I've got a checkbox that I want hidden on the page. My obvious first attempt was the following:
<input type='checkbox' style='display:none' />
However, I noticed jquery mobile automagically wraps the checkbox in a div that looks like this:
<div class='ui-checkbox'>
<input type='checkbox' style='display:none;' />
</div>
I would assume that there's some kind of data- element that would prevent this additional styling, but haven't found it in the docs or elsewhere. It's easy enough to override the .ui-checkbox in css to hide it as well, but would prefer a more jquery mobile-standard approach. Does such a thing exist?
The attribute that prevents styling is data-role="none"
<input type='checkbox' style='display:none' data-role="none" />
See the Jquery doc: "Preventing auto-initialization of form elements"
For future users.
Just in case you want to disable for every form element or your forms are loading dynamically where you cannot edit markup use this.
$(document).on('pagebeforecreate', function( e ) {
$( "input, textarea, select", e.target ).attr( "data-role", "none" );
});
I have too many places to change inputs and add data-role="none"
The following code works for me:
<script>
$(document).bind('mobileinit',function(){
$.mobile.page.prototype.options.keepNative = "select,input";
});
</script>
<script src="http://code.jquery.com/mobile/1.4.2/jquery.mobile-1.4.2.min.js"></script>
Related
I am using jQuery UI controlgroup to style checkboxes in an HTML form. After the input values are processed by a PHP script, the results are displayed on the the same page along with the form itself, so that the user can adjust the filters. What I am trying to do, is to have the boxes that were checked previously remain checked after the form has been processed, so that the user sees what selection criteria were used. To achieve that I store all the PHP $_POST data in a JS variable using json_encode, which I'd like to use to iterate through the labels and mark those that were checked previously. The problem is that the only option of the controlgroup widget that I can use is classes with ui-controlgroup-item which shows every single label within the group as active, and for the life of me I cannot figure out how to make it conditional, e.g. so that I can use if(label[for=' + var.value +'])', var being <?php echo json_encode($_POST) ?> or something similar. Will appreciate any suggestions.
Here is the HTML:
<div id="currencyList">
<label for="gbp">GBP</label>
<input type="checkbox" value="gbp" name="currency[]" id="gbp" >
<label for="usd">USD</label>
<input type="checkbox" value="usd" name="currency[]" id="usd">
<label for="eur">EUR</label>
<input type="checkbox" value="eur" name="currency[]" id="eur">
</div>
And this is the JavaScript bit:
$( "#currencyList" ).controlgroup({
classes: {
"ui-controlgroup-item": "ui-checkboxradio-checked ui-state-active"
}
});
After trying to find a solution for several days I decided to skip trying via the classes option and instead to move outside the controlgroup widget. So here is my not-so-pretty-but-working solution:
var postData = <?php echo json_encode($_POST) ?>;
$( "#currencyList" ).controlgroup();
$('#currencyList').children('label').each(function () {
if(postData.currency.indexOf($(this).attr("for")) >= 0){
$(this).addClass( "ui-checkboxradio-checked ui-state-active");
}
});
In iOS 8 and above, to show the Search button on the iOS keyboard, you use the action attribute in the form. From Anton's answer here ... Show 'Search' button in iPhone/iPad Safari keyboard
<form action=".">
<input type="search" />
</form>
But this does not work when you are using an AngularJS form with ng-submit like this
<form action="." ng-submit="doSearch(searchtext)">
<input type="search" ng-model="searchtext" />
</form>
The action attribute breaks the Angular form submit.
Any suggestions on how to put a dummy action attribute and still get ng-submit to handle the form processing? Or any other solution that would show the iOS keyboard's search key with an AngularJS HTML5 form.
Just encountered the same problem, key here is that angular prevents default form submission only if no action specified, so if you want to specify one you need to preventDefault manually, which should be pretty easy.
This should work (worked for me):
<form action="." ng-submit="$event.preventDefault();doSearch(searchtext)">
<input type="search" ng-model="searchtext" />
</form>
Also note, that you will need to blur() your input field after you made a Search request in order to auto-hide keyboard.
Update:
With the latter this directive will help you:
.directive('prettySubmit', function () {
return function (scope, element, attr) {
var textFields = $(element).children('input');
$(element).submit(function(event) {
event.preventDefault();
textFields.blur();
});
};
})
I have placed preventDefault() in directive, so your form will look like this:
<form action="." ng-submit="doSearch(searchtext)" pretty-submit>
<input type="search" ng-model="searchtext" />
</form>
I encountered the same problem.
Finally I decided to use
<form action="{{'#/search/' + searchText }}">
Instead, and it works.
I am trying to bind jquery mobile horizantal radio buttons using knock out teplate binding.
