's say I have a model Book with a field word_count, amongst potentially many other similar fields.
What is a good way for me to string together conditions in an "advanced search" of the database? In the above example, I'd have a search form with boxes for "word count between ___ and ___". If a user fills in the first box, then I want to return all books with word count greater than that value; likewise, if the user fills in the second box, then I want to return all books with word count less than that value. If both values are filled in, then I want to return word counts within that range.
Obviously if I do
Book.where(:word_count => <first value>..<second value>)
then this will break if only one of the fields was filled in. Is there any way to handle this problem elegantly? Keep in mind that there may be many similar search conditions, so I don't want to build separate queries for every possible combination.
Sorry if this question has been asked before, but searching the site hasn't yielded any useful results yet.

How about something like:
#books = Book
#books = #books.where("word_count >= ?", values[0]) if values[0].present?
#books = #books.where("word_count <= ?", values[1]) if values[1].present?
ActiveRecord will chain the where clauses
The only problem is that if values[0] && values[1] the query would not return anything if values[0] was greater than values[1].

For our advanced searching we create a filter object which encapsulates the activerecord queries into simple methods. It was originally based on this Thoughtbot post
A book filter could look something like this:
class BookFilter
def initialize
#relation = Book.scoped
end
def restrict(r)
minimum_word_count!(r[:first]) if r[:first].present?
maximum_word_count!(r[:second]) if r[:second].present?
recent! if r.try(:[], :recent) == '1'
#relation
end
protected
def recent!
where('created_at > ? ', 1.week.ago)
end
def minimum_word_count!(count)
where('word_count >= ? ', count)
end
def maximum_word_count!(count)
where('word_count <= ?', count)
end
def where(*a)
#relation = #relation.where(*a)
end
end
#to use
books = BookFilter.new.restrict(params)

Take a look at the ransack gem, which is the successor to the meta_search gem, which still seems to have the better documentation.
If you do want to roll your own, there's nothing preventing you from chaining clauses using the same attribute:
scope = Book
scope = scope.where("word_count >= ?", params[:first]) if params[:first]
scope = scope.where("word_count <= ?", params[:last]) if params[:last]
But it's really not necessary to roll your own search, there are plenty of ready solutions available as in the gems above.

Related

Rails best way to get previous and next active record object

I need to get the previous and next active record objects with Rails. I did it, but don't know if it's the right way to do that.
What I've got:
Controller:
#product = Product.friendly.find(params[:id])
order_list = Product.select(:id).all.map(&:id)
current_position = order_list.index(#product.id)
#previous_product = #collection.products.find(order_list[current_position - 1]) if order_list[current_position - 1]
#next_product = #collection.products.find(order_list[current_position + 1]) if order_list[current_position + 1]
#previous_product ||= Product.last
#next_product ||= Product.first
product_model.rb
default_scope -> {order(:product_sub_group_id => :asc, :id => :asc)}
So, the problem here is that I need to go to my database and get all this ids to know who is the previous and the next.
Tried to use the gem order_query, but it did not work for me and I noted that it goes to the database and fetch all the records in that order, so, that's why I did the same but getting only the ids.
All the solutions that I found was with simple order querys. Order by id or something like a priority field.
Write these methods in your Product model:
class Product
def next
self.class.where("id > ?", id).first
end
def previous
self.class.where("id < ?", id).last
end
end
Now you can do in your controller:
#product = Product.friendly.find(params[:id])
#previous_product = #product.next
#next_product = #product.previous
Please try it, but its not tested.
Thanks
I think it would be faster to do it with only two SQL requests, that only select two rows (and not the entire table). Considering that your default order is sorted by id (otherwise, force the sorting by id) :
#previous_product = Product.where('id < ?', params[:id]).last
#next_product = Product.where('id > ?', params[:id]).first
If the product is the last, then #next_product will be nil, and if it is the first, then, #previous_product will be nil.
There's no easy out-of-the-box solution.
A little dirty, but working way is carefully sorting out what conditions are there for finding next and previous items. With id it's quite easy, since all ids are different, and Rails Guy's answer describes just that: in next for a known id pick a first entry with a larger id (if results are ordered by id, as per defaults). More than that - his answer hints to place next and previous into the model class. Do so.
If there are multiple order criteria, things get complicated. Say, we have a set of rows sorted by group parameter first (which can possibly have equal values on different rows) and then by id (which id different everywhere, guaranteed). Results are ordered by group and then by id (both ascending), so we can possibly encounter two situations of getting the next element, it's the first from the list that has elements, that (so many that):
have the same group and a larger id
have a larger group
Same with previous element: you need the last one from the list
have the same group and a smaller id
have a smaller group
Those fetch all next and previous entries respectively. If you need only one, use Rails' first and last (as suggested by Rails Guy) or limit(1) (and be wary of the asc/desc ordering).
This is what order_query does. Please try the latest version, I can help if it doesn't work for you:
class Product < ActiveRecord::Base
order_query :my_order,
[:product_sub_group_id, :asc],
[:id, :asc]
default_scope -> { my_order }
end
#product.my_order(#collection.products).next
#collection.products.my_order_at(#product).next
This runs one query loading only the next record. Read more on Github.

