in iPhone App How to detect the screen resolution of the device - ios

Question

In iPhone App,
while running the App on device How to detect the screen resolution of the device on which App is running?

Answer 1

CGRect screenBounds = [[UIScreen mainScreen] bounds];
That will give you the entire screen's resolution in points, so it would most typically be 320x480 for iPhones. Even though the iPhone4 has a much larger screen size iOS still gives back 320x480 instead of 640x960. This is mostly because of older applications breaking.
CGFloat screenScale = [[UIScreen mainScreen] scale];
This will give you the scale of the screen. For all devices that do not have Retina Displays this will return a 1.0f, while Retina Display devices will give a 2.0f and the iPhone 6 Plus (Retina HD) will give a 3.0f.
Now if you want to get the pixel width & height of the iOS device screen you just need to do one simple thing.
CGSize screenSize = CGSizeMake(screenBounds.size.width * screenScale, screenBounds.size.height * screenScale);
By multiplying by the screen's scale you get the actual pixel resolution.
A good read on the difference between points and pixels in iOS can be read here.
EDIT: (Version for Swift)
let screenBounds = UIScreen.main.bounds
let screenScale = UIScreen.main.scale
let screenSize = CGSize(width: screenBounds.size.width * screenScale, height: screenBounds.size.height * screenScale)

Answer 2

UIScreen class lets you find screen resolution in Points and Pixels.
Screen resolutions is measured in Points or Pixels. It should never be confused with screen size. A smaller screen size can have higher resolution.
UIScreen's 'bounds.width' return rectangular size in Points
UIScreen's 'nativeBounds.width' return rectangular size in Pixels.This value is detected as PPI ( Point per inch ). Shows the sharpness & clarity of the Image on a device.
You can use UIScreen class to detect all these values.
Swift3
// Normal Screen Bounds - Detect Screen size in Points.
let width = UIScreen.main.bounds.width
let height = UIScreen.main.bounds.height
print("\n width:\(width) \n height:\(height)")
// Native Bounds - Detect Screen size in Pixels.
let nWidth = UIScreen.main.nativeBounds.width
let nHeight = UIScreen.main.nativeBounds.height
print("\n Native Width:\(nWidth) \n Native Height:\(nHeight)")
Console
width:736.0
height:414.0
Native Width:1080.0
Native Height:1920.0
Swift 2.x
//Normal Bounds - Detect Screen size in Points.
let width = UIScreen.mainScreen.bounds.width
let height = UIScreen.mainScreen.bounds.height
// Native Bounds - Detect Screen size in Pixels.
let nWidth = UIScreen.mainScreen.nativeBounds.width
let nHeight = UIScreen.mainScreen.nativeBounds.height
ObjectiveC
// Normal Bounds - Detect Screen size in Points.
CGFloat *width = [UIScreen mainScreen].bounds.size.width;
CGFloat *height = [UIScreen mainScreen].bounds.size.height;
// Native Bounds - Detect Screen size in Pixels.
CGFloat *width = [UIScreen mainScreen].nativeBounds.size.width
CGFloat *height = [UIScreen mainScreen].nativeBounds.size.width

