I get a url string and would like to transform it to a legal http url:
For example:
"http://one/two/three%four/five#five?six seven" should turn into "http://one/two/three%25four/five%23five?six%20seven"
However, HttpUtility.UrlEncode does not help, as it encodes the entire string (including the legal "://").
See if this what you want?
Uri uri = new Uri("http://one/two/three%four/#five?six seven");
string url = uri.AbsoluteUri + uri.Fragment;
// url will be "http://one/two/three%25four/#five?six%20seven#five?six%20seven"
How about splitting and rejoining:
string url = "http://one/two/three%four/#five?six seven";
string encodedUrl = "http://" + string.Join("/", url.Substring(7).Split('/').Select(part => HttpUtility.UrlEncode(part)).ToArray());
Related
Following is my code for URL encoding
extension String {
var encoded: String {
return self.addingPercentEncoding(withAllowedCharacters: .urlQueryAllowed) ?? ""
}
}
But I am facing issue if url contains %20. it is encoding it as %2520 although I have added urlQueryAllowed
Original url: https://mydomain.in/retailers_data_v2/retailer/320/17372-Tea%20Coffee%20Vending%20Machine.JPG
Encoded url: https://mydomain.in/retailers_data_v2/retailer/320/17372-Tea%2520Coffee%2520Vending%2520Machine.JPG
If you have an already encoded URL String, you first need to remove percent encoding before applying it again.
If you aren't sure whether the URL you have is already encoded or not, you can simply use an if let on removingPercentEncoding and depending on its result, either call addingPercentEncoding on the original URL or on the one that you removed the encoding from.
let alreadyEncodedURLString = "https://mydomain.in/retailers_data_v2/retailer/320/17372-Tea%20Coffee%20Vending%20Machine.JPG"
if let unencodedURLString = alreadyEncodedURLString.removingPercentEncoding {
unencodedURLString.addingPercentEncoding(withAllowedCharacters: .urlQueryAllowed)
} else {
alreadyEncodedURLString.addingPercentEncoding(withAllowedCharacters: .urlQueryAllowed)
}
when trying to decode the following encoded string, it does not work...it´s actually doing nothing...leaving the string as it is:
https://www.foodhat.app/?rOpeningTime=08:00&rClosingTime=20:00&rClosedUntil=2019-08-19&pId=557&rId=69&goTo=CUSTOMER_PRODUCT_DETAILS&cName=Duhok&pName=%D9%85%D9%86%D8%B3%D9%81+%D8%AF%D9%88%D9%84%D9%85%D8%A9&rName=Mansaf+Alzain&rMinOrderValue=15000
pName is arabic, so do not wonder the encoding of it.
I use str.removingPercentEncoding to decode the string...but as said...it doesn´t remove the "+" (e.g. in rName)!
Result is
let str = "https://www.foodhat.app/?rOpeningTime=08:00&rClosingTime=20:00&rClosedUntil=2019-08-19&pId=557&rId=69&goTo=CUSTOMER_PRODUCT_DETAILS&cName=Duhok&pName=%D9%85%D9%86%D8%B3%D9%81+%D8%AF%D9%88%D9%84%D9%85%D8%A9&rName=Mansaf+Alzain&rMinOrderValue=15000"
print(str.removingPercentEncoding!)
//https://www.foodhat.app/?rOpeningTime=08:00&rClosingTime=20:00&rClosedUntil=2019-08-19&pId=557&rId=69&goTo=CUSTOMER_PRODUCT_DETAILS&cName=Duhok&pName=منسف+دولمة&rName=Mansaf+Alzain&rMinOrderValue=15000
What am I doing wrong?
Use 'str.replacingOccurrences()' instead. A better solution would be to use 'URLComponents', 'queryItems' to perform the filtering on the targeted queryItem, to ensure that '+' removal is not done for the entire url.
When decoding an URL you should use URLComponents :
let url = URL(string:"https://www.foodhat.app/?rOpeningTime=08:00&rClosingTime=20:00&rClosedUntil=2019-08-19&pId=557&rId=69&goTo=CUSTOMER_PRODUCT_DETAILS&cName=Duhok&pName=%D9%85%D9%86%D8%B3%D9%81+%D8%AF%D9%88%D9%84%D9%85%D8%A9&rName=Mansaf+Alzain&rMinOrderValue=15000")!
let components = URLComponents(url: url, resolvingAgainstBaseURL: false)
print(components)
Output is :
[rOpeningTime=08:00, rClosingTime=20:00, rClosedUntil=2019-08-19, pId=557, rId=69, goTo=CUSTOMER_PRODUCT_DETAILS, cName=Duhok, pName=منسف+دولمة, rName=Mansaf+Alzain, rMinOrderValue=15000]
I have an url like this:
http://mywebsite.net/User/UserInfo?key=123&userId=456&json=[{"UserName":"user#gmail.com","Password":"","Test":"item","projectId":"123","ItemsJSON":[{"Id":10,"Id2":0,"Quantity":5}]
How do I make this url work in a NSURL. I will call UIApplication.sharedApplication().openURL
I tried doing:
let encodedString = sender.url.stringByAddingPercentEncodingWithAllowedCharacters(.URLUserAllowedCharacterSet())!
