So my scenario is that I've copied an http link (that I want to stream with vlc player) to the clipboard. I would like to write a simple script that plays the file located at the path on the clipboard. I've already tried
pbpaste | VLC -
pbpaste outputs the contents of the clipboard to stdout and "VLC -" attempts to play what's on stdout, so I was hoping VLC would pick up the path, read it, and then fetch the file to play, but apparently it expects an actual byte stream when you pipe things to it, not a string filepath. I've tried something similar on windows that failed so I don't think this is OS-specific
Any thoughts?
Thanks,
sh4d0w
Try this:
LOC=$(pbpaste); vlc -vvv $LOC
It should work as long as you've copied the "http://" as well. In fact, it will work for any string as described in this manual chapter
This works nowadays for the urls that I've been using
$url=Get-ClipBoard; $vlc=start-Process -FilePath "vlc" -ArgumentList $url,-f,vlc://quit
Related
I'm trying to configure my Jodit editor (v.3.0) in order to be able to upload also audio files.
I've put
$config['extensions'} = ['jpg', 'png', 'gif', 'jpeg', 'wav', 'mp3'];
in my config file and it stopped giving me the error "File type is not in white list", but it doesn't appear to execute any action.
What can I try?
Thanks
First you've closed the extensions array key with a } but I think is just a mistype
For the issue: I've figure out that the mp3 I'm trying to load is actually an mpeg file, even if the extension is .mp3
How to test: got to your connector, open the file connector>vendor>jodit>application>src>components>BaseApplication.php and comment out all the "if" statement with 'File type is not in white list' (for me is near line 365).
Now try to upload the file and you'll see the real extension. Mine was mpeg and after removing the comments to the BaseApplication.php file and adding the mpeg extention to the config.php the file was uploaded as expected.
Hope this can help you and a others (even my future me searching this issue again hehehe)
I just want to get a audio file(opus codec used) only in webm file.
I try to search what is webm format, how to parse, but I cant get info well.
I check that webm format is from mkv, then should I check the mkv first?
there is just one github code, but I cant find way how parse the audio from webm.
https://github.com/webmproject/libwebm/tree/master/webm_parser
You're really going to want the MKVToolNix. These include the tool mkvextract in another answer.
The MKVToolNix is actually a series of tools (mkvmerge, mkvinfo, mkvextract, mkvpropedit). First you asked how to parse the info. You can find the details using:
mkvinfo file.webm
mkvinfo file.webm -a
The first command will parse the overall structure. The second gives the detail of each frame. Use the --help switch if you want all commands.
To extract the audio, do
mkvextract file.webm tracks X:newfile.opus
Where X is the track number that you've identified as wanted from mkvinfo previously. Webm and MKV can have multiple tracks. "newfile.opus" is the new file that you want to create, choose the name you want.
There is also a mkvtoolnix gui, but I've never used that.
mkvextract can extract audio for you, and I recommend having a look at the mkvtoolsnix source code.
For example, you can extract audio from a WebM file into an Ogg Opus file like this:
$ mkvextract ~/audio/bubbles.webm tracks 0:audio.opus
Extracting track 0 with the CodecID 'A_OPUS' to the file 'audio.opus'. Container format: Ogg (Opus in Ogg)
Progress: 100%
I am using a luvit Lua environment to run my lua code through my control panel. I am looking to write to a .txt file, but with the simple code that i am running, its not working.
The reason I wish to write to a .txt file is to log notices from my Discord Bot I am working on in the Discordia library.
I have a folder called MezzaBOT. In this file i have a write.lua file and also a log.txt file. I have this simple code in my write.lua file:
io.output('log.txt')
io.write('hello\n')
io.close()
I then run in my command promt with Luvit environment:
>luvit Desktop\mezzabot\write.lua
I don't get any errors but the log.txt file continues to stay empty. Am I missing a line in my code, or do i need to access log.txt differently?
edit: my new code is the following
file = io.open('log.txt')
file:write('hello', '\n')
file:close()
and it is not making a new line for each time with \n
edit B:
Ok, i found my problem, its creating a log.txt in my C:\Users\PC.
