Given a spreadsheet with two columns, say A and B, each containing n values under it, all text; is there a formula that allows me to fill just one cell containing the amount of equal values in columns A and B?
Example:
A B
-----
1 M M
2 L M
3 L L
4 M M
5 M L
-----
3
Since columns A and B both contain an M in rows 1 and 4, and an L in row 3, the result is (i.e. 2+1).
A simple solution is to use QUERY function in google spreadsheet:
=SUM(QUERY(A1:B5, "Select 1 where A = B"))
Or using SUMPRODUCT:
=ARRAYFORMULA(SUM(((A:A)=(B:B)) * (1) ))
One of possible solution will be to add the following formula in column C: =N(EXACT(A1,B1)),
copy it throughout the column down to the last row and then sum up the column C values using =SUM(C1:C5).
Here we go:
=IF(EQ(LEFT(A0, 1), "A"),
SUM(ARRAYFORMULA(N(EXACT(TRANSPOSE(A1:A5), TRANSPOSE(B1:B5))))),
"")
Reading: if the value in row 0 (it doesn't exist, but my example above does ;) ) is equal to the text "A", take the sum of an array N, otherwise put in an empty string. ("")
Array N is build by taking the transpose of columns A and B. (Turning them, so they look like a row) and comparing the values. (Burnash gave me the options "N" and "EXACT") The formula N transforms this into a 1 or 0.
Copy paste the formula in an entire row and what do you know... It worked! That was hellish for something so trivial.
Thanks anyway.
Related
I have a table with three Columns:
Column A: name of Item,
Column B: Lowest value of series,
Column C: the Highest value of series.
enter image description here
What I want to achieve is:
Generate series of item sequence from lowest number to highest number per row
So Apple 7 9 will yield: "Apple_7", "Apple_8", "Apple_9"
Concatenate/Join such sequence per row into Column D
So
Item
From
Until
Result
Apple
7
9
"Apple_7, Apple_8, Apple_9"
Berry
3
8
"Berry_3, Berry_4, Berry_5, Berry_6, Berry_7, Berry_8"
Doing it all using one Arrayformula, so that new row added can be automatically calculated.
Here is example sheet: https://docs.google.com/spreadsheets/d/1R5raKmmt5-aOIorAZGHjv_-fdySKWjCMB_FRQwm1vag/edit#gid=0
I tried in Column D:
arrayformula(textjoin(", ",true,arrayformula(A3:A&"_"&sequence(1,C3:C-B3:B+1,B3:B,1))))
Apparently, the sequence function only take value from Column B and join it in first row.
Any help will be appreciated.
Try below BYROW() formula (see your file, harun24hr sheet).
=BYROW(A3:INDEX(A3:A,COUNTA(A3:A)),LAMBDA(x,TEXTJOIN(";",1,INDEX(x&"_"& SEQUENCE(INDEX(C:C,ROW(x))-INDEX(B:B,ROW(x))+1,1,INDEX(B:B,ROW(x)))))))
Here A3:INDEX(A3:A,COUNTA(A3:A)) will return a array of values as well cell reference from A3 to last non empty cell in column A (Assume you do not have any blank rows inside data). If you have blank row, then you have to use different approach. See this post by #TheMaster
Then LAMBDA() will apply TEXTJOIN() and SEQUENCE() function for each cell of B as well as C column.
SEQUENCE() will make series from start to end number and by concatenating A column and will generate your desired strings.
Finally TEXTJOIN() will join all those strings with delimiter to a single cell.
try REDUCE:
=INDEX(QUERY(REDUCE(, A3:INDEX(A:A, MAX(ROW(A:A)*(A:A<>""))),
LAMBDA(x, a, {x; JOIN(, LAMBDA(i, f, u, i&"_"&SEQUENCE(1, u-f+1, f)&";")
(a, OFFSET(a,,1), OFFSET(a,,2)))})), "offset 1", ))
I have a Sheet1 with data like this:
one
two
three
four
a
b
c
d
e
f
g
h
i
j
k
l
m
n
o
p
I have Sheet2 with data like this:
alpha
value
c
k
g
c
For each row in Sheet2, I want to look up Sheet2.alpha in Sheet1.three and return the value of Sheet1.one. I want to do this by putting an array formula in B2.
So, the expected result is:
alpha
value
c
a
k
i
g
e
c
a
I can use the new Google Sheet formulas they just released -- except named ranges. I feel like there is some clever trick using them, but I can't come up with it.
