Rails 3.0 Frontend URL's with slugs, backend URL's without - ruby-on-rails

Is there any way to use the slugs generated by overriding "to_param" in the model for only the frontend?
Eg, In my model I have:
def to_param
"#{id}-#{name.parameterize}"
end
And it works great on the frontend. But the problem seems to be, on the backend adminstrative side, you can edit the name/title. This ends up with a bunch of weird stuff when I start editing things.
Is there any easy way to simply use the #{id} only if I'm in the namespaced admin backend?

Please check the gem Friendly_ID. It deals with slugs in a very nice way.
If the name changes (which is your identifier for the edited object), the id does not change.
So when you edit or update an object, you could use the id for identification, rather than the slug.

Related

How to redirect old url to new url in rails using just routes?

The old sitemap of my application has already been indexed to Google now. For some one visiting my rails app with old url shouldn't go to 404.
The old url looked like this
/search?sub_category=210
Now after making them friendly, it looks like this:
/search?sub_category=milling-and-drilling.
I tried redirecting it from controller but it causes too much issues on other things. Such as filters which are using the same params. Is there a way I can do it from routes file?
Instead of using redirect_to route_path(id) you would do redirect_to route_path(object.find_by_id(id).name)
How to redirect old url to new url in rails using just routes?
AFAIK (As far as I know), no. (if through params)
The main job of routes.rb is to determine what "code" will handle the request, particularly that which matches request.url and the request.method. It does not concern yet of the request parameters nor its values: these would be handled in the controllers itself. Although, you can route based on parameters (or any information about the "request") through a routes constraint
Alternative Solution:
Instead of finding by ID, now find by "Slug name or ID".
In your models, particularly in this specific example of yours, add something like:
class SubCategory < ApplicationRecord
# if you're using a gem for the "friendly" urls, you don't need this method, and just use theirs.
def self.friendly_find!(friendly_id)
# this may not necessarily be `name`, maybe `slug`? or depending on your case
find_by(name: friendly_id) || find(friendly_id)
end
end
And in your controllers, just replace wherever you're finding a record (maybe also to other models not just SubCategory as needed be), particularly in your search action:
def search
sub_category = SubCategory.friendly_find!(params[:sub_category])
end
NOTE: friendly_find! will raise an Error if no record is found.

How to create a scaffold with differing controller and model names?

I'm making a versioned JSON API in rails, where the controllers also respond to HTML, meaning it can be accessed as a browser or through an app I'm developing. The controllers have the form Model::V1::UsersController (Model instead of API since they don't just respond to JSON), and I currently have the following in my routes.rb:
namespace :model, path: 'm', as: '' do
# For objects in the model, accessible by JSON (through the app) or HTML (through the browser, using forms to send data to the server).
scope module: 'v1', constraints: OrConstraint.new([APIConstraint.new(1), APIConstraint.new(:default)]) do
resources :users do
collection do
post :sign_in
end
end
end
end
I plan to add more models to my API, but how can I use scaffolding to do this? For example, to create a controller Model::V1::CommentsController, but using the Comment model, instead of Model::V1::Comments.
I've been trying to figure this out for hours, and googling for people with similar problems shows that a few people say not to use scaffolding at all in this case: I don't want to do this, as it would mean writing all the views myself, which would be very time-consuming. Apart from that, I can't find much. nifty-generators was suggested somewhere, but it doesn't seem to be maintained anymore: no activity since 2012. I'm new to rails, and it might be that I've missed something quite obvious, but I find it surprising that not many others have had the same issue.
I've considered making my own generator, but looking at the source of https://github.com/rails/rails/blob/master/railties/lib/rails/generators/rails/scaffold/scaffold_generator.rb, it seems very complicated.
EDIT: I've just discovered that I can pass the --model-name parameter to the rails scaffold generator to achieve what I want, but for some reason it still tries to create a model with the same name as the controller. How can I change this?
I've settled with this solution, by not generating a model at all using the scaffold generator:
To create Model::V1::CommentsController as the controller and Comments as the model:
rails g model comment
rails g scaffold model/v1/comments --model-name=comment --no-orm