One other problem is when writing, its not making a new line with the \n. Can someone please help me?
Lua, by default, opens files in read mode. You need to explicitly open a file in write mode if you want to write to it (see manual)
file = io.open('log.txt', 'w')
file:write('hello', '\n')
file:close()
Should work :)
i'm trying to record a webcam, save it and stream it to a local network.
The Problem is, i want to do this with different compression:
The stream for the local network should only have <400kbit/s, but the other one, which is stored to a local file, should be uncompressed or with up to 10 Mbit/s
So i tried two methods to solve this:
First i played a little bit with the VLC Gui. It is really easy to record the Webcam, then transcode it and save it to a file or/and stream it to the internet. The command line looks like this:
vlc v4l2:///dev/video0 :v4l2-standard= :live-caching=300 :sout="#transcode{vcodec=WMV2,vb=380,fps=1,scale=Automatisch,acodec=none}:duplicate{dst=file{dst=stream.asf,no-overwrite},dst=http{dst=:8080/stream.wmv}}" :sout-keep
But i had the problem that both, the internet stream and the file, are getting compressed. So i changed the order of "duplicate" and "transcode" to:
vlc v4l2:///dev/video0 :v4l2-standard= :live-caching=300 :sout="#duplicate{dst=file{dst=stream.asf,no-overwrite}, dst="transcode{vcodec=WMV2,vb=380,fps=1,scale=Automatisch,acodec=none}:http{dst=:8080/stream.wmv}"}" :sout-keep
My thought: Now i should have a compressed internet stream and the orignal file. But it doesn't stream it to the internet.
So i tried another method: I wanted to stream the original stream to port 8080 and then use two other VLC instances to generate a compressed network stream to port 8008 and a original file. But i cant stream a stream....
So i would be really thankful, if someone has another idea or a hint where my problem is.
Sorry for my english.
Have a nice day.
You are double quoting the :sout. If you plan to use quotes " inside the value then use apostrophe ' to enclose the whole argument like:
:sout='#duplicate{dst=file{...}, dst="transcode{...}:http{dst=:8080/stream.wmv}"}'
If you add a -v (verbose output) at the end of your command you'll see some other issues too like no-overwrite not being recognized. Also,scale=Automatisch should be scale=auto.
Please note that I checked just the syntax and not your encoding parameters.
I am trying to download YouTube videos through Wget. The first thing necessary is to capture the URL of the actual video resource. Suppose I want to download this video: video. Opening up the page in the Firebug console reveals something like this:
The link which I have encircled looks like the link to the resource, for there we see only the video: http://www.youtube.com/v/r-KBncrOggI?version=3&autohide=1. However, when I am trying to download this resource with Wget, a 4 KB file of name r-KBncrOggI#version=3&autohide=1 gets stored in my hard-drive, nothing else. What should I do to get the actual video?
And secondly, is there a way to capture different resources for videos of different resolutions, like 360px, 480px, etc.?
Here is one VERY simplified, yet functional version of the youtube-download utility I cited on my another answer:
#!/usr/bin/env perl
use strict;
use warnings;
# CPAN modules we depend on
use JSON::XS;
use LWP::UserAgent;
use URI::Escape;
