Convert HH:MM:SS to seconds in xcode - ios

Question

Hi I have the code to separate hour,min,sec
Now i have to convert it in to seconds.and nsnumber
NSRange range = [string rangeOfString:#":"];
NSString *hour = [string substringToIndex:range.location];
NSLog(#"time %#",hour);
NSRange range1= NSMakeRange(2,2);
NSString *min = [string substringWithRange:range1];
NSLog(#"time %#",min);
NSRange range2 = NSMakeRange(5,2);
NSString *sec = [string substringWithRange:range2];
NSLog(#"time %#",sec);

Answer 1

If you want to find out how many seconds the hours, minutes and seconds total, you can do something like this:
- (NSNumber *)secondsForTimeString:(NSString *)string {
NSArray *components = [string componentsSeparatedByString:#":"];
NSInteger hours = [[components objectAtIndex:0] integerValue];
NSInteger minutes = [[components objectAtIndex:1] integerValue];
NSInteger seconds = [[components objectAtIndex:2] integerValue];
return [NSNumber numberWithInteger:(hours * 60 * 60) + (minutes * 60) + seconds];
}

Answer 2

Just an alternative if you have to handle both "HH:mm:ss" and "mm:ss"
extension String {
/**
Converts a string of format HH:mm:ss into seconds
### Expected string format ###
````
HH:mm:ss or mm:ss
````
### Usage ###
````
let string = "1:10:02"
let seconds = string.inSeconds // Output: 4202
````
- Returns: Seconds in Int or if conversion is impossible, 0
*/
var inSeconds : Int {
var total = 0
let secondRatio = [1, 60, 3600] // ss:mm:HH
for (i, item) in self.components(separatedBy: ":").reversed().enumerated() {
if i >= secondRatio.count { break }
total = total + (Int(item) ?? 0) * secondRatio[i]
}
return total
}
}

Answer 3

Swift 4 - improved from #Beslan Tularov's answer.
extension String{
var integer: Int {
return Int(self) ?? 0
}
var secondFromString : Int{
var components: Array = self.components(separatedBy: ":")
let hours = components[0].integer
let minutes = components[1].integer
let seconds = components[2].integer
return Int((hours * 60 * 60) + (minutes * 60) + seconds)
}
}
Usage
let xyz = "00:44:22".secondFromString
//result : 2662

Answer 4

You can also try like this:
extension String{
//format hh:mm:ss or hh:mm or HH:mm
var secondFromString : Int{
var n = 3600
return self.components(separatedBy: ":").reduce(0) {
defer { n /= 60 }
return $0 + (Int($1) ?? 0) * n
}
}
}
var result = "00:44:22".secondFromString //2662
result = "00:44".secondFromString //2640
result = "01:44".secondFromString //6240
result = "999:10".secondFromString //3597000
result = "02:44".secondFromString //9840
result = "00:01".secondFromString //60
result = "00:01:01".secondFromString //61
result = "01:01:01".secondFromString //3661
result = "12".secondFromString //43200
result = "abcd".secondFromString //0

Answer 5

From what you've,
double totalSeconds = [hour doubleValue] * 60 * 60 + [min doubleValue] * 60 + [sec doubleValue];
NSNumber * seconds = [NSNumber numberWithDouble:totalSeconds];

Answer 6

The following is a String extension for converting a time string (HH:mm:ss) to seconds
extension String {
func secondsFromString (string: String) -> Int {
var components: Array = string.componentsSeparatedByString(":")
var hours = components[0].toInt()!
var minutes = components[1].toInt()!
var seconds = components[2].toInt()!
return Int((hours * 60 * 60) + (minutes * 60) + seconds)
}
}
how to use
var exampleString = String().secondsFromString("00:30:00")

Answer 7

You can use the following extension to do that (Swift 3):
extension String {
func numberOfSeconds() -> Int {
var components: Array = self.components(separatedBy: ":")
let hours = Int(components[0]) ?? 0
let minutes = Int(components[1]) ?? 0
let seconds = Int(components[2]) ?? 0
return (hours * 3600) + (minutes * 60) + seconds
}
}
And for example, use it like:
let seconds = "01:30:10".numberOfSeconds()
print("%# seconds", seconds)
Which will print:
3790 seconds