But I ended up with:
http%3A%2F%2Fmywebsite.net%2FUser%2FUserInfo%3Fkey=123&userId=456&json=%5B%7B%22UserName%22%3A%22user%40gmail.com%22,%22Password%22%3A%22%22,%22Test%22%3A%22item%22,%22projectId%22%3A%22123%22,%22ItemsJSON%22%3A%5B%7B%22Id%22%3A10,%22Id2%22%3A0,%22Quantity%22%3A5%7D%5D
I'm using the following code to search for a place:
let correctedAddress:String! = self.searchResults[(indexPath as NSIndexPath).row].addingPercentEncoding(withAllowedCharacters: CharacterSet.symbols)
let url = URL(string: "https://maps.googleapis.com/maps/api/geocode/json?address=\(correctedAddress)&sensor=false")
self.searchResults[(indexPath as NSIndexPath).row] returns a string like this: "São Paulo - State of São Paulo, Brazil"
The string that is the parameter of URL is like this (after the encoding):
https://maps.googleapis.com/maps/api/geocode/json?address=Optional(\%22State%20of%20S%C3%A3o%20Paulo%2C%20Brazil\%22)&sensor=false
If I search for this URL in my web browser, the JSON is shown. So I assume it is a valid URL, but the URL(string: ..) method always returns nil
I probably need to change my encoding, I tried using CharacterSet.urlPathAllowed but always return nil.
What kind of encoding I should use? Or there is something else wrong?
Try to remove the Optional(...) string in the url
https://maps.googleapis.com/maps/api/geocode/json?address=\%22State%20of%20S%C3%A3o%20Paulo%2C%20Brazil\%22&sensor=false
I believe that's the reason for the URL is returning nil.
This worked for me :
"https://maps.googleapis.com/maps/api/geocode/json?address=" + correctedAddress + "&sensor=false"
App crashes with following url:
let jsonUrl = "http://api.com/алматы/events"
let session = NSURLSession.sharedSession()
let shotsUrl = NSURL(string: jsonUrl)
let task = session.dataTaskWithURL(shotsUrl!)
Log:
fatal error: unexpectedly found nil while unwrapping an Optional value
It's because of cyrillic symbols in url. How can I solve this issue. Thanks for your help!
Swift 4
Using String Extension
Create a swift file named String+Extension.swift and paste this code
import UIKit
extension String{
var encodeUrl : String
{
return self.addingPercentEncoding(withAllowedCharacters: NSCharacterSet.urlQueryAllowed)!
}
var decodeUrl : String
{
return self.removingPercentEncoding!
}
}
and Use it like so: (sample according to question):
"http://api.com/алматы/events".encodeUrl
Try this:
let encodedUrl = jsonUrl.stringByAddingPercentEncodingWithAllowedCharacters(URLQueryAllowedCharacterSet)
Something like this:
let apiHost = "http://api.com/"
let apiPath = "алматы/events"
let escapedPath = apiPath.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLHostAllowedCharacterSet())
let url = NSURL(string: "\(apiHost)\(escapedPath!)")
Obviously you should do something smarter than just force unwrap escapedPath.
Using the Wikipedia page for Swift as an example:
https://ru.wikipedia.org/wiki/Swift_(язык_программирования)
Becomes:
https://ru.wikipedia.org/wiki/Swift_(%D1%8F%D0%B7%D1%8B%D0%BA_%D0%BF%D1%80%D0%BE%D0%B3%D1%80%D0%B0%D0%BC%D0%BC%D0%B8%D1%80%D0%BE%D0%B2%D0%B0%D0%BD%D0%B8%D1%8F)
Which when pasted into the browser takes you to the right page (and most browsers will conveniently render the UFT-8 characters for you).
Non-ASCII characters (and many special characters) need to be escaped in a URL. Chrome and other browser do it automatically. And they unescape the URLs in the address bar for a nicer display.
So if you have a static URL, just paste it into the adressbar, press enter, selected the URL again, copy and paste it to your app:
So instead of:
let jsonUrl = "http://api.com/алматы/events"
You'll get:
let jsonUrl = "http://api.com/%D0%B0%D0%BB%D0%BC%D0%B0%D1%82%D1%8B/events"
Try stringByAddingPercentEncodingWithAllowedCharacters: defined on NSString. You may see people suggesting stringByAddingPercentEscapesUsingEncoding:, but that method is deprecated in iOS 9.
There are also a few predefined NSCharacterSets in Foundation, such as URLHostAllowedCharacterSet and URLPathAllowedCharacterSet. Therefore, if you really have to parse the unescaped URL in code (using preprocessed URLs, mentioned in the accepted answer, is usually a much better idea), you can write a helper method like this:
import Foundation
func url(scheme scheme: String, host: String, path: String) -> NSURL? {
let components = NSURLComponents()
components.scheme = scheme
components.host = host.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLHostAllowedCharacterSet())
components.path = path.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLPathAllowedCharacterSet())
return components.URL
}
// evaluates to http://api.com/%25D0%25B0%25D0%25BB%25D0%25BC%25D0%25B0%25D1%2582%25D1%258B/events
url(scheme: "http", host: "api.com", path: "/алматы/events")
Note that the above documentation mentions that
This method is intended to percent-encode an URL component or subcomponent string, NOT an entire URL string.
That's because according RFC 3986, not all parts of an URL can be percent-encoded (e.g. scheme - http/https/etc.)
in xamarin:
var uri = new Uri (url);
var nsurl = new NSUrl (uri.GetComponents (UriComponents.HttpRequestUrl, UriFormat.UriEscaped));
UIApplication.SharedApplication.OpenUrl (nsurl);
URLs cannot contain Cyrillic characters. There are standards how to translate Cyrillic characters into valid URLs - you might find something if you search for "Punicode" (the P is intentional).