Im getting a response from twitter in the form of a string,
What I need is to send the parts where is a comment to an array,
here an example of the string
[{"geo":null,"coordinates":null,"retweeted":false,...
"text":"#KristinaKlp saluditos y besos d colores!"},{"geo":null,"coordinates...
so what I really need are the posts after "text":" =
#KristinaKlp saluditos y besos d colores!
So, how can I take the string and parse it so I get all the messages in an array hopefully?
Thanks a lot!
I haven't done JSON parsing myself in an iOS App, but you should be able to use a library like the json-framework. This library will allow you to easily parse JSON and generate json from dictionaries / arrays (that's really all JSON is composed of).
SBJson docs:
JSON is mapped to Objective-C types in the following way:
null -> NSNull
string -> NSString
array -> NSMutableArray
object -> NSMutableDictionary
true -> NSNumber's -numberWithBool:YES
false -> NSNumber's -numberWithBool:NO
integer up to 19 digits -> NSNumber's -numberWithLongLong:
all other numbers -> NSDecimalNumber
Since Objective-C doesn't have a dedicated class for boolean values,
these turns into NSNumber instances. However, since these are
initialised with the -initWithBool: method they round-trip back to JSON
properly. In other words, they won't silently suddenly become 0 or 1;
they'll be represented as 'true' and 'false' again.
As an optimisation integers up to 19 digits in length (the max length
for signed long long integers) turn into NSNumber instances, while
complex ones turn into NSDecimalNumber instances. We can thus avoid any
loss of precision as JSON allows ridiculously large numbers.
#page objc2json Objective-C to JSON
Objective-C types are mapped to JSON types in the following way:
NSNull -> null
NSString -> string
NSArray -> array
NSDictionary -> object
NSNumber's -initWithBool:YES -> true
NSNumber's -initWithBool:NO -> false
NSNumber -> number
#note In JSON the keys of an object must be strings. NSDictionary
keys need not be, but attempting to convert an NSDictionary with
non-string keys into JSON will throw an exception.
NSNumber instances created with the -numberWithBool: method are
converted into the JSON boolean "true" and "false" values, and vice
versa. Any other NSNumber instances are converted to a JSON number the
way you would expect.
Tutorials
Are there any tutorials? Yes! These are all tutorials provided by
third-party people:
JSON Framework for iPhone - a Flickr tutorial in three parts by John
Muchow. JSON Over HTTP On The iPhone - by Dan Grigsby. AS3 to Cocoa touch: JSON by Andy Jacobs.
There are other libraries you can check out as well like TouchJSON, JSONKit, Yet Another JSON Library
NSJSONSerialization does the job of converting your JSON data into usable data structures as NSDictionary or NSArray very well. I recommend it, even more because it is part of the Cocoa public interface and it is maintained by Apple.
However, if you want to map the content of your JSON to your Objective-C objects, you will have to map each attribute from the NSDictionary/NSArray to your object property. This might be a bit painful if your objects have many attributes.
In order to automatise the process, I recommend you to use the Motis category (personal project) on NSObject to accomplish it, thus it is very lightweight and flexible. You can read how to use it in this post. But just to show you, you just need to define a dictionary with the mapping of your JSON object attributes to your Objective-C object properties names in your NSObject subclasses:
- (NSDictionary*)mjz_motisMapping
{
return #{#"json_attribute_key_1" : #"class_property_name_1",
#"json_attribute_key_2" : #"class_property_name_2",
...
#"json_attribute_key_N" : #"class_property_name_N",
};
}
and then perform the parsing by doing:
- (void)parseTest
{
NSData *data = jsonData; // <-- YOUR JSON data
// Converting JSON data into NSArray (your data sample is an array)
NSError *error = nil;
NSArray *jsonArray = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableContainers error:&error];
if (error)
return; // <--- If error abort.
// Iterating over raw objects and creating model instances
NSMutableArray *parsedObjects = [NSMutableArray array];
for (NSDictionary *rawObject in jsonArray)
{
// Creating an instance of your class
MyClass instance = [[MyClass alloc] init];
// Parsing and setting the values of the JSON object
[instance mjz_setValuesForKeysWithDictionary:rawObject];
[parsedObjects addObject:instance];
}
// "parseObjects" is an array with your parsed JSON.
