I want to have 2 models in one view. The page contains both LoginViewModel and RegisterViewModel.
e.g.
public class LoginViewModel
{
public string Email { get; set; }
public string Password { get; set; }
}
public class RegisterViewModel
{
public string Name { get; set; }
public string Email { get; set; }
public string Password { get; set; }
}
Do I need to make another ViewModel which holds these 2 ViewModels?
public BigViewModel
{
public LoginViewModel LoginViewModel{get; set;}
public RegisterViewModel RegisterViewModel {get; set;}
}
I need the validation attributes to be brought forward to the view. This is why I need the ViewModels.
Isn't there another way such as (without the BigViewModel):
#model ViewModel.RegisterViewModel
#using (Html.BeginForm("Login", "Auth", FormMethod.Post))
{
#Html.TextBoxFor(model => model.Name)
#Html.TextBoxFor(model => model.Email)
#Html.PasswordFor(model => model.Password)
}
#model ViewModel.LoginViewModel
#using (Html.BeginForm("Login", "Auth", FormMethod.Post))
{
#Html.TextBoxFor(model => model.Email)
#Html.PasswordFor(model => model.Password)
}
There are lots of ways...
with your BigViewModel
you do:
#model BigViewModel
#using(Html.BeginForm()) {
#Html.EditorFor(o => o.LoginViewModel.Email)
...
}
you can create 2 additional views
Login.cshtml
#model ViewModel.LoginViewModel
#using (Html.BeginForm("Login", "Auth", FormMethod.Post))
{
#Html.TextBoxFor(model => model.Email)
#Html.PasswordFor(model => model.Password)
}
and register.cshtml same thing
after creation you have to render them in the main view and pass them the viewmodel/viewdata
so it could be like this:
#{Html.RenderPartial("login", ViewBag.Login);}
#{Html.RenderPartial("register", ViewBag.Register);}
or
#{Html.RenderPartial("login", Model.LoginViewModel)}
#{Html.RenderPartial("register", Model.RegisterViewModel)}
using ajax parts of your web-site become more independent
iframes, but probably this is not the case
I'd recommend using Html.RenderAction and PartialViewResults to accomplish this; it will allow you to display the same data, but each partial view would still have a single view model and removes the need for a BigViewModel
So your view contain something like the following:
#Html.RenderAction("Login")
#Html.RenderAction("Register")
Where Login & Register are both actions in your controller defined like the following:
public PartialViewResult Login( )
{
return PartialView( "Login", new LoginViewModel() );
}
public PartialViewResult Register( )
{
return PartialView( "Register", new RegisterViewModel() );
}
The Login & Register would then be user controls residing in either the current View folder, or in the Shared folder and would like something like this:
/Views/Shared/Login.cshtml: (or /Views/MyView/Login.cshtml)
#model LoginViewModel
#using (Html.BeginForm("Login", "Auth", FormMethod.Post))
{
#Html.TextBoxFor(model => model.Email)
#Html.PasswordFor(model => model.Password)
}
/Views/Shared/Register.cshtml: (or /Views/MyView/Register.cshtml)
#model ViewModel.RegisterViewModel
#using (Html.BeginForm("Login", "Auth", FormMethod.Post))
{
#Html.TextBoxFor(model => model.Name)
#Html.TextBoxFor(model => model.Email)
#Html.PasswordFor(model => model.Password)
}
And there you have a single controller action, view and view file for each action with each totally distinct and not reliant upon one another for anything.
Another way is to use:
#model Tuple<LoginViewModel,RegisterViewModel>
I have explained how to use this method both in the view and controller for another example: Two models in one view in ASP MVC 3
In your case you could implement it using the following code:
In the view:
#using YourProjectNamespace.Models;
#model Tuple<LoginViewModel,RegisterViewModel>
#using (Html.BeginForm("Login1", "Auth", FormMethod.Post))
{
#Html.TextBoxFor(tuple => tuple.Item2.Name, new {#Name="Name"})
#Html.TextBoxFor(tuple => tuple.Item2.Email, new {#Name="Email"})
#Html.PasswordFor(tuple => tuple.Item2.Password, new {#Name="Password"})
}
#using (Html.BeginForm("Login2", "Auth", FormMethod.Post))
{
#Html.TextBoxFor(tuple => tuple.Item1.Email, new {#Name="Email"})
#Html.PasswordFor(tuple => tuple.Item1.Password, new {#Name="Password"})
}
Note that I have manually changed the Name attributes for each property when building the form. This needs to be done, otherwise it wouldn't get properly mapped to the method's parameter of type model when values are sent to the associated method for processing. I would suggest using separate methods to process these forms separately, for this example I used Login1 and Login2 methods. Login1 method requires to have a parameter of type RegisterViewModel and Login2 requires a parameter of type LoginViewModel.
