Is there a way to access method arguments in Ruby? - ruby-on-rails

New to Ruby and ROR and loving it each day, so here is my question since I have not idea how to google it (and I have tried :) )
we have method
def foo(first_name, last_name, age, sex, is_plumber)
# some code
# error happens here
logger.error "Method has failed, here are all method arguments #{SOMETHING}"
end
So what I am looking for way to get all arguments passed to method, without listing each one. Since this is Ruby I assume there is a way :) if it was java I would just list them :)
Output would be:
Method has failed, here are all method arguments {"Mario", "Super", 40, true, true}

In Ruby 1.9.2 and later you can use the parameters method on a method to get the list of parameters for that method. This will return a list of pairs indicating the name of the parameter and whether it is required.
e.g.
If you do
def foo(x, y)
end
then
method(:foo).parameters # => [[:req, :x], [:req, :y]]
You can use the special variable __method__ to get the name of the current method. So within a method the names of its parameters can be obtained via
args = method(__method__).parameters.map { |arg| arg[1].to_s }
You could then display the name and value of each parameter with
logger.error "Method failed with " + args.map { |arg| "#{arg} = #{eval arg}" }.join(', ')
Note: since this answer was originally written, in current versions of Ruby eval can no longer be called with a symbol. To address this, an explicit to_s has been added when building the list of parameter names i.e. parameters.map { |arg| arg[1].to_s }

Since Ruby 2.1 you can use binding.local_variable_get to read value of any local variable, including method parameters (arguments). Thanks to that you can improve the accepted answer to avoid evil eval.
def foo(x, y)
method(__method__).parameters.map do |_, name|
binding.local_variable_get(name)
end
end
foo(1, 2) # => 1, 2

One way to handle this is:
def foo(*args)
first_name, last_name, age, sex, is_plumber = *args
# some code
# error happens here
logger.error "Method has failed, here are all method arguments #{args.inspect}"
end

This is an interesting question. Maybe using local_variables? But there must be a way other than using eval. I'm looking in Kernel doc
class Test
def method(first, last)
local_variables.each do |var|
puts eval var.to_s
end
end
end
Test.new().method("aaa", 1) # outputs "aaa", 1

If you need arguments as a Hash, and you don't want to pollute method's body with tricky extraction of parameters, use this:
def mymethod(firstarg, kw_arg1:, kw_arg2: :default)
args = MethodArguments.(binding) # All arguments are in `args` hash now
...
end
Just add this class to your project:
class MethodArguments
def self.call(ext_binding)
raise ArgumentError, "Binding expected, #{ext_binding.class.name} given" unless ext_binding.is_a?(Binding)
method_name = ext_binding.eval("__method__")
ext_binding.receiver.method(method_name).parameters.map do |_, name|
[name, ext_binding.local_variable_get(name)]
end.to_h
end
end

This may be helpful...
def foo(x, y)
args(binding)
end
def args(callers_binding)
callers_name = caller[0][/`.*'/][1..-2]
parameters = method(callers_name).parameters
parameters.map { |_, arg_name|
callers_binding.local_variable_get(arg_name)
}
end

You can define a constant such as:
ARGS_TO_HASH = "method(__method__).parameters.map { |arg| arg[1].to_s }.map { |arg| { arg.to_sym => eval(arg) } }.reduce Hash.new, :merge"
And use it in your code like:
args = eval(ARGS_TO_HASH)
another_method_that_takes_the_same_arguments(**args)

If the function is inside some class then you can do something like this:
class Car
def drive(speed)
end
end
car = Car.new
method = car.method(:drive)
p method.parameters #=> [[:req, :speed]]

If you would change the method signature, you can do something like this:
def foo(*args)
# some code
# error happens here
logger.error "Method has failed, here are all method arguments #{args}"
end
Or:
def foo(opts={})
# some code
# error happens here
logger.error "Method has failed, here are all method arguments #{opts.values}"
end
In this case, interpolated args or opts.values will be an array, but you can join if on comma. Cheers

It seems like what this question is trying to accomplish could be done with a gem I just released, https://github.com/ericbeland/exception_details. It will list local variables and vlaues (and instance variables) from rescued exceptions. Might be worth a look...