Ordering by specific value in Activerecord

In Ruby on Rails, I'm trying to order the matches of a player by whether the current user is the winner.
The sort order would be:
Sort by whether the current user is the winner
Then sort by created_at, etc.
I can't figure out how to do the equivalent of :
Match.all.order('winner_id == ?', #current_user.id)
I know this line is not syntactically correct but hopefully it expresses that the order must be:
1) The matches where the current user is the winner
2) the other matches
You can use a CASE expression in an SQL ORDER BY clause. However, AR doesn't believe in using placeholders in an ORDER BY so you have to do nasty things like this:
by_owner = Match.send(:sanitize_sql_array, [ 'case when winner_id = %d then 0 else 1 end', #current_user.id ])
Match.order(by_owner).order(:created_at)
That should work the same in any SQL database (assuming that your #current_user.id is an integer of course).
You can make it less unpleasant by using a class method as a scope:
class Match < ActiveRecord::Base
def self.this_person_first(id)
by_owner = sanitize_sql_array([ 'case when winner_id = %d then 0 else 1 end', id])
order(by_owner)
end
end
# and later...
Match.this_person_first(#current_user.id).order(:created_at)
to hide the nastiness.
This can be achived using Arel without writing any raw SQL!
matches = Match.arel_table
Match
.order(matches[:winner_id].eq(#current_user.id).desc)
.order(created_at: :desc)
Works for me with Postgres 12 / Rails 6.0.3 without any security warning
If you want to do sorting on the ruby side of things (instead of the SQL side), then you can use the Array#sort_by method:
query.sort_by(|a| a.winner_id == #current_user.id)
If you're dealing with bigger queries, then you should probably stick to the SQL side of things.
I would build a query and then execute it after it's built (mostly because you may not have #current_user. So, something like this:
query = Match.scoped
query = query.order("winner_id == ?", #current_user.id) if #current_user.present?
query = query.order("created_at")
#results = query.all

Efficient ActiveRecord association conditions

Let's say you have an assocation in one of your models like this:
class User
has_many :articles
end
Now assume you need to get 3 arrays, one for the articles written yesterday, one of for the articles written in the last 7 days, and one of for the articles written in the last 30 days.
Of course you might do this:
articles_yesterday = user.articles.where("posted_at >= ?", Date.yesterday)
articles_last7d = user.articles.where("posted_at >= ?", 7.days.ago.to_date)
articles_last30d = user.articles.where("posted_at >= ?", 30.days.ago.to_date)
However, this will run 3 separate database queries. More efficiently, you could do this:
articles_last30d = user.articles.where("posted_at >= ?", 30.days.ago.to_date)
articles_yesterday = articles_last30d.select { |article|
article.posted_at >= Date.yesterday
}
articles_last7d = articles_last30d.select { |article|
article.posted_at >= 7.days.ago.to_date
}
Now of course this is a contrived example and there is no guarantee that the array select will actually be faster than a database query, but let's just assume that it is.
My question is: Is there any way (e.g. some gem) to write this code in a way which eliminates this problem by making sure that you simply specify the association conditions, and the application itself will decide whether it needs to perform another database query or not?
ActiveRecord itself does not seem to cover this problem appropriately. You are forced to decide between querying the database every time or treating the association as an array.
There are a couple of ways to handle this:
You can create separate associations for each level that you want by specifying a conditions hash on the association definition. Then you can simply eager load these associations for your User query, and you will be hitting the db 3x for the entire operation instead of 3x for each user.
class User
has_many articles_yesterday, class_name: Article, conditions: ['posted_at >= ?', Date.yesterday]
# other associations the same way
end
User.where(...).includes(:articles_yesterday, :articles_7days, :articles_30days)
You could do a group by.
What it comes down to is you need to profile your code and determine what's going to be fastest for your app (or if you should even bother with it at all)
You can get rid of the necessity of checking the query with something like the code below.
class User
has_many :articles
def article_30d
#articles_last30d ||= user.articles.where("posted_at >= ?", 30.days.ago.to_date)
end
def articles_last7d
#articles_last7d ||= articles_last30d.select { |article| article.posted_at >= 7.days.ago.to_date }
end
def articles_yesterday
#articles_yesterday ||= articles_last30d.select { |article| article.posted_at >= Date.yesterday }
end
end
What it does:
Makes only one query maximum, if any of the three is used
Calculates only the used array, and the 30d version in any case, but only once
It does not however simplifies the initial 30d query even if you do not use it. Is it enough, or you need something more?