// Do whatever you want with it here.
}
The setting of the properties from the dictionary is done via KeyValueCoding (KVC) and you can validate each attribute before setting it via KVC validation.
I recently had to do this. After looking at the various options out there, I threw JSONKit into my app (I found it on a JSON discussion on StackOverflow). Why?
A) It is VERY VERY simple. I mean, all it has is the basic parsing/emitting functions, what more do you need?
B) It is VERY VERY fast. No overhead - just get the job done.
I should note, I had never done JSON before - only heard of the term and didn't even know how to spell it. I went from nothing, to a working app, in about 1 hour. You just add one class to your app (the .h, .m), instantiate it, and call the parser to a dictionary object. Voila. If it contains an array, you just get the objectForKey, cast it as an NSArray. It's really hard to get simpler than that, and very fast.
For a good comparison of the speed of the different libraries for JSON parsing on iOS, take a look at The Ultimate Showdown.
-(IBAction)btn_parse_webserivce_click:(id)sender
{
// Take Webservice URL in string.
NSString *Webservice_url = self.txt_webservice_url.text;
NSLog(#"URL %#",Webservice_url);
// Create NSURL from string.
NSURL *Final_Url = [NSURL URLWithString:Webservice_url];
// Get NSData from Final_Url
NSData* data = [NSData dataWithContentsOfURL:
Final_Url];
//parse out the json data
NSError* error;
// Use NSJSONSerialization class method. which converts NSData to Foundation object.
NSDictionary* json = [NSJSONSerialization
JSONObjectWithData:data
options:kNilOptions
error:&error];
// Create Array
NSArray* Response_array = [json objectForKey:#"loans"];
NSLog(#"Array: %#", Response_array);
// Set Response_array to textview.
self.txt_webservice_response.text = [NSString stringWithFormat:#"%#"
,Response_array];
}
How about NSJSONSerialization? I've been using it to parse JSON
http://developer.apple.com/library/ios/#documentation/Foundation/Reference/NSJSONSerialization_Class/Reference/Reference.html
Related
The following code to conditionally concatenate strings for a dictionary seems to work up to the point where I try to place the concatenated result in the dictionary. Can anyone see the error?
NSDictionary *jsonDictionary;
NSString* dictString = #"#\"first\":first,#\"last"
NSString *dictString2=dictString;
if (date.length>0&&![date isKindOfClass:[NSNull class]]) {
//only include this key value pair if the value is not missing
dictString2 = [NSString stringWithFormat:#"%#%s", dictString, "#\"date\":date"];
}
jsonDictionary = #{dictString2}; //syntax error. Says expected colon but that does not fix anything
The syntax for creating an NSDictionary using object literals is:
dictionary = #{key:value}
(and optionally, it can contain multiple key/value pairs separated by commas, but never mind that right now.)
Where "key" and "value" are both NSObjects.
Your line that is throwing the error only contains 1 thing. The contents of a the string in dictString2 has nothing to do with it.
It looks to me like you are trying to build a JSON string manually. Don't do that. Use NSJSONSerialization. That class has a method dataWithJSONObject that takes an NSObject as input and returns NSData containing the JSON string. That's how you should be creating JSON output.
Creating an NSDictionary with values that may be null:
NSDictionary *dict = #{
#"key" : value ?: [NSNull null],
};
When serializing a dictionary, NSNulls are translated to null in the JSON.
If you want to exclude such keys completely, instead of having them with a null value, you'll have to do more work. The simplest is to use an NSMutableDictionary and test each value before adding it.
So I was working on a project that required me to work with some JSON, I was running into a few issues regarding the best way of representing things. First of, this is how the JSON looks:
"phoneList": [
{
"phoneReason": "End of Contract",
"phoneType": [
{
"id": 5,
"phoneType": "Android Smartphone"
}
]
}
]
I want to know the most appropriate way of representing this.
For example, I do know that that my phoneReason will just be a simple NSString while my phoneType is actually a NSArray. However,I wasn't sure how to represent a)the id, I know this is an integer, but should this be an NSInteger or an NSNumber and b)could someone point me in the direction of some sample code where I can understand how to model a dictionary object containing an integer and a string and also where I can understand how to model an array of dictionaries.
