Error generating files in ANTLR - parsing

Question

So I'm trying to write a parser in ANTLR, this is my first time using it and I'm running into a problem that I can't find a solution for, apologies if this is a very simple problem. Anyway, the error I'm getting is:
"(100): Expr.g:1:13:syntax error: antlr: MismatchedTokenException(74!=52)"
The code I'm currently using is:
grammar Expr.g;
options{
output=AST;
}
tokens{
MAIN = 'main';
OPENBRACKET = '(';
CLOSEBRACKET = ')';
OPENCURLYBRACKET = '{';
CLOSECURLYBRACKET = '}';
COMMA = ',';
SEMICOLON = ';';
GREATERTHAN = '>';
LESSTHAN = '<';
GREATEROREQUALTHAN = '>=';
LESSTHANOREQUALTHAN = '<=';
NOTEQUAL = '!=';
ISEQUALTO = '==';
WHILE = 'while';
IF = 'if';
ELSE = 'else';
READ = 'read';
OUTPUT = 'output';
PRINT = 'print';
RETURN = 'return';
READC = 'readc';
OUTPUTC = 'outputc';
PLUS = '+';
MINUS = '-';
DIVIDE = '/';
MULTIPLY = '*';
PERCENTAGE = '%';
}
#header {
//package test;
import java.util.HashMap;
}
#lexer::header {
//package test;
}
#members {
/** Map variable name to Integer object holding value */
HashMap memory = new HashMap();
}
prog: stat+ ;
stat: expr NEWLINE {System.out.println($expr.value);}
| ID '=' expr NEWLINE
{memory.put($ID.text, new Integer($expr.value));}
| NEWLINE
;
expr returns [int value]
: e=multExpr {$value = $e.value;}
( '+' e=multExpr {$value += $e.value;}
| '-' e=multExpr {$value -= $e.value;}
)*
;
multExpr returns [int value]
: e=atom {$value = $e.value;} ('*' e=atom {$value *= $e.value;})*
;
atom returns [int value]
: INT {$value = Integer.parseInt($INT.text);}
| ID
{
Integer v = (Integer)memory.get($ID.text);
if ( v!=null ) $value = v.intValue();
else System.err.println("undefined variable "+$ID.text);
}
| '(' e=expr ')' {$value = $e.value;}
;
IDENT : ('a'..'z'^|'A'..'Z'^)+ ; : .;
INT : '0'..'9'+ ;
NEWLINE:'\r'? '\n' ;
WS : (' '|'\t')+ {skip();} ;
Thanks for any help.
EDIT: Well, I'm an idiot, it's just a formatting error. Thanks for the responses from those who helped out.

Answer 1

You have some illegal characters after your IDENT token:
IDENT : ('a'..'z'^|'A'..'Z'^)+ ; : .;
The : .; are invalid there. And you're also trying to mix the tree-rewrite operator ^ inside a lexer rule, which is illegal: remove them. Lastly, you've named it IDENT while in your parser rules, you're using ID.
It should be:
ID : ('a'..'z' | 'A'..'Z')+ ;