BYROW() and XLOOKUP() are your friend in this case.
=BYROW(A2:INDEX(A2:A,COUNTA(A2:A)),LAMBDA(x,XLOOKUP(x,Sheet1!C2:C,Sheet1!A2:A,"Not Found")))
I want to combine multiple columns in a Google sheet into one cell, including headers / labels. My input sheet looks like this:
Name
Description
Col 1
Col 2
Col 3
Foo
val 1
val 2
val 3
Bar
val x
val y
val z
And I want to concatenate the values in each column into a single cell, including the headers for each value. Desired output:
Name
Description
Foo
Col 1val 1Col 2val 2Col 3val 3
Bar
Col 1val xCol 2val yCol 3val z
This formula concatenates the columns into one, however it doesn't include the headers (note that char(10) produces a linebreak):
=TEXTJOIN(char(10),true,B2:E2)
I can produce a similar result using REDUCE (I can't believe I'm writing a reducer in a Google Sheet):
=REDUCE("", B2:E2, LAMBDA(accumulator, current_value, CONCATENATE(accumulator, current_value, char(10))))
However the lambda function doesn't seem to provide the index of the current iteration, so I'm not sure how to grab the column name above it.
Use this formula
=ARRAYFORMULA(
QUERY({"Description";
TRIM(SUBSTITUTE(FLATTEN(QUERY(TRANSPOSE(
IF(B2:D="",,","&B1:D1&","&B2:D&",")),"",9^9)),",",CHAR(10)))},
" Where Col1 is not null" ) )
try the old way:
=ARRAYFORMULA(TRIM(REGEXREPLACE(TRIM(FLATTEN(QUERY(TRANSPOSE(
IF(B2:D="",,"×"&B1:D1&"×"&B2:D&"×")),,9^9))), "×", CHAR(10))))
or in one cell if that's what you want:
=INDEX(TRIM(REDUCE(, B1:D1&CHAR(10)&B2:D3&CHAR(10),
LAMBDA(a, c, a&c&CHAR(10)))))
Using your current TEXTJOIN() formula you can just include the Column Headers with the dollar sign ($) which means absolute reference so it will not change when copied/dragged down to rows below.
Try:
=TEXTJOIN(char(10),true,C$1,C2,char(10),D$1,D2,char(10),E$1,E2)
Drag down to rows.
Result:
Refer to this link for more info on Absolute Reference: https://www.lido.app/tutorials/absolute-reference-on-google-sheets
I currently have a google sheet in which I count values in Column L against a reference sheet 'Ref' and then against a status Column W
IF(AND(COUNTIF(Ref!$A$1:$A$100,L2),W2 <>"Cancelled",W2 <>"Postponed",W2 <> "Dropped"),"Y", "N")
However the values have now changed in Column L. Instead of defined values in each cell they will be a string of values in each cell, the permutations will be too great to enter into my reference sheet.
How do I still count the values in column L to correctly return a 'Y' or 'N'
I have tried
=IF(AND(COUNTIF(L2,{"*LEE*","*LON*","*LAM*"}),W2 <>"Cancelled",W2 <>"Postponed",W2 <> "Dropped"),"Y", "N")
=IF(AND(COUNTIF(Ref!$A$1:$A$100,"*"&L2&"*"),W2 <>"Cancelled",W2 <>"Postponed",W2 <> "Dropped"),"Y", "N")
=IF(AND(COUNTIF(L2,{"*LEE*","*LON*","*LAM*"}),W2 <>"Cancelled",W2 <>"Postponed",W2 <> "Dropped"),"Y", "N")
The values I which need to count will feature one of the following phrases 'LEE', 'LON','LAM'.
The new values that are entered into column L will look like the following
<Area1: Y - LEE>,<Area2: Y - MIL>
<Area3: WF>,<Area4: Y - MUN>
<Area1: YY - MUN>,<Area2: YY - LON>,<Area3: YY-LAM>
So I need to be able to search within the cell for 1 of the 3 phrases.
Any help greatly appreciated
Thanks
I have a solution that might work, using arrayformula() in a single cell.
If I've understood correctly, it looks like you're checking Col L to see if cells contain LEE LON or LAM. You're also checking to see that they appear in Ref!$A$1:$A$100.