Friendly URLs in Github

How has Github managed to get friendly URLs for representing repos of users? For a project called abc by username foo, how do they work around with a URL like: http://github.com/foo/abc. Are they fetching the abc model for the DB from the title in the URL (which sounds unreasonable as they are modifying the titles). How are they transferring the unique ID of the abc repo which they can fetch and show in the view?
The reason I ask is that I am facing a similar problem of creating friendlier URLs to view a resource. MongoDB's object IDs are quite long and make the URL look horrific. Is there a workaround? All the tutorials that demonstrate CRUD (or REST) URLs for a resource always include the object's unique ID(e.g. http://mysite.org/post/1 or http://mysite.org/post/1/edit. Is there a better way to do it?
Not having seen their code, I couldn't tell you exactly how they do it, but if you're using Rails there are at least two Ruby gems that will give you similar results:
Take a look at Slugged and friendly_id
http://github.com/foo/abc is a unique repository identifier (for that repo's master branch). I'd assume that somewhere they have a table that looks like:
repository-id | user-id | project-id
and are just looking up based on user and project rather than repository-id.
You'd need to do some domain-specific mapping between internal and user-friendly ids, but you'd need to make sure that was a 1:1 mapping.
See this rails cast on methods, gems and solutions to common problems you might get while modifying the application to use friendly urls.
http://railscasts.com/episodes/314-pretty-urls-with-friendlyid?view=asciicast
(although Ryan Bates deserves the rep+ for this)
I mocked a structure like this using FriendlyID and Nested Resources.
Essentially, use friendly ID to get the to_param-ish slugs in your routes, then set up nested resources. Using GitHub as an example:
routes.rb
resources :users do
resources :repositories
end
Then in your controller, say, for repositories, you can check the existence of params[:user_id] and use that to determine the user from the route. The reason I check for existence is because I did something like (roughly):
/myrepositories/:repository_id
/:user_id/:repository_id
So my controller does:
def show
#user = params[:user_id] ? User.find(params[:user_id]) : current_user
end
I followed this tutorial here to get started with this same project.
This is called URL rewriting if the web server does it (such as Apache), and routing when it happens in a web application framework (such as Ruby on Rails).
http://www.sinatrarb.com/intro#Routes
http://httpd.apache.org/docs/current/mod/mod_rewrite.html

Thoughts regarding model ids in rails routes and validation

I am new to RoR and started working on a typical 'has_many' association (ie. a user has many friends). I have everything working correctly, but I don't like having the ids exposed in the url. I find that I need to add extra validation in my controller to make sure the ids represent valid associations in case the user manually entered different ids.
Personally I would like to see the ids out of the url and passed via some other means but that is not always possible. Shallow nesting of resources will help reduce the number of ids I need to validate at least.
What is the RoR philosophy on this? I have not seen anything specific to this issue.
Thanks
the URL has parameters if it is a GET url.
Try using POST parameters, which means your url will no longer be cluttered. Note that a malicious user can still send a made-up POST request using curl.
My approach to this is implementing proper authorization. If the user requests information for an object he is not permitted to read, this should be handled by an authorization framework.
With CanCan or Declarative Authorization you can define rules that replace your "manual" (and error-prone) checks in controllers.
I like the IDs being in the URL. That is what REST is about. Getting information for specific Resources, which have to be identified with an ID.
You can use Friendly ID in order to replace the integer ID by a slug (e.g. users/tollbooth instead of users/42).
basically ror routes by default takes id as key to generate urls. If you are not fan of id based urls then you can always override urls by using to_param inside model.
def to_param
# make sure this field is always present & unique
username
end
then by default you will start seeing username instead of id inside urls
How to find object inside controller actions
User.find_by_username(params[:id])
If you dont want to do this manually make use of slug gems like friendly id

url optimization in rails?

Hello I want to create seo optimize url in rails.Same like done in stackoverflow.
Right now this is my url
http://localhost:3000/questions/56
I want to make it something like this:-
http://localhost:3000/questions/56/this-is-my-optimized-url
i am using restful approach.
is there any plug-in available for this.
I know you asked for a plugin, but a dead simple approach is just to override the to_param method in your model. You can just append the seo name to the id.
For example:
class Question < ActiveRecord::Base
#has attribute name.
def to_param
"#{id}-#{name.parameterize}"
end
end
The path/url helpers will then generate a path like so:
show_question_path(#question)
>> /questions/12345-my-question-name
You do not need to do anything to your routes.
Your controller will remain Question.find(params[:id]) as the param will have to_i called on it, which will strip off the name and just return the id.
I highly recommend looking into the friendly_id plugin. The FriendlyId Guide is a great place to start. I have been using this in production for a number of months and it works great.
Using the cached slugs feature makes this a very scalable solution. Additionally I'd recommend using it combination with stringex if you deal with non-ASCII characters.

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