Before I go further, you're passing too many arguments into foo. It looks like all of those arguments are attributes on a Model, correct? You should really be passing the object itself. End of speech.
You could use a "splat" argument. It shoves everything into an array. It would look like:
def foo(*bar)
...
log.error "Error with arguments #{bar.joins(', ')}"
end

Related

yield to an anonymous block two functions up

there is probably a simple way to do this.
I'm trying to refactor something like the following
def foo(baz)
baz.update_first
if baz.has_condition?
yield baz.val if block_given?
baz.a
else
baz.b
end
end
called like
foo(baz) {|b| b.modify}
to something like
def foo(baz)
baz.update_first
bar(baz) {|i| yield i if block_given? }
end
def bar(baz)
if baz.has_condition?
yield baz.val if block_given?
baz.a
else
baz.b
end
end
Will that work? How?
I think it will, but I'd appreciate a clear explanation of how yielding inside a block works... reading through proc.c and vm.c and a relevant git commit in the ruby source code , I think when bar is called in foo it executes until it yields, and then you walk up the frame stack to the local environment pointer for block defined in foo, which is called, where the yield walks up to the block foo is called with, executes it, and then you are back in bar. Is that correct? Is there a better way to do this?
This feels a little weird to me, like inverting control, and it requires foo to know about baz more then I'd like, but I unfortunately can't simply pass a proc or lambda in this code.
I think maybe the concept of yield will be more clear if you look at an alternative syntax, which is converting the bloc to a proc argument.
For example, the following examples are the same
def my_each(arr)
arr.each { |x| yield x }
end
def my_each(arr, &blk)
arr.each { |x| blk.call(x) }
end
# Both are called the same way
my_each([1,2,3]) { |x| print x }
# => 123
When using yield, the variable is available in the method without declaring it in the parameters list. Prepending an & sign to a parameter converts it to a proc, so in the method it can be run with .call.
Here's an example of providing a block to one method then executing it two scopes in:
def method_a(number, &blk)
method_b do
method_c do
blk.call(number)
end
end
end
def method_b(&blk)
blk.call
end
def method_c(&blk)
blk.call
end
method_a(1) { |num| puts num + 1 }
# => 2
Note that blk is not a magic word - you can name the variable whatever you want.
Here's the same thing with yield:
def method_a(number)
method_b do
method_c do
yield number
end
end
end
def method_b
yield
end
def method_c
yield
end
method_a(1) { |num| puts num + 1 }
# => 2
I think using the &blk syntax is clearer because it assigns a variable to the proc. Just because a proc is used in the method doesn't mean you have to ever run Proc.new. The block is automatically converted to a proc.

How to DRY a list of functions in ruby that are differ only by a single line of code?

I have a User model in a ROR application that has multiple methods like this
#getClient() returns an object that knows how to find certain info for a date
#processHeaders() is a function that processes output and updates some values in the database
#refreshToken() is function that is called when an error occurs when requesting data from the object returned by getClient()
def transactions_on_date(date)
if blocked?
# do something
else
begin
output = getClient().transactions(date)
processHeaders(output)
return output
rescue UnauthorizedError => ex
refresh_token()
output = getClient().transactions(date)
process_fitbit_rate_headers(output)
return output
end
end
end
def events_on_date(date)
if blocked?
# do something
else
begin
output = getClient().events(date)
processHeaders(output)
return output
rescue UnauthorizedError => ex
refresh_token()
output = getClient().events(date)
processHeaders(output)
return output
end
end
end
I have several functions in my User class that look exactly the same. The only difference among these functions is the line output = getClient().something(date). Is there a way that I can make this code look cleaner so that I do not have a repetitive list of functions.
The answer is usually passing in a block and doing it functional style:
def handle_blocking(date)
if blocked?
# do something
else
begin
output = yield(date)
processHeaders(output)
output
rescue UnauthorizedError => ex
refresh_token
output = yield(date)
process_fitbit_rate_headers(output)
output
end
end
end
Then you call it this way:
handle_blocking(date) do |date|
getClient.something(date)
end
That allows a lot of customization. The yield call executes the block of code you've supplied and passes in the date argument to it.
The process of DRYing up your code often involves looking for patterns and boiling them down to useful methods like this. Using a functional approach can keep things clean.
Yes, you can use Object#send: getClient().send(:method_name, date).
BTW, getClient is not a proper Ruby method name. It should be get_client.
How about a combination of both answers:
class User
def method_missing sym, *args
m_name = sym.to_s
if m_name.end_with? '_on_date'
prop = m_name.split('_').first.to_sym
handle_blocking(args.first) { getClient().send(prop, args.first) }
else
super(sym, *args)
end
end
def respond_to? sym, private=false
m_name.end_with?('_on_date') || super(sym, private)
end
def handle_blocking date
# see other answer
end
end
Then you can call "transaction_on_date", "events_on_date", "foo_on_date" and it would work.

ruby pass method as a parameter

Im trying to pass a method as a parameter to method_2, execute this one and return the result:
def method_2( method_p, param )
res = method(method_p).call(param)
return res
end
def method_1
klass = MyKlass.instance
return method_2( klass.foo, "test" )
end
this's MyKlass file:
class MyKlass
def foo(param)
param+param
end
end
All I got is an error
wrong number of arguments (0 for 1)
You can use symbols to refer to methods:
def method_2(method_symbol, *args)
send method_symbol, *args
end
However, since you're calling the method on a specific object, you would either have to pass that in as an additional argument, or use a proc or a lambda, which is like a block wrapped in an object:
def method_2(proc, *args)
proc.call(*args)
end
method_2(->(param){ klass.foo(param) }, "test")
It's more common to just use blocks to do this:
def method_2(receiver, *args, &block)
yield receiver, *args
end
method_2(klass, "test") do |receiver, param|
receiver.foo(param)
end
All of these are fairly contrived examples; is there a specific problem you're trying to solve?
When you:
return method_2( klass.foo, "test" )
klass.foo requires one arg, that might be what's causing your error.

