I get the tree in symfony with propel with this way:
$tree = FoldersQuery::create()->findTree();
Now, how to list the tree with each child properly?
I want parents be on a specific div, children on an another div and list them. But how?
How to get the relationships between each item and know how to render it?
Thanks a lot.
You should read this documentation http://www.propelorm.org/behaviors/nested-set.
You can get all children with getChildren(), know whether it's a root node or not with isRoot(), know the level, ...
See more on the API section, it will help you :)
Related
I am working on creating nodes and relationships. For a particular type of node, there is a hyperlink that I would like attach to it(perhaps as a property) so that users would be able to click and see more details on that node.
Does anyone know if that is possible? Happy to provide more details if needed.
Thanks in advance.
A standard string property would work just fine. It works as a regular hyperlink in the Neo4j browser.
CREATE (n:Sample {link: "https://google.com"}) RETURN n;
I have to show nested level table in tree structure. the level may be 5 or 6 times nested.
Please suggest me how I will achieve this.
I am not sure what you are looking for but you can try to find an open source component that can do this for you.
You can find such components by using this website for example:
https://www.cocoacontrols.com/search?utf8=%E2%9C%93&q=tableview
I have strange question. I want in my helper to have array of paths that are available for specific resource.For example, if we have a model Comment I want to have an array which will have the following elements: [new_comment_path, comments_path] etc. Is this possible to do?
Edit:
I build left side menu in rails. It will work like tree menu. I don't want to use external plugins. Only thing that i must do is to have a all paths for my models.
You can do
Rails.application.routes.routes.map{|x| x.name}.reject{|x| x.blank?}
Which will get all named routes. I'm not sure if there is a way of just getting routes for one resource though
I know this is possible but I can't seem to find the right search string to get the answer online.
I have MyForm()
and I want to create 5 of these rendered within the same form so I want to change the naming structure of the form elements thus:
name="forms[1][fieldname1]"
name="forms[1][fieldname2]"
name="forms[2][fieldname1]"
name="forms[2][fieldname2]"
etc
so that when it is submitted I can just iterate through the $_POST['forms'] array, binding each one to a MyForm instance and validating.
I'm sure you can customise he naming of fields for symfony forms in some global way rather than going through each widget but I just can't find it on the web.
Anyone point me in the right direction?
Thanks.
Solved own problem :
$this->widgetSchema->setNameFormat('my_form[][%s]');
SmartGWT has this property for a TreeGrid object:
employeeTreeGrid.setSelectionAppearance(SelectionAppearance.CHECKBOX);
This by default 'prepends' every nodes (including root) with checkbox.
(Just making myself clear.)
Also, I am aware of this similar solved question:
GWT tree with checkbox:How to get all checked tree items?
However, I do not seek this kind of solution..
What I'm looking for is a more efficient way, where I don't have to loop through 1000 items.
Is there any way to do this, if possible, using the widget I am using now?
If not, is there any other way, using other widget?
Thank you very much!
I think as you use SelectionAppearance.CHECKBOX you tell to the grid that the selected records are marked by the checkbox field value. So every time you check one you select a record.
You can get the set of selected records by either getSelection() method or getSelectedRecords(boolean) because of deprecation of the previuous one.
You can have a look at the code of this example of the smartgwt showcase.