if an actionlink is required you can use:
#Html.ActionLink("Edit", "Edit", new { id=Model.Item1.Id })
in the controller's method for the view, a variable of type Tuple needs to be created and then passed to the view.
Example:
public ActionResult Details()
{
var tuple = new Tuple<LoginViewModel, RegisterViewModel>(new LoginViewModel(),new RegisterViewModel());
return View(tuple);
}
or you can fill the two instances of LoginViewModel and RegisterViewModel with values and then pass it to the view.
Use a view model that contains multiple view models:
namespace MyProject.Web.ViewModels
{
public class UserViewModel
{
public UserDto User { get; set; }
public ProductDto Product { get; set; }
public AddressDto Address { get; set; }
}
}
In your view:
#model MyProject.Web.ViewModels.UserViewModel
#Html.LabelFor(model => model.User.UserName)
#Html.LabelFor(model => model.Product.ProductName)
#Html.LabelFor(model => model.Address.StreetName)
Do I need to make another view which holds these 2 views?
Answer:No
Isn't there another way such as (without the BigViewModel):
Yes, you can use Tuple (brings magic in view having multiple model).
Code:
#model Tuple<LoginViewModel, RegisterViewModel>
#using (Html.BeginForm("Login", "Auth", FormMethod.Post))
{
#Html.TextBoxFor(tuple=> tuple.Item.Name)
#Html.TextBoxFor(tuple=> tuple.Item.Email)
#Html.PasswordFor(tuple=> tuple.Item.Password)
}
#using (Html.BeginForm("Login", "Auth", FormMethod.Post))
{
#Html.TextBoxFor(tuple=> tuple.Item1.Email)
#Html.PasswordFor(tuple=> tuple.Item1.Password)
}
Add this ModelCollection.cs to your Models
using System;
using System.Collections.Generic;
namespace ModelContainer
{
public class ModelCollection
{
private Dictionary<Type, object> models = new Dictionary<Type, object>();
public void AddModel<T>(T t)
{
models.Add(t.GetType(), t);
}
public T GetModel<T>()
{
return (T)models[typeof(T)];
}
}
}
Controller:
public class SampleController : Controller
{
public ActionResult Index()
{
var model1 = new Model1();
var model2 = new Model2();
var model3 = new Model3();
// Do something
var modelCollection = new ModelCollection();
modelCollection.AddModel(model1);
modelCollection.AddModel(model2);
modelCollection.AddModel(model3);
return View(modelCollection);
}
}
The View:
enter code here
#using Models
#model ModelCollection
#{
ViewBag.Title = "Model1: " + ((Model.GetModel<Model1>()).Name);
}
<h2>Model2: #((Model.GetModel<Model2>()).Number</h2>
#((Model.GetModel<Model3>()).SomeProperty
a simple way to do that
we can call all model first
#using project.Models
then send your model with viewbag
// for list
ViewBag.Name = db.YourModel.ToList();
// for one
ViewBag.Name = db.YourModel.Find(id);
and in view
// for list
List<YourModel> Name = (List<YourModel>)ViewBag.Name ;
//for one
YourModel Name = (YourModel)ViewBag.Name ;
then easily use this like Model
My advice is to make a big view model:
public BigViewModel
{
public LoginViewModel LoginViewModel{get; set;}
public RegisterViewModel RegisterViewModel {get; set;}
}
In your Index.cshtml, if for example you have 2 partials:
#addTagHelper *,Microsoft.AspNetCore.Mvc.TagHelpers
#model .BigViewModel
#await Html.PartialAsync("_LoginViewPartial", Model.LoginViewModel)
#await Html.PartialAsync("_RegisterViewPartial ", Model.RegisterViewModel )
and in controller:
model=new BigViewModel();
model.LoginViewModel=new LoginViewModel();
model.RegisterViewModel=new RegisterViewModel();
I want to say that my solution was like the answer provided on this stackoverflow page: ASP.NET MVC 4, multiple models in one view?