My other question is also similar in that say I'm actually posting something, how do I model this, specifically say for like dictionary type (JSON Curly Brace)objects that contain a number/integer and a string.
For example, this is the JSON I'm trying to model and then do something like this:
"phoneReason": "Upgrade",
"phoneInfo": {
"id": "2"
},
//And then I want to pass ID
-(void) createOurRequest:(NSNumber *)id {
NSDictionary *myDictionary = #{
#"phoneReason" : [NSString stringWithFormat:#"%i", s elf.dat.reason],
//How do I then represent the phoneInfo element exactly?
};
Sorry, for the clumsy question, would really appreciate any guidance on modeling JSON in iOS or just generally.
I'm assuming you're asking questions a) and b), and also how to model a JSON.
a) The unfortunate thing with Obj-C is that all collection elements have to be objects. Integers are value types, so they will need to be converted to NSNumbers to work. However, if you're parsing a JSON string, the builtin JSON parser does it for you. I'll describe it below.
b) The model is based on the JSON. You describe the object collection and the parser will determine the model for you. In your example, you would have a NSDictionary<NSString *: NSArray<NSDictionary<NSString *: id>*>*>. The innermost element has value of id because you can either have an NSString ("End of Contract") or an NSArray ("phoneType": [ { "id": 5, "phoneType": "Android Smartphone" } ])
Of course, the model is defined by your JSON, so if you run it through a parser, you get a structured object. You can access each element based on your model (object[#"phoneList"][#"phoneReason"]).
The class method to use is:
+ (id)JSONObjectWithData:(NSData *)data
options:(NSJSONReadingOptions)opt
error:(NSError **)error
Where you pass it a NSData representation of your string, options (or 0), and a NSError pointer (error*). You get back a parsed JSON with the proper structure you defined.
NSDictionary *parsedJSONObject = [NSJSONSerialization JSONObjectWithData:jsonData options:0 error:NULL
I have no options to use and I know there will be no error, so I pass nothing for those parameters. The resulting object will be in whatever structure your JSON is.
Using the objects and the json layout you provided in your first example, this is how I would go about creating the dictionaries and arrays to get the json in the format you specified. Hopefully this helps make it a little clearer for you.
// example constructor method
-(void) jsonStringWithPhoneReason:(NSString*)reason phoneId:(NSInteger)phoneId phoneType:(NSString*)phoneType
{
// create device detail dictionary
NSDictionary *deviceOneDetail = #{
#"id" : #(phoneId), // <- set phone id as NSNumber
#"phoneType" : phoneType // <- set your string phone type
};
// create device dictionary
NSDictionary *deviceOne = #{
#"phoneReason" : reason, // <- set your phone reason string
#"phoneType" : #[deviceOneDetail] // <- set your phone type dictionary within an array
};
// create phone list dictionary with any device dictionaries you want to add
NSDictionary *phoneListDict = #{
#"phoneList" : #[
deviceOne, // <- add your device to the phone list array of dictionaries
// deviceTwo...
]
};
NSString *jsonString = [self convertToJsonString:phoneListDict]; // <- convert the dictionary into a json string and use however you wish
// your json string should now look like this assuming you pass 'End of Contract', 5 & 'Android Smartphone' as arguments to this method
// {"phoneList":[{"phoneReason":"End of Contract","phoneType":[{"id":5,"phoneType":"Android Smartphone"}]}]}
}
-(NSString*) convertToJsonString:(NSDictionary*)dictionary
{
NSError *error;
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:dictionary
options:0 // Pass 0 if you don't care about the readability of the generated string
error:&error];
if (error)
{
NSString *errorDesc = [NSString stringWithFormat:#"Error creating json data from dictionary: %#", error.localizedDescription];
NSLog(#"ERROR: %#", errorDesc);
jsonData = nil;
return nil;
}
NSString *returnString = nil;
if(jsonData != nil)
{
returnString = [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding];
}
return returnString;
}
I have a problem when encode an NSMutableArray array of custom object (Room).
My custom object is : -nameRoom (NSString) -numberRoom (NSInteger).
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:array options:NSJSONWritingPrettyPrinted error:&error];
NSString *jsonString = [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding];
This is the error:
Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'Invalid type in JSON write (Room)
Thanks.
