jQuery.parseJSON not working for JsonResult from MVC controller action - asp.net-mvc

Question

I am trying to use jQuery.parseJSON to parse out the return value from an MVC3 controller action.
Controller:
[HttpPost]
public JsonResult LogOn(LogOnModel model, string returnUrl)
{
.. do stuff ..
if (errors.Count() < 0)
{
return Json(new object[] { true, model, errors });
}
return Json(new object[] { false, model, errors });
}
jQuery:
$.ajax({
url: form.attr('action'),
type: "POST",
dataType: "json",
data: form.serialize(),
success: function (data) {
var test = jQuery.parseJSON(data);
}
});
Json result from fiddler:
Content-Type: application/json; charset=utf-8
[false,{"UserName":"1","Password":"2","RememberMe":false},[{"Key":"","Errors":[{"Exception":null,"ErrorMessage":"The
user name or password provided is incorrect."}]}]]
Fiddler can parse the results:
The call to jQuery.parseJSON is returning null.
My questions is, how can I parse the json return value into an object?
Thanks!

Answer 1

You don't need to call parseJSON in your success handler, because ajax will have already parsed the JSON result (it does this automatically because you specified dataType:'json') into your array.
However, I'd recommend returning some sort of result object (whether you create an actual class in C# or use an anonymous type).
[HttpPost]
public JsonResult LogOn(LogOnModel model, string returnUrl)
{
.. do stuff ..
if (errors.Count() < 0)
{
return Json(new { success=true, model, errors });
}
return Json(new { success=false, model, errors });
}
and at the client
$.ajax({
url: form.attr('action'),
type: "POST",
dataType: "json",
data: form.serialize(),
success: function (result) {
alert(result.success);
// also have result.model and result.errors
}
});

Answer 2

You are actually returning an array of objects and they shoould be accessed like this in the success function:
var booleanValue = data[0];
var yourModel = data[1];
var yourErrors = data[2];
I did give #HackedByChinese an up vote because naming the properties might be a better way to go about it in the end. Howvbere this will solve your immediate problem.