However, in my case, the linq query they used in their Controller did not work for me.
This is said query:
var viewModels =
(from e in db.Engineers
select new MyViewModel
{
Engineer = e,
Elements = e.Elements,
})
.ToList();
Consequently, "in your view just specify that you're using a collection of view models" did not work for me either.
However, a slight variation on that solution did work for me. Here is my solution in case this helps anyone.
Here is my view model in which I know I will have just one team but that team may have multiple boards (and I have a ViewModels folder within my Models folder btw, hence the namespace):
namespace TaskBoard.Models.ViewModels
{
public class TeamBoards
{
public Team Team { get; set; }
public List<Board> Boards { get; set; }
}
}
Now this is my controller. This is the most significant difference from the solution in the link referenced above. I build out the ViewModel to send to the view differently.
public ActionResult Details(int? id)
{
if (id == null)
{
return new HttpStatusCodeResult(HttpStatusCode.BadRequest);
}
TeamBoards teamBoards = new TeamBoards();
teamBoards.Boards = (from b in db.Boards
where b.TeamId == id
select b).ToList();
teamBoards.Team = (from t in db.Teams
where t.TeamId == id
select t).FirstOrDefault();
if (teamBoards == null)
{
return HttpNotFound();
}
return View(teamBoards);
}
Then in my view I do not specify it as a list. I just do "#model TaskBoard.Models.ViewModels.TeamBoards" Then I only need a for each when I iterate over the Team's boards. Here is my view:
#model TaskBoard.Models.ViewModels.TeamBoards
#{
ViewBag.Title = "Details";
}
<h2>Details</h2>
<div>
<h4>Team</h4>
<hr />
#Html.ActionLink("Create New Board", "Create", "Board", new { TeamId = #Model.Team.TeamId}, null)
<dl class="dl-horizontal">
<dt>
#Html.DisplayNameFor(model => Model.Team.Name)
</dt>
<dd>
#Html.DisplayFor(model => Model.Team.Name)
<ul>
#foreach(var board in Model.Boards)
{
<li>#Html.DisplayFor(model => board.BoardName)</li>
}
</ul>
</dd>
</dl>
</div>
<p>
#Html.ActionLink("Edit", "Edit", new { id = Model.Team.TeamId }) |
#Html.ActionLink("Back to List", "Index")
</p>
I am fairly new to ASP.NET MVC so it took me a little while to figure this out. So, I hope this post helps someone figure it out for their project in a shorter timeframe. :-)
Create one new class in your model and properties of LoginViewModel and RegisterViewModel:
public class UserDefinedModel()
{
property a1 as LoginViewModel
property a2 as RegisterViewModel
}
Then use UserDefinedModel in your view.
you can always pass the second object in a ViewBag or View Data.
This is a simplified example with IEnumerable.
I was using two models on the view: a form with search criteria (SearchParams model), and a grid for results, and I struggled with how to add the IEnumerable model and the other model on the same view. Here is what I came up with, hope this helps someone:
#using DelegatePortal.ViewModels;
#model SearchViewModel
#using (Html.BeginForm("Search", "Delegate", FormMethod.Post))
{
Employee First Name
#Html.EditorFor(model => model.SearchParams.FirstName,
new { htmlAttributes = new { #class = "form-control form-control-sm " } })
<input type="submit" id="getResults" value="SEARCH" class="btn btn-primary btn-lg btn-block" />
}
<br />
#(Html
.Grid(Model.Delegates)
.Build(columns =>
{
columns.Add(model => model.Id).Titled("Id").Css("collapse");
columns.Add(model => model.LastName).Titled("Last Name");
columns.Add(model => model.FirstName).Titled("First Name");
})
...
)
SearchViewModel.cs:
namespace DelegatePortal.ViewModels
{
public class SearchViewModel
{
public IEnumerable<DelegatePortal.Models.DelegateView> Delegates { get; set; }
public SearchParamsViewModel SearchParams { get; set; }
....