Rails: how and where to add this method

I have an app where I retrieve a list of users from a specific country.
I did this in the UsersController:
#fromcanada = User.find(:all, :conditions => { :country => 'canada' })
and then turned it into a scope on the User model
scope :canada, where(:country => 'Canada').order('created_at DESC')
but I also want to be able to retrieve a random person or multiple persons from the country. I found this method that's supposed to be an efficient way to retrieve a random user from the database.
module ActiveRecord
class Base
def self.random
if (c = count) != 0
find(:first, :offset =>rand(c))
end
end
end
end
However, I have a few questions about how to add it, and how the syntax works.
Where would I put that code? Direct in the User model?
Syntax: so that I don't use code that I don't understand, can you explain how the syntax is working? I don't get (c = count). What is count counting? What is rand(c) doing? Is it finding the first one starting at the offset? If rand is an expensive method (hence the need to create a different more efficient random method), why use the expensive 'rand' in this new more efficient random method?
How could I add the call to random on my find method in the UsersController? How to add it to the scope in the model?
Building on question 3, is there a way to get two or three random users?
I wouldn't monkey patch that (or anything else!) into ActiveRecord, putting that into your User would make more sense.
The count is counting how many elements there are in your table and storing that number in c. Then rand(c) gives you a random integer in the interval [0,c) (i.e. 0 <= rand(c) < c). The :offset works the way you think it does.
rand isn't terribly expensive but doing order by random() inside the database can be very expensive. The random method that you're looking at is just a convenient way to get a random record/object from the database.
Adding it to your own User would look something like this:
def self.random
n = scoped.count
scoped.offset(rand(n)).first
end
That would allow you to chain random after a bunch of scopes:
u = User.canadians_eh.some_other_scope.random
but the result of random would be a single user so your chaining would stop there.
If you wanted multiple users you'd want to call random multiple times until you got the number of users you wanted. You could try this:
def self.random
n = scoped.count
scoped.offset(rand(n))
end
us = User.canadians_eh.random.limit(3)
to get three random users but the users would be clustered together in whatever order the database ended up with after your other scopes and that's probably not what you're after. If you want three you'd be better off with something like this:
# In User...
def self.random
n = scoped.count
scoped.offset(rand(n)).first
end
# Somewhere else...
scopes = User.canadians_eh.some_other_scope
users = 3.times.each_with_object([]) do |_, users|
users << scopes.random
scopes = scopes.where('id != :latest', :latest => users.last.id)
end
You'd just grab a random user, update your scope chain to exclude them, and repeat until you're done. You would, of course, want to make sure you had three users first.
You might want to move the ordering out of your canada scope: one scope, one task.
That code is injecting a new method into ActiveRecord::Base. I would put it in lib/ext/activerecord/base.rb. But you can put it anywhere you want.
count is a method being called on self. self will be some class inheriting from ActiveRecord::Base, eg. User. User.count returns the number of user records (sql: SELECT count(*) from users;). rand is a ruby stdlib method Kernel#rand. rand(c) returns a random integer in the Range 0...c and c was previously computed by calling #count. rand is not expensive.
You don't call random with find, User#random is a find, it returns one random record from all User records. In your controller you say User.random and it returns a single random record (or nil if there are no user records at all).
modify the AR::Base::random method like so:
module ActiveRecord
class Base
def self.random( how_many = 1 )
if (c = count) != 0
res = (0..how_many).inject([]) do |m,i|
m << find(:first, :offset =>rand(c))
end
how_many == 1 ? res.first : res
end
end
end
end
User.random(3) # => [<User Rand1>,<User Rand2>,<User Rand3>]

How to filter results by multiple fields?

I am working on a survey application in ruby on rails and on the results page I want to let users filter the answers by a bunch of demographic questions I asked at the start of the survey.
For example I asked users what their gender and career was. So I was thinking of having dropdowns for gender and career. Both dropdowns would default to all but if a user selected female and marketer then my results page would so only answers from female marketers.
I think the right way of doing this is to use named_scopes where I have a named_scope for every one of my demographic questions, in this example gender and career, which would take in a sanitized value from the dropdown to use at the conditional but i'm unsure on how to dynamically create the named_scope chain since I have like 5 demographic questions and presumably some of them are going to be set to all.
You can chain named scopes together:
def index
#results = Results.scoped
#results = #results.gender(params[:gender]) unless params[:gender].blank?
#results = #results.career(params[:career]) unless params[:career].blank?
end
I prefer however to use the has_scope gem:
has_scope :gender
has_scope :career
def index
#results = apply_scopes(Results).all
end
If you use has_scope with inherited_resources, you don't even need to define the index action.
named_scope :gender,lambda { |*args|
unless args.first.blank?
{ :conditions => [ "gender = ?", args.first] }
end
}
If you write named scopes in this way, you can have all them chained, and if one of your params will be blank wont breaks.
Result.gender("Male") will return male results.
Result.gender("") will return male and female too.
And you can chain all of your methods like this. Finally as a filtering you can have like:
Result.age(16).gender("male").career("beginer")
Result.age(nil).gender("").career("advanced") - will return results with advanced career, etc.
Try some like this:
VistaFact.where( if active then {:field => :vista2} else {} end)
Or like this:
VistaFact.where(!data.blank? ? {:field=>data.strip} : {}).where(some? ? {:field2 => :data2} : {}).where ...
That work for me very nice!

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