Initial and place an UIButton in an UIActionSheet with an UIPickerView - ios

Question

I am implementing picker by Add UIPickerView & a Button in Action sheet - How?. I tried to replace the UISegmentedControl with a UIButton but it does not working. Could someone remind me why UIButton cannot be shown here?
Thank you.
- (IBAction) makeButtonPressed: (id) sender;
{
UIActionSheet *actionSheet = [[UIActionSheet alloc] init];
[actionSheet setTitle:#"Select Make"];
[actionSheet setActionSheetStyle:UIActionSheetStyleBlackOpaque];
UIPickerView *pickerView = [[UIPickerView alloc] initWithFrame:CGRectMake(0, 44, 0, 0)];
pickerView.dataSource = self;
pickerView.delegate = self;
pickerView.showsSelectionIndicator = YES;
[actionSheet addSubview:pickerView];
// UISegmentedControl *doneButton = [[UISegmentedControl alloc] initWithItems:[NSArray arrayWithObject:#"Done"]];
// doneButton.momentary = YES;
// doneButton.frame = CGRectMake(260, 7.0f, 50.0f, 30.0f);
// doneButton.segmentedControlStyle = UISegmentedControlStyleBar;
// doneButton.tintColor = [UIColor blackColor];
// [doneButton addTarget:self action:#selector(makeDone:) forControlEvents:UIControlEventValueChanged];
// [actionSheet addSubview:doneButton];
UIButton *doneButton = [[UIButton alloc] init];
doneButton.frame = CGRectMake(260, 7.0f, 50.0f, 30.0f);
[doneButton addTarget:self action:#selector(makeDone:) forControlEvents:UIControlEventValueChanged];
[actionSheet addSubview:doneButton];
[actionSheet showInView:[[UIApplication sharedApplication] keyWindow]];
[actionSheet setBounds:CGRectMake(0, 0, 320, 460)];
}

Answer 1

The designated initializer for UIButton is +buttonWithType:. You should create your button with one of the predefined styles, or use UIButtonTypeCustom.
UIButton *doneButton = [UIButton buttonWithType:UIButtonTypeRoundRect];
doneButton.frame = CGRectMake(260, 7.0f, 50.0f, 30.0f);
[doneButton addTarget:self action:#selector(makeDone:) forControlEvents:UIControlEventValueChanged];
[actionSheet addSubview:doneButton];