How to pass Arguments and use those in (resque-status) Resque::JobWithStatus?

my resque worker class is:
require 'resque'
require 'resque/job_with_status'
class PatstatResqueWorker < Resque::JobWithStatus
#queue = :my_worker_q
def self.perform(query, label)
puts "query:"
puts options['query']
puts "label:"
puts options['label']
end
end
and my controller part, where I call this resque is...
class MyController < ApplicationController
def resque
job_id = PatstatResqueWorker.create(:query => #query, :label => "yes")
status = Resque::Plugins::Status::Hash.get(job_id)
end
end
and its not working :(
if i remove the parameter from resque function it says Wrong number of arguments (2 for 0) and if i add the parameter section back it says options not defined :(
Could you help?
The reason you're getting the "options not defined" error is that you haven't defined options in the method that uses it. Your self.perform method expects to receive two distinct arguments, query and label, but the code inside the method expects to have an options hash. You've got to choose one or the other.
Either do this:
def self.perform(query, label)
# use the parameters we've already defined
puts "query:"
puts query
puts "label:"
puts label
end
# call it like this
PatstatResqueWorker.create(#query, "yes")
Or else do this:
# change the method signature to match what you're doing
def self.perform(options)
puts "query:"
puts options['query']
puts "label:"
puts options['label']
end
# call it like this, with string keys
PatstatResqueWorker.create('query' => #query, 'label' => "yes")
Notice that with the hash version, I changed the call to use strings for the hash keys instead of symbols. You can use symbols if you want, but you'd have to change it in the body of the method as well (i.e. options[:query] instead of options['query']). You've just got to be consistent.

How to define a method some how like the 'yield' ( I mean, automatically catch the block)?

If I need to define a method called 'yields' which will call yiled 3 times:
def yields
3.times do
yield
end
end
And then I will use it in an other method:
def call_me_3_times
yields
end
In the console or irb:
>> call_me_3_times { puts 'me'} # => Cause error
=> LocalJumpError: no block given (yield)
from (irb):32:in `yields'
from (irb):35:in `call_me_3_times'
I hope you can read what I want;
And how to make the 'yields' autolly capture the block given?
I mean that when we use the 'yields',we don't need to pass it a '&block', just like the usage of 'yield'(we don't have to even mustn't pass the '&block' to 'yield', need we?).
Something like:
def call_me_3_times &block
yields &block
end
I tried to look at yield implementation to see if we could reproduce its behaviour, but I think it is a keyword, so there's no way to look at the implementation.
I tried with block_given, and looking at the implementation from the ruby core rdocs, I found that block_given? is implemented this way :
rb_f_block_given_p()
{
if (ruby_frame->prev && ruby_frame->prev->iter == ITER_CUR && ruby_block)
return Qtrue;
return Qfalse;
}
As you see, it's C, so it's too low-level implementation. We can't do the same.
If block_given? methods needs to rely on C implementation to just check that a block is given, I can't see how we could get that block and call it within ruby code.
So I think there's no way to do what you want.
You need given a block to you yields method or avoid yield if no block
no yield if no block :
def yields
3.times do
yield if block_given?
end
end
Pass a block to your yields methods
def call_me_3_times
yields { puts 'hello' }
end
A solution to this can be created using the techniques described in this blog post http://weblog.raganwald.com/2008/06/what-does-do-when-used-as-unary.html
def call_me_three_times
yields &(Proc.new) if block_given?
end
When you define a method as def some_method(&block) ruby will expect you to pass a block to the method. It will convert that block to a Proc and store it in the block variable.
If you prefix a Proc object with an & it will convert it to a block.
If you call Proc.new within a method and do not provide it with a block then it will create a Proc from the block passed to it.
Some test results are below
def yields
puts "Tripling"
3.times do
yield
end
end
def call_me_three_times
yields &(Proc.new) if block_given?
end
x="Foo"
call_me_three_times { puts x }
x="Bar"
call_me_three_times { puts x }
call_me_three_times
Output
Tripling
Foo
Foo
Foo
Tripling
Bar
Bar
Bar

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