# Initialize the User Agent
# YouTube servers are weird, so *don't* parse headers!
my $ua = LWP::UserAgent->new(parse_head => 0);
# fetch video page or abort
my $res = $ua->get($ARGV[0]);
die "bad HTTP response" unless $res->is_success;
# scrape video metadata
if ($res->content =~ /\byt\.playerConfig\s*=\s*({.+?});/sx) {
# parse as JSON or abort
my $json = eval { decode_json $1 };
die "bad JSON: $1" if $#;
# inside the JSON 'args' property, there's an encoded
# url_encoded_fmt_stream_map property which points
# to stream URLs and signatures
while ($json->{args}{url_encoded_fmt_stream_map} =~ /\burl=(http.+?)&sig=([0-9A-F\.]+)/gx) {
# decode URL and attach signature
my $url = uri_unescape($1) . "&signature=$2";
print $url, "\n";
}
}
Usage example (it returns several URLs to streams with different encoding/quality):
$ perl youtube.pl http://www.youtube.com/watch?v=r-KBncrOggI | head -n 1
http://r19---sn-bg07sner.c.youtube.com/videoplayback?fexp=923014%2C916623%2C920704%2C912806%2C922403%2C922405%2C929901%2C913605%2C925710%2C929104%2C929110%2C908493%2C920201%2C913302%2C919009%2C911116%2C926403%2C910221%2C901451&ms=au&mv=m&mt=1357996514&cp=U0hUTVBNUF9FUUNONF9IR1RCOk01RjRyaG4wTHdQ&id=afe2819dcace8202&ratebypass=yes&key=yt1&newshard=yes&expire=1358022107&ip=201.52.68.216&ipbits=8&upn=m-kyX9-4Tgc&sparams=cp%2Cid%2Cip%2Cipbits%2Citag%2Cratebypass%2Csource%2Cupn%2Cexpire&itag=44&sver=3&source=youtube,quality=large&signature=A1E7E91DD087067ED59101EF2AE421A3503C7FED.87CBE6AE7FB8D9E2B67FEFA9449D0FA769AEA739
I'm afraid it's not that easy do get the right link for the video resource.
The link you got, http://www.youtube.com/v/r-KBncrOggI?version=3&autohide=1, points to the player rather than the video itself. There is one Perl utility, youtube-download, which is well-maintained and does the trick. This is how to get the HQ version (magic fmt=18) of that video:
stas#Stanislaws-MacBook-Pro:~$ youtube-download -o "{title}.{suffix}" --fmt 18 r-KBncrOggI
--> Working on r-KBncrOggI
Downloading `Sourav Ganguly in Farhan Akhtar's Show - Oye! It's Friday!.mp4`
75161060/75161060 (100.00%)
Download successful!
stas#Stanislaws-MacBook-Pro:~$
There might be better command-line YouTube Downloaders around. But sorry, one doesn't simply download a video using Firebug and wget any more :(
The only way I know to capture that URL manually is by watching the active downloads of the browser:
That largest data chunks are video data, so you can copy its URL:
http://s.youtube.com/s?lact=111116&uga=m30&volume=4.513679238953965&sd=BBE62AA4AHH1357937949850490&rendering=accelerated&fs=0&decoding=software&nsivbblmax=679542.000&hcbt=105.345&sendtmp=1&fmt=35&w=640&vtmp=1&referrer=None&hl=en_US&nsivbblmin=486355.000&nsivbblmean=603805.166&md=1&plid=AATTCZEEeM825vCx&ns=yt&ptk=youtube_none&csipt=watch7&rt=110.904&tsphab=1&nsiabblmax=129097.000&tspne=0&tpmt=110&nsiabblmin=123113.000&tspfdt=436&hbd=30900552&et=110.146&hbt=30.770&st=70.213&cfps=25&cr=BR&h=480&screenw=1440&nsiabblmean=125949.872&cpn=JlqV9j_oE1jzk7Zc&nsivbblc=343&nsiabblc=343&docid=r-KBncrOggI&len=1302.676&screenh=900&abd=1&pixel_ratio=1&bc=26131333&playerw=854&idpj=0&hcbd=25408143&playerh=510&ldpj=0&fexp=920704,919009,922403,916709,912806,929110,928008,920201,901451,909708,913605,925710,916623,929104,913302,910221,911116,914093,922405,929901&scoville=1&el=detailpage&bd=6676317&nsidf=1&vid=Yfg8gnutZoTD4G5SVKCxpsPvirbqG7pvR&bt=40.333&mos=0&vq=auto
However, for a large video, this will only return a part of the stream unless you figure out the URL query parameter responsible for stream range to be downloaded and adjust it.
A bonus: everything changes periodically as YouTube is constantly evolving. So, don't do that manually unless you carve pain.