jQuery UI sortable with fixed rows - jquery-ui

Question

I'm using a jQuery UI sortable with a table (works fine). I would like to make the header and last row fixed (non-moveable).
The jQuery UI docs indicate this can be done using a selector for items, but I am at a loss for the syntax.
Here is the relevant code:
<script type="text/javascript">
$(function () {
$("#response_options tbody.content").sortable();
$("#response_options tbody.content").disableSelection();
});
</script>
<table id="response_options" class="data-table">
<tbody class="content">
<tr>
<th>Links</th><th>Response</th>
</tr>
<tr class="sortable-row">
<td>Edit</td>
<td>Item 1</td>
</tr>
<tr class="sortable-row">
<td>Edit</td>
<td>Item 2</td>
</tr>
<tr class="sortable-row">
<td>Edit</td>
<td>Item 3</td>
</tr>
<tr class="sortable-row">
<td>Edit</td>
<td>Item 4</td>
</tr>
<tr class="sortable-row">
<td>Edit</td>
<td>Item 5</td>
</tr>
<tr>
<td>Edit</td>
<td>Item 1</td>
</tr>
</tbody>
</table>
The selector goes inside .sortable(...):
$("#response_options tbody.content").sortable();
as
$("#response_options tbody.content").sortable( items: ??? );
and it should be possible to select only items with class="sortable-row"; but again, I am at a loss for the syntax.

Answer 1

This should work:
$("#response_options tbody.content").sortable({items: 'tr.sortable-row'});

Answer 2

This worked for me:
jQuery(".sortable tbody").sortable({
items: 'tr:not(:first)'
});

Answer 3

For this markup:
<table id="tableid">
<thead>
<tr>
<th>namr</th>
<th>id</th>
</tr>
</thead>
<tbody>
<tr>
<td>jagadeesh</td>
<td>1</td>
</tr>
<tr>
<td>jagadeesh</td>
<td>2</td>
</tr>
</tbody>
</table>
Use this jQuery:
$('#tableid tbody').sortable();
It will move only body content of table you cannot move header part.