DelegateController.cs:
// GET: /Delegate/Search
public ActionResult Search(String firstName)
{
SearchViewModel model = new SearchViewModel();
model.Delegates = db.Set<DelegateView>();
return View(model);
}
// POST: /Delegate/Search
[HttpPost]
public ActionResult Search(SearchParamsViewModel searchParams)
{
String firstName = searchParams.FirstName;
SearchViewModel model = new SearchViewModel();
if (firstName != null)
model.Delegates = db.Set<DelegateView>().Where(x => x.FirstName == firstName);
return View(model);
}
SearchParamsViewModel.cs:
namespace DelegatePortal.ViewModels
{
public class SearchParamsViewModel
{
public string FirstName { get; set; }
}
}
I have created a dropdownlist by fetching data from database.I want to display the selected value on click of submit. In controller I am trying to store the selected value in ViewBag and display it. When I debugged the code, I came to know that viewbag stores null value.The following line stores the value in viewbag.
ViewBag.scode = emp.Service_Code;
While debugging, Service_Code shows the value but it gets stored as null in ViewBag. Please help me in solving this issue.
Model
public class Employee
{
public int Service_Code { get; set; }
public string Service_Name { get; set; }
public IEnumerable<SelectListItem> ser_code { get; set; }
}
View
#model mvclearn.Models.Employee
#{
ViewBag.Title = "menu";
}
<link href="~/Content/bootstrap.css" rel="stylesheet" />
<div class="container">
#using (Html.BeginForm("save", "Test", FormMethod.Post))
{
#Html.DropDownListFor(m => m.Service_Code, Model.ser_code, "--select-",new { #class = "form-control" })
<input type="submit" value="submit" class="btn-block" />
}
</div>
<div>You entered:#ViewBag.scode</div>
Controller
public ActionResult menu()
{
RevenueDashboardEntities rdb = new RevenueDashboardEntities();
var model = new Employee()
{
ser_code = new SelectList(db.Services, "Service_Code", "Service_Name")
};
return View(model);
}
[HttpPost]
public ActionResult save(Employee emp)
{
RevenueDashboardEntities rdb = new RevenueDashboardEntities();
ViewBag.scode = emp.Service_Code;
return View("menu");
}
The selected value is already getting post in the action via model in Service_Code property of it.
What you need here is return your model back to view and it will populate the selected value with what was selected at form post:
[HttpPost]
public ActionResult save(Employee emp)
{
RevenueDashboardEntities rdb = new RevenueDashboardEntities();
// this is needed to populate the items of dropdown list again
emp.ser_code = new SelectList(db.Services, "Service_Code", "Service_Name");
// sending model back to view
return View("menu",emp);
}
Now the value will be auto selected on page load after form is posted and you can display the value on the page inside div by writing:
<div>You entered: #Model.Service_Code</div>
I have a view which contains a dropdown list and on dropdownlist item being selected I load a partial view. And when the form is submitted I want to be able to get both the values from main view and partial view during form submit.
Here is the main view
#model AdminPortal.Areas.Hardware.Models.CreateModule
#{
ViewBag.Title = "Create Module";
Layout = "~/Views/shared/_BootstrapLayout.basic.cshtml";
}
#Html.ValidationSummary(true)
<fieldset class="form-horizontal">
<legend>Add a Module <small>Create</small></legend>
#using (Html.BeginForm("CreateModule", "Module", new{id="AddModuleForm"}))
{
#Html.ValidationSummary(true)
<div class ="controls">
<div class="input-block-level">#Html.TextBoxFor(model => model.ModuleId, new {#placeholder = "ModuleID"})</div>
<br/>
<div class ="input-block-level" id="selectedModuleTypeName">#Html.DropDownListFor(model => model.SelectedModuleTypeName, Model.TypeNames,"Select Moduletype", new{id = "ModuleList"})</div>
<br/>
<div id="partialDiv"></div>
</div>
<div class="form-actions" id="buttons">
<button type="submit" class="btn btn-primary" id="Submit">Save changes</button>
#Html.ActionLink("Cancel", "ModuleList", null, new { #class = "btn " })
</div>
}
</fieldset>
<div>
#Html.ActionLink("Back to List", "ModuleList")
</div>
<script>
$("#buttons").hide();
$("#ModuleList").on("change", function() {
var modId = $(this).val();
$.get('#Url.Action("GetModulePropertyName", "Module")', { moduleTypeValue: modId }, function(result) {