From the docs (yes, sometimes reading the documentation is helpful)
You use the NSJSONSerialization class to convert JSON to Foundation
objects and convert Foundation objects to JSON.
An object that may be converted to JSON must have the following
properties:
The top level object is an NSArray or NSDictionary.
All objects are instances of NSString, NSNumber, NSArray, NSDictionary, or NSNull.
All dictionary keys are instances of NSString.
Numbers are not NaN or infinity.
Other rules may apply. Calling isValidJSONObject: or attempting a
conversion are the definitive ways to tell if a given object can be
converted to JSON data.
JSON does not support custom objects.
See: Introducing JSON.
In order to support a custom object you will have to break it down into a graph of standard JSON objects. In the OP's case it will simply be a dictionary containing nameRoom and numberRoom.
I have a cuestion about parsing a Json strings.
If i'm getting a string like:
[["AR","Argentina","flag_of_argentina","en","F","1"],
["AU","Australia","flag_of_australia","en","B","4"]]
How can i save this string into an entity when normally i see Jsons that have something like this:
(
(
"Group_id": 1,
"Date" : "2014-04-08",
"Hour" : "18:00:00",
"Location":"Guayaquil, Ecuador",
"State" : A
),
...
If i have to make an array or something else to store it to the entity in core data how can i do it?
I hope my question is well made and I appreciate your help. Thank you very much.
Cocoa Touch provides a built in class that helps you serialize this data. It's called NSJSONSerialization.
So, that looks to me like you have arrays within an array. First you're going to want to convert the NSString to NSData:
NSData *JSONdata = [yourJSONString dataUsingEncoding:NSUTF8StringEncoding];
Then serialize it into an array:
NSArray *JSONArray = [NSJSONSerialization JSONObjectWithData:JSONdata options:NSJSONReadingMutableContainers error:&error];
Then you can access any subarray by writing:
NSArray *countryData = [JSONArray objectAtIndex:i];
And from there you can access the data that you need.
~
As for building JSON Data, you'll need to construct an NSMutableDictionary and populate it accordingly. Once you have that, use the same class NSJSONSerialization to convert it to a JSON string.
I'm doing some testing on AddressBook and though I can get the data I am looking for I'm curious about how it is delivered. Specifically CFDictionaryRef. When I cast this to a NSDictionary and log to console I just get a string value, not a key=value pair. If I try to log allKeys my test app breaks.
Here's the code snippet I'm using:
if ([contactName isEqualToString:ownerName]) {
//get reference to their email addresses
ABMultiValueRef contactEmails = ABRecordCopyValue(thisPerson, kABPersonEmailProperty);
//loop
for (NSUInteger e = 0; e < ABMultiValueGetCount(contactEmails); e++){
CFDictionaryRef thisPersonCFEmailDict = ABMultiValueCopyValueAtIndex(contactEmails, e);
NSDictionary* thisPersonEmailDict = (__bridge NSDictionary*)thisPersonCFEmailDict;
NSLog(#"%#", [thisPersonEmailDict allKeys]);
}
}
You're assuming ABMultiValueCopyValueAtIndex() returns a CFDictionaryRef. It doesn't. It returns whatever value is appropriate for that multi-value, as evidenced by the CFTypeRef return value.
You can use ABMultiValueGetPropertyType() to find out what type of value a particular multi-value record has. If that returns kABDictionaryPropertyType then you know it's a dictionary, but in your case it's probably returning kABStringPropertyType. It could also return kABInvalidPropertyType, which may indicate that the multi-value contains different types. If so, you'll need to resort to using CFGetTypeID() to identify the type of value returned from ABMultiValueCopyValueAtIndex().
CFDictionaryRef is the Core Foundation counterpart of NSDictionary. Because NSDictionary and CFDictionary are “toll-free bridged,” you can substitute a CFDictionary object for a NSDictionary object in your code (with appropriate casting). Although they are corresponding types, CFDictionary and NSDictionary do not have identical interfaces or implementations, and you can sometimes do things with CFDictionary that you cannot easily do with NSDictionary. Toll-free bridging, means that you can use the same data type as the parameter to a Core Foundation function call or as the receiver of an Objective-C message.