Answer 3

Use it in App Delegate: I am using storyboard
- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions{
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;
//----------------HERE WE SETUP FOR IPHONE 4/4s/iPod----------------------
if(iOSDeviceScreenSize.height == 480){
UIStoryboard *iPhone35Storyboard = [UIStoryboard storyboardWithName:#"iPhone" bundle:nil];
// Instantiate the initial view controller object from the storyboard
UIViewController *initialViewController = [iPhone35Storyboard instantiateInitialViewController];
// Instantiate a UIWindow object and initialize it with the screen size of the iOS device
self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
// Set the initial view controller to be the root view controller of the window object
self.window.rootViewController = initialViewController;
// Set the window object to be the key window and show it
[self.window makeKeyAndVisible];
iphone=#"4";
NSLog(#"iPhone 4: %f", iOSDeviceScreenSize.height);
}
//----------------HERE WE SETUP FOR IPHONE 5----------------------
if(iOSDeviceScreenSize.height == 568){
// Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone4
UIStoryboard *iPhone4Storyboard = [UIStoryboard storyboardWithName:#"iPhone5" bundle:nil];
// Instantiate the initial view controller object from the storyboard
UIViewController *initialViewController = [iPhone4Storyboard instantiateInitialViewController];
// Instantiate a UIWindow object and initialize it with the screen size of the iOS device
self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
// Set the initial view controller to be the root view controller of the window object
self.window.rootViewController = initialViewController;
// Set the window object to be the key window and show it
[self.window makeKeyAndVisible];
NSLog(#"iPhone 5: %f", iOSDeviceScreenSize.height);
iphone=#"5";
}
} else if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {
// NSLog(#"wqweqe");
storyboard = [UIStoryboard storyboardWithName:#"iPad" bundle:nil];
}
return YES;
}

Answer 4

For iOS 8 we can just use this [UIScreen mainScreen].nativeBounds , like that:
- (NSInteger)resolutionX
{
return CGRectGetWidth([UIScreen mainScreen].nativeBounds);
}
- (NSInteger)resolutionY
{
return CGRectGetHeight([UIScreen mainScreen].nativeBounds);
}

Answer 5

See the UIScreen Reference: http://developer.apple.com/library/ios/#documentation/uikit/reference/UIScreen_Class/Reference/UIScreen.html
if([[UIScreen mainScreen] respondsToSelector:NSSelectorFromString(#"scale")])
{
if ([[UIScreen mainScreen] scale] < 1.1)
NSLog(#"Standard Resolution Device");
if ([[UIScreen mainScreen] scale] > 1.9)
NSLog(#"High Resolution Device");
}

Answer 6

Use this code it will help for getting any type of device's screen resolution
[[UIScreen mainScreen] bounds].size.height
[[UIScreen mainScreen] bounds].size.width

Answer 7

If your goal is to get the model resolution type and not the resolution values themeselfs, this Swift solution might be helpful:
import UIKit
#objc(IphoneModelScreenSize)
public class IphoneModelScreenSize: NSObject {
// MARK: Enums
public enum IphoneModelScreenSize: Int {
case notAnIphone = 0,
twoThreeOrFour = 1,
se = 2,
sixSevenOrEight = 3,
plus = 4,
elevenXorXS = 5,
elevenProMaxOrXsMax = 6
}
// MARK: Class properties
public class func screenSize() -> IphoneModelScreenSize {
let bounds = UIScreen.main.bounds
let screenWidth = bounds.size.width
let screenHeight = bounds.size.height
switch (screenWidth, screenHeight) {
case (320.0, 480.0):
return .twoThreeOrFour
case (320.0, 568.0):
return .se
case (375.0, 667.0):
return .sixSevenOrEight
case (414.0, 736.0):
return .plus
case (375.0, 812.0):
return .elevenXorXS
case (414.0, 896.0):
return .elevenProMaxOrXsMax
default:
return .notAnIphone
}
}
public class func screenSizeStringValue() -> String {
return screenSizeEnumToString(screenSize())
}
// MARK: Private properties
private class func screenSizeEnumToString(_ screenSize: IphoneModelScreenSize) -> String {
var screenSizeAsString: String
switch screenSize {
case .notAnIphone:
screenSizeAsString = "Not an Iphone"
case .twoThreeOrFour:
screenSizeAsString = "2G, 3G, 3GS, 4 or 4s"
case .se:
screenSizeAsString = "5, 5s, 5c or SE"
case .sixSevenOrEight:
screenSizeAsString = "6, 6s, 7 or 8"
case .plus:
screenSizeAsString = "6+, 6s+, 7+ or 8+"
case .elevenXorXS:
screenSizeAsString = "11 Pro, X or Xs"
case .elevenProMaxOrXsMax:
screenSizeAsString = "11, Xr, 11 Pro Max or Xs Max"
}
return screenSizeAsString
}
}