On your sheet that contains col F and Col W (Status), try this in row 1 (I've used AB1):
=arrayformula({"Check";if(if(L2:L<>"",regexreplace(regexreplace(regexreplace(flatten(query(transpose({if(regexmatch(split(regexreplace(L2:L,"[^A-Z]",char(9999)),char(9999)),"LAM|LEE|LON"),split(regexreplace(L2:L,"[^A-Z]",char(9999)),char(9999)),"|")}),"",9^9)),"\ ",""),"(\|)+","\|"),"^\||\|$",),)<>"",if(REGEXMATCH(join(" ",Ref!A2:A),if(L2:L<>"",regexreplace(regexreplace(regexreplace(flatten(query(transpose({if(regexmatch(split(regexreplace(L2:L,"[^A-Z]",char(9999)),char(9999)),"LAM|LEE|LON"),split(regexreplace(L2:L,"[^A-Z]",char(9999)),char(9999)),"|")}),"",9^9)),"\ ",""),"(\|)+","\|"),"^\||\|$",),)),if(regexmatch(W2:W,"Cancelled|Postponed|Dropped"),"N","Y"),),)})
To show the working, I've got three helper columns, AD, AE and AF:
AD1 gets LAM LEE or LON from col L:
=arrayformula({"LAM|LEE|LON entry";if(L2:L<>"",regexreplace(regexreplace(regexreplace(flatten(query(transpose({if(regexmatch(split(regexreplace(L2:L,"[^A-Z]",char(9999)),char(9999)),"LAM|LEE|LON"),split(regexreplace(L2:L,"[^A-Z]",char(9999)),char(9999)),"|")}),"",9^9)),"\ ",""),"(\|)+","\|"),"^\||\|$",),)})
AE1 checks the values in col AD to see if they appear in Ref!A2:A:
=arrayformula({"LAM|LEE|LON match";if(AD2:AD<>"",REGEXMATCH(join(" ",Ref!A2:A),AD2:AD),)})
AF1 checks if the value in col AE is true, then the status from col W:
=arrayformula({"Check";if(AE2:AE=true,if(regexmatch(W2:W,"Cancelled|Postponed|Dropped"),"N","Y"),)})
The 3 helper columns are combined in AB1.
Suppose I've got a text values column (named Data), generated by =unique() function. Also, there is an array of patterns to find and replace for (Find and Replace columns).
Which formula should I use to scan each cell in Data for multiple patterns in Find and replace it, if match?
Data Find Replace Result
1 a c z a
2 b f y b
3 c e x z
4 d d
5 e x
6 c z
Tried =SUBSTITUTE() and =IF() functions, but it fails, when I set an array of patterns, instead of single one.
If the table you is in range A1:E7, try this formula
=TRANSPOSE(SPLIT(REGEXREPLACE(REGEXREPLACE(REGEXREPLACE(ARRAYFORMULA(CONCATENATE($B$2:$B$7&"|")),$C$2,$D$2),$C$3,$D$3),$C$4,$D$4),"|"))
You can read further about this in an older post and google docs forum.
Array solution
This formula takes range to replace, so it can be used for variable number of patterns:
=QUERY(ARRAYFORMULA({REGEXMATCH(A2,$B$2:$B$4),
REGEXREPLACE(A2,$B$2:$B$4,$C$2:$C$4)}),
"select Col2 order by Col1 desc limit 1")
or this one:
=INDEX(ArrayFormula(REGEXREPLACE(A2,$B$2:$B$4,$C$2:$C$4)),IFERROR(MATCH(A2,$B$2:$B$4,0),1))
or this:
=IFERROR(INDEX($C$2:$C$4,MATCH(A2,$B$2:$B$4,0)),A2)
The formula is need to be dragged down.
Single Formula & Array solution
Also this single ArrayFormula will do the trick:
=ArrayFormula(trim(transpose(query({IF(--REGEXMATCH(TRANSPOSE(A2:A7),$B$2:$B$4)=1,
REGEXREPLACE(TRANSPOSE(A2:A7),$B$2:$B$4,$C$2:$C$4),"");
TRANSPOSE(if(--not(REGEXMATCH(A2:A7,JOIN("|",B2:B4))),A2:A7,""))},,COUNTA(A2:A)))))
or this shorter formula:
=ArrayFormula(IFERROR(VLOOKUP(MATCH(A2:A7,B2:B4,0),{ROW(INDIRECT("a1:a"&COUNTA(C2:C4))),C2:C4},2,0),A2:A7))
Please, see explanations in Sample file