I don't know if there's a good answer for this. Let's say I have:
users = User.where(:location => "Utopia") #=> Returns [user1,user2,user3,user4]
I would like do something like:
users.photos #=> Returns all photos this group of users has
And simply get all the photos back without iterating over them. I ask because each iteration is a DB call. Is there any good way that does a single DB call?
The most straightforward way to do this is to use the eager loader:
users = User.where(:location => 'Utopia').includes(:photos)
That will fetch the users in one pass, then the relationships and their associated photos in another. You can wrap it all up into one call if you either use a JOIN or a subselect, it's your call, but it'll look something like this:
photos = Photo.includes(:user).where('users.location' => 'Utopia')
There's more information available in the Active Record Query Interface documentation in section 12.
Related
I'm not sure if this is just a lacking of the Rails language, or if I am searching all the wrong things here on Stack Overflow, but I cannot find out how to add an attribute to each record in an array.
Here is an example of what I'm trying to do:
#news_stories.each do |individual_news_story|
#user_for_record = User.where(:id => individual_news_story[:user_id]).pluck('name', 'profile_image_url');
individual_news_story.attributes(:author_name) = #user_for_record[0][0]
individual_news_story.attributes(:author_avatar) = #user_for_record[0][1]
end
Any ideas?
If the NewsStory model (or whatever its name is) has a belongs_to relationship to User, then you don't have to do any of this. You can access the attributes of the associated User directly:
#news_stories.each do |news_story|
news_story.user.name # gives you the name of the associated user
news_story.user.profile_image_url # same for the avatar
end
To avoid an N+1 query, you can preload the associated user record for every news story at once by using includes in the NewsStory query:
NewsStory.includes(:user)... # rest of the query
If you do this, you won't need the #user_for_record query — Rails will do the heavy lifting for you, and you could even see a performance improvement, thanks to not issuing a separate pluck query for every single news story in the collection.
If you need to have those extra attributes there regardless:
You can select them as extra attributes in your NewsStory query:
NewsStory.
includes(:user).
joins(:user).
select([
NewsStory.arel_table[Arel.star],
User.arel_table[:name].as("author_name"),
User.arel_table[:profile_image_url].as("author_avatar"),
]).
where(...) # rest of the query
It looks like you're trying to cache the name and avatar of the user on the NewsStory model, in which case, what you want is this:
#news_stories.each do |individual_news_story|
user_for_record = User.find(individual_news_story.user_id)
individual_news_story.author_name = user_for_record.name
individual_news_story.author_avatar = user_for_record.profile_image_url
end
A couple of notes.
I've used find instead of where. find returns a single record identified by it's primary key (id); where returns an array of records. There are definitely more efficient ways to do this -- eager-loading, for one -- but since you're just starting out, I think it's more important to learn the basics before you dig into the advanced stuff to make things more performant.
I've gotten rid of the pluck call, because here again, you're just learning and pluck is a performance optimization useful when you're working with large amounts of data, and if that's what you're doing then activerecord has a batch api you should look into.
I've changed #user_for_record to user_for_record. The # denote instance variables in ruby. Instance variables are shared and accessible from any instance method in an instance of a class. In this case, all you need is a local variable.
I have a collection that contains a class like:
locations = Location.all
class Location < ActiveRecord::Base
end
The location class has a property: code
I wan to remove an item from the collection if code == "unused".
How many different ways can I do this in ruby?
I am currently doing this:
locations = Location.all.select { |l| l.code != "unused" }
This works great but just wondering what other ways I could do this just for learning purposes (if there big performance advantages in another way that would be good to know also).
Update
Please ignore the fact that I am loading my collection initially from the database, that wasn't the point. I want to learn how to remove things in-memory not simple where clauses :)
You can simply fetch records from your database what you need:
Rails 4 onwards:
locations = Location.where.not(code: "unused")
Before Rails 4:
locations = Location.where("code != ?", "unused")
If you have a collection and you want to reject some items from it, then you can try this:
locations.reject! {|location| location.code != "unused"}
You are doing this the wrong way. In your case, you are retrieving all records from DB and getting an array of records. Then you are looking for records you need in the array. Instead, you should get the records directly from DB:
Location.where("code != 'unused'")
# or in Rails 4 and latest
Location.where.not(code: "unused")
If you need to remove records from DB, you can do it like this:
Location.where.not(code: "unused").destroy_all
If you just want to know what is the best way to remove elements from an existing array, I think you are on the right track. Besides select there are reject, reject!, delete_if methods. You can learn more about them in the documentation http://ruby-doc.org/core-2.3.1/Array.html
There is a related post that might give more information: Ruby .reject! vs .delete_if
In our rails 3.2 app, we need to retrieve all customer records out of customer table and assign them to a variable customers and do query (such as .where(:active => true) on variable customers late on. There are 2 questions here:
what's the better way to retrieve all records?