$("#partialDiv").html(result);
});
//uncomment following section to check if the partial view is working properly
/*.done(function() { alert("done"); })
.fail(function() { alert("fail"); })
.always(function() { alert("completed"); });*/
});
$("#buttons").show();
</script>
and here is the partial view
#model IEnumerable<string>
#foreach(var names in Model)
{
<div class="input-block-level">#Html.TextBoxFor(m=>names, new{Value="", placeholder=names})</div>
<br/>
}
Here is my model
public class CreateModule
{
//Empty form to handle form serialization
public CreateModule()
{
}
[Required]
public string ModuleId { get; set; }
[DataType(DataType.DateTime)]
public DateTime DateEntered { get; set; }
[Required]
public string SelectedModuleTypeName { get; set; }
public IEnumerable<SelectListItem> TypeNames { get; set; }
public List<Property> Properties { get; set; }
}
public class Property
{
public string Name { get; set; }
public string Value { get; set; }
}
Here is the method that script in main view forwards to
[HttpGet]
public ActionResult GetModulePropertyName(string moduleTypeValue)
{
var moduleKindId = _repository.GetModuleKindId(moduleTypeValue);
var modulePropertyNames = _repository.GetModuleKindPropertyNames(moduleTypeValue);
return PartialView("GetModulePropertyName",modulePropertyNames);
}
and finally here is httppost method for the main view
[HttpPost]
public ActionResult CreateModule(CreateModule moduleV)
{
var module = new Module
{
ModuleTypeId = Convert.ToInt64(moduleV.SelectedModuleTypeName),
ModuleId = moduleV.ModuleId,
DateEntered = moduleV.DateEntered,
};
if (ModelState.IsValid)
{
_repository.AddModule(module);
Success("Module added successfully!");
return RedirectToAction("ModuleList", "Module", new {area = "Hardware"});
}
Error("Something went wrong!");
return RedirectToAction("CreateModule", "Module", new { area = "Hardware" });
}
Current situation:
When the form is posted, the properties value of the model that is being passed via partial view is null. I get other values, like typename, Module ID.
What I'd want:
I also want to get the value of properties that is being passed via partial view.
You don't have any input field for the Properties property anywhere in your form. So it will always be null. That's normal.
Here's how you could proceed. Start by setting the correct navigational property so that the helper generates correct names of the corresponding input fields.
Also make sure that you are passing an IEnumerable<Property> model to the partial if you want to be able to get them back correctly:
[HttpGet]
public ActionResult GetModulePropertyName(string moduleTypeValue)
{
var moduleKindId = _repository.GetModuleKindId(moduleTypeValue);
IList<Property> model = ...
return PartialView("GetModulePropertyName", model.ToList());
}
and in your partial view use an editor template:
#model IList<Property>
#{
// This indicates the current navigational context to the helpers
ViewData.TemplateInfo.HtmlFieldPrefix = "Properties";
}
#Html.EditorForModel()
and the last step is to define a custom editor template for the Property class: ~/Views/Shared/EditorTemplates/Property.cshtml (note that the name and location of the template is important)
#model Property
<div class="input-block-level">
#Html.HiddenFor(m => m.Name)
#Html.TextBoxFor(m => m.Value, new { placeholder = Model.Name })
</div>
<br />
Try using the
List<Property>
as a model in your partial view and pass the CreateModule.Properties as model from your View
The problem is model binder can not figure out there
#Html.TextBoxFor(m=>names, new{Value="", placeholder=names})
belongs to as the "names" is not a property on your model class. If you need to bind to the CreateModule.Properties you need to change the partial view to emit textboxes with aproprate names, like this one:
#model IEnumerable<string>
#
{
int i=0;
}
#foreach(var names in Model)
{
<div class="input-block-level">#Html.TextBox("Properties[" + i + "].Value")</div>
<br/>
}
I'm trying to make a file upload to the server using Uploadify, but not working the TempData to pass variables between controllers and I have not found an error.
I'm trying passing the variables fileName and file with TempData of the controller "GetFile" to the controller "ModelCreate".
