In an Ant buildfile I have a path stored in an Ant property: ${file}.
How can I get just the filename and extension without the full path?
Use the Basename task
<basename property="filename" file="${file}"/>
Related
It is possible to make a fileset optional by setting the attribute erroronmissingdir to false.
How to do the same with an embedded src node in the javac task?
I have a source directory which always exists and I have an source directory with generated source files which exists only sometimes. If I try this:
<javac>
<src path="${src-dir}"/>
<src path="${build-dir}/${src-dir}" erroronmissingdir="false"/>
</javac>
I get the error that the attribute erroronmissingdir is not supported by the src element. The there an alternative?
You should be able to encapsulate filset within a src.
<src>
<fileset dir="${build-dir}/${src-dir}" erroronmissingdir="false"/>
</src>
Let me know if that works for you.
let's say I have a file named build_dev_linux.xml.
My question is
How can I find the ant script XML file's own name, build_dev_linux.xml
so I can put it on variable or property in that XML file.?
Ant defines a useful list of built-in properties:
basedir the absolute path of the project's basedir (as set
with the basedir attribute of <project>).
ant.file the absolute path of the buildfile.
ant.version the version of Ant
ant.project.name the name of the project that is currently executing;
it is set in the name attribute of <project>.
ant.project.default-target
the name of the currently executing project's
default target; it is set via the default
attribute of <project>.
ant.project.invoked-targets
a comma separated list of the targets that have
been specified on the command line (the IDE,
an <ant> task ...) when invoking the current
project.
ant.java.version the JVM version Ant detected; currently it can hold
the values "1.2", "1.3",
"1.4", "1.5" and "1.6".
ant.core.lib the absolute path of the ant.jar file.
The ant.file property is what you need. If you want just the file name without the path then you can use the basename task like
<basename file="${ant.file}" property="buildfile"/>
How can I use Ant to execute each php file in a directory? The output for the php execution should overwrite the original file.
The directory is on a localhost webserver with php installed. I assume the solution would involve GET and have src point to the http equivalent of each file.
Some dynamic version of
c:/webroot/php/file1.php
c:/webroot/php/file2.php
translate into
get src="localhost/php/file1.php"
get src="localhost/php/file2.php"
and then have the output overwrite itself.
Why not use the php command line combined with the ANT apply task?
Something like:
<apply executable="C:\PHP5\php.exe">
<arg value="-f"/>
<fileset dir="c:/webroot/php" includes="*.php"/>
</apply>
It's not clear to me why you want to overwrite your source files....
Update
Alternatively use an embedded groovy script
<fileset id="phpfiles" dir="c:/webroot/php" includes="*.php"/>
<groovy>
project.references.phpfiles.each {
def file = new File(it.toString())
ant.get(src:"http://localhost/php/${file.name}", dest:"output/${file.name}")
}
</groovy>
When creating a zip from ant, how can I exclude all sub directories and files from a given directory?
I have tried the following but it doesn't seem to prevent them from being included in the zip
<target name="zip">
<zip destfile="C:\Projects\example\builds\.zip"
excludes="C:\Projects\example\logs\**\*.*">
...
...
</zip>
</target>
From reading the documentation, and from reading the ant definitive guide I would assume that **\ should exclude any directory, and *.* would exclude any file of any extension
I want to include the logs directory, but nothing inside it.
I would recommend the following:
Change the name of your destfile to "C:\Projects\example\builds\logs.zip"
Set your basedir to "C:\Projects\example\"
Change your excludes value to "C:\Projects\example\logs\**\*" (that means any file)
Another option might be to use the project-defined basedir, and change all your paths to relative UNIX-like values.
I don't want to get the basedir -- that appears to contain the build.xml script -- I want the CWD of the call to ant itself.
Basically, I want to do this:
$ cd /home/chrisr/projects/some_project
$ ant -f ../../tools/ant-build-rules/library.xml build-library
At this point, I need two things:
The path to ant-build-rules in absolute form; this is currently found in the basedir property, so I'm set there.
The path of some_project, in absolute form. This is what I don't know how to get.
Which property contains this information?
The java property user.dir contains the current directory
<project name="demo" default="printCWD">
<target name="printCWD">
<echo message="${user.dir}"/>
</target>
</project>
There is no such property, but you can run a script to get it.
${bsh:WorkDirPath.getPath()}
See urbancode.com.