Customer.all works. However according to rails document, it may have performance issue when Customer table gets large. We tried Customer.find_each and it has error "no block given (yield)".
How to make the variable customers query_able?
When performing query on variable customers (like customers.where(:active => true)), there is an error: undefined methodwhere' for #. It seems that thecustomersis an array object and can't takewhere. How can we retrievecustomers` in such a way it can be query-able?
Thanks for help.
In Rails < 4 .all makes database call immediately, loads records and returns array. Instead use "lazy" scoped method which returns chainable ActiveRecord::Relation object. E.g.:
customers = Customer.scoped
...
customers = customers.where(:active => true)
customers = customers.where(...)
etc...
And at the moment when you will need to load records and iterate over them you can call find_each:
customers.find_each do |customer|
...
end
I am using Braintree for managing subscriptions in my Rails app.
I have a Subscription model that stores the braintree customer ID and subscription ID.
I want to filter active subscriptions in my Subscription model. So far I have
def find_active_subscriptions
#active_subscriptions = Braintree::Subscription.search do |search|
search.status.is "Active"
end
But now I want to use the subscription IDs in #active_subscriptions to find all of the objects in my local Subscription model with the same subscription IDs and put that into a variable such as #local_active_subscriptions.
The reason I have to do this is to use the local info to access Braintree::Address and only pull active addresses.
Thanks for the help.
One you have the #active_subscriptions you can collect all of the ids into an array and pass them right into the find method of your local Subscription model. I don't know what attributes you are using here, so I'm just making some guesses:
#active_subscription_ids = #active_subscriptions.collect(&:subscription_id)
#local_active_subscriptions = LocalSubscriptionModel.find(#active_subscription_ids)
I'm not sure what Braintree::Subscription.search returns, but if it's something akin to ActiveRecords, could you use something like:
#local_active_subscriptions = Subscription.where("id IN(?)", #active_subscriptions.map{ |act_subs| act_subs.id })
The .map function should put all the IDs into an array, and then ActiveRecord query would look for all the Subscriptions in your subscriptions table whose ID is in that array.
I'm not certain about mapping on Braintree::Subscriptions; I've never used that.
Edit
Like ctcherry said, you can also do the search with find. And I guess collect is good for mapping the ids into an array too. You could also maybe use #active_subscriptions.map(&:id)
I write follow code to get one record from the table webeehs:
webeehs_result = Webeeh.find(:all, :conditions=>["webeeh_project_id=#{project_id}"])
Then I want to get one column value from this record, how could I do?
For example, the column name is webeeh_date.
first of all, never EVER write code like that. Building your own conditions as pure strings can leave you vulnerable to SQL injection exploits. If you must do conditions, then do it like this:
:conditions => ["webeeh_project_id = ?", project_id]
if you have a Project model, you should rename the webeeh_project_id column from your Webeeh model into project_id and have an association in your Project model like has_many :webeehs
Then, you won't need to call that find anymore, just do a p = Project.find(id) and then p.webeehs will return the webeehs you need.
the result will be an array which you can iterate through. And to get your webeeh.webeeh_date member, just call it like this:
result.each do |webeeh|
date = webeeh.webeeh_date
end
webeehs_result = Webeeh.findwebeeh_dates
is enough to get all columnn values.
For a different method and performance issues check the following: http://www.stopdropandrew.com/2010/01/28/finding-ids-fast-with-active-record.html
webeeh_result will usually be an array of results for the database.
You can iterate throughit using
webeehs_result.each do |webeeh|
# use "webeeh.webeeh_date" to access the column_name or do whatever you want with it.
end