The controller "GetFile" works well, but when I check the value of "date1" and "date2" in the controller "ModelCreate" is null
I just want to make the file saved in the controller "ModelCreate"
public string GetFile(HttpPostedFileBase file)
{
var fileName = this.Server.MapPath("~/Informs/" + System.IO.Path.GetFileName(file.FileName));
if (System.IO.File.Exists(fileName))
return "has been uploaded successfully";
file.SaveAs(fileName);
TempData["NameFile"] = fileName;
TempData["File"] = file;
return "1";
}
[HttpPost]
public ActionResult ModelCreate(INFORME inform)
{
var date1 = TempData["NameFile"] as string;
var date2 = TempData["File"] as HttpPostedFileBase;
date2.SaveAs(date1);
.
.
.
.
}
why "date1" and "date2" are null?
Blessings
There's not enough information to provide an answer to this question. As requested in the comments section I will provide a full example illustrating a form allowing the user to fill a couple of input fields and upload a file.
As always we start by defining the view model which will reflect the information that we want to display on the view:
public class MyViewModel
{
[Required]
public string TextField { get; set; }
[DataType(DataType.MultilineText)]
public string TextAreaField { get; set; }
public bool CheckBoxField { get; set; }
[Required]
public HttpPostedFileBase FileField { get; set; }
}
Then we could have a controller with 2 actions: a GET action that simply displays the form and a POST action that processes the form information when submitted:
public class HomeController : Controller
{
public ActionResult Index()
{
var model = new MyViewModel();
return View(model);
}
[HttpPost]
public ActionResult Index(MyViewModel model)
{
if (!ModelState.IsValid)
{
// there were validation errors => redisplay the view
return View(model);
}
// at this stage the model is valid => we could do some processing
// first let's save the file
var appData = Server.MapPath("~/app_data");
var file = Path.Combine(appData, Path.GetFileName(model.FileField.FileName));
model.FileField.SaveAs(file);
// then we could process the other properties
// ...
return Content("Thanks for submitting the data");
}
}
and finally a strongly typed view top the view model:
#model MyViewModel
#Html.ValidationSummary(false)
#using (Html.BeginForm(null, null, FormMethod.Post, new { enctype = "multipart/form-data" }))
{
<div>
#Html.EditorFor(x => x.TextField)
#Html.ValidationMessageFor(x => x.TextField)
</div>
<div>
#Html.EditorFor(x => x.TextAreaField)
#Html.ValidationMessageFor(x => x.TextAreaField)
</div>
<div>
#Html.CheckBoxFor(x => x.CheckBoxField)
#Html.ValidationMessageFor(x => x.CheckBoxField)
</div>
<div>
#Html.LabelFor(x => x.FileField)
#Html.TextBoxFor(x => x.FileField, new { type = "file" })
</div>
<button type="submit">OK</button>
}
I have the following models:
class A
{
// ...some properties
public B InnerField { get; set; }
}
and
class B
{
public int Id { get; set; }
// ..other properties
}
and a page that has a model Class A and inside the page I have a partial view bound to Class B inside a form.
The value of the Id (in the partial view) is set correctly to the model's Id value (different from 0) but when I submit the page the model has the Id value 0. The Id value is not modified in the component or elsewhere.
Page
...other parts of main page
<%using (Html.BeginForm("ModifyHotel", "Hotel",
FormMethod.Post, new { enctype = "multipart/form-data"}))
{%>
<% Html.RenderPartial("~/Views/Shared/ModifyBaseItem.ascx",
new ModifyItemRequestBaseView() { ItemId = Model.Item.Id });%>
<%}%>
...other parts of main page
Partial View
...other parts of partial view
<br/>
Add Photo: <%:Html.FileBoxFor(x => x.PhotoFile, null)%>
<br/>
Add Video: <%:Html.FileBoxFor(x => x.VideoFile, null)%>
<br/>
<input type="submit" value="Submit changes" />
...other parts of partial view
What can I do to keep the value of the inner model when the post is made?
Thanks,
Controller:
public class HomeController : Controller
{
public ActionResult Index()
{
A model = new A() { InnerField = new B() { Id = 5 }};
return View(model);
}
[HttpPost]
public ActionResult Index(B model)
{
//on postback the model should have the value 5 here
return View();
}
}
View:
#model MvcApplication11.Models.A
#using (Html.BeginForm())
{
#Html.Partial("_IndexForm", Model.InnerField)
<input type="submit" />
}
Partial:
#model MvcApplication11.Models.B
#Html.EditorFor(m => m.Id)