The fielsset in template looks like
<fieldset data-role="controlgroup" data-bind="attr: {id:QuestionID+'_fld'},template: {name:'optionTemplate', foreach: OptionList}">
</fieldset>
and the option template looks like
<script type="text/x-jquery-tmpl" id="optionTemplate">
<input type="radio" data-bind="attr: { id:OptionID+'_radio',value:OptionID, name: QuestionID+'_rd'}, checked:$parent.OptionId" />
<label data-bind="text:OptionText, attr: {id:OptionID+'_optn', for : QuestionID+'_rd' }"> </lable>
</script>
I have tried
$('input[type=radio]').checkboxradio().trigger('create');
$('fieldset').controlgroup().trigger('create');
Here my problem is that the mobile css is not applying to the fiedset.
You must do this after the template has built your page or during the page initialization event, something like this:
$(document).on('pagebeforeshow', '#pageID', function(){
});
Page content can be enhanced ONLY when content is safely loaded into the DOM.
Second this do NOT mix refresh functions with trigger create. Either one or the other. Trigger create is used to enhance whole content, and it should NOT be used on single elements. No point in restyling whole page every time you add new content.
Basically you only want to use:
$('input[type=radio]').checkboxradio().checkboxradio('refresh');
or if first line throws an error:
$('input[type=radio]').checkboxradio();
and:
$('fieldset').controlgroup();
But I would advise you to only use this line after everything has been appended:
$('#contentID').trigger('create');
where #contentID is an id of your div data-role="content" object. Or in case you are not using content div, only data-role="page" div then use this:
$('#pageID').trigger('pagecreate');
where #pageID is an id of your page.
To find out more about marku enhancement of dynamically added content take a look at this answer.
With knockoutjs and jquery mobile, I need to create a list of checkboxes from an array. It seems the checkbox list is rendered, but it did not respond to click. http://jsfiddle.net/9zx7F/
I used a fieldset tag with data-role of controlgroup to build the list. I tried ul with listview as well, same issue.
Edit: further details - I found it seems related to timing of ko.applyBindings happens. I created a page with same code running on my localhost, it was okay. Then added a timer around ko.applyBindings, the issue happened again. http://jsfiddle.net/gonglei/9zx7F/12/
I solved this with two steps;
1) unwrapping the label from the input and hooking them together with 'for' attribute
<input type="checkbox" data-role="checkbox" data-bind="uniqueName: true, uniqueID: true, value: ID />
<label data-bind="uniqueIDFor: true" >Click me</label>
ko.bindingHandlers.uniqueIDFor = {
init: function (element) {
element.setAttribute("for", "ko_unique_" + ko.bindingHandlers.uniqueName.currentIndex);
}
};
ko.bindingHandlers.uniqueID = {
init: function (element) {
element.setAttribute("id", "ko_unique_" + ko.bindingHandlers.uniqueName.currentIndex);
}
};
2) telling jqm to update the new content
$('input:checkbox').trigger('create');
I would change the model for this:
<!-- ko foreach: listItems-->
<input type="checkbox" name="itemsList" value="name" />
<span data-bind="text: name"></span>
<!-- /ko -->
the main thing to consider is the "value" property in the input control to render in the proper way.
Regards.
#tredder's solution works! Here's a fork of your fiddle using the attr data-bind attribute to bind the label, which to me looks cleaner: http://jsfiddle.net/aib42/AnKR6/
I have a form inside an iframe which is inside a jQuery UI dialog box. The form contains a file input type. The jQuery UI dialog contains an Upload button. When this button is clicked, I would like to programmatically call the submit method. My question is how I could select the form which is in a iframe using jQuery. The following code should clarify the picture:
<div id="upload_file_picker_dlg" title="Upload file">
<iframe id="upload_file_iframe" src="/frame_src_url" frameborder=0 width=100% scrolling=no></iframe>
</div>
frame_src_url contains:
<form action="/UploadTaxTable" enctype="multipart/form-data" method="post" id="upload-form">
<p>Select a file to be uploaded:</p>
<p>
<input type="file" name="datafile" size="60">
</p>
The jQueryUI dialog box javascript code:
$('#upload_file_picker_dlg').dialog({
...
buttons: {
'Close': function() {
$(this).dialog('close');
},
'Upload': function() {
$('#upload-form').submit(); //question is related to this line
$(this).dialog('close');
}
},
....
});
From the javascript code snippet above, how can I select the form with id upload-form that is in the iframe whose id is upload_file_iframe ?
Accessing an element inside an iframe is tricky.
You should use the following syntax:
$('#iframeID').contents().find('#upload-form').submit();
where 'iframeID' is obviously an ID you've given to the iframe.
Hope it is correct!
The answer is:
$('#upload_file_iframe').contents().find('#upload-form').submit();
which I learned from http://simple.procoding.net/2008/03/21/how-to-access-iframe-in-jquery/
Off the top of my head I'd say you might have to add the logic to the file where the iframe source is from.